생체계측 ii report #2 2005200427 송성진
DESCRIPTION
생체계측 II Report #2 2005200427 송성진. Phase–sensitive Demodulation. : 10Hz sinusoid (T x = 0.1s). : 50Hz sinusoid (T c = 0.02s). x(t)c(t). x(t). x 0. t. t. -x 0. 0.05s. 0.1s. 0.05s. 0.1s. Matlab 1. When Xo = 2, x(t) is figured by using matlab. c(t) is figured by - PowerPoint PPT PresentationTRANSCRIPT
![Page 1: 생체계측 II Report #2 2005200427 송성진](https://reader036.vdocuments.mx/reader036/viewer/2022062410/568158d6550346895dc61df6/html5/thumbnails/1.jpg)
Medical Instrumentation II
![Page 2: 생체계측 II Report #2 2005200427 송성진](https://reader036.vdocuments.mx/reader036/viewer/2022062410/568158d6550346895dc61df6/html5/thumbnails/2.jpg)
Phase–sensitive Demodulation
Medical Instrumentation II
)102sin()( 0 txtx
)502sin()( ttc
: 10Hz sinusoid (Tx = 0.1s)
: 50Hz sinusoid (Tc = 0.02s)
0.05s
0.1s
t
x(t)x0
-x0
t
x(t)c(t)
0.05s
0.1s
![Page 3: 생체계측 II Report #2 2005200427 송성진](https://reader036.vdocuments.mx/reader036/viewer/2022062410/568158d6550346895dc61df6/html5/thumbnails/3.jpg)
Matlab 1.
Medical Instrumentation II
When Xo = 2, x(t) is figured byusing matlab
![Page 4: 생체계측 II Report #2 2005200427 송성진](https://reader036.vdocuments.mx/reader036/viewer/2022062410/568158d6550346895dc61df6/html5/thumbnails/4.jpg)
Medical Instrumentation II
c(t) is figured by
using matlab
![Page 5: 생체계측 II Report #2 2005200427 송성진](https://reader036.vdocuments.mx/reader036/viewer/2022062410/568158d6550346895dc61df6/html5/thumbnails/5.jpg)
Medical Instrumentation II
x(t)c(t) is figured by
using matlab
![Page 6: 생체계측 II Report #2 2005200427 송성진](https://reader036.vdocuments.mx/reader036/viewer/2022062410/568158d6550346895dc61df6/html5/thumbnails/6.jpg)
Medical Instrumentation II
When c(t) is changed, figured
by Matlab
![Page 7: 생체계측 II Report #2 2005200427 송성진](https://reader036.vdocuments.mx/reader036/viewer/2022062410/568158d6550346895dc61df6/html5/thumbnails/7.jpg)
Medical Instrumentation II
When c(t)’s frequency is
1000, x(t)c(t) is figured by
using matlab
![Page 8: 생체계측 II Report #2 2005200427 송성진](https://reader036.vdocuments.mx/reader036/viewer/2022062410/568158d6550346895dc61df6/html5/thumbnails/8.jpg)
)]22cos(1[2
1)( tftx c
Medical Instrumentation II
Gi ven x(t)c(t) = y(t) , find x(t) = ?
X LPF ?y(t)
c(t) = sin(2πx50t)
x(t)c(t)²
O(t)
)2(sin)()()( 22 tftxtctx c
)22cos()(2
1)(
2
1)()( 2 tftxtxtctx c
Because 2fc is High frequency, cut off by LPF
)(2
1)( txtO
![Page 9: 생체계측 II Report #2 2005200427 송성진](https://reader036.vdocuments.mx/reader036/viewer/2022062410/568158d6550346895dc61df6/html5/thumbnails/9.jpg)
Problem 9.
A conductor board is setting chest at 1mm, this is one of capacitor. Distance to chest and conductor board is changed by heart rate, A change is x(t) = 1 + 0.2sin(2πft) [mm]. At this time f is heart rate frequency. You measure x(t) that is chest’s motion by heart rate. A is 5cm² and dielectricconstant ε₀ is 8.8 x 10⁻¹² F/m, heart rate is 60bpm.
