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Catalog – Helical and Bevel-Helical X.. Series Gear Units 47

4Additional documentationProject Planning for Drives

4

4 Project Planning for Drives4.1 Additional documentation

In addition to the information in this catalog, SEW-EURODRIVE offers extensivedocumentation covering the entire topic of electrical drive engineering. This is primarilydocumentation from the "Drive Engineering Practical Implementation" series. You canorder the latest documentation from SEW-EURODRIVE. The documentation can alsobe downloaded in PDF format from the SEW homepage (http://www.sew-eurodrive.com).

Drive Engineer-ing Practical Implementation

The publication "Drive Engineering Practical Implementation Drive Selection withSEW-EURODRIVE Gearmotors" provides extensive information on characteristics,differentiating features and application areas of SEW drives. A comprehensivecollection and assignment of the most important formulae for drive calculation as well asdetailed examples for the most frequently used applications make this documentationan important tool for project planning and an essential addition to SEW-EURODRIVEproduct catalogs.

4.2 Project planning procedureThe following flow diagram illustrates the process for the project planning of X seriesindustrial gear units.

Fill out the drive selection sheet

Calculate the basic data

Select the application factors

Calculate the required nominal gear unit torque

Select the gear unit size

Check the thermal rating

Check the peak load conditions

M , , n i,

F , F , F

M

M M

K2 2

Smin F start

N2

K2 max K2 zul

η

≤

Request

Step 1

Step 2

Step 3

Step 4

Step 5

Select the nominal motor power P

M

Step 6

Step 7

Step 8

Check the external additional forcesF , F , F , FR2 R1 A1 A2

Step 9

Select the optional accessories (if requested), such as- Oil drain valve- Alternative sealing system- Motor connecton (e.g. motor adapter)- Connection for auxiliary drive- Condition monitoring- Drive package for conveyor belt drives (incl. swing base, drive coupling,...)- Surface protection and final color

Step10

Summary of technical information

Step 11

,

P K1

<P T

48 Catalog – Helical and Bevel-Helical X.. Series Gear Units

4 Project planning procedureProject Planning for Drives

Step 1: Drive selection data

60603AEN

1.0 Machine on LSS (usually driven machine)

1.3 Ambient te,perature [°C] [...]normal min.

1.5 Installation location [X]

small rooms (va � 0.5 m/s)

large rooms and halls (va � 1.4 m/s)

outside protected against the sun (va � 3 m/s)

1.6 Ambient conditions [X]normal

dusty

damp

corrosive

dry

1.4 Altitude [m] [...]

max.

2.0 Load characteristics2.1 Required speed n [1/min] [...]

2.2 Operating power on HSS P [kW] [...]

2.3 Operating torque on LSS M [kNm] [...]

2.4 Frequency of load peaks (M or P )

normal min. max.

per hour

2.5 Starts per hour [...]starts

2.6 Direction of location under load (LSS) [X]clockwise (CW)counterclockwise (CCW)

both directionsreversible

2.7 Operating hours/day [X]< 3 hours3 ... 10 hours> 10 hours

2.8 Backstop required [X]NoYes

2.9 Exact load cycle attached [X]NoYes

3.0 Machine on HSS (usually driving machine)3.1 Type: [X]

AC motor AC motor/inverter DC motor

Hydraulic motor Servomotor

3.2 Motor power P [kW] [...]

3.4 Nominal motor torque M [kNm] [...] 3.5 Input speed n [1/min] [...]

3.6 If electric motor: [X] [...] IEC

NEMAMotor size (IEC or NEMA code):

3.7 Mounting of the motor [X] [...] B3B5V1other:

4.0 Gear unit requirements

4.1 Gear unit type [X]Helical gear unit X.F.. Bevel-helical gear unit X.K..

4.4 Shaft position [X]

normal min. max.

2

K1

K2

K1 max.K2 max.

M

M 1

normal min. max.

normal min. max.

normal min. max. normal min. max.

0 1 2

3 4

1.1 Area of application/industry [...]

1.2 Application [...]

4.2 Mounting position [X]M1M2M3

M4M5M6

4.3 Mounting surface [X]F1F2F3

F4F5F6

3.3 Motor speed n [kW] [...]normal min. max.

M

Legend: [...] = data to be filled in [X] = indicate your selection w.

