10 lectures ppt
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PowerPoint Lectures for
Biolog y: Concepts and Connect ions, Fi f th Edi t ion
– Campbell , Reece, Taylor, and Simon
Lectures by Chris Romero
Chapter 10
Molecular Biology of the
Gene
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10.2 DNA and RNA are polymers of nucleotides
• Nucleic acids are polynucleotides made of longchains of nucleotide monomers
– Nitrogenous bases
• Single-ring pyrimidines: thymine (T),
cytosine ( C)
• Double-ring purines: adenine (A), guanine
(G)
– Sugar-phosphate backbone
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• DNA and RNA are identical except for two
things
– Nitrogenous bases
• DNA: A, C, G, T
• RNA: A, G, C, U
– Sugars
•DNA: deoxyribose
• RNA: ribose
Animation: DNA and RNA Structure
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LE 10-2a
Sugar-phosphate backbone Phosphate group Nitrogenous base
Sugar
DNA nucleotide
DNA polynucleotide DNA nucleotide
Sugar
(deoxyribose)
Thymine (T)
Nitrogenous base
(A, G, C, or T)Phosphate
group
A
C
T
G
T T
G
T
C
A
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LE 10-2b
Thymine (T) Cytosine (C) Pyrimidines
Adenine (A) Purines
Guanine (G)
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LE 10-2c
Phosphate
group
Nitrogenous base
(A, G, C, or U)
Sugar
(ribose)
Uracil (U)
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LE 10-2dKey
Hydrogen atom
Phosphorus atom
Carbon atom Nitrogen atom Oxygen atom
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10.3 DNA is a double-stranded helix
• James Watson and Francis Crick worked outthe three-dimensional structure of DNA, based
on X-ray crystallography by Rosalind Franklin
• DNA consists of two polynucleotide strandswrapped around each other in a double helix
– Sugar-phosphate backbones are on the
outside and nitrogenous bases on the inside
Animation: DNA Double Helix
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– Each base pairs with a complementary
partner
• A with T, and G with C
– Hydrogen bonds between the bases hold
the strands together
• The Watson-Crick model of DNA suggested a
molecular explanation for genetic inheritance
LE 10 3
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LE 10-3c
Twist
LE 10 3d
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LE 10-3d
Hydrogen bond Base
pair
Ribbon model Partial chemical structure Computer model
G C T A
A T
T A
C C
G G
G C
T T
T T
A A A
A
G C A T
A
C
T
G
C G
A T
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DNA REPLICATION
10.4 DNA replication depends on specific base pairing
•
The Watson-Crick model of DNA structure suggesteda mechanism for its replication
– DNA strands separate
– Enzymes use each strand as a template toassemble new nucleotides into complementary
strands
• The mechanism of DNA replication is
semiconservative
– Each new double helix consists of one old and one
new strand
LE 10 4
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LE 10-4a
Parental
molecule
of DNA
Both parental
strands serve
as templates
Two identical
daughter molecules
of DNA
T
Nucleotides
C G A
G C A
A T
T
A
A
A C
C C
T
T
G G
A C
A A A
A
A
A
C C C
C G
T G
T T
T
T G
T
T T
G G
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• DNA replication is a complex process
– Some of the helical DNA molecule mustuntwist
Animation: DNA Replication Overview
LE 10 4b
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LE 10-4b
G C T A
A T G
G C C
C
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10.5 DNA replication: A closer look
• DNA replication begins at specific sites (originsof replication) on the double helix
– Proteins attach and separate the strands
– Replication proceeds in both directions,
creating replication bubbles
• Parent strands open, daughter strands
elongate
– Replication occurs simultaneously at many
sites
LE 10 5a
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LE 10-5a
Origin of replication
Bubble
Parental strand Daughter strand
Two daughter DNA molecules
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• DNA's sugar-phosphate backbones are
oriented in opposite directions
– The enzyme DNA polymerase adds
nucleotides at only the 3’ end
•One daughter strand is synthesized as acontinuous piece
• The other strand is synthesized as a series
of short pieces
• The two strands are connected by the
enzyme DNA ligase
