3360 unit 09 2014-i-01
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ENGR 3360U Winter 2014Unit 9
Other Choosing Techniques
Dr. J. Michael Bennett, P. Eng., PMP, UOIT,
Version 2014-I-01
Unit 9 Other Choosing Analyses
Change Record
• 2014-I-01 Initial Creation• Text Chapter 9
2014-I-019-2 Dr. J.M. Bennett, P.Eng., PMP ENGR 3360U Eng Eco
Unit 9 Other Choosing Analyses
Course Outline1. Engineering Economics2. General Economics
1. Microeconomics2. Macroeconomics3. Money and the Bank of
Canada3. Engineering Estimation4. Interest and Equivalence5. Present Worth Analysis6. Annual Cash Flow7. Rate of Return Analysis8. Picking the Best Choice9. Other Choosing Techniques
10. Uncertainty and Risk11. Income and Depreciation12. After-tax Cash Flows13. Replacement Analysis14. Inflation15. MARR Selection16. Public Sector Issues17. What Engineering should know
about Accounting18. Personal Economics for the
Engineer
2014-I-01 Dr. J.M. Bennett, P.Eng., PMP ENGR 3360U Eng Eco1-3
Unit 9 Other Choosing Analyses
Learning Objectives
• 9.1 Future Worth Analysis• 9.2 Benefit–Cost Ratio• 9.3Payback Period Analysis• 9.4 Sensitivity Analysis• 9.5 Break-even Analysis
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Unit 9 Other Choosing Analyses
-• In contrast to present worth analysis, one might
want to know the situation of a set of alternatives at any point in time in the future.
• Future worth analysis is very similar to present worth analysis but the analysis exists at some future point in time.
• As in present worth analysis, the evaluation of alternatives must be over the same time period.– This implies that the use of LCM or a specified
time period is needed.
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Unit 9 Other Choosing Analyses
Example 9.1
Ron is a 20-year old UOIT student who smokes a carton of ciggies a week. If he stops smoking and places this money in a savings account which earns 5% compounded semi-annually, what is his future worth at 65 if a carton costs $85?
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Answer
Semi-savings = 85x26 = 2,210FW = (F/A, 2.5%, 90) = 2210(329.2)
= $727, 532 (at least)
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Unit 9 Other Choosing Analyses
9.2 Benefit-Cost Ratio Analysis• At a given MARR an alternative that would be
acceptable when:PW of benefits – PW of costs >= 0orEUAB – EUAC >= 0
• This makes sense as the benefits outweigh the costs for a net positive benefit at MARR over a specified lifetime.
• This could also be stated as a ratio:PW of benefits/PW of costs >= 1
• Called the Benefit–Cost Ratio
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Unit 9 Other Choosing Analyses
Benefit-Cost Ratio Analysis cont.
• In the public sector it is common that:– The numerator includes all consequences to the
user or public (Benefits – Disbenefits).– The denominator includes the consequences to
the government or sponsor.• The ratios may differ in exact value by this
method, but, more importantly, the decision point (> or < 1) does not.
• The conclusions remain the same.
2014-I-019-9 Dr. J.M. Bennett, P.Eng., PMP ENGR 3360U Eng Eco
Unit 9 Other Choosing Analyses
Example 9-2
Two machines have a life of 5 years. A costs $1000 and will earn $300 annually. B costs $1350 and will earn $300, the first year, $350 the second and so on. At 7%, which machine should be selected?
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Solution
Incremental B-APWcosts = 1350 – 1000 = 350
PWbenefits = (0-0) + 50(P/G, 7%, 5) = 382
B/C = 382/350 = 1.09
Note that direct calculation gives the wrong answer.
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Unit 9 Other Choosing Analyses
Example 9.3
Here are 6 mutually exclusive alternatives. They have a 20 year life. At 6%, using B/C ratio, which would you pick?