Combustion engine 1...3 cylinders

Combustion engine � 4 cylinders

4

1

2

3

4

6

0

5

35 6


4Project planning procedureProject Planning for Drives

4

60606AEN

6

4.6 Required service factor FS min. [X] [...]

4.7 Required bearing service life Lh min [...]

Foot-mounted

Flange-mounted

Torque Arm

4.9 LSS connection to customer machine shaft [X] [...]

Elastic coupling (claw coupling or pin coupling)

Flexible coupling

Rigid flange coupling

Drum couplingChain sprocket

4.8 Housing fixation [X]

4.10 LSS gear unit version [X] [...]LSS version (if solid shaft)

4.15 Electrical supply [X] [...]

4.11 HSS connection to motor [X]

Customer installation (base frame)

Motor power PM / Motor torque MM

Operating power on LSS PK2 Operating torque on LSS MK2

based on

Hours

Solid shaft with keyway

Other

LSS version (if hollow shaft)Hollow shaft with keyway

Other

Hollow shaft for shrink disc connection,includes shrink disc

Pinion

Hollow shaft – torque arm

Hollow shaft – foot mounting

Hollow shaft – flange mounting

Other

Mains supply VMains

3-phase 1-phaseAC DC

V

Auxiliary voltage VAux

3-phase 1-phaseAC

DC

V

Enclosure IP

Explosion protection required

YesNo

Solid shaft without keywaySplined solid shaft DIN 5480

Splined hollow shaft DIN 5480

Motor adapter with elastic coupling

Swing base/base frameMotor scoop with V-belt drive

4.12 Machine shaft bearings2 Bearings, gear unit transfers only torque1 bearing opposite gear unit, the gear unit acts as a bearing point1 bearing directly at the gear unit, the gear unit acts as a bearing point

4.14 Forces acting on drive shaft HSS [X] [...]

Axial force FA [kN]

Radial force FR [kN]

Distance from shaft shoulder X [mm]

Application angle of the radial force [°]

or variable

4.13 Forces acting on the output shaft LSS [X] [...]

Shaft 3 Shaft 4

Axial force FA [kN]

Radial force FR [kN]

Distance from shaft shoulder X [mm]

Application angle of the radial force [°]

or variable

4.16 Permitted cooling (if required) [X]

Fan

External oil/air cooler

External oil/water cooler

Not permittedPermitted

Cooling water available

YesNo

Motor scoopOther, see diagram

Cooling cover/cartridge

Cooling water temperature °C

HZ

HZ

Shaft 3

Shaft 3

Shaft 4

Shaft 4

Shaft 0 Shaft 1

Shaft 0

Shaft 0

Shaft 1

Shaft 1

Shaft 2

Shaft 2

Shaft 2

4

3

1

2 0

α

0°FA

- +

X

FR

5



Step 2: Calculating the basic data – MK2, n2, i, η

Constant torqueMK2 = Operating torque on LSS [Nm]PK1 = Operating power on HSS [kW]n2 = Output speed (LSS) rpmPM = Nominal motor power [kW]h = Efficiency

Equivalent torque with load spectrum and constantSpeed n2

The following figure shows a load example:

MK2 = Operating torque on LSS [Nm]

= Time slice of the load

I, II,...n = Types of load

Gear ration1 = Input speed (HSS) rpmn2 = Output speed (LSS) rpm

The following efficiency levels apply to gear units – η

η = f (i; gear unit type)The efficiency of the gear unit is mainly determined by the gearing and bearing friction as well by churning losses. The following guide values apply for calculating splash and pressure lubrication:

X2F.. = 0.975 X3F.. = 0.96X4F.. = 0.94X2K.. = 0.97X3K.. / X3T.. = 0.955X4K.. / X4T.. = 0.935

P= K1MK2

ηxn2

9550xComment: If is not known -> = PK1

PK1 P M [Nm]

× ×t

= IMK2equiv

(M )K2

I

tII

+t n

(M )K2

II

+ .... (M )K2

n

×6.66.66.6

6.6

∑ tN∑ tN ∑ tN

I

II III IV

tI

tII

tIII t

IV

∑ tN

MK2 M

K2

MK2 M

K2M

K2

MK2equi

I

IIIII

IV

∑ tN

tI

∑ tN

tI

....

i =n

n

1

2



4

Step 3: Selecting the application factors

Application-specific service factor FS minThe application-specific service factor FSmin takes account of the typical load behaviorwith regard to the driven machine.Recommended values with reference to• Field of application• Type of driven machine• Operating period / dayare given in the following table.

Application-specific service factor FS min

Peak load factor FF page 54Startup factor Fstart page 54

INFORMATIONThese tables apply only to gear units driven by electric motors. For other types of drivemotors, the following correction values apply:• Combustion engines with four or more cylinders:

• FS min (selection table) + 0.25

• Combustion engines with one to three cylinders: FS min (selection table) + 0.5

INFORMATIONIn the event of deviations from the typical load behavior, please consult SEW-EURODRIVE.



