10.3 systems of linear equations: matrices

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10.3 Systems of Linear Equations: Matrices

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10.3 Systems of Linear Equations: Matrices. A matrix is defined as a rectangular array of numbers,. Column j. Column n. Column 1. Column 2. Row 1. Row 2. Row 3. Row 4. Augmented Matrix:. Row Operations on an Augmented Matrix. 1. Interchange any two rows. - PowerPoint PPT Presentation

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Page 1: 10.3  Systems of Linear Equations: Matrices

10.3 Systems of Linear Equations:

Matrices

Page 2: 10.3  Systems of Linear Equations: Matrices

A matrix is defined as a rectangular array of numbers,

Column 1 Column 2 Column j Column n

Row 1

Row 2

Row 3

Row 4

Page 3: 10.3  Systems of Linear Equations: Matrices

Augmented Matrix:

Page 4: 10.3  Systems of Linear Equations: Matrices

Row Operations on an Augmented Matrix

1. Interchange any two rows.

2. Replace a row by a nonzero multiple of that row.

3. Replace a row by the sum of that row and a constant multiple of some other row.

Page 5: 10.3  Systems of Linear Equations: Matrices

Echelon Form of an Augmented Matrix

Page 6: 10.3  Systems of Linear Equations: Matrices

Solve

Find the echelon form.

Find the augmented matrix:

R2=-2 R1+ R2

Page 7: 10.3  Systems of Linear Equations: Matrices

R2 =R2/3

R3 =-4R2+R3

Page 8: 10.3  Systems of Linear Equations: Matrices

R3=R3*(-3/25)

The third row of the matrix represents the equation z =-7/25. Substituting this into the equation represented by the second row we get:

Page 9: 10.3  Systems of Linear Equations: Matrices

Let z =-7/25, y =-44/25 in the first:

Solution is:

Page 10: 10.3  Systems of Linear Equations: Matrices

Solve

using a graphing utility.

Page 11: 10.3  Systems of Linear Equations: Matrices

Substitute z = 5 into the second.

Substitute z=5, y =-2 into the first.

Page 12: 10.3  Systems of Linear Equations: Matrices

Solution is (x, y, z) = (1, -2, 5).

Page 13: 10.3  Systems of Linear Equations: Matrices

Dependent system: Infinitely many solutions.

Solve using a graphing utility:

Using rref(.) function we get:

Page 14: 10.3  Systems of Linear Equations: Matrices

Solve for y from the second: Solve for x from the first:

Solution is (x, y, z) = (18/5 - (7/5)z, 7/5 + (2/5)z, z)