A B C D E FCost 4K 2K 6K 1K 9K 10KPW 7.3K 4.7K 8.7K 1.3K 9K 9.5KB/C 1.8 2.4 1.5 1.3 1.0 0.95
2014-I-01 Dr. J.M. Bennett, P.Eng., PMP ENGR 3360U Eng Eco9-12
Unit 9 Other Choosing Analyses
Benefit-Cost Ratio Analysis
• Graphed individual project points from Example 9-5• The slopes indicate B/C ratios of the increments between projects.
Example(s): B – D slope is greater than 1.0 A – C slope is less than 1.0 F is not considered (B/C ratio is less <1)
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Unit 9 Other Choosing Analyses
Solution
Discard F (B/C < 1)
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Solution
Δ B-D Δ A-B Δ C-A Δ E-AΔ Cost 1K 2K 2K 5KΔ Benefit 3.4K 2.6K 1.4K 1.7KB/C 3.4 1.3 0.7 0.341) Chose B over D2) Chose A over B3) Chose A over C4) Chose A over E
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Unit 9 Other Choosing Analyses
9.3 Payback Period• Payback period is:
– The period of time required for the profit or Other Choosing benefits of a project to equal the cost.
– Note: Interest Rate is NOT considered• Four important points:
1) This is an approximate calculation.2) Costs/benefits/savings are included with no consideration
of timing differences.2) All economic consequences beyond the payback are
ignored, including salvage!3) Due to its approximate nature, it may not select the correct
alternative.
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Unit 9 Other Choosing Analyses
Example 9.4
A firm is trying to decide which of 2 scales it should buy. If both have a 6-year life, which should be selected at 8%, using PB?
Choice Cost UAB Salvage A 2K 450 100 B 3K 600 700
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Payback Period Example
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Unit 9 Other Choosing Analyses
Solution
Ignore Salvage and interest ratePBA = cost/UAB = 2000/450 = 4.4 years
PBB = 3000/600 = 5 years
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Unit 9 Other Choosing Analyses
9.4 Sensitivity Analysis
• Since economic problem solving often considers future consequences, there is uncertainty regarding accuracy.
• To better evaluate the impact of estimates, we can compute how much an estimate can change and the effect on a particular decision.
• This is ‘Sensitivity Analysis’.
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Unit 9 Other Choosing Analyses
9.5 Break-Even Analysis
• Break-Even Analysis is a form of sensitivity analysis.
• Typically presented as a break-even chart.• It indicates the point at which two
alternatives are equal to each Other Choosing.– The point of indifference
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Unit 9 Other Choosing Analyses
Example 9-5Consider a project that may be constructed to full
capacity now or may be built in 2 stages. Assume 40 year life at 8%, no SV.Costs
2-Stage first stage now 100,0002nd stage n years out 120,000
Full capacitydo it now 140,000
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Solution
Full Cap = 140,0002-Stage
PW = 100000 + 120000(P/F, 8%, n) n=05 PW = 182,700 n=10 PW = 155,600 n=20 PW = 125,700 n=40 PW = 111,900
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Break-Even Analysis, cont’d.• Example 9-11
– Shows present worth of building both stages now versus building a second stage at a later date.
– The point at which they are equal is when the second stage is built in year 15.
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Unit 9 Other Choosing Analyses
Summary
• Future Worth Analysis– Comparisons between alternatives made based
on a future time• Benefit-Cost Ratio Analysis
– Analyses the ratio of benefits to costs through present worth or annual worth.
– Incremental benefit-cost ratios are used for multiple alternatives when neither input nor output are fixed.
– Often used in various levels of government.
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Unit 9 Other Choosing Analyses
Summary, cont’d.
• Payback Period Analysis– The period of time required for profit or Other
Choosing benefits to equal the cost of the investment.
– A poor method for ranking alternatives because interest rate is NOT considered.
– Simply measures the time it takes to recover the investment in original dollars.
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Unit 9 Other Choosing Analyses
Summary, cont’d.
• Sensitivity Analysis– Used to determine how sensitive a decision is
to estimates and parameters.– Examination of the range of values to
determine their effect on a decision.
• Break-Even Analysis– To locate the condition where alternatives are
equivalent.– Often uses a break-even chart.
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