11 warm-up: (let h be measured in feet) h(t) = -5t 2 + 20t + 15 a. estimate the instantaneous...
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11
Warm-Up: (let h be measured in feet) h(t) = -5t2 + 20t + 15
a. Estimate the instantaneous velocity of the ball 3 seconds after it’s thrown.
b. Estimate the acceleration of the ball 3 seconds after it’s thrown.
c. Estimate the maximum height.
v(t) = -10t + 20
v(3) = -30 + 20 = -10 ft/s
a(t) = -10 ft/ s2
0 = -10t + 20
t = 2
h(2) = 35 feet
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Area and the Fundamental Theorem of Calculus
5.4
Day 1 Homework: p. 348/9: 2-8 EVEN, 18-28 EVENDay 2 Homework: p. 348: 10-16 EVEN, p. 349: 48-56 EVEN
33
Understand the relationship between area and definite integrals.
Evaluate definite integrals using the Fundamental Theorem of Calculus.
Use definite integrals to solve marginal analysis problems.
Find the average values of functions over closed intervals.
Use properties of even and odd functions to help evaluate definite integrals.
Objectives
44
Rules for Definite Integrals
Order of Integration
Zero
Constant Multiple
b
a
a
b
dxxfdxxf )()(
0)( a
a
dxxf
b
a
b
a
dxxfkdxxkf )()(
b
a
b
a
dxxfdxxf )()(
55
Example 1 Using the Rules for Definite Integrals
Suppose
Find each of the following integrals, if possible.
.14 and,11,93
4
5
3
3
4
dxxhdxxfdxxf
3
5
dxxf 5
3
dxxf
1111
66
Example 1 Using the Rules for Definite Integrals
Suppose
Find each of the following integrals, if possible.
.14 and,11,93
4
5
3
3
4
dxxhdxxfdxxf
5
4
dxxf
5
3
3
4
dxxfdxxf
119 2
77
Example 1 Using the Rules for Definite Integrals
Suppose
Find each of the following integrals, if possible.
.14 and,11,93
4
5
3
3
4
dxxhdxxfdxxf
4
3
dxxf
Not possible; not enough information given.
88
From your study of geometry, you know that area is a number that defines the size of a bounded region. For simple regions, such as rectangles, triangles, and circles, area can be found using geometric formulas.
In this section, you will learn how to use calculus to find the areas of nonstandard regions, such as the region R shown in Figure 5.5.
Area and Definite Integrals
Figure 5.5
99
Example 2: Use the graph of the integrand and areas to evaluate the integral
.)32/(4
2
dxx
2 5
6A=1/2(6)(2+5)=
21
1010
Example 2 – Evaluating a Definite Integral Using a Geometric Formula
The definite integral
represents the area of the region bounded by the graph of f (x) = 2x, the x-axis, and theline x = 2, as shown in Figure 5.6.
Figure 5.6
1111
Example 3 – Evaluating a Definite Integral Using a Geometric Formula
The region is triangular, with a height of 4 units and a base of 2 units. Using the formula for the area of a triangle, you have
cont’d
1212
If f is any function that is continuous on a closed interval [a, b] then the definite integral of f (x) from a to b is defined to be
where F is an antiderivative of f. Remember that definite integrals do not necessarily represent areas and can be negative, zero, or positive.
The Fundamental Theorem of Calculus
1313
Example 4: Evaluating a Definite Integral
dx
u = x – 2
du = dx
du
-
dx
• No substitution needed here.
= 0
=
0 – = -
u = 3 - 2
u = 0 - 2
1414
Closure: Area Under a Curve
Determine the area under the curve over the interval [–4, 4].
216 xy
2
2
1rA
242
1 A
8A
1515
Warm-Up: v(t) = 800 – 32t. Find the distance traveled between 8 and 20 seconds.
Solution: Velocity is the derivative of distance, so you can graph the velocity function and find the area under the line to the x-axis.
The shape is a trapezoid.
A = ½ h (b1 + b1 )
h = 20 -8 = 12
b1 = v(8) =544
b2 = v(20) = 160
A = ½ (12)(544 + 160)
= 4224 units
1616
Warm-Up, p. 349: 32
Let u =
du = 4x dx;
u(2) = and u(0) = = 1
= du = =
= 1.5 and = .5
1.5 - .5 = 1
1717
Area and Definite Integrals
1818
Example 1 – Finding Area by the Fundamental Theorem
Find the area of the region bounded by the x-axis and the graph of
Solution:
Note that on the interval as shown in Figure 5.9.
Figure 5.9
1919
Example 1 – Solution
So, you can represent the area of the region by a definite integral. To find the area, use the Fundamental Theorem of Calculus.
cont’d
2020
Example 1 – Solution
So, the area of the region is square units.
cont’d
2121
Example 2 – Interpreting Absolute Value
Evaluate
Solution:
The region represented by the definite integral is shown in Figure 5.11.
Figure 5.11
2222
Example 2 – Solution
Using Property 3 of definite integrals, rewrite the integral as two definite integrals.
cont’d
2323
In this section, you will examine the reverse process. That is, you will be given the marginal cost, marginal revenue, or marginal profit and you will use a definite integral to find the exact increase or decrease in cost, revenue, or profit obtained by selling one or several additional units.
Marginal Analysis
2424
Example 3 – Analyzing a Profit Function
The marginal profit for a product is modeled by
a. Find the change in profit when sales increase from 100 to 101 units.
b. Find the change in profit when sales increase from 100 to 110 units.
2525
Example 3(a) – Solution
The change in profit obtained by increasing sales from 100 to 101 units is
2626
Example 3(b) – Solution
The change in profit obtained by increasing sales from 100 to 110 units is
2727
Average (Mean) Value
If f is integrable on the interval [a, b], the function’s average (mean) value on the interval is
.1
b
a
dxxfab
fav
2828
Example 4 – Finding the Average Cost
The cost per unit c of producing MP3 players over a two-year period is modeled by
where t is the time (in months). Approximate the average cost per unit over the two-year period.
Solution:
The average cost can be found by integrating c over the interval [0, 24].
2929
Example 4 – Solutioncont’d
Figure 5.12
3030
Even and Odd FunctionsExample 8: Evaluate each definite integral.
3131
Example 8 – Integrating Even and Odd Functions
Solution:
a. Because is an even function,
b. Because is an odd function,
3232
Closure: Applying the Definition of Average (Mean) Value
Find the average value of f (x) = 6 – x2 on [0, 5].
b
a
dxxfab
fav1
5
0
22 605
16 dxxxav
667.115
1
3334.2