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    Semiconducting materials The basics of solid state physics PN-junctions and diodes Calculations with diodes

    Electronics The basics of semiconductor physics

    Prof. Marta Rencz, Gergely Nagy

    BME DED

    September 4, 2012

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    Semiconducting materials The basics of solid state physics PN-junctions and diodes Calculations with diodes

    The basic properties of semiconductors

    Semiconductors conductance is between that of conductorsand insulators.

    They conduct current and have a negative thermalcoefficient (NTC), which means thattheir conductivitydecreases when temperature rises.

    This is exactly the opposite behaviour of metals.

    At the moment semiconductors are the basic materials ofelectronic devices.

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    Semiconducting materials The basics of solid state physics PN-junctions and diodes Calculations with diodes

    The most important semiconductors

    The most important semiconductors:Monocristalline or single-cristal materials:

    Semiconductor elements: Si (silicon), Ge (germanium)They are used in integrated circuits and semiconducting devices.Compound semiconductors: GaAs (gallium arsenide), GaAsP(gallium arsenide phosphide)They are used to create LEDs.

    Amorphous semiconductors: amorphous Si mainlyTFTs, solar cells are made of them.Organic semiconductors: OLEDs (Organic LEDs)

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    Semiconducting materials The basics of solid state physics PN-junctions and diodes Calculations with diodes

    The band structure I.

    The electrons energy is a quantized quantity there arecertain energy levels that are allowed for electrons, the rest ofthe levels are forbidden.

    When electrons take part in a system (atom or a crystalline

    consisting of many atoms), every electron has to be at adifferent level. The electrons take energy levels very close tothe allowed levels thus in large systems the electrons takeplace in energy bands that are seperated by band gaps.

    The energy bands of electrons in alarge insulator/semiconductorstructure.

    The bands are shown in grey, theband gaps are white.

    S i d i i l Th b i f lid h i PN j i d di d C l l i i h di d

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    Semiconducting materials The basics of solid state physics PN-junctions and diodes Calculations with diodes

    The band structure II.

    Conductance band:electrons that can movefreely.

    Valence band: electrons

    that take part in bonds andthus are bound to atoms.

    From the viewpoint of conductance the important bands:

    The highest band that contains electrons (valence band).

    The band above the valence band, which is almost empty(conductance band).

    The band gap between them.

    S i d ti t i l Th b i f lid t t h i PN j ti d di d C l l ti ith di d

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    Semiconducting materials The basics of solid state physics PN-junctions and diodes Calculations with diodes

    Insulators and conductors

    Conductors: the valence band and the conductance bandsoverlap.

    Insulators and semiconductors: there are bandgaps thewidth of the bandgap (Wg) decides whether a material is aninsulator or a semiconductor.

    Si (semiconductor): Wg = 1.12 eV

    SiO2 (insulator): Wg = 4.3 eV

    1 eV = 0.16 aJ = 0.161018 J

    Semiconducting materials The basics of solid state physics PN junctions and diodes Calculations with diodes

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    Semiconducting materials The basics of solid state physics PN-junctions and diodes Calculations with diodes

    The charge carriers I.

    Electrons: at the bottom of theconductance band,

    Holes: at the top of the valence band ahole is an absence of electron.

    Both electrons and holes take part inconductance!

    Generation: happens when an electron gets to the

    conductance band from the valence band.This means that two charge carriers are created: an electron in the conductance

    band and a hole in the valence band.

    Recombination: the opposite of generation when an

    electron falls back to the valence band.

    Semiconducting materials The basics of solid state physics PN junctions and diodes Calculations with diodes

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    Semiconducting materials The basics of solid state physics PN-junctions and diodes Calculations with diodes

    The charge carriers II.

    Charge and mass of charge carriers

    Electrons: have a negative charge and a positive mass.

    Holes: have a positive charge and a positive mass (!).This can be explained in solid state physics were not going into such depth.

