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n tt nghip Thit kquy trnh cng nghchto chi tit tay bin D165

GVHD: GS.TS. Trn Vn ch SVTH: Hong Tun Anh - Nguyn Vn Chinhttp://www.ebook.edu.vn Nguyn Vn Thn Phm ThThy

1

Li ni u

Mn hc cng nghchto my ng vai tr quan trng trong chngtrnh o to ksv cn bkthut vthit kv chto cc loi my, ccthit bphc vcc ngnh cng nghip, nng nghip, giao thng vn ti ...

n mn hc cng nghchto my k6 l mt trong cc n ctm quan trng nht i vi mt sinh vin khoa ckh. n gip cho sinhvin hiu nhng kin thc hc khng nhng mn cng nghchto mym cc mn khc nh: my cng c, dng cct... n cn gip cho sinhvin c hiu dn v thit kv tnh ton mt qui trnh cng nghch tomt chi tit cth.

c sgip v hng dn tn tnh ca thy TRN VN CHtrong bmn cng nghchto my n nay n mn hc ca em honthnh. Tuy nhin vic thit k n khng trnh khi sai st em rt mongc schbo ca cc thy v schbo ca cc bn.

Em xin chn thnh cm n thy TRN VN CH gip emhon thnh cng vic c giao.


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Trng i Hc Bch Khoa H Ni Cng ha x hi chngha Vit NamVin CKh c lp_Tdo_Hnh phc

Bmn:Cng NghChTo My

NHIM VTHIT KN TT NGHIP

Hv tn sinh vin: Hong Tun AnhNguyn Vn ChinNguyn Vn ThnPhm Thi ThuLp:07GT02CT Kha:2007-2010 Chuyn ngnh:CTin KThut

I.u thit k:Thit k quy trnh cng ngh ch to chi tit TayBin D165

II.Cc sliu ban u:

Sn lng hng nm:6.000 chi tit

iu kin sn xut:Tchn

III.Ni dung cc phn thuyt minh v tnh ton:

1. Phn tch chc nng lm vic ca chi tit.2. Phn tch tnh cng nghtrong kt cu ca chi tit.3. Xc nh dng sn xut.4. Chn phng php chto phi5. Lp th tcc nguyn cng (v sg t,k hiu nh v,k

hiu kp cht,chn my,chn dao,k hiu chiu chuyn ng cadao v ca chi tit).

6. Tnh lng d cho mt b mt (mt trn ngoi,mt trn tronghoc mt phng) v tra lng dcho cc bmt cn li.

7. Tnh chct cho mt nguyn cng(tnh cho cc nguyn cngcn thit kg) v tra chct cho cc nguyn cng cn li.

8. Tnh thi gian gia cng cbn cho tt ccc nguyn cng.


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3

9. Tnh v thit kmt g (lp sg t,tnh lc kp,thit kcc c cu ca g,tnh sai s chun,sai s kp cht,sai smn,sai siu chnh,sai sch to cho php ca g,t yucu kthut ca g,lp bng k khai cc chi tit ca g).

10. Nghin cu chuyn cng nghgia cng trn my CNC

IV.Phn bn v:

1. Chi tit lng phi:1 bn (khgiy A1hoc A0).2. Snguyn cng:1 bn (khgiy A0).3. g:1 bn (khgiy A0 hoc A1).4. Sgia cng trn my CNC:1 bn (khA0).

H Ni: ngy thng nm 2010

Ngi nhn Cn bhng dn


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Trng i Hc Bch Khoa H Ni Cng ha x hi chngha Vit NamVin CKh c lp - Tdo - Hnh phc

Bmn Cng nghchto my

GIO VIN HNG DN NHN XTN TT NGHIP

Hv tn sinh vin: Hong Tun AnhNguyn Vn Chin

Nguyn vn ThnPhm ThThu

Lp : 07GT02CTti tt nghip:

Thit kquy trnh cng nghchto chi tit Tay Bin D165

NI DUNG NHN XT:

I.Khi lng n:

1.Phn thuyt minh:trang2.Phn bn v:.bn Ao

II.u im ca n:


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6

III.Nhc im ca n:

IV.Kt lun:

1. Ni dung ca n m bo khi lng v cht lng ca n ttnghip ngnh cng nghchto my.

2. ngh n c bo v trc hi ng chm thit k tt nghip

ngnh cng nghchto my vin ckh trng HBK H Ni.

