التوزيع الكهربى
DESCRIPTION
التوزيع الكهربىTRANSCRIPT
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Electrical Distribution
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of 150m, the cable to be clipped to the wall and close protection provided. The
rating tables in the IEE Regulations indicate that a 35mm copper conductor PVC
SWA PVC cable would be suitable for the loading required, but the voltage drop
must be checked.
Volt drop = Y x current x length
= 1.1 x 100 x 150 millivolts
= 1.1 x 100 x 150 volts/1000
= 16.5 volts
where Y = value from tables in mV/A/m Unless a particular value of voltage
drop, acceptable to the user, is
specified, the IEE Regulations figure of 10.5 volts must be adhered to.
Thus: total volt drop = 10.5 volts
10.5 = Y x 100 x 150
Therefore Y = 10.5/100 x 150
= 0.7/1000 volts/ampere/meters
Reference to the voltage drop tables indicates that the cable size with a voltage
drop of 0.7/1000 V/A/m
(0.7mV/A/m) OR LESS is a 70mm copper conductor.
Therefore, in order to transmit a 3 phase current of 100A per phase over a route
length of 150m, with a total voltage drop equal to or less than the statutory
maximum 10.5 volts, the use would require a 70mm (cu.) multi core PVC.
Conversely
The user may have 150m of 35mm (Cu.) multi core PVC cable and require to
know what maximum current rating can be applied without exceeding the
allowable voltage drop. The method is exactly the same as above,
viz:total drop = 16.6
= YxAxM
= 1.1 x A x 150/1000
from the tables Y = 1.1mV/A/m
=1.1/1000V/A/m
therefore A = 10.5 x 1000/1.1.x 150
=64 amperes
From the foregoing, it is apparent that knowing any two values of Y, A or m,
the remaining, unknown value can
readily be calculated.
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