    Semiconducting materials The basics of solid state physics PN-junctions and diodes Calculations with diodes

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    Semiconducting materials The basics of solid state physics PN-junctions and diodes Calculations with diodes

    The crystal structure of silicon

    3D crystal structure (diamond lattice) Simplified, 2D crystal structure

    Silicon has four electrons that take part in the bond betweenits atoms.

    Density: = 2.33 gcm3

    Lattice constant: a = 0.543 nm

    Semiconducting materials The basics of solid state physics PN-junctions and diodes Calculations with diodes

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    Semiconducting materials The basics of solid state physics PN junctions and diodes Calculations with diodes

    The intrinsic silicon

    If the temperature is above 0 K, someelectrons become thermally activatedand get into the conductance band.

    Intrinsic charge carrier concentration

    ni=pi= 1010

    /cm3

    ni: electron concentration (1/cm3)

    pi: hole concentration (1/cm3)

    The charge carrier density is very low: a cube with edgesof 10 m contains 10 electrons.

    The crystalline is doped in order to increase the chargecarrier density.

    Semiconducting materials The basics of solid state physics PN-junctions and diodes Calculations with diodes

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    g p y j

    Doping

    A small number ofatoms of a different kind is injectedinto the crystal structure.

    This is done in a way that the dopants are placed on positionswhere normally Si atoms are located.

    Typical doping density: 1015 1019/ cm3 this is indeeddoping and not alloying (the density is very low).The atom density of silicon is 51022/cm3, so a typical doping of1017/cm3

    means that two atom is changed to a dopant out of every one million, which

    leaves us with a purity of 99.9998 %.

    Semiconducting materials The basics of solid state physics PN-junctions and diodes Calculations with diodes

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    g p y j

    The n-type semiconductors

    Donor dopants: dopants that inject atoms that have one extra

    electrons at their valence band (P (phosporus), As (arsenic), Sb(antimony)).The extra electron is easier to raise into the conductance band, because it cannot take

    part in a strong bond. Thus its energy level is in the band gap, close to the

    conductance band.

    Electronsare the majoritycharge carriersHolesare the minority charge

    carriers

    donor concentration: Ndelectron concentration: nn

    hole concentration: pn

    Concentrations in n-type Si

    nn Nn

    nn > pn

    Semiconducting materials The basics of solid state physics PN-junctions and diodes Calculations with diodes

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    g y j

    The p-type semiconductors

    Acceptor dopants: dopants that inject atoms that have one lesselectrons at their valence band (B (boron), Al (aluminium), In(indium)).Less electrons result in extra holes, that are easier to bring down to the valence band,

    because they cannot take part in a strong bond. Thus their energy level is in the

    band gap, close to the valence band.

    Electronsare the minoritycharge carriersHolesare the majority charge

    carriers

    acceptor concentration: Naelectron concentration: nphole concentration: pp

    Concentrations in p-type Si

    pp Nppp

    > np

    Semiconducting materials The basics of solid state physics PN-junctions and diodes Calculations with diodes

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    Drift current I.

    When a semiconductor is placed into an electric field, theelectrons start to drift in the opposite direction of the field.

    No external field External field is present

    Semiconducting materials The basics of solid state physics PN-junctions and diodes Calculations with diodes

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    Drift current II.

    Drift current is the movement of charge carriers due to anexternal electric field.

    Drift velocity is the speed of the charge carriers in the driftcurrent:

    Drift velocity

    vd = n Evd =p E

    wherevd: is the drift velocityn: is the mobility of electrons (Si: n= 1500

    cm2

    V s)

    p: is the mobility of holes (Si: p = 475 cm2

    V s)

    Semiconducting materials The basics of solid state physics PN-junctions and diodes Calculations with diodes

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    Diffusion current

    Diffusion current: is the movement of charge carriers due to aninhomogeneity in their density.The movement is due to thermally induced movement of the electrons that is always

    present at temperatures above 0 K.

    Semiconducting materials The basics of solid state physics PN-junctions and diodes Calculations with diodes

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    The pn-junction: a semiconductor diode I.

    A pn-junction is a monocrystalline transitional area where ap-type and an n-type semiconductor is next to each other.

    The diode is a device that consists of one single pn-junction.

