18/6/2008 andrew beddall tr-atlas gaziantep grid workshop june 19-21 2008 1 introduction to data...

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18/6/2008 Andrew Beddall TR-ATLAS Gaziantep Grid Workshop June 19-21 2008 1 Introduction to Data Analysis 1. An Apple Collider Experiment (Toy Monte Carlo Simulation) 2. A couple of analysis examples from ALEPH at the LEP collider (data taking 1989 to 1995) 3. What does it look like at ATLAS? (data taking 2008[?] ...) Dr Andrew Beddall, University of Gaziantep

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18/6/2008 Andrew Beddall TR-ATLAS Gaziantep Grid Workshop June 19-21 2008 1

Introduction to Data Analysis1. An Apple Collider Experiment

(Toy Monte Carlo Simulation)

2. A couple of analysis examples from ALEPH at the LEP collider (data taking 1989 to 1995)

3. What does it look like at ATLAS? (data taking 2008[?] ...)

Dr Andrew Beddall, University of Gaziantep

Introduction to Data Analysis

1. An Apple Collider Experiment(Toy Monte Carlo Simulation)

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Counting ExperimentsExperimental High Energy Physics is about counting (frequency) experiments.

Example: An apple-apple collider.

If we perform n apple-apple collisions (at high energy, of course)and observe m cherries amongst the mush, then we can say therate (or probability) R(apple,apple cherry + mush) m/n Or more specifically R = (m/n) ± (m /n) (counting error)*

But what is the relationship between probability and counting?

*assuming m is > 10 or so.

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AfterBefore

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You can find anything at Wikipedia!http://en.wikipedia.org/wiki/Frequentist

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Counting (n = n):Entries 436 ± 20.9 cherries Log likelihood fit:L.L. fit = 27.250 ± 1.305 x16 bins 436.0 ± 20.9 cherries

Cherry rate calculation:C = 436.0 ± 20.9 cherries 106 collisions

(4.360 ± 0.209) x 10-4

Cherries per collision

Experiment 1: Say, in nature R(apple,apple cherry + mush) = 4 x 10-4

Perform one million apple-apple collisions, count the number of cherries.

χ2 fitting underestimates in the presence of low statistics (the dash line); so we won’t use that here.

x

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Counting (n = n):Entries 374 ± 19.3 cherries Log likelihood fit:L.L. fit = 23.375 ± 1.2086 x16 bins 374.0 ± 19.3 cherries

Cherry rate calculation:C = 374.0 ± 19.3 cherries 106 collisions

(3.740 ± 0.193) x 10-4

Cherries per collision

Experiment 2: Repeat the experiment.

x

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Counting (n = n):Entries 414 ± 20.3 cherries Log likelihood fit:L.L. fit = 25.875 ± 1.2716 x16 bins 414.0 ± 20.3 cherries

Cherry rate calculation:C = 414.0 ± 20.3 cherries 106 collisions

(4.140 ± 0.203) x 10-4

Cherries per collision

Experiment 3: Repeat the experiment.

x

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Summary:

In nature R(apple,apple cherry + mush) = 4 x 10-4

Exp. 1: C = (4.36 ± 0.21) x 10-4 (1.7 )Exp. 2: C = (3.74 ± 0.19) x 10-4 (1.4 )Exp. 3: C = (4.14 ± 0.20) x 10-4 (0.7 )

But is “n = n” true, and is actually meaningful?

Number of standard deviations from the true rate.

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The normal (Gaussian) distribution.The numbers of ’s defines confidence intervals.

Exp. 1: R = (4.36 ± 0.21) x 10-4 R = (4.36 ± 0.42) x 10-4

Exp. 2: R = (3.74 ± 0.19) x 10-4 R = (3.74 ± 0.38) x 10-4

Exp. 3: R = (4.14 ± 0.20) x 10-4 R = (4.14 ± 0.40) x 10-4

1 68% confidence 2 ’s 95% confidence

We expect that if we repeat the experiment many times, then 68% (95%) of our results would be within 1 (2 ) of the true rate.

true rate 4 x 10-4

SO LET’S DO IT! ...