Field of application Type of application(driven machine)

Application-specific service factor FS minOperating period / day

< 3 h 3-10 h > 10 h

Waste water treatment

Impeller areator - 1.80 2.00

Thickeners 1.15 1.25 1.50

Vacuum filters 1.15 1.30 1.50

Collectors 1.15 1.25 1.50

Screw pumps - 1.30 1.50

Brush areators - - 2.00

Mining

Crushers 1.55 1.75 2.00

Screens and shakers 1.55 1.75 2.00

Slewing drives - 1.55 1.80

Bucket wheel excavators 1) 1) 1)

Energy

Frequency inverters - 1.80 2.00

Water wheels (low speed) - - 1.70

Water turbines - - 1)

Conveyors

Bucket elevators - 1.40 1.50

Vertical conveyors other - 1.50 1.80

Belt conveyors ≤ 100 kW 1.15 1.25 1.40

Belt conveyors > 100 kW 1.15 1.30 1.50

Apron feeders - 1.25 1.50

Screw feeders 1.15 1.25 1.50

Shakers, screens 1.55 1.75 2.00

Escalators 1.25 1.25 1.50

Passenger lifts 1) 1) 1)

Rubber and plastic industry

Extruders (plastic) - 1.40 1.60

Extruders (rubber) - 1.50 1.80

Rubber rollers (two in a row) 1.55 1.75 2.00

Rubber rollers (three in a row) - 1.50 1.75

Warming mills 1.35 1.50 1.75

Calenders - 1.65 1.65

Mills 1.55 1.75 2.00

Mixing mills 1) 1) 1)

Slab rollers 1.55 1.75 2.00

Refiners 1.55 1.75 2.00

Tire machines 1) 1) 1)

Timber industry Timber industry 1) 1) 1)

Cranes and hoists Cranes and hoists 2) 2) 2)

Food industry

Crushers and mills - - 1.75

Beet slicers - 1.25 1.50

Drying drums - 1.25 1.50

Metal production and processing

Winders - 1.60 1.75

Slitters 1.55 1.75 2.00

Table conveyors, individual drives 1) 1) 1)

Table conveyors, group drives 1) 1) 1)

Table conveyors, reciprocating 1) 1) 1)

Wire drawing machines 1.35 1.50 1.75

Rollers 1) 1) 1)



4

Mills and drums

Coooling and drying drums - 1.50 1.60

Rotary kilns - - 2.00

Ball mills - - 2.00

Coal mills - 1.50 1.75

Pulp and paper industry

Debarking drums and machines 1.55 1.80 -

Rolls (pick-up, wire drive, wire suction) - 1.80 2.00

Drying cylinders (anti-friction bearings) - 1.80 2.00

Calenders (anti-friction bearings) - 1.80 2.00

Filters (pressure and vacuum) - 1.80 2.00

Beaters and chippers 1.55 1.75 2.00

Jordan mills - 1.50 1.75

Presses (bark, felt, glue, suction) - - 1.75

Reels - - 1.75

Pulpers 1) 1) 1)

Washer filters - - 1.50

Yankee cylinders (dryers) 1) 1) 1)

Pumps

Centrifugal pumps 1.15 1.35 1.45

Reciprocating pumps (single-cylinder) 1.35 1.50 1.80

Reciprocating pumps (multi-cylinder) 1.20 1.40 1.50

Screw pumps - 1.25 1.50

Rotary pumps (gear type, vane) - - 1.25

Agitators and mixers

Agitators for liquids 1.00 1.25 1.50

Agitators for liquids (variable density) 1.20 1.50 1.65

Agitators for solids (non-uniform material) 1.40 1.60 1.70

Agitators for solids (uniform material) - 1.35 1.40

Concrete mixers - 1.50 1.50

Cableways

Material ropeways - 1.40 1.50

Aerial tramways 1) 1)

Surface lifts 1) 1) 1)

Continuous aerial tramways 1) 1) 1)

Funicular railways 1) 1) 1)

Fans

Heat exchangers 1.50 1.50 1.50

Dry cooling towers - - 2.00

Dry cooling tower 2.00 2.00 2.00

Blowers (axial and radial) 1.50 1.50 1.50

Compressors

Reciprocating compressors - 1.80 1.90

Radial compressors - 1.40 1.50

Screw-type compressors - 1.50 1.75

1) Consult SEW-EURODRIVE2) Please contact SEW-EURODRIVE; dimensioning according to FEM1001

Field of application Type of application(driven machine)

Application-specific service factor FS minOperating period / day

< 3 h 3-10 h > 10 h



Peak load factor FF

The peak load factor FF takes account of the overload capacity of the gearing and therotating parts.

