04 (algebraic formulae)
TRANSCRIPT
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TOPIC 7 : ALGEBRAIC FORMULAE
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1. Given that 5p = 4m + 3 , then m =
Diberi bahawa 5p = 4m + 3 , maka m =
2.If , thenx =
Jika , maka x =
3.
Given that 72
3
12=
q
q, then q =
Diberi bahawa 723
12=
q
q, maka q =
4.Given that then k =
Diberi bahawa maka k =
5. It is given that2
4 xy = . Find the value of y when 3=xDiberi bahawa 24 xy = . Cari nilai y apabila 3=x
6. Given that = + , express u in terms ofw and v
Diberi bahawa = + , ungkapkan u dalam sebutan w dan v
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PMR past year questions
2003
1). Given that 3h = 5k + 4, express k
in terms ofh.
[2 marks]
2004
2). Given that 5
k
3)2(p=
, express p in
terms of k.
[2 marks]
2005
3). Given 2py
3-4y=
+, express yin terms
ofp.
[2 marks]
2006
4). Given5
nk-3n=F , express n in terms of
F and k.
[2 marks]
2007
5). Given that r2+ 7 =p, express rin
terms ofp.
[2 marks]
2008
6). Given qr+ s =p, express rin terms of
p , q and s.
[2 marks]
2009
2010
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7.Given that5
3 yyk
=+
,express y in terms of k.
Diberi bahawa5
3 yyk
=+ ,
ungkapkan y dalam sebutan k.
8.Given that yk
=
3
72
,express k in
terms of y.
Diberi bahawa yk
=
3
72
,
ungkapkan k dalam sebutan y.
2011
9. Given 8= kmk ,express m interms of k.
Diberi 8= kmk ,
ungkapkan m dalam sebutan
k.
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ANSWERS
TOPIC 7 : ALGEBRAIC FORMULAE
1.
2.
3.
4.
5.
6.
7.
8.
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10.
11.
12.
13.
14.
15.
5
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PMR past year questions
2003
1). 5k = 3h - 4
k =3 4
5
h
1
1
2004
2). 2p - 6 = 5k
2p = 5k + 6
p =5 6
2
k+
1
1
1
2005
3). 4y - 3 = 2y + 2p
2y = 2p + 3
y =2 3
2
p +
1
1
1
2006
4). 5F = 3n - nk
n(3 - k) = 5F
n =5
3
F
k
1
1
1
2007
5). 2r = p - 7
r = 7p
1
1
2008
6). qr = p - s 1
6
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r =p s
q
1
ENRICHMENT
1 Writeyas the subject of the equationy
kx
5=
2 Writexas the subject of the equationtm
xk
26
=
3 Given that a = 5, b = 7, and c = 4, find the value oftin the equation
c
bat
)(2 =
4 Given thatvuf
111+= , find the value of f if u = 3 and v= 4.
5 Given that qxkypx =+27 , writexas the subject of the equation.
6 If 62 += kxxy , then find the value ofyif x= 5 and k = 5.
7 Given that 52 =++ mn , write m as the subject of the equation.
8 If )],5)(3[( += xxky then find the value ofywhen x= 2 and k= 3.
9 If f
yxf 5
2
+
= , writex as the subject of the equation.
10 The price of a ticket to the zoo for an adult is RMxand the ticket price forchildren is half of that. Write an equation for the total amount of moneypaid, T, for 3 adults and 5 children.
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PMR past year questions
2003
1). Given that 3h = 5k + 4, express k
in terms ofh.
[2 marks]
2004
2). Given that 5
k
3)2(p=
, express p in
terms of k.
[2 marks]
2005
3). Given 2py
3-4y=
+, express yin terms
ofp.
[2 marks]
2006
4). Given5
nk-3n=F , express n in terms of
F and k.
[2 marks]
2007
5). Given that r2+ 7 =p, express rin
terms ofp.
[2 marks]
2008
6). Given qr+ s =p, express rin terms of
p , q and s.