H Ni,ngy thng nm 2010

nh gi Cn bnhn xt


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7

THUYT MINH:

Ni dung 1:Phn tch chc nng lm vic ca chi tit:

Da vo bn vchi tit ta thy tay bin D165 c kt cu v chc nng nhsau:

Tay bin D165 l mt chi tit bao gm c hai lcbn m ng tm cachng song song vi nhau.

Tay bin D165 c chc nng bin chuyn ng thng ca piston thnhchuyn ng quay ca trc khuu (ng ct trong Diesel D165)

Tay bin D165 ngoi hai lcbn cn c gia cng chnh xc, cn c ldu, rnh then, cc mt ct u ca lv nhng yu tkhc cn c gia

cng. Nhng iu kin kthut ca tay bin D165: Khi gia cng tay bin D165 cn t c nhng yu cu sau y: Tay bin ti ci thin cng t HRC 26-31 chnh lch so vi cng

khng qu 4 n vkim tra cng H. Tchc th i t trong mt ct dc ca thanh truyn phi hnh thnh th

kim loi dc theo ng trc thanh truyn, khng c hin tng t onxp qu nhit im trng,bt kh phn tng v cc cht phi kim loi cho

php thay i hng cc thkim loi nhng chct hnh thnh mt

ghp. Tchc kim loi ca thanh truyn c kim tra theo mt ct ngang cch

ng tm u nhthanh truyn 50-60mm.Kt cu ca n phi l nhng ht xcbich nh u n .Khng cho

php c Pherit dng tp cht ring bit ,chiu su ca lp ct thot cacbontheo bmt th ca bmt ct khng c ln hn 0,1mm vmt pha.

Gc thot khun dp l 70 bn knh ln sng ghi R3mm. Trn ton bbmt thanh truyn khng cho php c vt nt ,vt trai,vt

gp mp,vt kp,vt r,vt lm,r,n mn,bavia,rnh nhv cht bn.

Trn thanh truyn khng cho php cc khuyt tt sinh ra do cha in ykhun dp,khng cho php sa li khuyt tt bng hn. cn v ovan ca 70 khng qu 0.012mm

39 0.018mmBc sau khi p vo u nhc cn v ovan l 0,01mmcn v ovan ca cutxine sau khi p vo u to bin l0.024mm

o mt mt ca u to thanh truyn so vi ng trc ca cutxinekhng qu 0.1mm trn 100mm chiu di.


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8

khng song song ca ng trc 2 l70 v 39 cho php 0.03mmtrn 100 mm chiu di.

khng song song ca ng trc bc thanh truyn p vo u nhv cutxine vo u to ca thanh truyn khng qu 0.03mm trn 100mm chiudi.

ng trc lu nhthanh truyn v ng trc bc p vo u nhphinm trong cng mt mt phng vi ng trc ca lu to v cutxine pvo u to.Sai lch khng c ln hn 0.06mm trn 100mm chiu di.

khng ng tm ca l16H8 vi lren M12x1.25 cho php 0.07 mm. khng trng ca mt F vi ng tm l70 l 0.1mm. Hai l ren M12 phi sch ,khng bi xc,bavia,khng c vt xy xt.

khng vung gc vi ng trc hai lren M12 so vi mt phng F khngqu 0.15mm trn 100mm chiu di.

ng ni tm 2 l70 v 39 lch so vi ng i xng ca thanh tmtruyn l 0.5mm.

Vt mp lm cn cc cnh sc. Sai strng lng khng qu 15 gam,iu chnh trng lng vtr Q v S. Cho php bdu S nu trng lng thanh truyn .

+Vt liu dng chto tay bin D165 l thp 45 vi thnh phn hahc nhsau:C Si Mn S P Ni Cr

0,4 0,17/0,37 0,5/0,8 0,045 0,045 0,03 0,03

V tay bin D165 lm vic vi ti trng ln,tng bn nn dng vt liuthp 45 c nhit luyn.Dng phi chto nn chi tit tay bin D165 l dng phi dp.

Ni dung 2:phn tch tnh cng nghtrong kt cu chi tit.*Cng nh cc dng chi tit khc, i vi chi tit tay bin D165 tnh cngngh c ngha quan trng v c nh hng trc tip n sn xut v chnh xc gia cng.V vy khi thit ktay bin D165 nn ch n kt cuca n nhsau:- cng vng ca tay bin D165-Chiu di cc lcbn nn m bo kch thc v cc mt u ca chngnm trn 2 mt phng song song vi nhau.


