12 vector spaces ii
DESCRIPTION
Διανυσματικοί χώροι μαθηματικάTRANSCRIPT
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(2) Jewrome ton dianusmatik qro (R3,+, ) kai
ta snola
W1 = {(x1, x2, x3) R3 : 2x1 4x2 + 2x3 = 5}
kai
W2 = {(x1, x2, x3) R3 : 3x1 + 2x2 4x3 = 0}.
Ja meletsoume poi ap ta parapnw snola
enai dianusmatiko upqwroi tou (R3,+, ).
Arqik, parathrome ti to mhdenik stoiqeo
(0, 0, 0) th omda (R3,+) den ankei sto W1,
afo 2 0 4 0 + 2 0 = 0 6= 5, opte to W1 den
enai upqwro tou (R3,+, ).
Antjeta, (0, 0, 0) W2, opte W2 6= . Epi-
plon, an , R kai x,y W2, me
x = (x1, x2, x3), y = (y1, y2, y3), tte
3x1 + 2x2 4x3 = 0 kai 3y1 + 2y2 4y3 = 0.
Pollaplasizonta ti parapnw do isthte
me kai antstoiqa kai prosjtonta ti is-
thte pou prokptoun, petai ti
(3x1 + 2x2 4x3) + (3y1 + 2y2 4y3) = 0,20
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opte
3(x1 + y1) + 2(x2 + y2) 4(x3 + y3) = 0
kai epomnw,
x + y = (x1 + y1, x2 + y2, x3 + y3) W2,
ra, bsei th Prtash 1, toW2 enai upqwro
tou (R3,+, ).
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(3) 'Estw (M2,+, ) o pragmatik dianusmatik
qro twn 2 2 mhtrn me pragmatik stoiqea
kai
W1 = {
[
2 1
]: , , R},
W2 = {
[4 3
0
]: , , R}.
Ja meletsoume poi ap ta parapnw snola
enai upqwroi tou (M2,+, ).
Arqik, parathrome ti to mhdenik stoiqeo[0 0
0 0
]den ankei sto W1, opte to W1 den enai
upqwro tou (M2,+, ).
Antjeta,
[0 0
0 0
]W2, opte W2 6= .
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Epiplon, an , R kai[41 31
1 0
],
[42 32
2 0
]W2,
tte enai
[41 31
1 0
]+
[42 32
2 0
]
=
[41 31
1 0
]+
[42 32
2 0
]
=
[4(1 + 2) 3(1 + 2)
(1 + 2) 0
]W2.
'Ara, bsei th Prtash 1, to W2 enai upqw-
ro tou (M2,+, ).
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Tom dianusmatikn upoqrwn
H tom do perissterwn upoqrwn en dianu-
smatiko qrou enai upqwro. Sugkekrimna, an
V1, V2 enai upqwroi tou (V,+, ), tte V1 V2 enai
upqwro tou (V,+, ).
Prgmati, epeid 0 V1 kai 0 V2, petai ti
0 V1 V2, opte V1 V2 6= .
An , F kai x,y V1 V2, tte epeid ta V1,
V2 enai upqwroi kai x,y V1 kai x,y V2, petai
ti
x + y V1 kai x + y V2.
Opte, x+y V1V2 kai smfwna me thn Prta-
sh 1, petai ti V1 V2 enai upqwro tou (V,+, ).
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'Enwsh dianusmatikn upoqrwn
H nwsh do perissterwn upoqrwn en dianu-
smatiko qrou den enai en gnei upqwro. Sugke-
krimna, an V1, V2 enai upqwroi tou (V,+, ), tte
V1 V2 enai upqwro tou (V,+, ) an kai mno an
V1 V2 V2 V1.
Prgmati, an V1V2 enai upqwro tou (V,+, ) kai
V1 * V2, ja apodeiqje ti V2 V1. 'Estw, x V2.
Epeid V1 * V2, ja uprqei y V1, me y / V2.
Epeid x,y V1V2, petai ti x+y V1V2, opte
x+y V1 x+y V2. An x+y V2, tte epeid
x V2 (afo x V2), petai ti y = x+(x+y)
V2, to opoo enai topo. 'Ara, x + y / V2, opte
x+y V1 kai epeid y V1 (afo y V1), petai
ti x = (x + y) + (y) V1. 'Ara, V2 V1.