Here, is about 0.2 (the experimental accuracy)

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Each entry in the histogram is the result of an experiment to determine R.

We have a perfect fit to a Gaussian function!

The value of is 0.2 That’s the same as the accuracy of our individual results. This explains what is .

Furthermore, is the standard deviation of the distribution, the standard error SE = /10000 = 0.002 x 10-4 is a measure of the uncertainty in the mean.

So we can write the overall result as: R = (3.995 ± 0.002) x 10-4 fitted R = (3.999 ± 0.002) x 10-4 calculated[two more decimal places of accuracy]

Summary so far• I did not fiddle the results in any way – honest!

• This toy Monte Carlo has demonstrated the basic concept of n errors and how they are used to obtain estimates of accuracy in counting experiments.

• The experimental accuracy scales as 1/ n .but if statistics are large then systemic errors dominate.

• χ2 fits tend to underestimate when statistics are small.

• If stats are very small (discoveries) probability estimation is very different(see the endless debates in the statistic forums/conferences).

• What if our signal is mixed with background?See next .....

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New situation: R(apple,apple cherry + mush) = 4 x 10-4

But the some of the mush is selected with the signalPerform one million apple-apple collisions, count the number of cherries.

The background mixes with the signal, the bin-to-bin variations are increased in the signal region and we don’t know which is signal and which is background!

This time we must use fitting, to estimate the background + signal and subtract the background estimate from the signal estimate.

The fitting function is

f(x) = p1 + p2 for 0.42 < x < 0.58 f(x) = p2 elsewhere p1 x 16 bins = signal count.

p1 and p2 are free parameters in the fit.

x

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Experiment 1: (same signal as in the previous Exp 1)Perform one million apple-apple collisions, count the number of cherries.

Entries 2962 cherries+mush

Log likelihood fit:p1 = 27.842 ± 1.894x16 bins 445.5 ± 30.3 cherries

(4.455 ± 0.303) x 10-4

Cherries per collision

Check:p2 = 25.170 ± 0.546x100 bins 2517.0 ± 54.6 mush

445.5+2517.0 = 2962.5 entries, ok.x

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Experiment 2: (same signal as in the previous Exp 2)Repeat the experiment .

Entries 2862 cherries+mush

Log likelihood fit:p1 = 25.384 ± 1.841x16 bins 406.1 ± 29.5 cherries

(4.061 ± 0.295) x 10-4

Cherries per collision

Check:p2 = 24.562 ± 0.539x100 bins 2456.2 ± 53.9 mush

406.1+2456.2 = 2862.3 entries, ok.x

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Experiment 3: (same signal as in the previous Exp 3)Repeat the experiment.

Entries 2961 cherries+mush

Log likelihood fit:p1 = 25.095 ± 1.857x16 bins 401.5 ± 29.7 cherries

(4.015 ± 0.297) x 10-4

Cherries per collision

Check:p2 = 25.599 ± 0.550x100 bins 2559.9 ± 55.0 mush

401.5+2559.9 = 2961.4 entries, ok.x

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Summary and Discussion: the analysis repeated with background

In nature R(apple,apple cherry + mush) = 4 x 10-4

Exp. 1: C = (4.46 ± 0.30) x 10-4 (1.5 )Exp. 2: C = (4.06 ± 0.30) x 10-4 (0.2 )Exp. 3: C = (4.02 ± 0.30) x 10-4 (0.05 ) chance!

Number of standard deviations from the true rate.

The effect of background has been to increased from 0.20 to 0.30

Let’s repeat the experiment 10,000 times and look at the distribution of R values. .....

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Again, we have a perfect fit to a Gaussian function!

The value of is 0.28 That’s about the same as the accuracy of our individual results (0.30).

The standard error SE = /10000 = 0.0028 x 10-4 is a measure of the uncertainty in the mean.

