2.6 rational functions
DESCRIPTION
2.6 Rational Functions. JMerrill,2010. Domain. Find the domain of. Think: what numbers can I put in for x????. Denominator can’t equal 0 (it is undefined there). You Do: Domain. Find the domain of. Denominator can’t equal 0. You Do: Domain. Find the domain of. - PowerPoint PPT PresentationTRANSCRIPT
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2.6Rational Functions
JMerrill,2010
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Domain
Find the domain of 2x1f(x)
Denominator can’t equal 0 (it is undefined there)
2 0
2
x
x
Domain , 2 2,
Think: what numbers can I put in for x????
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You Do: Domain
Find the domain of 2)1)(x(x
1-xf(x)
Denominator can’t equal 0
1 2 0
1, 2
x x
x
Domain , 2 2, 1 1,
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You Do: Domain
Find the domain of 2
xf(x)x 1
Denominator can’t equal 02
2
1 0
1
x
x
Domain ,
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Vertical AsymptotesAt the value(s) for which the domain is undefined, there will be one or more vertical asymptotes. List the vertical asymptotes for the problems below.
2x1f(x)
2x
2)1)(x(x1-xf(x)
1, 2x x
2
xf(x)x 1
none
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Vertical Asymptotes
The figure below shows the graph of 2x1f(x)
The equation of the vertical asymptote is 2x
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Vertical Asymptotes
Definition: The line x = a is a vertical asymptote of the graph of f(x) if
or
f x f x
as x a from either the left or the right.
Look at the table of values for 2x
1f(x)
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Vertical Asymptotesx f(x)
-3 -1
-2.5 -2
-2.1 -10
-2.01 -100
-2.001 -1000
As x approaches____ from the _______,
f(x) approaches _______.
-2
left
x f(x)
-1 1
-1.5 2
-1.9 10
-1.99 100
-1.999 1000
As x approaches____ from the _______,
f(x) approaches _______.
-2right
Therefore, by definition, there is a vertical asymptote at
2x
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Vertical Asymptotes Describe what is happening to x and determine if a vertical asymptote exists, given the following information:
x f(x)-4 -1.333
-3.5 -2.545
-3.1 -12.16
-3.01 -120.2
-3.001 -1200
x f(x)-2 1-2.5 2.2222
-2.9 11.837
-2.99 119.84
-2.999 1199.8
As x approaches____ from the _______, f(x) approaches _______.
As x approaches____ from the _______, f(x) approaches _______.
-3 -3
left right
Therefore, a vertical asymptote Therefore, a vertical asymptote occurs at x = -3.occurs at x = -3.
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Vertical Asymptotes
Set denominator = 0; solve for x Substitute x-values into numerator. The
values for which the numerator ≠ 0 are the vertical asymptotes
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Example
What is the domain? x ≠ 2 so
What is the vertical asymptote? x = 2 (Set denominator = 0, plug back into
numerator, if it ≠ 0, then it’s a vertical asymptote)
( , 2) (2, )
22 3 1( )
2
x xf x
x
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You Do
Domain: x2 + x – 2 = 0 (x + 2)(x - 1) = 0, so x ≠ -2, 1
Vertical Asymptote: x2 + x – 2 = 0 (x + 2)(x - 1) = 0 Neither makes the numerator = 0, so x = -2, x = 1
( , 2) ( 2,1) (1, )
2
2
2 7 4( )
2
x xf x
x x
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The graph of a rational function NEVER crosses a vertical asymptote. Why?
Look at the last example:
Since the domain is , and the vertical asymptotes are x = 2, -1, that means that if the function crosses the vertical asymptote, then for some y-value, x would have to equal 2 or -1, which would make the denominator = 0!
( , 1) ( 1,2) (2, )
2
2
2 7 4( )
2
x xf x
x x
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Horizontal Asymptotes
Definition:The line y = b is a horizontal asymptote if f x b as x or x
Look at the table of values for f x 1
x 2
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Horizontal Asymptotesx f(x)
1 .3333
10 .08333
100 .0098
1000 .0009
y→_____ as x→________
0
x f(x)
-1 1
-10 -0.125
-100 -0.0102
-1000 -0.001
y→____ as x→________
0
Therefore, by definition, there is a horizontal Therefore, by definition, there is a horizontal asymptote asymptote at y = 0.at y = 0.
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Examples
f xx
( )
4
12f x
x
x( )
2
3 12
What relationships exists between the numerator and the denominator in each of these problems?
The degree of the denominator is larger than the degree of the numerator.
Horizontal Asymptote at y = 0
Horizontal Asymptote at y = 0
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Examples
h xx
x( )
2 1
1 82x
15xg(x)
2
2
What relationships exists between the numerator and the denominator in each of these problems?
The degree of the numerator is the same as the degree or the denominator.
Horizontal Asymptote at y = 2
Horizontal Asymptote at 5
2y
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Examples
13x
54x5x3xf(x)
23
2x
9xg(x)
2
What relationships exists between the numerator and the denominator in each of these problems?
The degree of the numerator is larger than the degree of the denominator.
No Horizontal Asymptote
No Horizontal Asymptote
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Asymptotes: Summary1. The graph of f has vertical asymptotes at the _________ of the denominator.
2. The graph of f has at most one horizontal asymptote, as follows:
a) If n < d, then the ____________ is a horizontal asymptote.
b) If n = d, then the line ____________ is a horizontal asymptote (leading coef. over leading coef.)
c) If n > d, then the graph of f has ______ horizontal asymptote.
zeros
line y = 0
no
ay
b
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Asymptotes
Some things to note: Horizontal asymptotes describe the behavior at the
ends of a function. They do not tell us anything about the function’s behavior for small values of x. Therefore, if a graph has a horizontal asymptote, it may cross the horizontal asymptote many times between its ends, but the graph must level off at one or both ends.
The graph of a rational function may or may not cross a horizontal asymptote.
The graph of a rational function NEVER crosses a vertical asymptote. Why?
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You DoFind all vertical and horizontal asymptotes of the following function
2 1
1
xf x
x
Vertical Asymptote: x = -1
Horizontal Asymptote: y = 2
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You Do - AgainFind all vertical and horizontal asymptotes of the following function
2
4
1f x
x
Vertical Asymptote: none
Horizontal Asymptote: y = 0
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The Last You-Do (for now :)Find all asymptotes of the following function
2 9
2
xf x
x
Vertical Asymptote: x = 2
Horizontal Asymptote: none
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Slant Asymptotes
The graph of a rational function has a slant asymptote if the degree of the numerator is exactly one more than the degree of the denominator. Long division is used to find slant asymptotes.
The only time you have an oblique asymptote is when there is no horizontal asymptote. You cannot have both.
When doing long division, we do not care about the remainder.
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ExampleFind all asymptotes.
2 2
1
x xf x
x
Vertical
x = 1
Horizontal
none
Slant
2
2
1 2
-2
x
x x x
x x
y = x
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Example
Find all asymptotes: 2 2
( )1
xf x
x
Vertical asymptote at x = 1
n > d by exactly one, so no horizontal asymptote, but there is an oblique asymptote.
2
2
11 2
2
( 1)
1
-
xx x
x x
x
x
y = x + 1
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Graphing Rational Functions
To graph a rational function, you find all asymptotes
You must show your work You must identify the domain and range You must identify the x- and/or y-intercepts You may have to “blow up” part of the
graph (Zoom:Box) to actually see how the graph fits next to the asymptote.