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-Kt cu c mt phng song song vi nhau ta phi gia cng cng mt lc, vcc lcbn ta phi dng phng php khoan khot doa trn cng mt phng.-Hnh dng thun li cho chn chun th v chun tinh thng nht.* m bo nhng yu cu kthut chc nng lm vic ca tay bin D165th tay bin phi c kt cu hp l nhm nng cao tnh cng ngh, cho phpgim khi lng lao ng, tng h s s dng vt liu v hgi thnh sn

phm.-Theo bn vta nhn thy kt cu chi tit hp l tha mn y cc yu cuvtnh cng nghtrong kt cu ca chi tit dng cng ta khng phi sa likt cu ca chi tit na.-Chi tit c gc dp l 7ov n chto bng vt liu thp tng nng sut

cho sn xut ta chn phng php to phi theo phng php dp th tchkhun hth ta nhn thy cc u im sau:+Nng sut to phi cao.+ Gi thnh lm khun hrhn rt nhiu so vi lm khun kn.Mt khc,bmt ngoi ca chi tit gia cng chcn lm sch bavia.Cng vidng sn xut hng lot ta ch chn phng php to phi nh trn th githnh sn phm srhn nhiu so vi to phi bng khung kn.Trc khi gia cng chi tit ta cn phi lm sch bavia v kim tra xem xt chitit c bnt rkhng,sau mi gia cng chi tit.

Nhvy ng vi cc iu kin vkt cu th chi tit dng cng gia cng ltha mn khng cn sa li kt cu ca chi tit.


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Ni dung 3:Xc nh dng sn xut.

Trong chto my ngi ta phn bit ra lm ba loi nhsau: Dng sn xut n chic:l sn xut c slng hng nm rt t ,sn phm

khng n nh do chng loi nhiu,chu k ch to li khng c xcnh.Sdng cc thit b,dng c,cc g vn nng.

Dng sn xut hng lot:l dng sn xut c sn lng hnh nm khngqu t,sn phm c chto theo tng lot vi chu kxc nh.Sn phmtng i n nh.Sdng cc my vn nng v chuyn dng.

Dng sn xut hng khi:l dng sn xut coa sn lng rt ln,sn phmn nh trong thi gian di.Sdng g chuyn dng,dng cchuyn

dng v cc thit bo tng ha.Ty theo mi dng sn xut c nhng c im ring ,ph thuc vo nhngyu tkhc nhau nhphng php cng nghhon thnh chi tit.Mun xc nh c dng sn xut ta phi bit c sn lng hng nm cachi tit gia cng.Sn lng hng nm c xc nh theo cng thc:

N=N1.m.( 1++100

)

Trong :N : Schi tit c sn xut trong mt nm;

N1 : Ssn phm (smy) c sn xut trong mt nm;m : Schi tit trong mt sn phm; :schi tit c chto thm dtr(5%-7%) :sphphm(3%-6%)

N1=545chic/nm;m=1;=4%;=6%

=>N=545.1.(1+6+4100

)=6000 chic/nm

Ta c:N=6000 chic/nmV=0.2371(dm3)Trng lng ca tay bin sau khi lp rp Q=0,2371.7,852=1,861kg

Nhvy:N=6000 chic/nm,Q=1,861kgTheo bng 2-trang14(TKACNCTM)ta c dng sn xut l hng lot ln.


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Ni dung 5:Thit kquy trnh cng nghgia cng chi tit.

1/Xc nh ng li cng ngh:Trong dng sn xut hng lot ln ,quy trnh cng nghc xc nh theonguyn tc phn tn hoc tp trung nguyn cng.

Theo nguyn tc phn tn nguyn cng th th quy trnh cng nghcchia ra cc nguyn cng n gin c thi gian gia cng nhnhau(nhp)hoc bi s ca nhp.y mi my c thc hin mt nguyn cngnht nh v g c sdng l g chuyn dng.