So we can write the overall result as:

R = (3.992 ± 0.003) x 10-4

That’s 2.7 ’s from the true value; slightly off target, but we would normally be more conservative than this;fitting can be tricky a tricky business.

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Note that the background amplitude is the about the same as the signal amplitude.

As n then, because we have twice the number of counts, we expect to increase by a factor of 2.

For signal only data = 0.198 x 10-4

With signal + background we expect = 0.198 x 10-4 x 2 = 0.280 x 10-4

We actually see 0.281 x 10-4 Same!

Conclusion:In our counting experiment, the statistics behave as we expect.

x

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An Apple Collider Experiment (Toy Monte Carlo Simulation)

SUMMARY * This was a long winded way to say: “We observe n events with an uncertainty n”, but we proved it! (for this experiment at least).

* Background degrades statistical accuracy (see signal significance). Caution: * If we have background we usually rely on fitting (which is not to be trusted 100%).

* χ2 fits tend to underestimate when statistics are small.

* If stats are very small (discoveries) probability estimation is very different. (use Poisson statistics).

* Experiments are much more complex than this toy simulation (see next section).

* In reality R(apple,apple cherry + mush) <<< 4 x 10-4 !

Additional Notes – Signal Significance, Q

We select S signal events with and uncertainty (S+B)where B is the number of selected background events.

The ratio Q = S/ (S+B) is called signal significance;sometimes written as S/ B (what if B 0 ?!)

It is desirable to maximise Q (to minimise the relative error in a measurement).This is usually done by optimising cuts such that background is reduced withminimal reduction in signal.

“Optimal” is often not easy to quantify, especially where selection cuts aremulti-dimensional.

A quantitative method for cut optimisation is to maximise the product:

Signal Purity x Signal Efficiency

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Selection of signalwith more or less background

Signal

Signal

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Introduction to Data Analysis

2. A couple of analysis examples from ALEPH at the LEP collider

(data taking 1989 to 1995)

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LEP – the Large Electron Positron collider – was a Z Boson factory.

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Example 1

A simple analysis: BR(Z + -)

Extracts from the presentation given by Bob Jacobsen

“From Raw Data to Physics”CERN Summer School 2006

For the full presentation (on video), seehttp://agenda.cern.ch/fullAgenda.php?ida=a062776

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Measure:

Take a sample of events, and count those with a final state.

Look for two tracks, approximately back-to-back with the expected |p|Empirically, other kinds of events have more tracks

Look for muon hits in outer layersMuons are very penetrating, travel through entire detector

Look for only small energy in calorimetersElectrons will deposit most of their energy early in the calorimeter,muons deposit little energy.

BR Z 0 Number of events

Total number of events

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And so on ....... For ~ a million events

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We see, for example, 26400 Z + - events in a total of 1,000,000 events.

The result, including statistical uncertainty is

BR( Z + - ) = N / Ntotal ± N/ Ntotal

= 0.026400 ± 0.000162

But we don’t see all events (some are lost own the beam pipe) and so we need to apply an efficiency correction factor of, for example 1.250 ± 0.004

The final result is:

BR( Z + - ) = 0.0330 ± 0.0002 ± 0.0001

0.026400 x 1.25 0.0330 x 0.004/1.250=0.0330 x 0.32% 0.000162 x 1.25

Statistical error Systematic error

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Example 2

± meson production in Z decays

We wish to measure the production rate of the ±

(average number per hadronic Z decay), and themomentum spectra.

test of hadronisation models.

http://durpdg.dur.ac.uk/hepdata/online/rsig/index.htmlAn up-to-date archive of data on hadronic cross sectionmeasurements in e+e- interactions.

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This is a very problematic analysis!

• Large combinatoric background from charge particles• Huge combinatoric background from neutral pions• Very wide signal (on a large background)

also: • Reflections from other resonances• Böse Einstein correlations

both complicate the background shape

Very difficult to extract the signal!

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Let’s go back to the beginning and see how the analysis is done.....