Startup factor Fstart

The startup factor Fstart takes account of the overload caused by startup.

Step 4: Calculating the required nominal gear unit torque MN2

Constant load direction – constant torque:

Reversing direction of load constant torque:

Peak factor FF

Frequency of peak load per hour

1...5 6...20 21...40 41...80 81...160 > 160

1.0 1.2 1.3 1.5 1.75 2.0

Startup mode Startup factor Fstart

Direct 3.0

Soft start 1.8

Frequency inverter 1.5...2.01)

1) Dependent on setting

Star / delta 1.3

Hydraulic coupling without delay chamber 2.0

Hydraulic coupling with delay chamber 1.6

MN2MK2FS min

= Nominal gear unit torque [kNm]= Operating torque on the LSS [kNm]= Application-specific service factor

MN2MK2FS min


MN2 FS min [kNm]x MK2>

x 1.43MN2 FS min [kNm]x MK2>



4

Step 5: Selecting the gear unit size MN2

The selection of the gear unit size is based on the nominal gear unit torque MN2according to the tables showing the overview of speed and power ratings on page 147and subsequent pages.

The selection table guide on the foldout page of the catalog can be used to quickly locatethe speed/power overview table and to make a preliminary selection of the gear unitsize.If input speed n1 < 1000 rpm, then the value for 1000 rpm can be used for MN2.For input speeds n1 > 1800 rpm, please contact SEW-EURODRIVE. The following table shows an excerpt from the selection tables as an example.

X.F200...n1 = 1000 1/min 79 kNm PTH [kW]

i N n2 MN2 PN1

[min-1] [kNm] [kW]

6.37.189

1011.212.5141618

155137125110998779696154

66.970.171.975.076.879.079.079.079.079.0

11151029967889817741668589521459

315300320305300300300295270265

530500520485470465465460415410

920860850760690650620590510480

880830820750680660630600520500

10501000990910840810780750660630

*)*)*)*)*)*)

240240250250

*)*)

315305380380430425415410

800770880830840820850830760740

13501300135012001150110011001050920870

1550145015001400130012501250120010501000

*)*)*)

225265265290290275275

395385460435455455475470440430

1000950

1000940910890890870780760

780740780710670640630600540510

980930960880840810790760680650

2022.42528

31.535.54045505663718090

4843393431272522211816141311

77.679.079.079.079.079.079.079.079.079.079.079.079.079.0

40736533129226723521919317615613311710795

195185175170170165160155155155140135135130

295285265260260250240235235230205200200195

330305275265255235225215210200175170165160

335315285275265250235230220215185180175170

430405370360350330310300295285250245240235

170165160155160150160160155155145145140140

285275260255260245250245240240220215215210

510485450440435410395385380370330320315305

570530475455440405385370355340295285275265

660620560540520490465445430415360350340330

195185175175175165170165165160150145145140

310295280275275260255250250245220215215210

530500465455450425405395385375330320315310

335315290280270255245235230220195190185180

445415385370365340325315310300265260255250

100112125140160180200224250280315355

108.98.17.26.65.85.04.44.03.63.32.9

79.079.079.079.079.079.079.079.079.079.079.079.0

877770625750433835312825

1101051051059795868585837775

------------

------------

130125125125110110989595938683

------------

115115115110105100939292908481

------------

------------

190180180175155150135130130125115110

------------

115115115115105100949292918481

------------

------------

1401351351301201151051001001009289

------------

M1M5M4

2/3/4

M1 M5 M4

H O2

H O2 +H O2

H O2

H O2 +H O2

H O2

H O2 +H O2



Step 6: Selecting the nominal motor power PM

Step 7: Checking the peak load conditions MK2 zul; MK2 max

Permitted peak output torque MK2 zul:Constant load direction

Reversing load direction:

Calculate the peak output torque MK2 max:

* If the startup factor Fstart is not specified, please take account of page 54.

Check the gear unit selection:

PMPK1PK2η

= Nominal motor power [kW]= Operating power on HSS [kW]= Operating power on LSS [kW]= Efficiency

P =PK2

M ηPK1≥ [kW]

INFORMATIONFor gear units with bath lubrication, please contact SEW-EURODRIVE.