LE 10-5b
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LE 10-5b
3 end 5 end
5 end 3 end
P
4 A
T
C
G
HO
OH
P 1 3
2
5 P
P
P
P
C
G
P
P
A
T
P
4 3
1 2
5
LE 10-5c
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LE 10-5cDNA polymerase
molecule
Parental DNA Daughter strand
synthesized
continuously
Daughter
strand
synthesized
In pieces
3
5
3
5
5
3
3
5
DNA ligase Overall direction of replication
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Animation: Origins of Replication
Animation: Leading Strand
Animation: Lagging Strand
Animation: DNA Replication Review
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THE FLOW OF GENETIC INFORMATIONFROM DNA TO RNA TO PROTEIN
10.6 The DNA genotype is expressed as
proteins, which provide the molecular basis for
phenotypic traits
• The information constituting an organism's
genotype is carried in its sequence of DNA
bases
• A particular gene—a linear sequence of many
nucleotides—specifies a particular polypeptide
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• The flow of genetic information
1. Transcription of the genetic information in DNAinto RNA
2. Translation of RNA into the polypeptide
•
Beadle-Tatum one gene-one enzyme hypothesis – Studies of inherited metabolic disorders in mold
suggested that phenotype is expressed through
proteins
– A gene dictates production of a specific enzyme
– The hypothesis has been restated to one gene-
one polypeptide
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10.7 Genetic information written in codons is
translated into amino acid sequences
• Genetic information flows from DNA to RNA to
protein
• Nucleotide monomers represent letters in analphabet that can form words in a language
– Triplet code
• Three-letter words (codons)
• Each word codes for one amino acid in a
polypeptide
LE 10-7a
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DNA molecule
Gene 1
Gene 2
Gene 3
A A A A A C C G G C
C C G G G U U U U U U U
A A DNA strand
Transcription
RNA
Translation
Polypeptide Amino acid
Codon
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10.8 The genetic code is the Rosetta stone of life
• The genetic code specifies thecorrespondence between RNA codons and
amino acids in proteins
– Includes start and stop codons
– Redundant but not ambiguous
• Nearly all organisms use exactly the same
genetic code
LE 10-8a
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Second base
UUU U C A G
G A A
C
U
U
U
C
A C
A
G
G U C A G
U
C
A
G
UUC UUA UUG CUU CUC CUA CUG AUU AUC AUA
Leu
lle
AUG Met or
start GUU GUC GUA GUG
Val Ala
Thr
GCG GCA GCC GCU ACG ACA ACC ACU
Pro
CCG CCA CCC CCU UCG UCA UCC UCU
Ser Tyr Cys UAU
UAC UAA UAG CAU CAC CAA CAG
His
Gln
Stop Stop
UGU UGC UGA UGG Trp
Stop
Arg
CGU CGU CGA CGG
Asn
Lys
Asp
Glu Gly
Arg
Ser AAU AGU AAC AAA AAG GAU
GAG
AGC AGA AGG GGU GGC
GGG
Phe
Leu
GAC GAA GAG
GGA
LE 10-8b
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Strand to be transcribed
Transcription
DNA T
A G T
A C T T
T T
A A
A A G
C
G
C
T T
T A A
A
A G U RNA
Translation Start
codon
A A U U G U U A G
Stop
codon
Phe Lys Met Polypeptide
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10.9 Transcription produces genetic messages in
the form of RNA
• One DNA strand serves as a template for the
new RNA strand
• RNA polymerase constructs the RNA strand ina multistep process
– Initiation
• RNA polymerase attaches to the promotor
• Synthesis starts
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• Elongation:
– RNA synthesis continues
– RNA strand peels away from DNA template
– DNA strands come back together in
transcribed region
• Termination
– RNA polymerase reaches a terminator sequence at the end of the gene
– Polymerase detaches
LE 10-9a
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RNA
polymerase RNA nucleotides
Template
strand of DNA Direction of
transcription
Newly made RNA
A A C C
C C A
G T T
U A
G T A
LE 10-9b
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RNA polymerase
Initiation
Promoter
DNA Terminator
DNA
Area shown
In Figure 10.9A
Initiation
Elongation
Termination Growing
RNA
Completed RNA RNA
polymerase
DNA of gene
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Animation: Transcription
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10.10 Eukaryotic RNA is processed before
leaving the nucleus
• The RNA that encodes an amino acid
sequence is messenger RNA (mRNA)
