2.4 the chain rule. we now have a pretty good list of “shortcuts” to find derivatives of simple...
TRANSCRIPT
2.4 The Chain Rule
We now have a pretty good list of “shortcuts” to find derivatives of simple functions.
Of course, many of the functions that we will encounter are not so simple. What is needed is a way to combine derivative rules to evaluate more complicated functions.
Consider a simple composite function:
6 10y x
2 3 5y x
If 3 5u x
then 2y u
6 10y x 2y u 3 5u x
6dy
dx 2
dy
du 3
du
dx
dy dy du
dx du dx
6 2 3
and another:
5 2y u
where 3u t
then 5 3 2y t
3u t
15dy
dt 5
dy
du 3
du
dt
dy dy du
dt du dt
15 5 3
5 3 2y t
15 2y t
5 2y u
and one more:29 6 1y x x
23 1y x
If 3 1u x
3 1u x
18 6dy
xdx
2dy
udu
3du
dx
dy dy du
dx du dx
2y u
2then y u
29 6 1y x x
2 3 1dy
xdu
6 2dy
xdu
18 6 6 2 3x x This pattern is called the chain rule.
dy dy du
dx du dx Chain Rule:
If is the composite of and , then:f g y f u u g x
at at xu g xf g f g
example: sinf x x 2 4g x x Find: at 2f g x
cosf x x 2g x x 2 4 4 0g
0 2f g
cos 0 2 2
1 4 4
We could also do it this way:
2sin 4f g x x
2sin 4y x
siny u 2 4u x
cosdy
udu
2du
xdx
dy dy du
dx du dx
cos 2dy
u xdx
2cos 4 2dy
x xdx
2cos 2 4 2 2dy
dx
cos 0 4dy
dx
4dy
dx
Here is a faster way to find the derivative:
2sin 4y x
2 2cos 4 4d
y x xdx
2cos 4 2y x x
Differentiate the outside function...
…then the inside function
At 2, 4x y
Here’s another
Now plug in u and simplify
Another example:
2cos 3d
xdx
2cos 3
dx
dx
2 cos 3 cos 3d
x xdx
derivative of theoutside function
derivative of theinside function
It looks like we need to use the chain rule again!
Another example:
2cos 3d
xdx
2cos 3
dx
dx
2 cos 3 cos 3d
x xdx
2cos 3 sin 3 3d
x x xdx
2cos 3 sin 3 3x x
6cos 3 sin 3x x
The chain rule can be used more than once.
(That’s what makes the “chain” in the “chain rule”!)
Derivative formulas include the chain rule!
1n nd duu nu
dx dx sin cos
d duu u
dx dx
cos sind du
u udx dx
2tan secd du
u udx dx
etcetera…
The most common mistake on the chapter 2 test is to forget to use the chain rule.
Every derivative problem could be thought of as a chain-rule problem:
2dx
dx2d
x xdx
2 1x 2x
derivative of outside function
derivative of inside function
The derivative of x is one.
Don’t forget to use the chain rule!
HW Pg. 138 7-29 odd, 39-53, 91, 93, 102