MK2 zulMN2FF

= Permitted peak output torque [kNm]= Nominal gear unit torque [kNm]= Peak load factor

MK2 zulMN2FF


MK2 maxPMFstartn2η

= Peak output torque [kNm]= Nominal motor power [kW]= Startup factor = Output speed [rpm]= Efficiency

MK2 maxMK2 zul

= Peak output torque [kNm]= Permitted peak output torque [kNm]

M =K2 zul

2 x MN2

FF

[kNm]

M =K2 zul

2 x MN2

FF

[kNm]x 0.7

M =K2 maxP x 9.55 M

n2 [kNm]

x ηx

Fstart*

MK2 zul

MK2 max

≤



4

Step 8: Checking the thermal rating PTThe thermal rating PT of a gear unit is the power that a gear unit can transmitcontinuously without exceeding a certain oil temperature.

The thermal rating PT depends on the following factors:• Ambient temperature• Air circulation and sunlight exposure at the installation site• Installation altitude• Heat conduction to the foundation at the installation site• Gear unit type, size and gear ratio • Type of gear unit external cooling• Type of gear unit lubrication• Lubricant type• Cyclic duration factor

For the following ambient conditions, the thermal rating can be directly read from theselection tables on page 147 and subsequent pages:• Ambient temperature 20 °C • Installation in a large hall (air velocity ≥ 1.4 m/s)• Natural cooling or cooling with

– Fan– Integrated cooler (water cooling cover or water cooling cartridge)– Combination of fan with cooling cartridge

• Foundation as steel support structure• Installation altitude < 1 000 m above sea level

INFORMATION• For other ambient temperatures and types of lubricants, you can calculate the

thermal rating PT using the temperature factor fT and the lubrication factor fL. Theresulting calculation results are approximate values. Please contact SEW-EURODRIVE to determine the exact values.

• Sufficient protection from direct sunlight is absolutely necessary for outdoorinstallation.



Refer to the selection tables on page 147 and subsequent pages to find the thermal rat-ing PTH of the gear unit [kW] for the following types of lubrication and mounting positioncombinations: The thermal rating for other combinations can be determined usingfactors.

Schmierungsarten / Raumlagen

X.F.. X.K.. X.T..

M1 M5 M4 M1 M5 M4 M1 M3 M4

X.F100 X.K100 X.T100 *

X.F110 X.K110 X.T110 *

X.F120 X.K120 X.T120 *

X.F130 X.K130 X.T130 *

X.F140 X.K140 X.T140 *

X.F150 X.K150 X.T150 *

X.F160 X.K160 X.T160 *

X.F170 X.K170 X.T170 *

X.F180 X.K180 X.T180 *

X.F190 X.K190 X.T190 *

X.F200 X.K200 X.T200 *

X.F210 X.K210 X.T210 *

X.F220 X.K220 X.T220 *

X.F230 X.K230 X.T230 *

X.F240 X.K240 X.T240 *

X.F250 X.K250 X.T250 *

X.F260 X.K260

X.F270 X.K270

X.F280 X.K280

X.F290 X.K290

X.F300 X.K300

X.F310 X.K310

X.F320 X.K320

SL

BL BL

SL

BL

BL BL

BL

SL

PL

SL

PL

PL

BL

PL

BL

BL

PL

PL PL PL PL

= Bath lubrication

= Splash lubrication

= Pressure lubrication

* = Contact SEW-EURODRIVE

BL

SL

PL



4Altitude factor f1 The following table shows the altitude factor f1

Temperature factors fTThe following table shows the temperature factor fT depending on the type of lubrication,ambient temperature, and cooling option.

When PT < 1/3 x PN1 → contact SEW-EURODRIVE

The gear unit's thermal rating must be at least as large as the operating power on theinput shaft [HSS].

PT = Thermal rating of the gear unit [kW]

PTH = Nominal thermal rating of the gear unit [kW]. The values in the selection tables on page 147 and subsequent pages depend on the type of cooling, mounting positions, and type of lubrication.

f1 = Altitude factor

fT = Temperature factor

PT f1 [kW]xPTH fT x=

Altitude factorAltitude H [m above sea level]

Up to 999 1000 - 2000 2000 - 3000 3000 - 4000 4000 - 5000

f1 1.00 0.95 0.91 0.87 0.83

Temperature factor fT

• without additional coolingor

• with fan

• with cooling coveror

• with cooling cartridgeor

• with cooling cartridge and fan

Type of lubrication Ambient temperature [°C] Ambient temperature [°C]

10 20 30 40 50 10 20 30 40 50

Splash and pressure lubrication 1.15 1 0.85 0.7 0.55

1.1 1 0.9 0.8 0.7Bath lubrication 1.18 1 0.85 0.65 0.48


PN1 = Nominal gear unit power


PK1 = Operating power on HSS [kW]

PK1

PT

≤



Pressure lubrication factor fLThe following table shows the pressure lubrication factor fT depending on the gear unitsize, mounting position, and cooling option.