• In prokaryotes, transcription and translationboth occur in the cytoplasm
• In eukaryotes, RNA transcribed in the nucleus
is processed before moving to the cytoplasmfor translation
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• RNA Splicing
– Noncoding segments called introns are cutout
– Remaining exons are joined to form a
continuous coding sequence
– A cap and a tail are added to the ends
LE 10-10
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Exon Exon Exon Intron Intron
Cap DNA
RNA
transcript
with cap
and tail
mRNA
Coding sequence Nucleus
Cytoplasm
Exons spliced together
Tail Introns removed
Transcription
Addition of cap and tail
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10.11 Transfer RNA molecules serve as interpreters
during translation
• Transfer RNA (tRNA) molecules match the right amino
acid to the correct codon
• tRNA is a twisted and folded single strand of RNA
– Anticodon loop at one end recognizes a particular
mRNA codon by base pairing
– Amino acid attachment site is at the other end
• Each amino acid is joined to the correct tRNA by a
specific enzyme
LE 10-11a
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Amino acid attachment site
Hydrogen bond
RNA polynucleotide chain
Anticodon
LE 10-11bAmino acid
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Anticodon
Amino acid
attachment site
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10.12 Ribosomes build polypeptides
• A ribosome consists of two subunits
– Each is made up of proteins and ribosomal
RNA (rRNA)
• The subunits of a ribosome
– Hold the tRNA and mRNA close together in
binding sites during translation
– Allow amino acids to be connected into a
polypeptide chain
LE 10-12a
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tRNA
molecules Growing
polypeptide
Largesubunit
Small
subunit mRNA
LE 10-12btRNA-binding sites
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tRNA-binding sites
Largesubunit
Small
subunit
mRNA
binding
site
LE 10-12c
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Growing
polypeptide
mRNA
Codons
tRNA
Next amino acid
to be added to
polypeptide
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10.13 An initiation codon marks the start of an
mRNA message
• The initiation phase of translation
– Brings together mRNA, a specific tRNA,
and the two subunits of a ribosome
– Establishes exactly where translation will
begin
• Ensures that mRNA codes are translated in
the correct sequence
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• Initiation is a two-step process
– Step 1
• mRNA binds to a small ribosomal subunit
• Initiator tRNA, carrying the amino acid Met,
binds to the start codon
– Step 2
•
A large ribosomal subunit binds to the smallone, forming a functional ribosome
• Initiator tRNA fits into one binding site; the
other is vacant for the next tRNA
LE 10-13a
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Start of genetic message
End
LE 10-13b
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C
Initiator tRNA P site
mRNA Start codon
Small ribosomal
subunit
A site
Large
Ribosomal
subunit
C A U A A U
U G A G U
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10.14 Elongation adds amino acids to the
polypeptide chain until a stop codon terminates
translation
• Once initiation is complete, amino acids are
added one by one in a three-step elongation
process
1. Codon recognition
2. Peptide bond formation
3. Translocation
• Elongation continues until a stop codon reaches
the ribosome's A site, terminating translation
LE 10-14Amino
id
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Polypeptide P site
mRNA
A site
Codons Anticodon
acid
Condon recognition
Peptide bond
formation New
peptide
bond
Translocation
Stop
codon
mRNA
movement
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Animation: Translation
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10.15 Review: The flow of genetic information in
the cell is DNA RNA protein
• The sequence of codons in DNA, via the
sequence of codons in RNA, spells out the
primary structure of a polypeptide
1. Transcription of mRNA from a DNA
template
2. Attachment of amino acid to tRNA
3. Initiation of polypeptide synthesis
4. Elongation
5. Termination
LE 10-15DNA Transcription
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mRNA RNA
polymerase mRNA is
transcribed from a
DNA template.
