1.1 imperial measurements mfm2p. in the beginning back in the day (1000s of years ago) when people...

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1.1 Imperial Measurements MFM2P

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1.1 Imperial Measurements

MFM2P

In the beginning

Back in the day (1000s of years ago) when people built things themselves, it wasn’t necessary to measure things because everyone did it themselves.

I need a bolt as wide as thumb

What you talkin’ ‘bout Willis?

However, projects became more complicated, it became necessary to have others work different parts, therefore they had to standardize measurement.

Sir, I don’t know what your

thumb looks like…

moron…

Birth of Imperialism

So they decide to take the most popular guy, measure his thumb and call it an inch. This guy was the King!

An inch was the width of a thumb

A foot was the size of the kings foot, which eventually became 12

inches.

A yard was the distance from the tip of a man's nose to the end of his outstretched arm. Eventually,

3 feet became a yard

Other systems

The British empire used this method to devise measurements for mass, volume and time. For instance a pound was equal to 7002 troy grains

Other countries developed their own units of measure7001? That’s

stupid! A pound should

be 7002…

Your sands are no match

for our stones!

What’s a troy grain?

We use wheat seeds

A new day

Eventually (in the 1800s), the French developed the Metric System

In the 1970s many commonwealth (former British colonies) switched to the metric system.

Imperial Systems

Today, the entire world is metric, except for the US, Myanmar and Liberia

The Imperial Empire

Unfortunately, the US has a HUGE influence on our culture. This influences the way we communicate and think about various systems of measurement.

Time is in seconds, minutes, hours, days,etc…

How tall are you? 5 feet 10 inches

How much do you weight? 210 lb

Football field yards

Fluids (Guinness) pint

Going the distance…

Length

inches (in or “), foot (ft or ‘), yard (yd), mile (mi)

Pump up the Volume!

VolumeTeaspoon (tsp), tablespoon (tbsp), fluid ounce (fl oz), cup (c), pint (pt), quart (qt),

gallon (gal)

Weight

WeightOunce (oz), pound

(lb), ton (tn)

Miscellaneous

Imperial Units

Length

inches (in or “), foot (ft or ‘), yard (yd), mile (mi)

VolumeTeaspoon (tsp), tablespoon (tbsp), fluid ounce (fl oz),

cup (c), pint (pt), quart (qt), gallon (gal)

WeightOunce (oz), pound (lb), ton (tn)

1 yd

If 1 yd = 3ft, then 4 yd2 = ft2

3ft

4 yd22 yd

2 yd

6 ft

6 ft

36 ft2

= (2 x 12”) + 7”= 3 feet x 12 inches 1 foot

Converting Feet to Inches

1 foot = 12 inches

3’ = 3 feet

= 36”

2’ 7” = 2‘ + 7”

= 24” +7”

= 31”

= 8.5 x 12”

8.5’ = 8.5 feet

= 102”

Page 3 Question 3

Converting Inches to Feet

1 foot = 12 inches

71 inches = How many times does 12 go into 71?

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15

1 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15

2 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30

3 3 6 9 12 15 18 21 24 27 30 33 36 39 42 45

4 4 8 12 16 20 24 28 32 36 40 44 48 52 56 60

5 5 10 15 20 25 30 35 40 45 50 55 60 65 70 75

6 6 12 18 24 30 36 42 48 54 60 66 72 78 84 90

7 7 14 21 28 35 42 49 56 63 70 77 84 91 98 105

8 8 16 24 32 40 48 56 64 72 80 88 96 104 112 120

9 9 18 27 36 45 54 63 72 81 90 99 108 117 126 135

10 10 20 30 40 50 60 70 80 90 100 110 120 130 140 150

11 11 22 33 44 55 66 77 88 99 110 121 132 143 154 165

12 12 24 36 48 60 72 84 96 108 120 132 144 156 168 180

13 13 26 39 52 65 78 91 104 117 130 143 156 169 182 195

14 14 28 42 56 70 84 98 112 126 140 154 168 182 196 210

15 15 30 45 60 75 90 105 120 135 150 165 180 195 210 225

71 inches = 5 feet + ??? inches

71 inches = 5 feet + 11 inches

5’ = 60”

71” -60” = 11”

Page 3 Question 4a

The school gymnasium floor needs to be resurfaced. Hardwood flooring costs $6 per square foot plus $2.50 per square foot for installation. The gym measures 180ft by 220ft.

a) Size of gym = (length) (width)

= (220 ft) (180 ft)

= 39 600ft2 Therefore the gym is 39 600ft2.

b) Cost to buy hardwood = ($6.00/ft2) (39 600ft2)

= $237 600 The cost of the hardwood is $237 600.

c) Cost of Installation = ($2.50/ft2) (39 600ft2)

= $99 000 Therefore the cost of installation is $99 000

Word ProblemsPage 3 Question 6