032616 week3 impulse_and_momentum
TRANSCRIPT
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Honors Physics
Impulse and Momentum
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Impulse = MomentumConsider Newton’s 2nd
Law and the definition of acceleration
Units of Impulse: Units of Momentum:
Momentum is defined as “Inertia in Motion”
NsKg x m/s
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Impulse – Momentum Theorem
vmFt IMPULSE CHANGE IN MOMENTUM
This theorem reveals some interesting relationships such as the INVERSE relationship between FORCE and TIME
tvmF
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Impulse – Momentum Relationships
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Impulse – Momentum Relationships
VmfT Constant
Since TIME is directly related to the VELOCITY when the force and mass are constant, the LONGER the cannonball is in the barrel the greater the velocity.
Also, you could say that the force acts over a larger displacement, thus there is more WORK. The work done on the cannonball turns into kinetic energy.
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How about a collision?Consider 2 objects speeding
toward each other. When they collide......
Due to Newton’s 3rd Law the FORCE they exert on each other are EQUAL and OPPOSITE.
The TIMES of impact are also equal.
Therefore, the IMPULSES of the 2 objects colliding are also EQUAL
21
21
2121
)()(JJFtFt
ttFF
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How about a collision?If the Impulses are equal
then the MOMENTUMS are also equal!
22221111
222111
2211
21
21
)()(
oo
oo
vmvmvmvmvvmvvm
vmvmppJJ
22112211 vmvmvmvm
pp
oo
afterbefore
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Momentum is conserved!The Law of Conservation of Momentum: “In the
absence of an external force (gravity, friction), the total momentum before the collision is equal to the total momentum after the collision.”
smkgpsmkgpsmkgp
smkgp
smkgp
smkgmvp
total
car
truck
totalo
caro
otrucko
/*3300/*18005.4*400/*15003*500
/*3300
/*800)2)(400(
/*2500)5)(500(
)(
)(
)(
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Types of Collisions A situation where the objects DO NOT STICK
is one type of collision
Notice that in EACH case, you have TWO objects BEFORE and AFTER the collision.
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A “no stick” type collision
pbefore = pafter
1
1
1
22112211
100010000)10)(3000())(1000(0)20)(1000(
vvvvmvmvmvm oo
-10 m/s
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Types of CollisionsAnother type of collision is one where the
objects “STICK” together. Notice you have TWO objects before the collision and ONE object after the collision.
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A “stick” type of collision
pbefore = pafter
T
T
T
TToo
vvv
vmvmvm
400020000)4000(0)20)(1000(
2211
5 m/s
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The “explosion” typeThis type is often referred to as “backwards inelastic”. Notice you have ONE object ( we treat this as a SYSTEM) before the explosion and TWO objects after the explosion.
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Backwards Inelastic - Explosions
Suppose we have a 4-kg rifle loaded with a 0.010 kg bullet. When the rifle is fired the bullet exits the barrel with a velocity of 300 m/s. How fast does the gun RECOIL backwards?
pbefore = pafter
2
2
2
2211
430))(4()300)(010.0()0)(010.4(
vv
vvmvmvm TT
-0.75 m/s
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Collision SummarySometimes objects stick together or blow apart.
In this case, momentum is ALWAYS conserved.
2211)(
022011
2211022011
vmvmvmvmvmvmvmvmvmvm
pp
totalototal
totaltotal
afterbefore
When 2 objects collide and DON’T stick
When 2 objects collide and stick together
When 1 object breaks into 2 objects
Elastic Collision = Kinetic Energy is ConservedInelastic Collision = Kinetic Energy is NOT Conserved
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Elastic Collision
JAfterKE
JAfterKE
JmvBeforeKE
car
truck
car
000,50)10)(1000(5.0)(
000,150)10)(3000(5.0)(
000,200)20)(1000(5.021)(
2
2
22
Since KINETIC ENERGY is conserved during the collision we call this an ELASTIC COLLISION.
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Inelastic Collision
JAfterKE
JmvBeforeKE
cartruck
car
000,50)5)(4000(5.0)(
000,200)20)(1000(5.021)(
2/
22
Since KINETIC ENERGY was NOT conserved during the collision we call this an INELASTIC COLLISION.
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Example Granny (m=80 kg) whizzes around the rink with a velocity of 6 m/s. She suddenly collides with Ambrose (m=40 kg) who is at rest directly in her path. Rather than knock him over, she picks him up and continues in motion without "braking." Determine the velocity of Granny and Ambrose.How many objects do I have before the collision?
How many objects do I have after the collision?
2
1
T
T
TToo
ab
vv
vmvmvm
pp
120)0)(40()6)(80(2211
4 m/s
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Collisions in 2 DimensionsThe figure to the left shows
a collision between two pucks on an air hockey table. Puck A has a mass of 0.025-kg and is moving along the x-axis with a velocity of +5.5 m/s. It makes a collision with puck B, which has a mass of 0.050-kg and is initially at rest. The collision is NOT head on. After the collision, the two pucks fly apart with angles shown in the drawing. Calculate the speeds of the pucks after the collision.
vA
vB
vAcos
vAsin
vBcosvBsin
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Collisions in 2 dimensions
vA
vB
vAcos
vAsin
vBcosvBsin
)37cos)(050(.)65cos)(025(.0)5.5)(025.0( BA
xBBxAAoxBBoxAA
xox
vvvmvmvmvm
pp
BA vv 040.00106.01375.0
AB
AB
BA
yBByAA
yoy
vvvv
vv
vmvm
pp
757.00227.00300.0
)37sin)(050.0()65sin)(025.0(0
0
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Collisions in 2 dimensions
AB vv 757.0
smvv
vvvv
A
A
AA
AA
/84.204845.01375.0
03785.00106.01375.0)757.0)(050.0(0106.01375.0
BA vv 040.00106.01375.0
smvB /15.2)84.2(757.0