1 cs 201 compiler construction lecture 1 introduction

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1 CS 201 Compiler Construction Lecture 1 Introduction

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Page 1: 1 CS 201 Compiler Construction Lecture 1 Introduction

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CS 201Compiler Construction

Lecture 1Introduction

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Instructor Information

Rajiv GuptaOffice: Engg.II Room 408E-mail: [email protected]: (951) 827-2558Office Hours: T, Th 1-2 pm

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Course Requirements

Grading:Test 1: 35 pointsTest 2: 35 pointsProject: 30 points

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Course Overview

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Three Address Intermediate Code

Arithmetic Operationsdst = src1 op src2

where op in {+, -, *, /, %}Relational Operators

dst = src1 relop src2where relop in {<,<=,!

=,==,>=,>}Logical Operations

dst = src lop src2, where lop in {||,&&}dst = ! src

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Three Address Intermediate Code

Array Accessesdst = src[index]dst[index] = src

Pointersdst = & src* dst = src

Copy Assignmentdst = src

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Three Address Intermediate Code

Branchesunconditional:

goto labelconditional:

if predicate goto labelor

if src1 relop src2 goto labellabels:

declared or instruction numbers

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Examples

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See handouts.

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Control Flow Graph (CFG)

Intermediate Code can be transformed from linear representation to a directed graph form called Control flow Graph:

Nodes – Basic Blocks: Basic block consists of a sequence of intermediate code statements that must be entered at the top and exited at the bottom, i.e. once the block is entered, all intermediate code statements will be executed.

Edges: directed edges connect basic blocks according to control flow.

CFG representation will be used for program analysis and optimization.

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CFG Construction Algorithm

• Identify Leaders: the first instruction in a basic block is a leader.– First instruction in the program– Target instruction of a conditional or

unconditional branch– Instruction immediately following a

conditional or unconditional branch

• Construct Basic Blocks: – Starting from the leader append subsequent

instructions up to, but not including, the next leader or the end of the program

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CFG Construction Algorithm

• Add Edges: add a directed edge from basic block B1 to basic block B2 if:– There is a conditional or unconditional

branch from the last statement in B1 to the leader of B2; or

– B2 immediately follows B1 in program order and B1 does not end in an unconditional branch.

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Example

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1. A = 42. T1 = A * B3. T2 = T1 / C4. If T2<W goto 75. M = T1 * K6. T3 = M + I7. H = I8. M = T3 – H9. If T3>= 0 goto 1110. goto 311. Halt