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'Ajroisma dianusmatikn upoqrwn
To jroisma do perissterwn upoqrwn en
dianusmatiko qrou enai upqwro. Sugkekrimna,
an V1, V2 enai upqwroi tou (V,+, ), tte to snolo
V1 + V2 = {x1 + x2 : x1 V1,x2 V2}
onomzetai jroisma twn upoqrwn V1, V2 kai enai
upqwro tou (V,+, ).
Prgmati, epeid 0 V1 kai 0 V2, petai ti
0 = 0 + 0 V1 + V2, opte V1 + V2 6= . Epiplon,
an , F kai x,y V1 + V2, tte x = x1 + x2kai y = y1 + y2, pou x1,y1 V1 kai x2,y2 V2.
Epeid oi V1, V2 enai upqwroi, petai ti
x1 + y1 V1 kai x2 + y2 V2.
Tte mw, epeid
x + y = (x1 + x2) + (y1 + y2)
=(x1 + y1) + (x2 + y2) V1 + V2
kai smfwna me thn Prtash 1, petai ti V1 + V2
enai upqwro.
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Shmeinoume ti V1 V2 V1 + V2. Prgmati,
epeid gia kje x V1 isqei ti x = x+0 V1+V2,
petai ti V1 V1 + V2. Omow apodeiknetai ti
V2 V1 + V2, opte telik V1 V2 V1 + V2.
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Grammik sunduasm
'Estw (V,+, ) dianusmatik qro ep tou sma-
to (F,+, ) kai
x1,x2, . . . ,xn V.
Tte, kje stoiqeo x V pou mpore na grafe sth
morf
x = 1x1 + 2x2 + + nxn,
pou 1, 1, . . . , n F , onomzetai grammik
sunduasm twn x1,x2, . . . ,xn.
Oi telest 1, 2, . . . , n onomzontai suntele-
st tou grammiko sunduasmo. Profan, kje
grammik sunduasm enai stoiqeo tou V .
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Pardeigma: 'Estw o pragmatik dianusmatik
qro (R3,+, ). Na exetasje an to dinusma x =
(10,5, 5) R3 enai grammik sunduasm twn dia-
nusmtwn
x1 = (3,1, 2), x2 = (1, 0, 4), x3 = (1, 1, 1).
Ja exetsoume an uprqoun 1, 2, 3 R, me x =
1x1 + 2x2 + 3x3. Enai
x = 1x1 + 2x2 + 3x3
(10,5, 5)=1(3,1, 2) + 2(1, 0, 4) + 3(1, 1, 1)
(10,5, 5)=(31,1, 21)+(2, 0, 42)+(3, 3, 3)
(10,5, 5)=(31+23,1+3, 21+42+3)
31 + 2 3 = 10
1 + 3 = 5
21 + 42 + 3 = 5
Epilonta to parapnw ssthma, prokptei ti
1 = 2, 2 = 1 kai 3 = 3, opte x = 2x1+x23x3kai epomnw to x enai grammik sunduasm twn
x1,x2,x3.
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Grammik jkh sunlou
'Estw (V,+, ) dianusmatik qro ep tou sma-
to (F,+, ) kai stw S = {x1,x2, . . . ,xn} na pe-
perasmno uposnolo tou V . To snolo lwn twn
grammikn sunduasmn twn x1,x2, . . . ,xn onomze-
tai grammik jkh ( apl jkh ) tou S kai sum-
bolzetai me < S > < x1,x2, . . . ,xn >, dhlad
< x1,x2, . . . ,xn >
={1x1 + 2x2 + + nxn : 1, 1, . . . , n F}.
An U =< x1,x2, . . . ,xn >, tte lgetai ti to s-
nolo U pargetai genntai ap ta diansmata
x1,x2, . . . ,xn ( ap to snolo S). Mia llh isod-
namh kfrash enai ti ta diansmata x1,x2, . . . ,xn
( to snolo S) pargoun gennon to snolo
U .
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To snolo < x1,x2, . . . ,xn > enai upqwro tou
(V,+, ), afo gia , F kai
x = 1x1 + 2x2 + + nxn,
y = 1x1 + 2x2 + + nxn,
to stoiqeo
x + y = (1 + 1)x1+(2 + 2)x2+
+(n + n)xn
ankei sto < x1,x2, . . . ,xn >.
