1-1 application of percents - portion formula portion (p) = base (b) x rate (r) portion “is”...

1-1

Application of Percents - Portion Formula

Portion (P) = Base (B) x Rate (R)

Portion “is”

Base “of” Rate “%”

Base: 100% - whole. Usually given afterthe word of – but not always

Rate: Usually expressed as a percent butcould also be a decimal or fraction.

Portion: A number – not a percent andnot the whole

1-2

Solving for Portion

Sales of McDonalds drive-thru customers are 60% of total sales. Total sales are $1,600,000. What are the drive-thru sales?

Portion = Base x Rate

P = $1,600,000 x .60

P = $960,000

1-3

Solving for Rate

Sales of McDonalds drive-thru customers are $960,000. Total sales are $1,600,000. What Percent of customers eat in the restaurant?

Rate = Portion Base

R = $640, 000 $1,600,000

R = 40%

$1,600,000 - 960,000

1-4

Solving for Base

Sales of McDonalds drive-thru customers are 60% of total sales. Sales of eat-in customers are $640,000. What are total sales?

Base = Portion Rate

B = $640,000 .40

B = $1,600,000

eat in sales

Percent of customers that eat-in

1-5

Rate of Percent Decrease

15 oz.

Rate = PortionBase

Rate = 12 15

Amount of Decrease (P)

Original Weight (B).80 or 80%

Decrease3 oz.

Original New

Percent of Decrease (R)

1-6

Rate of Percent Increase

$1,000

Rate = PortionBase

Rate = $1,500 $1,000

Original sales (B)1.5 or 150%

Increase$2,500

Original New

Amount of Increase (P)

Percent of Increase (R)

1-7

Solving Word Problems for Unknowns

1) Read the entire Problem

2) Ask: “What is the problem looking for

3) Let a variable represent the unknown

4) Visualize the relationship between the unknowns and variables. Then set up equation

5) Check your results

Y = Computers

4Y + Y = 600

1-8

Solving Word Problems for the Unknown

Unknown(s) Variable(s) Relationship

1-9

Solving Word Problems for the Unknown

Unknown(s) Variable(s) Relationship

Barbie and Ken sell cars at the Auto World. In April they sold 15 cars. Barbie sold twice as many cars as Ken. How many cars did each sell?

2C + C = 153C = 15

C = 5

Barbie - 10 Cars

Ken 5 Cars

Cars Sold

Barbie 2C 2C

Ken C +C

15

1-10

Solving and Graphing Inequalities

** If you multiply or divideby a negative number, switch the direction of

the inequality.

1-11


5x 2 7

2 2

5x 5

5x 5

5 5

x 1

1-12


5x 2 7

2 2

5x 5

5x 5

5 5

x 1

1-13


5x 2 7

2 2

5x 5

5x 5

5 5

x 1

1-14


5x 2 7

2 2

5x 5

5x 5

5 5

x 1

1-15


5x 2 7

2 2

5x 5

5x 5

5 5

x 1

1-16


5x 2 7

2 2

5x 5

5x 5

5 5

x 1

0 1

1-17


5x 2 7

2 2

5x 5

5x 5

5 5

x 1

0 1

1-18


5x 2 7

2 2

5x 5

5x 5

5 5

x 1

0 1

1-19


** If you multiply or divideby a negative number, switch the direction of

the inequality.

1-20


3 x 4 6 x 3 3x 12 6x 18

6x 6x

3x 12 18

12 12

3x 6

3x3

63

x 2

1-21


3 x 4 6 x 3 3x 12 6x 18

6x 6x

3x 12 18

12 12

3x 6

3x3

63

x 2

1-22


3 x 4 6 x 3 3x 12 6x 18

6x 6x

3x 12 18

12 12

3x 6

3x3

63

x 2

1-23


3 x 4 6 x 3 3x 12 6x 18

6x 6x

3x 12 18

12 12

3x 6

3x3

63

x 2

1-24


3 x 4 6 x 3 3x 12 6x 18

6x 6x

3x 12 18

12 12

3x 6

3x3

63

x 2

1-25


3 x 4 6 x 3 3x 12 6x 18

6x 6x

3x 12 18

12 12

3x 6

3x3

63

x 2

1-26


3 x 4 6 x 3 3x 12 6x 18

6x 6x

3x 12 18

12 12

3x 6

3x3

63

x 2

1-27


3 x 4 6 x 3 3x 12 6x 18

6x 6x

3x 12 18

12 12

3x 6

3x3

63

x 2

1-28


x 2

-2 0

1-29


x 2

-2 0

1-30


x 2

-2 0

1-1 application of percents - portion formula portion (p) = base (b) x rate (r) portion “is”...

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