Each amino acid
attaches to its proper tRNA with the help of a
specific enzyme and ATP.
Translation Amino acid
mRNA
Enzyme
ATP
Anticodon Large
ribosomal
subunit Initiator
tRNA
Start Codon Small
ribosomalsubunit
U A A U
C G
Initiation of
polypeptide synthesis
The mRNA, the first
tRNA, and the ribosomal
Sub units come together.
Stop codon
A succession of tRNAs
add their amino acids to
the polypeptide chain
as the mRNA is moved
through the ribosome,
one codon at a time.
Growingpolypeptide
New peptidebond forming
mRNA
Polypeptide
Codons
Elongation
Termination The ribosome recognizes
a stop codon. The poly-
peptide is terminated
and released.
tRNA
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10.16 Mutations can change the meaning of
genes
• Mutation: any change in the nucleotide
sequence of DNA
– Caused by errors in DNA replication or recombination, or by mutagens
– Can involve large regions of a chromosome
or a single base pair
– Can cause many genetic diseases, such as
sickle-cell disease
LE 10-16a
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Normal hemoglobin DNA
mRNA
C T T
A A G
Normal hemoglobin Glu
mRNA
C
G
A
Sickle-cell hemoglobin Val
Mutant hemoglobin DNA
A
T
U
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• Two general categories of genetic mutations
–
Base substitutions replace one base withanother
• Most are harmful but may occasionally have
no effect or be beneficial
– Base insertions or deletions alter the
reading frame
• Result is most likely a nonfunctioning
polypeptide
• Mutagenesis caused by spontaneous error or
a physical or chemical mutagen
LE 10-16bNormal gene
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Base substitution
Protein mRNA
Base deletion
Missing
Met
Met
Met Lys
Lys
Lys Phe Gly Ala
Ala Phe
Ala
Ser
Leu His
A
A A A A
A A A
A
A A A A A U U U U
U U U U
U U U U G G G G G
G G G G
C C
C C
G G G G G C C
U
MICROBIAL GENETICS
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10.17 Viral DNA may become part of the host
chromosome
• Viruses are infectious particles consisting of
nucleic acid enclosed in a protein capsid
• Viruses depend on their host cells for thereplication, transcription, and translation of
their nucleic acid
– DNA enters host bacterium, circularizes,and enters one of two pathways
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– Lytic cycle
•
Host produces more viruses
• Host cell lyses (breaks open) to release new
viruses
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– Lysogenic cycle
•
Phage DNA inserted by recombination intothe host chromosome; is now a prophage
• Prophages replicated each time host cell
divides; passed on to generations of
daughter cells
• Does not destroy host
•
Environmental signal may trigger switchfrom lysogenic to lytic cycle
LE 10-17
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Phage
Phage DNA
Attaches
to cell
Cell lyses,
releasing phagesPhage injects DNA
Lytic cycle
Phages assemblePhage DNA
circularizes
New phage DNA and
proteins are synthesized
Bacterial
chromosome
OR
Lysogenic cycle
Prophage
Many cell
divisions
Lysogenic bacterium repro-
duces normally, replicating the
prophage at each cell division
Phage DNA inserts into the bacterial
chromosome by recombination
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Animation: Simplified Viral Reproductive Cycle
Animation: Phage T4 Lytic Cycle
Animation: Phage Lambda Lysogenic and Lytic Cycles
CONNECTION
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10.18 Many viruses cause disease in animals
• Structure of a virus that invades animal cells
– Genetic material may be RNA (examples:
flu, HIV) or DNA (examples: hepatitis,
herpes)
– Protein coat
– Sometimes a membranous envelope with
glycoprotein spikes
• The envelope helps the virus enter and leave
the host cell during its reproductive cycle
LE 10-18aMembranous
envelope
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envelope
RNA
Protein
coat
Glycoprotein spike
LE 10-18bVIRUS
Viral RNA Glycoprotein spike P t i t
