© boardworks ltd 20061 of 58 © boardworks ltd 2006 1 of 58 a2-level maths: statistics 2 for...

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© Boardworks Ltd 2006 1 of 58 © Boardworks Ltd 2006 1 of 58 A2-Level Maths: Statistics 2 for Edexcel S2.1 Binomial and Poisson distributions This icon indicates the slide contains activities created in Flash. These activities are not edit For more detailed instructions, see the Getting Started presentation.

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© Boardworks Ltd 20061 of 58 © Boardworks Ltd 20061 of 58

A2-Level Maths: Statistics 2for Edexcel

S2.1 Binomial and Poisson distributions

This icon indicates the slide contains activities created in Flash. These activities are not editable.

For more detailed instructions, see the Getting Started presentation.

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Binomial distributions

Binomial distributions

Mean and variance of a binomial

Use of binomial tables

The Poisson distribution

Poisson tables

Mean and variance

Approximating a binomial by a Poisson

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Many real-life situations can be modelled using statistical distributions. Examples of the types of problem that can be addressed using these distributions include:

Special distributions

In a board game, players needs a six before they can start. What is the probability that they haven’t started after 5 tries?

What proportion of the adult population have an IQ above 120?

The number of accidents on a stretch of motorway averages 1 every 2 days. How likely is it that there will be no accidents in a week?

12% of people are left-handed. What is the probability that a class of 30 people will have more than 6 left-handed people?

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Binomial distribution

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Introductory example:A spinner is divided into four equal sized sections marked 1, 2, 3, 4.

If the spinner is spun 6 times, how likely is it to land on 1 on four occasions?

The number of possible sequences is

Binomial distribution

!

! !6

4

6

4 2C

!. .

!..

!4 26

0 25 0 754 2

0 0330

One possible sequence would be 1 1 1 1 1′ 1′.

(i.e. the number of ways of arranging 6 items, where 4 are of one kind and 2 are of a different kind).

Each sequence has probability 0.254 × 0.752.

So the required probability is

Most calculators have an nCr

button

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A binomial distribution arises when the following conditions are met:

Binomial distribution

If the above conditions are satisfied and X is the random variable for the number of successes, then X has a binomial distribution. We write: X ~ B(n , p).

an experiment is repeated a fixed number (n) of times (i.e., there is a fixed number of trials);

the outcomes from the trials are independent of one another;

each trial has two possible outcomes (referred to as success and failure);

the probability of a success (p) is constant.

n and p are called parameters.

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Which of these situations might reasonably be modelled by a binomial distribution?

Binomial

Not binomial

Binomial

Binomial distribution

Joan takes a multiple choice examination consisting of 40 questions. X is the number of questions answered correctly if she chooses each answer completely at random.

A bag contains 6 blue and 8 green counters. James randomly picks 5 counters from the bag without replacement. X is the number of blue counters picked out.

A bag contains 6 blue and 8 green counters. Jan randomly picks 5 counters from the bag, replacing each counter before picking the next. X is the number of blue counters picked out.

Outcomes are not independent

1

2

3

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Which of these situations might reasonably be modelled by a binomial distribution?

Notbinomial

Not binomial

Binomial

Binomial distribution

Jon throws a dice repeatedly until he obtains a six. X is the number of throws he needs before a six arises.

Judy counts the number of silver cars that pass her along a busy stretch of road. X is the number of silver cars that pass in a minute.

Josh is a mid-wife. He delivers 10 babies. X is the number of babies that are girls.

1

2

3

The number of trials is not fixed

The number of trials is not fixed

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Binomial distribution

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If X ~ B(n , p), then

where q = 1 – p.

Binomial distribution

( ) , , ,...P for 0 1 2n x n xxX x C p q x n

( ) . . .12 1 111P 1 0 4 0 6 0 01741X C

( ) . . .12 3 93P 3 0 4 0 6 0 142X C

Number of possible

sequences

Probability of x

successes

Probability of n – x failures

( ) . . . .12 0 12 120P 0 0 4 0 6 0 6 0 00218X C

So P(X > 1) = 0.980 (3 s.f.)

a) (to 3 s.f.)

b) P(X > 1) = 1 – P(X = 0) – P(X = 1).

Example: X ~ B(12, 0.4).

Find a) P(X = 3)b) P(X > 1).

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Binomial distribution

( ) . . .10 4 64P 4 0 51 0 49 0 197X C a)

b)

( ) ( ) ( ) ( )

. . . .

.

.

. . .

10 8 2 10 9 108 9

P 8 P 8 P 9 P 10

0 51 0 49 0 51 0 49 0 51

0 04945 0 01144 0 0011

0 21

9

06

X X X X

C C

Example: The probability that a baby is born a boy is 0.51. A mid-wife delivers 10 babies. Find:

a) the probability that exactly 4 are male;

b) the probability that at least 8 are male.