1. introduction; equations, variables & units
TRANSCRIPT
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Processteknikens grunder (”PTG”)Introduction to Process Engineering
course # 424101.0 v. 2014
Ron ZevenhovenÅbo Akademi University
Thermal and flow engineering (Värme- och strömningsteknik: VST) *tel. 3223 ; [email protected]
1. Introduction; Equations, variables & units
* until August 2009: Heat engineering laboratory (Värmeteknik, VT)
Åbo Akademi University | Thermal and Flow Engineering | 20500 Turku | Finland
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1.1 Process engineering; This course
2014: weeks 36-44: 1 Sept. – 31 Oct.Mon + Tue + Thu 1-3 pm
Åbo Akademi University | Thermal and Flow Engineering | 20500 Turku | Finland
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Contents of course 2014 (lecture hours +/-)
Introduction; Equations, variables and units (2)
System boundaries; Mass balances; Other balances (2)
Energy balances (1st Law of Thermodynamics), Energy efficiency(2nd Law of Thermodynamics), Equilibrium (10-12)
Heat exchangers and Heat (steam) cycles (6-7)
Heat transfer (conduction, convection, radiation) (10-12)
Fluid flow and Tube flow (8-10)
Exercises / Old exams (10)
Additional material (not part of exam !) on– Mass transfer; Separation processes– Particle technology; Multi-phase systems– Process equipment– Process control
For those for whom this course will be the first and last engineering course : take a look......
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What is a process?
”A process occurs whenever some property of a system changes or if there is an energy or mass flow across the boundary of a system”(source: KJ05)
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What is process engineering ?
“Process engineering is often a synonym for chemical engineering and focuses on the design, operation and maintenance of chemical and material manufacturing processes” (source: wikipedia)
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A typical process: CO2 stripping
Picture: SA05
Natural gas + CO2
Liquid solventfor example
alkanol amine
Natural gas
Liquid solvent+ CO2
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Chemical process engineering
ThermodynamicsHeat transfer Fluids engineering
Separationprocesses
Process equipmentand plant design
Mass transfer
Process control andautomation
This course: a lot This course: a bit
”THERMAL SCIENCES”
Process economics and legislation
Chemical reaction engineering
Product, waste andby-product handling
Process safety and maintenance
Raw material pre-processing
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1.2 Process calculations; Equations, variables and units
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Process calculations /1
Engineering calculations often start with balance equations (mass balance, energy balance, element balances, etc.) – see #2
Dynamics equations are often ordinary or partial differential equations with time as onevariable. Very important are boundaryconditions and starting conditions.
! Always respect the Laws of Physics ! Always check whether the result of a
calculation makes sense and is possible.for example: 0 ≤ reactor mass < mass of earth,
temperature ≥ 0 K, pressure ≥ 0 Pa
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Process calculations /2
Back-of-the-envelope calculation may be morepowerful than a computer !
The results of good models may be close to reality but nonetheless will be incorrect.
Analytical solutions are often more useful(as a result of a wider range of applicability)
than numerical solutions. ! Too many decimals make no sense ! Engineering calculation results will be adjusted
and rounded-off to shop specifications: for example: calculated tube diameter 2.93 m 3 m
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Process calculations /3
Some basic rules for variable symbols: – don’t use one symbol for two different things– try to use one character per variable– choose symbols ”logically”: time t, volume V, ...
for example: pressure p, temperature T, etc.– use indices/subscripts if one symbol is needed
for several things, use vectors x1, x2, x3, ...– use supercripts 2, 3 etc. for square x2, cube x3, ..– vector notation can make equations compact
for example v = (vx, vy, vz) in x,y,z coordinates
Always remember: READ IT AS PHYSICS.Åbo Akademi University | Thermal and Flow Engineering | 20500 Turku | Finland
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Prefix symbols for scales of 10
be careful with decimal . or ,
use scales of 10: 1 Gg = 109 g = 106 kg;1 nm = 0.001 µm = 10-6 mm = 10-9 m;etc.
Engineers usuallystick to powers of 3:103, 10-6, 109, etc.
Table: KJ05
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Variables and units /1
A property or quantity (sv: storhet) of an object, substance or material can be defined as a characteristic that can be measured or calculated.