The thermal limit PT for pressure lubrication can be calculated as follows:

INFORMATIONFor other gear units sizes and mounting positions with pressure lubrication not listedin the selection tables on page 147 and subsequent pages, you can calculate the ther-mal limit PT using the pressure lubrication factor fL.

Pressure lubrication factor fLCooling options

Size Mounting position

• without additional cooling• with fan• with cooling cover

• with cooling cartridge• with cooling cartridge and

fan

XF/XK120-250 M5 1.05 Contact SEW

XF160-250 M4 1.1 Contact SEW

XT160-250 M4 1.1 Contact SEW

Size Thermal rating PT

XF120-250PT (M4 pressure lubrication) = PT (M1 splash lubrication) x fL

PT (M5 pressure lubrication) = PT (M1 splash lubrication) x fL

XK120-250 PT (M5 pressure lubrication) = PT (M1 splash lubrication) x fL

XT160-210 PT (M4 pressure lubrication) = PT (M3 pressure lubrication) x fL

XT220-250 PT (M4 pressure lubrication) = PT (M1 pressure lubrication) x fL



4

Selecting the cooling systemIf the thermal rating PT of a gear unit is not sufficient with cooling by fan, water coolingcover or water cooling cartridge, then you can use a cooling system with circulationcooling (see chapters 5.4.4, 5.4.5, 5.4.6 and 5.4.7).The proper size of the cooling system can be determined by approximation by means ofthe power loss PV of the gear unit.

The cooling requirements are determined by means of this power loss PV. The requiredcooling system is selected by using the tables (see chapters 5.4.4, 5.4.5, 5.4.6 and5.4.7) of the various circulation cooling types.The power loss PV of the gear unit must be smaller than the cooling capacity of thecooling system.PV < cooling capacity of cooling system [kW]

In addition, the selection of an appropriate cooling system depends on the followingfactors:• Actual power loss to be cooled• Present cooling water temperature and volume flow• Ambient temperature• Ratio of oil quantity in the gear unit and oil volume flow of cooling system > 2

PVPK1η

= Power loss [kW]= Operating power on HSS [kW]= Efficiency see page 50 (applies only to splash or pressure lubrication)

P =V (1 – ) [kW]ηP x K1

INFORMATIONPlease consult SEW-EURODRIVE for selecting the appropriate cooling system basedon the ambient conditions of your system.



Step 9: Checking the external additional forces FR:

Dependencies The permitted external forces depend on the following factors:• Service factor• Required bearing life• Direction of the axial load (from or towards gear unit)• Application angle of the overhung load (rotating or at a specific position)• Application angle of the overhung load in relation to the shaft shoulder• Relation of axial load and overhung load

Definition of the force application

Determining the overhung load

An important factor for determining the resulting overhung load is the type of transmis-sion element mounted to the shaft end. The following transmission element factors fZhave to be considered for various transmission elements.

The overhung load exerted on the gear shaft is then calculated as follows:

61440AXX

α

0°FA

X

FR

+–

INFORMATIONThe force application is always defined as viewed onto the output shaft end.

Transmission element Transmission element factor fZ

Comments

Gears 1.15 < 17 teeth

Chain sprockets 1.40 < 13 teeth

Chain sprockets 1.25 < 20 teeth

Narrow V-belt pulleys 1.75 Influence of the pre-tensioning

Flat belt pulleys 2.50 Influence of the pre-tensioning

Toothed belt pulleys 1.50 Influence of the pre-tensioning

FR = Overhung load [N]

MK2 = Torque [kNm]

d0 = Mean diameter of the installed transmission element in [mm]

fZ = Transmission element factor

=MdF

R[N]

X 2000

d0

x fz



4

Permitted overhung loads on the output shaft (LSS)

The following table shows the permitted overhung load on standard solid shafts thatapply under the following conditions:• The application point of the overhung load is on the midpoint of the shaft end• No external axial load FA acts on the output shaft• The gear unit service factor is 1.3 or higher• The application angle of the overhung load is applied at the most unfavorable point.

For mounting flanges with external overhung loads, please contact SEW-EURODRIVE.