(a) represent Cx by x function. Desire for max and
min capacitance. (b) Vi(t) = sin(2π x 10⁴t) V, C₀ is 4.4pF, V ₀(t) = ? (c) Propose Phase-sensitive demodulator that
desire x(t) by amplifier output V ₀(t)
Medical Instrumentation II
![Page 10: 생체계측 II Report #2 2005200427 송성진](https://reader036.vdocuments.mx/reader036/viewer/2022062410/568158d6550346895dc61df6/html5/thumbnails/10.jpg)
Capacitive Sensor
Medical Instrumentation II
Chest
x(t)
Non contact measure ]/[108.8,5 120
2 mfcmA
])[2sin(2.01)( mmfttx
bpmHR 60 Hzf 1
x
ACx 0 ][
)()( 0 f
tx
AtCx
O PAMP
+
-
O U T
Vo
Cx
Co
Vi
AB
BA ])[102sin()( 4 vtVi
][4.40 pFC o
x
i
o
Cj
Cj
1
1
)()( tVC
CtV i
x
oo )()()( tVtx
A
CtV i
o
oo
![Page 11: 생체계측 II Report #2 2005200427 송성진](https://reader036.vdocuments.mx/reader036/viewer/2022062410/568158d6550346895dc61df6/html5/thumbnails/11.jpg)
Matlab 2.
Medical Instrumentation II
X LPFVi(t)
Vo(t) )(2
1
0
0 txA
C
Constant is calculated and Vo(t) is figured
byusing matlab
![Page 12: 생체계측 II Report #2 2005200427 송성진](https://reader036.vdocuments.mx/reader036/viewer/2022062410/568158d6550346895dc61df6/html5/thumbnails/12.jpg)
Problem 10.
This is x₁ = x₀ + α(P1-P2), x₂ = x₀ - α(P1-P2), C₁ = εA/x₁, C₂ = εA/x₂, C₀ = εA/x₀. Ѵs = Vs <0 M Phase is 1KHz.
(a) Instrument Amplifier’s input voltage is Vi. Represent x₀, α, (P1-P2) and Ѵs. (b) Ѵs = 1[v], x₀ = 100[μm], α = 2[μm/mmHg]. Define Instrument Amplifier gain that output voltage phasor, V₀ sensitive magnitude is 0.1 [v/mmHg] (c) For desire (P1-P2) in V₀, using phase-sensitive demodulator, Represent circuit and explain
drive principal
Medical Instrumentation II
![Page 13: 생체계측 II Report #2 2005200427 송성진](https://reader036.vdocuments.mx/reader036/viewer/2022062410/568158d6550346895dc61df6/html5/thumbnails/13.jpg)
X1
Problem 10. Solution
Medical Instrumentation II
P1 P2 open
rigid
Diaphragm = very flexible
X2
A BC
Blow air
P1 > P2 P1 < P2
X1 increase / X2 decrease
)( 211 PPxX o
)( 212 PPxX o
00
22
11 ,,
c
AC
X
AC
X
AC
A C BC1
C2
When P1 = P2, C1 = C2
![Page 14: 생체계측 II Report #2 2005200427 송성진](https://reader036.vdocuments.mx/reader036/viewer/2022062410/568158d6550346895dc61df6/html5/thumbnails/14.jpg)
Medical Instrumentation II
O PAMP
+
-
O U T
A
C
B
C1
C2
C0
C0
os
i so GIA
0 ss ])[102sin()( 3 vtVstVs
CDi
sD 2
1ssC CC
C
CjCj
Cj
21
1
21
2
11
1
![Page 15: 생체계측 II Report #2 2005200427 송성진](https://reader036.vdocuments.mx/reader036/viewer/2022062410/568158d6550346895dc61df6/html5/thumbnails/15.jpg)
si CC
C
)2
1(
21
1
Medical Instrumentation II
s
PPxA
PPxA
PPxA
]
)()(
)(
2
1[
210210
210
sPPxPPx
PPx
])()(
)(
2
1[
210210
210
sx
PP
]
2
)(
2
1
2
1[
0
21
sPPx
)(2 21
0
])[102sin()(2
)( 321
0
vtPPx
VtV s
i
![Page 16: 생체계측 II Report #2 2005200427 송성진](https://reader036.vdocuments.mx/reader036/viewer/2022062410/568158d6550346895dc61df6/html5/thumbnails/16.jpg)
Medical Instrumentation II
]/[2],[100],[1 0 mmHgmmxvVs
])[102sin()(2
)( 321
0
vtPPx
VGtV s
o
Because High frequency, cut off by LPF
XLPFy(t)
sin(2πx10³t)
)(22
121
0
PPx
VG s