The value of a property or quantity)(sv: storhetvärde) is a combination of a numericalamount (sv: mätetal) and a unit (sv: måttenhet)
for example: length = 6.5 mquantity value unit
speed = 50 km/s
Without a unit the information of a value is of limited use or even useless !
Picture: KJ05
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Most engineering calculations are based on physicalquantities that can be expressed as combinations of seven base quantities (sv: grundstorheter)
In the SI system (Système Internationale) these have the following base units (sv: grundenheter):
Base quantity Base unit name Base unit symbol (SI)
Length meter m
Mass kilogram kg
Time second s
Temperature Kelvin K
Amount of substance mole mol
Electric current Ampère A
Luminous intensity candela cd
Variables and units /2
Mostrelevant
forprocess
technology
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Derived units (sv: härledda enheter) are based on combinations of basic units. Some examples of the ~ fifteen derived units:Quantity (symbol) Unit name, symbol Definition
Force (F) Newton, N kg m s-2
Pressure (p) Pascal, Pa kg m-1 s-2 = N m-2
Energy (E) Joule, J kg m2 s-2 = N m
Power (P) Watt, W kg m2 s-3 = J s-1
Frequency (f) Herz, Hz s-1
Electric charge (q) Coulomb, C A s
Catalytic activity katal, kat mol s-1
• Other units can always be rewritten as basic units:for example for dynamic viscosity: unit Pa·s = kg m-1 s-1
Variables and units /3
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Variables and units /4 Different sets of base units can be used,
for example 1 mil (in Sweden) = 10 km.
Most important are the Anglo-Saxon or US ConventionalSystem (USCS) units: 1” = 1 inch = 2.54 cm ;1 foot = 1 ft = 12” = 30.48 cm; 1 yard = 1 yd = 3 ft1 ounce = 1 oz = 28.35 g;1 pound = 1 lb = 16 oz = 0.454 kg ;1 pound per square inch = 1 psi = 6894.8 Pa; 1 bar = 105 Pa = 14.504 psi;1 gallon US = 3.7854 liter; 1 gallon UK = 4.5461 liter1 barrel US = 158.9873 liter
Temperature as °C or °F or K (see slide 24)1 British thermal unit = 1 BTU = 1055 J
one ounce of gold
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Variables and units /5
Calculatingnon-SI units ↔ SI unitsshould be a routine thing !
Use conversion tables.
Examples of some very important units:1 torr = 1 mm Hg (at 0°C)= 133.32 Pa; 1 atm = 101325 Pa1 t = 1 metric ton = 1000 kg; (viscosity: ) 1 centipoise = 1 cP = 0.001 Pa· s 1 kWh = 3.6 MJ; 1 calorie = 1 cal = 4.184 J; 1 Å = 0.1 nm
Picture: KJ05
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A property is a characteristic of a system (see #2), which is related to a mass or a subtance, or to energy: for example: temperature, mass, volume, pressure, viscosity
An extensive property depends on the mass in the system for example volume, energy, ...
An intensive property is independent of the amount of material for example temperature, pressure, density...
Picture: CB98
Properties, state properties /1
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Properties, state properties /2
A specific property is an extensive property per unitmass (resulting in an intensive property) for example specific volume = volume / mass = 1/density; unit: m3/kg ; specific energy = energy / mass; unit : J/kg
A set of state properties (sv: tillståndstorheter) defines the state of a system; the other properties are related to changes
The properties that depend on the present state of a system, independent of the way howthis state was prepared, are also calledstate functions
The properties that depend on how the present state was reached or how a system is affectedby a change are called path functions (for which the path must be specified !) (source: A83)
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Åbo Akademi University | Thermal and Flow Engineering | 20500 Turku | Finland
Two ways for the same result
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Equations /1
All elements of an equation must have the same dimension.
Sometimes a constant is needed whenvariables with a different dimension are related in an expression,
for example heat transfer by
radiation (see #5): Q” = σ ·T4, with heat flux Q” (W/m2) and
temperature T (K) gives
Stefan-Boltzmann constant
σ = 5.67×10-8 W/(m2·K4) Picture: KJ05
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Relations between quantities or variables non-specific to the unit system (sv: storhetsekvationer)
for example : for mass flow m of a fluid with density ρ, flowing at velocity v through a tube with radius r.
