-pressure system- root locus cory richardson dennis to jamison linden 6/14/2015, utc, engr-329
Post on 20-Dec-2015
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Contents
Background Description, SSOC, Input/Output
Transfer Function Step Response/Frequency Response Root Locus Modeling Results Conclusions
Background - SSOC
Steady State Operating Curve
0
2
4
6
8
10
12
0 10 20 30 40 50 60 70 80 90 100
m, Input Blower Pressure (%)
c, Output Pressure (cm-H20)
Operating Range for Output
Operating Range for Input
Background – Step Response
Experimental vs. Model, Step Response
0
0.5
1
1.5
2
2.5
13 14 15 16 17 18 19 20 21 22 23Time (s)
Ou
tpu
t (cm
-H2O
)
0
20
40
60
80
100
Inp
ut (
%)
Output(cm-H20)
Output
Input
Background – Step Response Results
Experiment Model
Gain0.1-0.35 cm-
H2O/%0.1-0.35 cm-
H2O/%
Dead Time 0.5 s 0.48 s
Time Constant 1.7 s 1.75 s
Frequency Response - Example
f=0.04, Frequency Response
40
45
50
55
60
65
0 10 20 30 40
Time, s
Inp
ut,
%
0
0.5
1
1.5
2
2.5
Ou
tpu
t, cm
-H2O
Input Value(%)
Output(cm-H20)
c (1.45)
T (25.3)
m (15)
t (-1.8)
Frequency Response – Bode Plots
Bode Plot 75-90% input
-270.00
-180.00
-90.00
0.00
0.01 0.10 1.00
Frquency (Hz)
Pha
se A
ngle
(deg
rees
)
fu=0.85 Hz
)(tan180 10 t
Bode Plot 75-90% input
0.010
0.100
1.000
0.01 0.10 1.00
Frquency (Hz)
Am
plit
ud
e R
ati
o
Frequency Response – Bode Plots
K= 0.35 cm-H2O/%
2nd Order
2
K
f
2
3
fu=0.85
AR=.024
fuARKcu
1
Modeling Approach – Bode PlotsBode Plot, 75 - 90% input
0.010
0.100
1.000
0.01 0.10 1.00
Frquency (Hz)
Am
plit
ud
e R
atio
AR
Model AR
Modeling Approach – Bode PlotsBode Plot, 75 - 90% input
-270.00
-180.00
-90.00
0.00
0.01 0.10 1.00
Frquency (Hz)
Ph
ase
An
gle
(deg
rees
)
PA
Model PA
Results Comparison
Experimental Results: K = 0.1 – 0.35(cm-H20/%)
t0 = 0.6 s = 1.7 s 2nd Order system Ultimate Frequency = 0.85 Hz Ultimate Controller
Gain = 42 – 204 (%/cm-H2O)
Experimental - Ultimate Frequency, fu
0
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
Hz
Lower (40-60%)
Middle(60-75%)
Upper(75-90%)
Experimental - Gain, K
0
0.05
0.1
0.15
0.2
0.25
0.3
0.35
0.4
(cm
-H2O
/%)
Lower (40-60%)
Middle(60-75%)
Upper(75-90%)
Experimental - Dead time, t0
0
0.1
0.2
0.3
0.4
0.5
0.6
0.7
seco
nds
Lower (40-60%)
Middle(60-75%)
Upper(75-90%)
Experimental - Time constant,
0
0.2
0.4
0.6
0.8
1
1.2
1.4
1.6
1.8
seco
nds
Lower (40-60%)
Middle(60-75%)
Upper(75-90%)
System
2nd order system fu = 0.85 Hz From the model:
K = 0.1 – 0.35 (cm-H2O/%)
t0 = 0.85 s = 1.7 s
Kcu = 18.2 – 55.6 (%/cm-H2O)
LocationsROOT LOCUS PLOT
-4
-3
-2
-1
0
1
2
3
4
-2.5 -2 -1.5 -1 -0.5 0 0.5
REAL AXIS
IMA
GIN
AR
Y A
XIS
ξ=1DR=0
ξ=.707DR=1/500
ξ=.344DR=1/10
ξ=.215DR=1/4
ξ=0DR=1
Kc Locations 45-60%ROOT LOCUS PLOT 45-60%
-4
-3
-2
-1
0
1
2
3
4
-3 -2.5 -2 -1.5 -1 -0.5 0 0.5 1
REAL AXIS
IMA
GIN
AR
Y A
XIS
Kc = 11.4DR=1/500
Kc = 36.3DR=1/4
Kc = 27.3DR=1/10
Kc = 4.4DR=0
Kcu = 55.4DR=1
Kc Locations 60-75%
ROOT LOCUS PLOT
-4.00
-3.00
-2.00
-1.00
0.00
1.00
2.00
3.00
4.00
-3.00 -2.50 -2.00 -1.50 -1.00 -0.50 0.00 0.50
REAL AXIS
IMA
GIN
AR
Y A
XIS
Kc=2.2DR=0
Kcu=28DR=1
Kc=18DR=1/4
Kc=16DR=1/10
Kc=5.9DR=1/500
Kc Locations 75-90%
ROOT LOCUS PLOT 75-90%
-4
-3
-2
-1
0
1
2
3
4
-2.5 -2 -1.5 -1 -0.5 0 0.5
REAL AXIS
IMA
GIN
AR
Y A
XIS
Kc=1DR=0
Kc=2.8DR=1/500
Kc=7.9DR=1/10
Kc=8.6DR=1/4
Kc=14DR=1
Root Locus Results (45-60%)
Ultimate Kcu=55 1/500th Decay Kc =11 1/10th Decay Kc =27 Quarter Decay Kc=36 Critically Damping Kc = 4.4 Underdamped 4.4< Kc < 55 Overdamped 0 < Kc < 4.4
*all units are %/cm H2O
Root Locus Results (60-75%)
Ultimate Kcu=28 1/500th Decay Kc =5.9 1/10th Decay Kc =16 Quarter Decay Kc=18 Critically Damping Kc = 2.2 Underdamped 2.2< Kc < 28 Overdamped 0 < Kc < 2.2
*all units are %/cm H2O
Root Locus Results (75-90%)
Ultimate Kcu=14 1/500th Decay Kc =2.8 1/10th Decay Kc =7.9 Quarter Decay Kc=8.6 Critically Damping Kc = 1.0 Underdamped 1.0< Kc < 14 Overdamped 0 < Kc < 1.0
*all units are %/cm H2O
Conclusions
For 45-60% Kc needed
Overdamped 0 < Kc < 4.4
Critically Damped Kc = 4.4
Underdamped 4.4< Kc < 55
Quarter Decay Kc = 36
*all units are % / cm H2O
Conclusions
For 60-75% Kc needed
Overdamped 0 < Kc < 2.2
Critically Damped Kc = 2.2
Underdamped 2.2< Kc < 28
Quarter Decay Kc = 18
*all units are % / cm H2O
Conclusions
For 75-90% Kc needed
Overdamped 0 < Kc < 1.0
Critically Damped Kc = 1.0
Underdamped 1.0< Kc < 14
Quarter Decay Kc = 8.6
*all units are % / cm H2O