[2 marks]
3. ALGEBRAIC FORMULAE
8
TICKET 3(a)
(a) h = 2k 3[k]
(b)2
5+=k
p [k]
(c)r
p
r
q=
21 [r]
(d) 122
= aab
[a]
(e) qr
q=5 [q]
TICKET 3(b)
(a)k
mmk = 5
[m]
(b) a = 1b
b
[b]
(c)3
5 hh
n= [h]
(d) h k(4 + h) = k[h](e)p q(3 p) = q [p]
TICKET 3(c)
(a)p
mmp = 6
[m]
(b)p r(7 +p) = r [p](c) 5h k(5 h) = k
[h]
(d) kkxxk
=
3
6[x]
(e)( )
rk
rk=
+
1
1[k]
TICKET 3(d)
(a)r
ppr = 4 [p]
(b) mkkm
=
5
[m]
(c) xy
x35
6= [y]
(d) mkkm
=5
[k]
(e)u
w
uw =
7[w]
TICKET 3(e)
(a)x(2y + m) = 3y,
[y]
(b) my y= 7,
[y]
(c) x3 = 2y,[x]
(d)2
=
y
yx ,
[y]
TICKET 3(f)
(a)n
nm
2
3+= ,
[n]
(b) mn
m=3 ,
[m]
(c)5
3 ee
d= ,
[e]
(d) p12
+= , [q]
TICKET 3(g)
(a)r
ppq =2 , [p]
(b)( )
2
2
=
n
mnm , [n]
(c)m
p
m
kp =+ , [p]
(d)q
prpq = , [p]
(e)q
r
q
pr =2 , [r]
TICKET 3(h)
(a) 3p = 2m r[m]
(b) m n(4 3m) = n,[n]
(c) kpr
=12
[p]
(d)pr
rk
+
= , [r]
(e) fg
f25 = , [f]
(f) 2m n(3 + m) = n,
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TICKET 3(i)
(a)a
baw 23 = , [a]
(b)nm
m
2
5
5=
,
[m]
(c)n
nm
2
4+= ,
[n]
(d) myy
m3
3
5= ,
[m]
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TICKET 3(j)
(a) r2 + 7 =p[r]
(b) k= 9 2p2
[p]
(c) kh =13 [h]
(d) 35
=
+ nm
mn,
[n]
(e) 523
32=
pp
[p]
TICKET 3(k)
(a)2
3 pk
= , [p]
(b)
2
=
x
xyd , [x]
(c)3
2 nm
= , [e]
(d)2
31 rp
= [r]
TICKET 3(l)
(a)1+
=
v
vwu [v]
(b) 32=
h
r[r]
(c)2
=
q
pqs [q]
(d)( )
h
mhm
21
12
= [h]
TICKET 3(m)
(a)x= 3y2 + 6[y]
(b) ps
23+ = r2, [s]
(c) 13 = kap , [a]
(d) yxmxy 3=+ , [x]
(e) cd 153= , [c]
(f)d
dkj
3
42 += , [d]
(g) h k(4 + h) = k,[h]
TICKET 3(n)
(a) km = 3(2k + p),[k]
(b)3=
pm ,[p]
(c) 23
22 =
rk , [k]
(d)1+
=
v
vwu ,
[v]
(e)yx
x 2
1
1=
+
,
TICKET 3(0)
(a) 43
52 =
rk [k]
(b)12
2
=
pk
[p]
(c)( )
532=
k
p[p]
(d) 234=
+
py
y
[y]5 mnm
=
TICKET 3(p)
(a)w
wy
+
=
1[w]
(b) 31
2=
n
t
[n]
(c)K
mT
3
1=
[m]
(d)k
kk
3
1
2
2
=
[k]
TICKET 3(q)
(a) mn
m25 = [n]
(b) ( )329
5= xy [x]
(c) 345
=
yx
xy[y]
(d) 51=+
xy [x]
(e) r (2p + q) = 3p,[p]
TICKET 3(r)
(a) dee
d3=
[e]
(b) xyy
x =1
[x]
(c)nm
m 2
2=
[m]
(d) dee
d3
2
5= [d]
(e) 2m n(3 + m) = n
TICKET 3(s)
(a)1
32
+
=
pt [p]
(b)x
yyx
243 = [y]
(c) k
p
r=1
2[p]
(d)5
83
yxy =+ [x]
(e) xxyyx
+=
3
25[x]
TICKET 3(t)
(a)2
=
x
xyd [x]
(b) mnm
43
2= [x]
(c)( )
1
1
+
=
p
mpm
[m]
(d) dee
d3
2
5= [d]
(e)5
83
yxy =+ [y]
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