    The figure is distorted: the n-type layer is muchshallowerin reality.

    Semiconducting materials The basics of solid state physics PN-junctions and diodes Calculations with diodes

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    The pn-junction: a semiconductor diode II.

    We will be concerned withthe area at the center of thestructure(physical distortions at the borders result in specialeffects that were not dealing with).

    Semiconducting materials The basics of solid state physics PN-junctions and diodes Calculations with diodes

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    Most important properties of the diode

    When a forward voltage is applied to it, its current is an

    exponential function of the voltage.I exp

    VVT

    Forward direction: the p side is at a higher potential.In the reverse direction its current is very low and is

    independent of the voltage:I 1012 A/mm2

    The current-voltage characteristic of the diode:

    Semiconducting materials The basics of solid state physics PN-junctions and diodes Calculations with diodes

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    The electrostatic conditions in the pn-junction

    The majority carriers at theproximity of the junction diffuseacross the junction to the otherside.This is because there are a lot of electrons on

    the n side, and a lot of holes on the p, whileeach side has a very low density of the

    minority charge carriers. There is a huge

    gradient in the densisty of charge carriers.

    This results in a depleted area / space charge region an

    area at the junction which is empty of majority charge carriers.

    The dopants left by their extra electrons/holes becomecharged ions that create an electric field, which preventsfurther diffusion by generating a drift current of minority

    carriers in the opposite direction.

    Semiconducting materials The basics of solid state physics PN-junctions and diodes Calculations with diodes

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    The operation of the diode

    Equilibrium: the diffusion of the majority carriers is inequilibrium with the drift current of the minority carriers(I= 0).

    Forward direction: the forward voltage lowers the electricfield of the dopant ions thus increasing the drift current of the

    majority carriers (big IF).Reverse direction: the reverse voltage enlarges the electricfield of the dopant ions thus lowering the diffusion current ofthe majority carriers and increasing that of the minoritycarriers moved by the drift current (small IR).

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    Semiconducting materials The basics of solid state physics PN-junctions and diodes Calculations with diodes

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    The characteristic equation of a real diode

    Due to secondary effects the equation in the forwarddirection:

    I=I0

    e

    V

    mVT 1

    where m is the ideality factor (a.k.a. quality factor or

    emission coefficient) it represents several secondary effectsand ranges from 1 to 2.

    In the reverse direction: thereverse current of the diode startsto increase steeply with the voltageat the breakdown voltage (VBR).

    If the the diodes current is limitedby external means, the breakdown

    state does not harm the structure.

    Semiconducting materials The basics of solid state physics PN-junctions and diodes Calculations with diodes

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    The application of the breakdown voltage

    As a very small change in the reverse voltage results in a bigchange in the reverse current at the breakdown state, it canbe used to stabilize voltage.

    The diode is placed in a negative feedback configuration.

    Zener diode: special diode created to serve as a voltagestabiliser in the breakdown state.

    Semiconducting materials The basics of solid state physics PN-junctions and diodes Calculations with diodes

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    The operating point of a diode I.

    The characteristic equation of a diode gives all thevoltage-current pairs that a diode can have.

    In operation the diode usually works at a certain operating

    point, i.e. at one of the voltage-current pairs of its equation.This point isdetermined by the elements surrounding thedevice.

    DC analysis: the calculations performed to find the DCoperating point of a non-linear device.

    The quantities describing the DC operating point are usuallydenoted with capital letters (V, I).

    Semiconducting materials The basics of solid state physics PN-junctions and diodes Calculations with diodes

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    The operating point of a diode II.

    The KVL for the circuit is:

    Vt=I Rt+ V

    which gives the equation of a line:

    I=Vt V

    Rt

    The line is called the load line it is the characteristicequation of the other element in the circuit (Rt) as a function

    of the diodes voltage.

    Semiconducting materials The basics of solid state physics PN-junctions and diodes Calculations with diodes

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    The operating point of a diode III.

    The operating point (denoted with M in the figure) is atthe intersecion of the two functions.

    If the graphical representation of the equations is given, this iseasy to find.