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(genome) Protein coat Envelope
Entry Plasma membrane
of host cell
Uncoating Viral RNA
(genome) RNA synthesis
by viral enzyme RNA synthesis
(other strand)
Template mRNA Protein
synthesis
New
viral proteins
New viral
genome Assembly
Exit
CONNECTION
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10.19 Plant viruses are serious agricultural pests
• Most plant viruses
– Have RNA genomes
– Enter their hosts via wounds in the plant's
outer layers
– May spread throughout the plant through
plasmodesmata
• There is no cure for most plant viruses
LE 10-19
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RNA
Protein
CONNECTION
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10.20 Emerging viruses threaten human health
•Emerging viruses have appeared suddenly or have recently come to the attention of
scientists
– Examples: HIV, SARS, Ebola, West Nile
• Processes contributing to emergence
– Mutation
– Contact between species
– Spread from isolated populations
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10.21 The AIDS virus makes DNA on an RNA
template
• HIV, the AIDS virus, is a retrovirus
– Flow of genetic information is RNA _ DNA
– Inside a cell, HIV uses its RNA as a
template for making DNA
– The enzyme reverse transcriptase catalyzes
reverse transcription
Animation: HIV Reproductive Cycle
LE 10-21a
Envelope
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p
Glycoprotein
Proteincoat
RNA
(two identicalstrands)
Reverse
transcriptase
LE 10-21b
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Viral RNA
DNA
strand Double-
stranded
DNA
Viral
RNA
and
proteins
C YTOPLASM NUCLEUS
Chromosomal
DNA Provirus
DNA
RNA
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10.22 Bacteria can transfer DNA in three ways
•Bacteria can transfer genes from cell to cell byone of three processes
– Transformation: the uptake of foreign DNA
from the surrounding environment
– Transduction: transfer of bacterial genes by
a phage
– Conjugation: union of two bacterial cells andthe transfer of DNA between them
LE 10-22a
DNA enters
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cell
Fragment of
DNA from
another
bacterial cell
Bacterial chromosome
(DNA)
LE 10-22bPhage
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Fragment of DNA from
another bacterial cell
(former phage host)
LE 10-22cMating bridge
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Recipient cell
(“female”)
Sex pili
Donor cell
(“male”)
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• Once new DNA is in a bacterial cell, part of it
may integrate into the recipient's chromosome
– Occurs by crossing over between the two
molecules
–
Leaves the recipient with a recombinantchromosome
LE 10-22d
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Donated DNA Crossovers Degraded DNA
Recombinant
chromosome Recipient cell’s
chromosome
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10.23 Bacterial plasmids can serve as carriers for
gene transfer
• The F factor is a piece of bacterial DNA
– Carries genes for things needed for
conjugation
– Contains an origin of replication
– Can transfer chromosomal DNA by
integrating into the donor bacterium's
chromosome or entering the cell as a
plasmid
LE 10-23aF factor (integrated)
Male (donor)
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Male (donor)
cell
Origin of F
replication
Bacterial
chromosome
F factor starts replication
and transfer of chromosome
Recipient cell
Only part of the
chromosome transfers
Recombination can occur
LE 10-23bF factor (plasmid)
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Cell now male
Plasmid completes
transfer and circularizes
F factor starts replication
and transfer
Bacterial
chromosome
Male (donor)
cell
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• Plasmids
– Small circular DNA molecules separatefrom the bacterial chromosome
– Can serve as carriers for the transfer of
genes
LE 10-23c
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Plasmids
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