Epiplon xi < x1,x2, . . . ,xn >, gia kje i [n],
afo
xi = 0x1 + + 0xi1 + 1xi + 0xi+1 + + 0xn.
Tlo, an W upqwro tou (V,+, ), me xi W ,
gia kje i [n], tte < x1,x2, . . . ,xn > W , a-
fo kje grammik sunduasm ap stoiqea en
dianusmatiko qrou (tou W ) enai stoiqeo tou.
Ap ta prohgomena prokptei h epmenh prtash.
Protash 2.H grammik jkh < x1,x2, . . . ,xn >
enai o mikrtero dianusmatik qro pou periqei
ta x1,x2, . . . ,xn.31
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Paratrhsh: Ap thn prohgomenh prtash pro-
kptei ti an ta diansmata y1,y2, . . . ,yn enai gram-
miko sunduasmo twn dianusmtwn x1,x2, . . . ,xn, t-
te isqei ti
< x1,x2, . . . ,xn,y1,y2, . . . ,yn >=< x1,x2, . . . ,xn > .
Pardeigma: Ston pragmatik dianusmatik qro
(Rn,+, ) an
ei = (0, 0, . . . , 0, 1i, 0, . . . , 0), i [n],
tte kje x Rn enai grammik sunduasm twn
e1, e2, . . . , en, afo, an x = (x1, x2, . . . , xn), tte
x = x1(1, 0, 0, . . . , 0) + x2(0, 1, 0, . . . , 0)+
+ xn(0, . . . , 0, 1)
= x1e1 + x2e2 + + xnen.
'Ara, isqei ti Rn =< e1, e2, . . . , en >. Exllou,
ap thn prohgomenh paratrhsh, prokptei ti
Rn =< e1, e2, . . . , en >=< e1 + e2, e1, e2, . . . , en >
=< e1 + e2, e2, . . . , en >,
dhlad gia nan dianusmatik qro mpore na upr-
qoun perisstera ap na snola, me to dio pljo
stoiqewn, pou ton pargoun.
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Grammik anexarthsa
'Estw (V,+, ) dianusmatik qro ep tou sma-
to (F,+, ). Ta diansmata x1,x2, . . . ,xn V enai
grammik exarthmna tan uprqoun
1, 2, . . . , n F,
qi la sa me to mhdenik stoiqeo tou F , ttoia
ste
1x1 + 2x2 + + nxn = 0.
An ta x1,x2, . . . ,xn den enai grammik exarthmna,
tte enai grammik anexrthta.
Isodnama, ta x1,x2, . . . ,xn enai grammik ane-
xrthta an kai mno an, gia kje 1, 2, . . . , n F ,
isqei
1x1+2x2+ +nxn = 0 1=2= =n=0.
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Paradegmata:
(1) Ta diansmata
ei = (0, 0, . . . , 0, 1i, 0, . . . , 0), i [n],
tou dianusmatiko qrou (Rn,+, ) enai grammi-
k anexrthta, afo, gia kje 1, 2, . . . , n
R, enai
1e1 + 2e2 + + nen = 0
1(1, 0, 0, . . . , 0) + 2(0, 1, 0, . . . , 0)+
+ n(0, . . . , 0, 1) = (0, 0, . . . , 0)
(1, 0, 0, . . . , 0) + (0, 2, 0, . . . , 0)+
+ (0, . . . , 0, n) = (0, 0, . . . , 0)
(1, 2, . . . , n) = (0, 0, . . . , 0)
1 = 2 = = n = 0.
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(2) Ta diansmata
x1 = (2,1, 0), x2 = (1, 3, 1), x3 = (1, 0, 2)
tou dianusmatiko qrou (R3,+, ) enai grammi-
k anexrthta, afo gia kje 1, 2, 3 R,
isqei ti
1x1 + 2x2 + 3x3 = 0
1(2,1, 0) + 2(1, 3, 1) + 3(1, 0, 2) = (0, 0, 0)
(21,1, 0)+(2, 32, 2)+(3, 0, 23)=(0, 0, 0)
21 + 2 3 = 0
1 + 32 = 0
2 + 23 = 0
1 = 2 = 3 = 0.
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