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Event SelectionBased on charged energy and charge multiplicity

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Selecting Neutral Pions

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Be careful get the position and width of the selection window right.

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Width calibration

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Mass calibration

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Selecting Charged Pions

Mostly pions, but there is some background from electrons, muons, kaons, protons, ...

Some background can be removed by inspecting the rate of ionisation in theTPC

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dE/dxRate of energy loss per unit distance.

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Significant background is removed with a cut in the range:

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Also make sure tracks originate from close to the Interaction point.

Systematics!Don’t cut too tight on quantities that are not well modelled in the MC

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Fitting massspectra.

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A fitted signal in one of the energy intervals.

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Repeat for each energy interval, and again many times to determine systematic uncertainties.

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Results !

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Total rate

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Introduction to Data Analysis

3. What does it look like at ATLAS? (data taking 2008[?] ...)

Extracts from the presentation given by Karl Jacobs“Physics at Hadronic Colliders”

CERN Summer School 2006

For the full presentation (on video), seehttp://agenda.cern.ch/fullAgenda.php?ida=a062814

Proton proton collisions at the LHC ~109 pp collisions / s (superposition of 23 pp-interactions per bunch crossing: pile-up)

~1600 charges particles in the detector

high particle densities high requirements for the detectors

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What experimental signatures can be used ?

If leptons with large transverse momentum are observed: interesting physics !

Example: Higgs boson production and decay

Important signatures: • Leptons und photons • Missing transverse energy

p pqq

q

p pqq

qq

H

WW

No leptons / photons in the initial and final state

Quark-quark scattering:

q

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Suppression of background: Reconstruction of objects with large transverse momentum

Reconstructed tracks with pt > 25 GeV

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The ATLAS experiment• Solenoidal magnetic field (2T) in the central region (momentum measurement)

High resolution silicon detectors: - 6 Mio. channels (80 m x 12 cm) -100 Mio. channels (50 m x 400 m) space resolution: ~ 15 m

• Energy measurement down to 1o to the beam line • Independent muon spectrometer (supercond. toroid system)

Diameter 25 mBarrel toroid length 26 mEnd-cap end-wall chamber span 46 mOverall weight 7000 Tons

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Top Quark Production

Pair production: qq and gg-fusion Electroweak production of single top-quarks(Drell-Yan and Wg-fusion)

Run I

1.8 TeV

Run II

1.96 TeV

LHC

14 TeV

qq

gg

90%

10%

85%

15%

5%

95%

(pb) 5 pb 7 pb 600 pb

Run I

1.8 TeV

Run II

1.96 TeV

LHC

14 TeV

(qq) (pb)

(gW) (pb)

(gb) (pb)

0.7

1.7

0.07

0.9

2.4

0.1

10

250

60

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BR (t→Wb) ~ 100%

Both W’s decay via W ℓ (ℓ=e or ; 5%) dilepton

One W decays via Wℓ (ℓ=e or ; 30%) lepton+jets

Both W’s decay via Wqq (44%) all hadronic, not very useful

Top Quark Decays

Important experimental signatures: : - Lepton(s)

- Missing transverse momentum

- b-jet(s)

dilepton channel

lepton + jet channel

Technique used for W-mass measurement at hadron colliders:

Observables: PT(e) , PT(had)

PT() = - ( PT(e) + PT(had) ) long. component cannot

be

measured

In general the transverse mass MT is used for the determination of the W-mass

(smallest systematic uncertainty).

Z ee

,cos12 lT

lT

TW PPM

Event topology:

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mTW (GeV)

mW= 79.8 GeV

mW= 80.3 GeV

Shape of the transverse mass distribution is sensitive to mW, the measured distribution is fitted with Monte Carlo predictions, where mW is a parameter

Main uncertainties:

result from the capability of the Monte Carlo prediction to reproduce real life:

• detector performance (energy resolution, energy scale, ….)