Theo nguyn tc tp chung nguyn cng th quy trnh cng ngh c

thc hin trn 1 hoc vi my tng ,bn tng.Nhtrn ta c dng sn xut l hng lot ln do nn chn phng n mtvtr ,mt dao gia cng tun t,tuy nhin ta c thkt hp cc phng n giacng vtr,nhiu dao v gia cng song song.Slng v tun tcc bc cng nghphthuc vo dng phi v chnhxc gia cng.Khi tp chung cc nguyn cng ta phi xem xt kt cu cacng,kh nng g nhiu dao trn my v cng ca chi tit.Cc nguyncng cn chnh xc cao,nn tch ring v p dng phng php gia cngmt vtr,mt dao v gia cng tun t.Cn cc nguyn cng trn dy truyntng c xc nh theo nguyn tc gia cng song song hoc tun tsongsong.2/Chn phng php gia cng:i vi dng sn xut hng lot ln mun chuyn mn ha cao c thtnng sut cao trong iu kin sn xut Vit Nam th ng li cng nghthch hp nht cho chi tit tay bin D165 l phn tn nguyn cng.y tadng cc loi my vn nng ng thi kt hp vi cc loi g chuyn dngv cc my chuyn dng chto.

Gia cng hai mt u to,u to ca tay bin t kch thc 38b1 (-0,17-0,33)Mt u to ca tay bin l b mt lm vic cn chnh xc vi cp nhnbng(theo bang 5 sch TKACNCTM {1} ta c nhn bng Rz=6.3m).Tathy dung sai kch thc hai mt u l =0.16(mm) tng ng chnhxc cp 3a,cn bng cp 7.

Nhvy theo bng 4 {1} ta chn phng php gia cng ln cui l mi bntinh.


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Vy gia cng hai mt u to ca tay bin t kch thc 38b1 (-0,17

-0,33) (mm)cn qua cc bc:

Phay thMi thMi bn tinh(t cp chnh xc 3 v7) Gia cng hai mt u nhca cng t kch thc 340-0,25

Mt u nhca cng l bmt lm vic do cn t chnh xc vi cpnhn bng 4(theo bng 5 {1} ta c nhn bng Rz=40m).Ta thy dungsai kch thc hai mt u l =0.25(mm) tng ng chnh xc cp 3,nhn bng4.Nhvy theo bng 4{1} ta chn phng php gia cng ln cui l phay tinh.Vy gia cng hai mt u nhca cng t kch thc 340-0,25(mm) cn qua

cc bc :phay th

phay tinh.V vi nguyn cng gia cng mt u to ca tay bin gia cng cmt unhnn n nguyn cng gia cng hai mt u nh ta chcn phay tinh ilng d t c kch thc 340-0,25(mm) vi cp nhn bng 4(nhn bng Rz=40m)--gia cng c cc lca tay bin trc tin ta cn phi gia cng cc

mt ghp ca thn bin v np bin lu to ca tay bin.--Gia cng lu to ca tay bin 700,019(mm) vt liu thp 45, cng

HRC26-31 ,cp nhn bng 7 theo bng 5{1} ta c nhn bng

Rz6,3m.Dung sai kch thc l=0,019mm,tng ng vi chnh xc cp2,cn bng cp7.--Gia cng cc lu to ca tay bin 700,019(mm) cn qua cc bc:Tin lt 68,5+0,250(mm)Doa th lt 69,5+0,10(mm)

Doa tinh lt 700+0,019 (mm)

--Gia cng lu nh ca tay bin t 390+0,025(mm)tng ng vi

chnh xc cp 3,cn bng cp6.

Nhvy da theo bng 4{1} ta chn phng php gia cng ln cui l doath.Vy gia cng lu nhca tay bin t 390

+0,025(mm) cn qua cc bc:Khoan lt 370

+0,39(mm)Chut lt 380-0,05(mm)Doa lt 390

+0,025(mm)


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V u nhtay bin c p bc nn sau khi p bc vo ta doa lu nht kch thc 35+0,034+0,009(mm).

Ngoi ra ta cn phi gia cng lu nh5,vt cc mp v phay rnhnh v.--Ngoi nhng nguyn cng gia cng tay bin t chnh xc vmt kch

thc cn cn chnh xc v trng lng do phi kim tra trng lngca tay bin,nu ln hn trng lng cho php th ta cn phi ra cng bbttrng lng nhng chkhng cn thit.

3/Lp tin trnh cng ngh:Xc nh thtgia cng cc bmt chi tit cng ta da vo cc nguyn tcsau:

Nguyn cng sau(bc sau) phi gim c sai sv tng c bngca nguyn cng trc (bc trc ) li. Trc ht phi gia cng c nhng b mt dng lm chun cho ccnguyn cng sau.

Tip theo cn gia cng nhng bmt c lng gia cng ln nht ckhnng pht hin nhng bin dng ca chi tit.

Cc bmt cn li nn gia cng theo trnh t:bmt no cng chnh xc thcng ghia cng sau.