Relations between quantities or variables specific to the unit system (sv: kvotekvationer)
for example :
for the density of an ideal gas as function of pressure p, temperature T and molar mass M.
vrm 2
m
kg
)K(T
kmol/kgM
kPap
.ρ
.
Equations /2
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Alternatively, but not recommended, equations are based on quantities and amounts (sv: mätetalsekvationer). The same unit system as the equation is based on must then be used.for examplefor the tube mass flow mentioned above, with r in mm, v in m/s, m in kg/h and ρ in kg/m3. Using other units will require a conversion and giveanother value for the constant.
vr.m 201130
.
Equations /3
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Mass, weight, moles
”Weight” is a force equal to Mass × Gravity. (sv: tyngd,vikt, massa; fi: kuorma, kuormitus, paino)
Mass = Molar mass × Number of molesnote: Molar mass as g/mol = kg/kmol = 10-3 kg/mol (!!!)
for example 1 mole O2 = 32×10-3 kg/mol
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Temperature scales
T(°F) = 1.8·T(°C) + 32 T(°C) = ( T(°F) – 32 )/1.8
T(K) = T(°C) + 273.15 T(°C) = T(K) - 273.15
T (R) = T(°F) + 459.67 T(R) = 1.8·T(K) Picture: SEHB06
for exampleuse symbols
T for T(K)and
θ for θ(°C)
Kelvin
Celsius
Fahrenheit
Rankine
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Dimensionless variables /1 The requirement of dimension-correctness of an
equation can also be used to determine physicalrelations between quantities.for example: velocity v = f ( time t, distance x)
test function: v = tα· xβ
unit left-hand-side: m+1· s-1; unit right-hand-side: sα· mβ
gives for time: α = -1; for length β = +1 → v = x / t
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Dimensionless variables /2 This method is very powerful and is used as so-called
dimension analysis in process engineering, combiningquantities in dimensionless groups. Very powerful for scale-up!
for example: pressure drop ∆p for flow of a fluid with density ρand dynamic viscosity η at velocity v in a pipe with diameter d and length L: ∆p = f(ρ,η,v,d,L) with 6 quantities and 3 basicunits (kg, m, s) requires 6 - 3 = 3 dimensionless groups. The result:
More on this method in VST course 424302 (7 sp)Massöverföring & separationsteknik / Mass transfer and separation technology
)Ld
()ηρvd
(Avρp∆
example for )Ld
,ηρvd
(fvρp∆ CB
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A few examples Calculate the diameter of a tube, in m, for a mass flow of 380 kg/s
water at 98°C, with density 960 kg/m3, at 3 m/s (ÖS96-1.1a)
answer:
For the ideal gas law p·V = n·R·T with pressure p (Pa), volume V (m3), number of moles (mol) and temperature T (K), show that the unit for the universal gas constant R is J / (mol· K)answer:
What temperature in K and in °C corresponds to 2000 °R ?answer: 2000°R = 2000/1.8 = 1111.11 K = 837.96 °C
m .v
m2 r2d
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Kmol
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323
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Sources #1 A83: P.W. Atkins ”Physical chemistry”, 2nd ed., Oxford Univ. Press
(1983) CB98: Y.A. Çengel, M.A. Boles “Thermodynamics. An Engineering
Approach”, McGraw-Hill (1998) KJ05: D. Kaminski, M. Jensen ”Introduction to Thermal and
Fluids Engineering”, Wiley (2005) SA05: Socolow, R.H. ”Can we bury global warming” Scientific
American, July 2005, 49-55 SEHB06: P.S. Schmidt, O. Ezekoye, J. R.
Howell, D. Baker “Thermodynamics: An Integrated Learning System” (Text + Web) Wiley (2006)
ÖS96: G. Öhman, H. Saxén ”Värmeteknikensgrunder”, Åbo Akademi University (1996)
Åbo Akademi University | Thermal and Flow Engineering | 20500 Turku | Finland