• physics: production model pT(W), W, ...... • backgrounds

Dominant error (today at theTevatron, and most likely also at the LHC) : Knowledge of lepton energy scale of the detector !

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Signature of Z and W decays

Zl+l– Wl

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How can one claim a discovery ?

Suppose a new narrow particle X is produced:

Signal significance:

B

S

N

N S

NS= number of signal eventsNB= number of background events

in peakregion

NB error on number of background events, for large numbers otherwise: use Poisson statistics

S > 5 : signal is larger than 5 times error on background. Gaussian probability that background fluctuates up by more than 5 : 10-7 discovery

peak width due to detectorresolution

m

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Two critical parameters to maximize S

1. Detector resolution: If m increases by e.g. a factor of two, then need to enlarge peak region by a factor of two to keep the same number of signal events

NB increases by ~ 2 (assuming background flat)

S = NS/NB decreases by 2

S ~ 1 / m

“A detector with better resolution has larger probability to find a signal”

Note: only valid if H << m. If Higgs is broad detector resolution is not relevant. mH = 100 GeV → H ~0.001 GeV mH = 200 GeV → H ~ 1 GeV

mH = 600 GeV → H ~ 100 GeV H ~ mH3

2. Integrated luminosity :

NS ~ LNB ~ L

S ~ L

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H → ZZ(*) → ℓℓℓℓSignal: BR = 5.7 fb (mH = 100 GeV)

Background: Top production tt → Wb Wb → ℓ cℓ ℓ cℓ BR ≈ 1300 fb

Associated production Z bb

Z bb → ℓℓ cℓ cℓ

Background rejection: Leptons from b-quark decays → non isolated → do not originate from primary vertex (B-meson lifetime: ~ 1.5 ps)Dominant background after isolation cuts: ZZ continuum

L = 100 fb-1

Discovery potential in mass range from ~130 to ~600 GeV/c2

PT(1,2) > 20 GeV PT (3,4) > 7 GeV|| < 2.5 Isolated leptons

M(ll) ~ MZ M(l‘l‘) ~ < Mz

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H→ contCMS 100 fb-1

100 fb-1

ATLAS

Signal / background ~ 4% (Sensitivity in mass range 100 – 140 GeV/c2)background (dominated by events *) can be determined from side bands important: -mass resolution in the calorimeters, / jet separation

*) detailed simulations indicate that the -jet and jet-jet background can be suppressed to the level of 10-20% of the irreducible -background

Two isolated photons: PT(1) > 40 GeV PT(2) > 25 GeV || < 2.5

Mass resolution for mH = 100 GeV/c2:

ATLAS : 1.1 GeV (LAr-Pb)CMS : 0.6 GeV (crystals)

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CERN-Fermilab Hadron Collider Physics Summer School August 9-18, 2006 “Physics Analysis”, John Womersleyhttp://vmsstreamer1.fnal.gov/VMS_Site_03/Lectures/HCPSS/060816Womersley/index.htm

CERN-Fermilab Hadron Collider Physics Summer School August 9-18, 2006 Louis Lyons - Practical Statistics for Discovery at Hadron Collidershttp://vmsstreamer1.fnal.gov/VMS_Site_03/Lectures/HCPSS/060817Lyons/index.htm

See also

2006 CERN-Fermilab HCP Summer Schoolhttp://vmsstreamer1.fnal.gov/VMS_Site_03/Lectures/HCPSS/index.htm

2007 CERN-Fermilab HCP Summer Schoolhttp://indico.cern.ch/conferenceOtherViews.py?view=cdsagenda&confId=6238

The 2008 Hadron Collider Physics Summer SchoolFermilab, August 12-22, 2008http://hcpss.web.cern.ch/hcpss/

CERN Summer School 2006“From Raw Data to Physics”, Bob Jacobsen http://agenda.cern.ch/fullAgenda.php?ida=a062776

CERN Summer School 2006“Physics at Hadronic Colliders”, Karl Jacobshttp://agenda.cern.ch/fullAgenda.php?ida=a062814

Further Viewing

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