19 august statistics for business and management

www.afterschoool.tk AFTERSCHO☺OL's MATERIAL FOR PGPSE PARTICIPANTS

STATISTICAL ANALYSIS

AFTERSCHO☺OL – DEVELOPING CHANGE MAKERS

CENTRE FOR SOCIAL ENTREPRENEURSHIP PGPSE PROGRAMME –

World’ Most Comprehensive programme in social entrepreneurship & spiritual entrepreneurship

OPEN FOR ALL FREE FOR ALL


STATISTICAL ANALYSISDr. T.K. Jain.

AFTERSCHO☺OLCentre for social entrepreneurship

BikanerM: 9414430763

[email protected]

www.afterschoool.tk

http://www.afterschool.tk/

http://www.afterschoool.tk/


CALCULATE MEAN DEVIATION FROM THE FOLLOWIND DATA? X

23

24

28

35

39

49


SOLUTION . . Step 1. prepare average of the numbers Step 2: find Dx or deviation of each

number from the mean. (ignore plus or minus signs)

Step 3: find our average of Dx. Mean deviation is available to us Answer = 8.


Solution x Dx

23 1024 928 535 239 649 1633 8


Find mean deviation from the following series?

X

frequency (f) FX Dx fdx

1 23 23 2.8852 66.363 45 135 0.8852 39.845 32 160 1.1148 35.677 21 147 3.1148 65.419 1 9 5.1148 5.115

122 474 212.43.89 1.741


SOLUTION . . MEAN DEVIATION = 1.74 Steps: 1. multiply X with F and get FX X = values, F = frequency Divide sum of FX by sum of F (total frequency). You

will get average = 3.89 Find DX by taking difference of X and Average. Now

multiply DX by F. we get FDX. Get average of FDX by dividing it by sum of

frequency. We get answer 1.74 answer.


Find Mean Deviation from the following data?

X Frequency

1 2

2 12

3 23

4 15

5 9


Solution . . X F

1 2 2 2 4.562 12 24 1 15.33 23 69 0 6.414 15 60 1 10.85 9 45 2 15.5

61 200 52.63.3 0.86


Answer . . Mean deviation is .86 (see excel sheet for details).


Find mean deviation from Median from the following data. . : 80, 75, 70, 52, 56, 68, 82? STEP 1: ARRANGE THE DATA IN

ASCENDING ORDER. STEP 2: FIND THE MID VALUE = HERE

IT IS 70. THIS IS MEDIAN. STEP 3: FIND Dx (DIFFERENCE)

FROM MEDIAN. FIND AVERAGE OF Dx.


Solution . .

x Dx52 1856 1468 270 075 580 1082 12

618.7


Solution .. Check the excel notes for this and final

answer is 8.7 answer.


Find MEDIAN from the following data? (see excel table). Use the following formulae to find

MEDIAN: 1. SUM UP ALL THE FREQUENCY. IT

IS 50. DIVIDE 50 BY 2 = 25. FIND OUT WHERE IS 25. 25 LIES IN

THE GROUP 60 TO 70. NOW APPLY FORMULAE . .


SOLUTION . . . L + (N/2) – p1/ (t-p1) *c =L = THE LOWER LIMIT OF CLASS. N = TOTAL FREQUENCY P1 = TOTAL OF PREVIOUS

FREQUENCY SET T = TOTAL OF MEDIAN CLASS C = GAP IN THE MEDIAN CLASS.


SOLUTION . . . L = 60 N = 50 (TOTAL FREQUENCY) P1 = 20 (TOTAL UPTO LESS THAN 60) T = 40 (TOTAL UPTO LESS THAN 70) C = (70 – 60) = 10 (gap of median class) =60 + (25-20) / (40-20) *10 60 + 2.5 =62.5 ANSWER.


Solution table : X Fry range f midLess than 50 8 40-50 8 45less than 60 20 50 - 60 12 55less than 70 40 60-70 20 65less than 80 50 70 -80 10 75

50


Branches AFTERSCHO☺OL will shortly open its

branches in important cities in India including Delhi, Kota, Mumbai, Gurgaon and other important cities. Afterschooolians will be responsible for managing and developing these branches – and for promoting social entrepreneurs.


Case Studies We want to write case studies on social

entrepreneurs, first generation entrepreneurs, ethical entrepreneurs. Please help us in this process. Help us to be in touch with entrepreneurs, so that we may develop entrepreneurs.


Basic values at afterschoool Share to learn more Interact to develop yourself Fear is your worst enemy Make mistakes to learn Study & discuss in a group Criticism is the healthy route to mutual support and

help Ask fundamental questions : why, when, how &

where? Embrace change – and compete with yourself only


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19 august statistics for business and management

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