1.given f (x) = 4x – 5, find f (1) substitute f (1) = 4(1) – 5 simplify f (1) = 4 – 5 f (1) =...

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Algebra I Concept Test # 6 – Functions Practice Test 1. Given f (x) = 4x 5, find f (1) Substitute f (1) = 4(1) 5 Simplify f (1) = 4 5 f (1) = −1 Simplify © 2007-09 by S-Squared, Inc. All Rights Reserved.

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Page 1: 1.Given f (x) = 4x – 5, find f (1) Substitute f (1) = 4(1) – 5 Simplify f (1) = 4 – 5 f (1) = −1 Simplify © 2007-09 by S-Squared, Inc. All Rights Reserved

Algebra I Concept Test # 6 – Functions Practice Test

1. Given f (x) = 4x – 5, find f (1)

Substitutef (1) = 4(1) – 5

Simplifyf (1) = 4 – 5

f (1) = −1 Simplify

© 2007-09 by S-Squared, Inc. All Rights Reserved.

Page 2: 1.Given f (x) = 4x – 5, find f (1) Substitute f (1) = 4(1) – 5 Simplify f (1) = 4 – 5 f (1) = −1 Simplify © 2007-09 by S-Squared, Inc. All Rights Reserved

0

2. Given the following graph,

Algebra I Concept Test # 6 – Functions Practice Test

a) find f (− 3)

b) find f (0)

f(x)

− 3

0

=

=

0

33

Note: You are looking for the y-coordinate when x is the given value.

Page 3: 1.Given f (x) = 4x – 5, find f (1) Substitute f (1) = 4(1) – 5 Simplify f (1) = 4 – 5 f (1) = −1 Simplify © 2007-09 by S-Squared, Inc. All Rights Reserved

x f(x)

− 1

0

1

3. a) Write the following equation in function notation:

y = 3x – 2f(x) = 3x – 2

c) Graph:

− 5

− 2

1

f(1) = 3 – 2 (1)

f(1) = – 2 (3)

f(1) = 1

− 1

0

1

f(0) = 3 – 2 (0)

f(0) = – 2 (0)

f(0) = − 2

f(−1) = 3 – 2 (−1)

f(− 1) = – 2 (− 3)

f(− 1) = − 5

( − 1, −5)

( 0, − 2)

( 1, 1)

f(x)

b) Using a table find 3 points that are solutions.

Algebra I Concept Test # 6 – Functions Practice Test

(− 1, − 5)

(0, − 2)

(1, 1)

Page 4: 1.Given f (x) = 4x – 5, find f (1) Substitute f (1) = 4(1) – 5 Simplify f (1) = 4 – 5 f (1) = −1 Simplify © 2007-09 by S-Squared, Inc. All Rights Reserved

C(0) = + 15(0)

C(0) = 15

C(15) = 5 + 15 (15)C(10) = 5 + 15 (10)

C(10) = + 15 (50)

C(0) = 5 + 15 (0)x C(x)

0

10

15

4. The cost of your New Year’s Eve party is $15.00 for the cake and $5.00 per person for party favors.

a) Write the cost function based on the number of people attending.

C(x) = 5x + 15

Algebra I Concept Test # 6 – Functions Practice Test

Note: x is the number of people who attend and

C(x) is the cost of the party.b) Using a table to find 3 points, graph the

function, clearly label the intervals and axes.

15

65

90

C(15) = + 15 (75)

C(15) = 90

0

10

15C(10) = 65

C(x) = 5x + 15

Page 5: 1.Given f (x) = 4x – 5, find f (1) Substitute f (1) = 4(1) – 5 Simplify f (1) = 4 – 5 f (1) = −1 Simplify © 2007-09 by S-Squared, Inc. All Rights Reserved

d) At the y-intercept, determine the number of people

who attend your party.

x C(x)

0

10

15

4. b) Graph the function clearly label the intervals and axes.

Algebra I Concept Test # 6 – Functions Practice Test

15

65

90

x (5)

C(x) (10)

0 5 10 15 20 25 30 35 40 45 50 55

120110100 90

80 70 60 50

40 30

20 10

(0, 15)

(10, 65)

(15, 90)

c) Determine the “rate of change.”

$ 5 per person

None

Note: The rate of change

is the slope.

Page 6: 1.Given f (x) = 4x – 5, find f (1) Substitute f (1) = 4(1) – 5 Simplify f (1) = 4 – 5 f (1) = −1 Simplify © 2007-09 by S-Squared, Inc. All Rights Reserved

x C(x)

0

10

15

4. b) Graph the function clearly label the intervals and axes.

Algebra I Concept Test # 6 – Functions Practice Test

15

65

90x (5)

C(x) (10)

0 5 10 15 20 25 30 35 40 45 50 55

120110100 90

80 70 60 50

40 30

20 10

e) Find the cost if 55 people attended.

C(55) = 5 + 15 (55)

C(55) = + 15 (275)

C(55) = 290$ 290.00

C(x) = 5x + 15

Page 7: 1.Given f (x) = 4x – 5, find f (1) Substitute f (1) = 4(1) – 5 Simplify f (1) = 4 – 5 f (1) = −1 Simplify © 2007-09 by S-Squared, Inc. All Rights Reserved

g) Identify whether the cost or the number of people represent the independent variable.

4.continued

Algebra I Concept Test # 6 – Functions Practice Test

x (5)

C(x) (10)

0 5 10 15 20 25 30 35 40 45 50 55

120110100 90

80 70 60 50

40 30

20 10

f) Find the number of people who

attended if the cost of the party was $415.00.

C(x) = 5x + 15

(415) = 5x + 15

400 = 5x

80 people

# of people

80 = x STAY

POSITIVE!