For the force FR

• The shaft speed is less than or equal to the given valueFor the force FRmax

• Applies only to foot-mounted gear units in mounting position M1• Values apply to favorable operating conditions. Please consult SEW-EURODRIVE.

X.F..

FR [kN] FRmax [kN]

Size X2FS.. X3FS.. X4FS.. X..S.

Speed n2 ≤ 125 min-1 ≤ 70 min-1 ≤ 20 min-1 -

Shaft position 14, 23 13, 24 14, 23 13, 24 14, 23 13, 24 all shaft positionsBearing STD HD STD HD STD HD STD HD STD HD STD HD

X.F100 9.6 - 8 - 16 - 15 - - - - - 30

X.F110 15 - 12 - 22 - 17 - - - - - 39

X.F120 25 - 14 - 32 - 21 - 53 - 42 - 60

X.F130 33 - 25 - 44 - 34 - 68 - 62 - 68

X.F140 35 - 19 - 45 - 30 - 76 - 61 - 87

X.F150 34 - 31 - 53 - 45 - 97 - 82 - 98

X.F160 53 - 37 - 75 - 54 - 124 - 103 - 127

X.F170 53 - 35 - 69 - 51 - 114 - 97 - 131

X.F180 71 - 41 - 93 - 63 - 155 - 125 - 170

X.F190 69 - 41 - 91 - 63 - 153 - 125 - 170

X.F200 80 - 43 - 105 - 68 - 176 - 139 - 190

X.F210 75 - 39 - 99 - 63 - 167 - 132 - 190

X.F220 83 152 39 108 128 195 84 151 230 230 214 230 230

X.F230 77 144 36 102 116 183 74 141 230 230 199 230 230

X.F240 123 217 68 162 184 276 129 221 280 280 280 280 280

X.F250 111 210 58 156 172 269 119 215 280 280 280 280 280

X.F260 56 208 21 145 151 271 88 208 290 290 273 290 290

X.F270 138 258 70 190 213 310 145 262 310 310 310 310 310

X.F280 133 254 67 188 208 310 143 260 310 310 310 310 310

X.F290 73 258 28 171 197 336 110 248 360 360 348 360 360

X.F300 52 257 20 165 175 325 80 230 360 360 318 334 360

X.F310 161 326 60 221 241 400 124 294 400 400 400 400 400

X.F320 149 322 59 212 217 392 92 266 400 400 379 400 400

FR = Overhung load STD = Standard bearing

n2 = Output speed HD = Reinforced bearing



X.K..

Permitted axial loads on the output shaft (LSS)

Please contact SEW-EURODRIVE.

Permitted overhung and axial loads input shaft (HSS)

Please contact SEW-EURODRIVE.

FR [kN] FRmax [kN]

Size X2KS.. X3KS.. X4KS.. X..S.

Speed n2 ≤ 125 min-1 ≤ 70 min-1 ≤ 20 min-1 -

Shaft position 03, 04 03, 04 03, 04 all shaft positions

Bearing STD HD STD HD STD HD

X.K100 10 - 16 - - 17

X.K110 17 - 22 - - - 25

X.K120 26 - 32 - 53 - 55

X.K130 36 - 44 - 68 - 68

X.K140 36 - 45 - 76 - 77

X.K150 39 - 53 - 97 97

X.K160 62 - 75 - 124 - 125

X.K170 56 - 69 - 114 - 115

X.K180 75 - 93 - 155 - 170

X.K190 73 - 91 - 153 - 170

X.K200 91 - 105 - 176 - 190

X.K210 87 - 99 - 167 - 190

X.K220 120 180 128 195 230 230 230

X.K230 113 171 116 183 230 230 230

X.K240 156 243 184 276 280 280 280

X.K250 154 241 172 269 280 280 280

X.K260 - - 151 271 290 290 290

X.K270 - - 213 310 310 310 310

X.K280 - - 208 310 310 310 310

X.K290 - - 197 336 360 360 360

X.K300 - - 175 325 360 360 360

X.K310 - - 241 400 400 400 400

X.K320 - - 217 392 400 400 400

FR = Overhung load STD = Standard bearing

n2 = Output speed HD = Reinforced bearing

INFORMATIONContact SEW-EURODRIVE in case of deviating conditions.