    Semiconducting materials The basics of solid state physics PN-junctions and diodes Calculations with diodes

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    The approximation of the operating point I.

    We take advantage of the fact that the exponential function isvery steep.

    The diode is substituted:with a voltage source when it is switched on,with an open circuit when it is switched off.

    The value of the voltage source (VD) can be looked up inthe datasheet of the diode (VD 0.7 V).

    Semiconducting materials The basics of solid state physics PN-junctions and diodes Calculations with diodes

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    The approximation of the operating point II.

    Weassume that the diode is switched

    on.The terminals of the resistor:

    left-hand side: supply voltage (Vs),right-hand side: the voltage of the diode(VD).

    According to Ohms law:

    I=Vs VD

    Rl

    IfVs= 5 V, VD = 0.7 V, Rl = 1 k then

    I=5 0.7

    103

    = 4.3 mA.

    Semiconducting materials The basics of solid state physics PN-junctions and diodes Calculations with diodes

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    Small-signal analysis I.

    It is important to investigate what happens when there are

    small changes in the input voltage e.g. when the supplyvoltage changes slightly during operation.

    For small changes the exponential function can beapproximated with a linear equation around the operating

    point.In terms of the electric model, this means that the diode issubstituted with its differential resistance.

    The differential resistance

    rd=V

    I =

    m VTI

    Semiconducting materials The basics of solid state physics PN-junctions and diodes Calculations with diodes

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    Small-signal analysis II.

    The differential resistance

    rd=

    V

    I =

    m VT

    I

    Iin the equation of the differential resistance is theoperating point current.

    Thus the value of the differential resistance has a very strongdependence on the operating point.

    Semiconducting materials The basics of solid state physics PN-junctions and diodes Calculations with diodes

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    The small-signal operation of diodes I.

    Lets investigate what happens when small changes occur atthe equilibrium state.

    Changes around the operating are usually denoted with lowercase letters.

    Vs=Vs0+ vs sin(t)

    If the changes are small, the diodes voltage and current aresinusoidal functions around the operating point.

    Semiconducting materials The basics of solid state physics PN-junctions and diodes Calculations with diodes

    Th ll l f d d II

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    The small-signal operation of diodes II.

    The calculation is performed in three steps:1 the DC operating point is determined,2 the AC analysis is performed by substituting the non-linear

    device with its small-signal model and calculating the effects ofthe changes on this model,

    3 the two results are added.

    DC analysis equilibrium AC analysis small changes

    It is important that only small changes can be calculated thisway!

    Semiconducting materials The basics of solid state physics PN-junctions and diodes Calculations with diodes

    Th ll i l i f di d III

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    The small-signal operation of diodes III.

    Thecalculation of the small signal operation:

    The small-signal changes:

    i= vs

    Rl+ rd

    andu= rd i= rd

    Rl+ rdvt

    IfRl = 1 k, Vt = 5 V and vt= 1 V:The differential resistance:

    rd=VT

    I =

    26mV

    4.3 mA= 6

    The change (amplitude) of the diodes current:

    i= 1

    1.006k 1mA

    the change (amplitude) of the diodes voltage:

    = = Semiconducting materials The basics of solid state physics PN-junctions and diodes Calculations with diodes

    Th Z di d I

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    The Zener diodes I.

    Supply voltages can be stabilized usingZener diodes.

    Consider the circuit on the left.

    Lets find the voltage and current of the Zener diode.Vin= 12 V, R= 150 and VBR = 3.3 V.

    As the input voltage is larger than the breakdown voltage:the diode is in the breakdown state.

    IVin VBR

    R =

    12 3.3

    0.15 = 60 mA

    Semiconducting materials The basics of solid state physics PN-junctions and diodes Calculations with diodes

    Th Z di d II

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    The Zener diodes II.

    How much does the output voltage change if the inputchanges by 1 V?

    The differential resistance is: 3 .

    vout=vin

    rd

    rd+ Rt =

    3

    153= 20 mV

    Thus the change at the input is reduced to 1/50 of its value!