zmsmsaskl. q 9 : topic form 4 : knowledge(1m) : understanding(4m) : conceptualize(5m) : problem...
TRANSCRIPT
ZMSMSASKL
Q 9 : Topic Form 4: Knowledge (1m)
: Understanding (4m): Conceptualize (5m)
: Problem Solving (10m)
Q 10 : Topic Form 5: Knowledge (1m)
: Understanding (4m): Conceptualize (5m)
: Problem Solving (10m)
Section B :ESSAY (Choose One)
30 minutes
Q11 : Topic Form 4 : Knowledge (1m)
: Understanding (4m) : Application (Quantitative) (5m)
: Decision Making (10m)
Q12 : Topic Form 5 : Knowledge (1m)
: Understanding (4m) : Application (Quantitative) (5m)
: Decision Making (10m)
SECTION C: ESSAY( Choose One)
30 minutes
18/5/08 …12 Jamadilawal 1429Hhro,SmscMuzaffarSyah,Melaka HRO
The ability to reason by identifying and analysing common characteristics or variables involve, and synthesis the common characteristic or relation with variables to create a physics concept..
CONCEPTUALISATION ELEMENT
Construct: Conceptualize 1. Make and state the observation
- Observation skill & critical thinking
2. Make comparison - State the similarities and
differences 3. State the relationship
- from the similarities and differences or state the
principle/law involved.
1 ) State the identical characteristic shown in the diagrams below and relate the relationship between their focal lengths and the curvature of mirrors
SPM 2004
5 marks
Curved mirror J Curved mirror K
Diagram 1.1 Diagram 1.2
CONSTRUCT: Conceptualization Skill Paper 2 - Section B
(Question 9 / Question 10)
- mirror K is more curve / K is more concave
- Reflection rays is focused at a
point /F
- The light focus point in mirror K is closer then mirror J
- Focal length is distance between F and P
- Curvature increase focal length
decrease // / inversely propotional
5 marks
Suggested answer
Problem Solving - Quantitative Section C: Q11/12)
Write all the information again. Use symbols.
Choose the formula. Make substitution Final answer with correct unit
1.The specification of a frying pan is 240V 1000W. Calculate the time taken for the frying pan to heat up 1000 cm3 cooking oil from the temperature 30 oC to 120 oC.Assume that all the electrical energy was used to increase the temperature of the oil only and no heat loss to the surrounding.[Specific heat capacity of oil is 2000 J kg–1 oC–1,
Density of oil is 800 kg m-3] [5
marks]
Problem Solving - Quantitative (Paper 2 Section B: Q9/10)
Model Answer
Given: P = 1000W V = 240 VVolume = 1000 cm3 = 1000 x 10-6 m3
θ = 120 – 30 = 90 oC.c of oil = 2000 J kg–1 oC–1, Density of oil = 800 kg m-3
Mass,m = 800 x 1000 x10-6
= 8 x 10-1 kgt = ?Solution: Heat supplied by heater = heat received by the oil By using formula:
pt = mcθ 1000(t) = (8 x10-1) x 2000 x 90
t = 144 s
Problem Solving- Qualitative (Paper 2 Section B: Q9/10) 1. Diagram below shows a saloon car.
Ahmad want to modify the car to be a safety racing car. State the modifications to be done by Ahmad and give a suitable physics concept for every of the aspect below:(i) Safety (ii) Shape(iii) Power (iv) Stability (v) Mass
[10 marks]
Suggestion Rationale
1 The front shape is long // The steering of the car is elastic
2 To lengthen the time of impact // impulsive force is
reduce
Any 5 correct
3 ShapeAerodynamic // The frame of the car is hard and stiff
4To reduce the air resistance // stiff / hard to bend
5 PowerHigh engine power
6Produce high acceleration // Bigger force
7 StabilityWide tyre // Lower the car’s body // fix spoiler to the car
8Low center Of Gravity
9 MassLow density material but stiff and strong // no added material
10Maximum acceleration/speed
TOTAL 10
OR:
DECISION MAKING STEPS
1. Distinguish the characteristics given
2. Explain the properties of every chosen characteristics and give the reason.
3. Distinguish the most suitable material based on the characteristics stated.
4. Give reasons why the material chosen.
DON’T WRITE THE CRITERIA FOR ALL THE CHOICE GIVEN IN THE QUESTION
DON’T STATE VALUE
DON’T COMPARE BETWEEN THE CRITERIA
Section C : DECISION MAKING NOTE
DO WRITE EACH CRITERIA FOR THE CHOSEN SUBJECT
DO STATE THE CHARACTERISTIC AS HIGH / LOW /LARGE /SMALL
DO THE JUSTIFICATION BY REPEATING ALL THE CHARACTERICS OF THE CHOSEN SUBJECT.
Section C : DECISION MAKING NOTE
Decision Making Skill(P2-Section A: Q 8; Section C: Q 11/12)
For every metal properties in the table above, explain the suitability of the properties tobe used as a material to make a frying pan. Hence determine the most suitable metal to make the frying pan. Give the justification for your choice.
[10 marks]
Metal Spec. heat
capacity /J kg–1 oC–1
Melting point /
oC
Density/kg m-3
Rate ofRusting
P 450 1540 7873 High
R 880 660 2698 High
S 510 1620 7800 Do not Rust
T 398 961 10500 Medium
U 377 978 8400 Do not rust
Q 1) As a researcher you are assign to investigate the properties of the metal in the table to be used as the material to make a quality frying pan.
Properties Explanation
Low specific heat capacity
Easily to be hot
High melting point Can sustain high temperature
Low density lighter
Low rate or rusty
S is chosen
So that it do not rust
Because of low specific heat capacity, high melting point, low density and low rate of rusty.
OR:
Good Luck for your SPM 2010 & Thank You