4Project planning example: Conveyor driveProject Planning for Drives

4

4.3 Project planning example: Conveyor driveThe following example shows the project planning for a conveyor drive.

Technical data and application conditions

• Bevel-helical gear unit, foot-mounted (mounting position M1), hollow shaft with key• Output speed n2 = 35 rpm• Input speed motor n1 = 1470 rpm• Operating power on the output shaft LSS PK2 = 135 kW• Peak operating torque on the output shaft LSS MK2 max = 55 kNm• Operating time: 16 Hours per day• The gear unit is started up once per hour (frequency of maximum output torque)• Motor control via frequency inverter• The gear unit is to be operated in a large hall under very dusty conditions and an

ambient temperature range between 0 °C and 40 °C.• Installation altitude H = 1200 m• Customer requirement: Service factor ≥1.4

61445AXX


4 Project planning example: Conveyor driveProject Planning for Drives

Step 1: Fill out the drive selection sheet

Step 2: Calculate the basic data

Constant operating torque MK2:

Calculate the gear unit reduction ratio using the following formula:

After having specified the gear unit size, this value is used to determine the nominal gearratio.

Step 3: Select the application factors

MK2 PK2n2

= Operating torque on the LSS [kNm]= Output power [kW]= Output speed LSS [rpm]

in1n2

= Gear ratio= Input speed (HSS) [rpm]= Output speed (LSS) [rpm]

P= K2MK2 n2

9550x 135 kW x 955035 min

= 36.8 kNm= -1

i =n1

n2=

1470

35 = 42

Application-specific service factor(Belt conveyor P > 100 kW, t > 10 h/day)

FS min = 1.5

Peak load factor(1...5 peak loads per hour)

FF = 1.0

Startup factor(frequency inverter)

Fstart = 1.6



4

Step 4: Calculate the required nominal gear unit torque

Required nominal gear unit torque MN2:

Step 5: Select the gear unit size

Select a gear unit of the next larger torque class using the foldout page at the end of thiscatalog.• Nominal gear unit torque MN2 = 58 kNmsee selection table on page 147 and subsequent pages.• Gear unit type X3KA180 /B• Nominal gear ratio iN = 45, see exact gear ratio iex = 43.6

Step 6: Select the nominal motor power

Required motor power:

Select a motor of the next larger power class: PM = 160 kW

MN2MK2FS min


MN2

FS min

x MK2

≥ = 36.8 kNm x 1.5 = 55.2 kNm

PMPK2PK1η

= Nominal motor power [kW]= Operating power on LSS [kW]= Operating power on HSS [kW]= Efficiency of page 50

= 135 kW

0.955= 141.4 kWP =

Pk2

M ηPK1

≥


4 Project planning example: Conveyor driveProject Planning for Drives

Step 7: Check the peak load conditions

Permitted peak torque MK2 zul:

Calculate the peak output torque MK2 max based on the motor power:

The peak output torque MK2 max must not exceed the permitted peak output torque MK2 zul.

→ This means you can use the selected gear unit size.

MK2 zulMN2FF


MK2 maxMK2 zul

= Peak output torque [kNm]= Permitted peak output torque [kNm]

M =K2 zul

2 x MN2

FF

2 x 58 kNm

1= = 116 kNm

P=

MM

K2 max n2

9.55x 160 kW x 9.55

35 1/min= 66.7 kNm=

ηx x 0.955x Fstart x 1.6

MK2 zul

MK2 max

≤

≤66.7 kNm 116 kNm



4

Step 8: Check the thermal rating

The operating power PK1 must not exceed the thermal rating PT (PK1 ≤ PT). Additionalcooling is required if PK1 > PT

141.4 kW > 80 kW→ Thermal rating not sufficient at 40 °C without additional cooling

With one fan:

→ Thermal rating sufficient at 40 °C with a fan

Step 9: Check the external additional forces

There are no external additional forces.

Step 10: Select the optional equipment

• Dusty environment → Taconite seals on the drive and output shafts (see page 26).

Step 11: Summary of all the technical information

• Gear unit type X3KA180 /B• Gear ratio iex = 43.6• Nominal gear unit torque MN2 = 58 kNm• Motor PM = 160 kW• Taconite seals on the drive and output shafts• Fan on the input shaft

PTPTHf1fT

= Thermal rating [kW]= Nominal thermal rating[kW]= Altitude factor= Temperature factor

PT f1xPTH≥ = 120 kW x 0.95 x 0.7 = 80 kW

= 0.95 see installation altitude 1200 m on page 59f1

fT x

= 0.7 see ambient temperature with splash lubrication without additional cooling on page 59

fT

141.4 kW < 153 kW

PT f1xPTH≥ = 230 kW x 0.95 x 0.7 = 153 kWfT x

4 project planning for drives - sew eurodrive · calculate the basic data select the application...

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