Cui cng l gia cng bmt c chnh xc cao nht v c ngha lnnht i vi tnh cht sdng ca chi tit.

Cc ltrn chi tit nn c gia cng sau cng(trnhng llm chun khigia cng).

Khng nn gia cng th v gia cng tinh bng dao nh thc trn cngmt my.

Nu chi tit cn phi nhit luyn nn chia quy trnh cng nghra hai giaion:trc v sau nhit luyn.

Cc nguyn cng kim tra phi c tin hnh sau khi dng nhng nguyncng c khnng gy nhiu phphm ,nhng nguyn cng phc tp v cuicng tng kim tra.


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15

Vi nhng nguyn tc trn ta thit lp nhng tin trnh cng ngh khi giacng tay bin D165.

1.

Nguyn cng 01:Phay hai mt phng thn bin dng my phay6H12,dao phay mt u 120 t bng4 v cp chnh xc 3.2. Nguyn cng 02:Phay hai mt phng np bin dng my phay

6H12,dao phay mt u 120 t bng4 v cp chnh xc 3.3. Nguyn cng 3: Mi phng hai mt thn bin dng my mi

phng 3B732, mi 5C 50M28 CT1 6K5 320x100x100 t bngRz10,cp bng6 cp chnh xc 3a.

4. Nguyn cng 04:Mi phng 2 mt np bin dng my mi phng3B732, mi 5C 50M28 CT1 6K5 320x100x100 t bng R

z10,cp

bng6 cp chnh xc 3a.5.

Nguyn cng 05:Khoan v vt mp lu nhdng my khoan2A150 v mi khoan 37,mi khot vt 90ot bng Rz40,cp 4 vcp chnh xc 5.

6. Nguyn cng 06:Chut lu nhdng my chut 7B52 v daochut K2400-4002 t bng Rz10,cp bng6 v cp chnh xc 2a.

7.

Nguyn cng 7:Phay chun dng my phay 6H82F v dao phaytr168 v 125 t bng Rz20,cp 5 v chnh xc 3a.

8.

Nguyn cng8:Phay mt ghp dng my phay 612 v dao phaymt u 125 ,t bng Rz80,cp bng3 v chnh xc 4a.

9. Nguyn cng 9:Khoan doa lnh vdng my khoan 2H55 vmi khoan 10,7,mi khot 15,7,mi doa 16H7(16N8),muuix khot90otaro M12x1,25 t bng Rz20,cp 5 v chnh xc 3a.

10. Nguyn cng 10:Mi mt gp dng my mi phng 3B732 v mi 64C32-HC1 6K3,t bng Rz6 ,cp bng7 v cp chnh xc 3a.

11.

Nguyn cng 11:Kha mt ta bulong dng my khoan 2H55 v

dao kha 24 c nh tm t bng Rz40,cp bng 4 v cp chnhxc 5a.

12.

Nguyn cng 12:Ngui lp rp dng cc dng c nh eto,dangui,da ngui 400,bchsni ng sthtchi tit v cle tut S19.

13.

Nguyn cng 13:Mi phng hai mt dng my mi 3B732 v mi 5C 100x85x150 t bng7 v cp chnh xc 3a.


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14. Nguyn cng14:Tin lu to dng my tin 1K36 v dao tinu thng 16x16TK t bng Rz40,cp 3 v cp chnh xc 5a.

15.

Nguyn cng 15:Doa ln mt lnh39 ca tay bin dng mykhoan ng 2A150 v ng hl18-50 t bng Rz10,cp bng6 vcp chnh xc 3a.

16.

Nguyn cng 16:Doa ln mt l ln 69,5 ca tay bin dngmy doa ngang v ng ho l50-120 t bng Rz10,cp bng 6v cp chnh xc 3a.

17.

Nguyn cng 17:p bc dng bulong-thanh kp ri,dao khot vt90o,da mn,chy p v khoan ldu cng my khoan 2M55 v mi khoan5 v12.

18. Nguyn cng 18:Tho chi tit dng cc dng cnheto cle tutS19.

19. Nguyn cng 19:Phay rnh nh vdng my phay 6H82T v daophay rnh then 5x30 t bng Rz20,cp bng5,cp chnh xc 3a.

20. Nguyn cng 20:Ngui lp rp dng cc dng c nh eto ,dangui,ba ngui 400,gilau l cle tut S19.

21.

Nguyn cng 21:Doa tinh 2 lnh35 tay bin dng my khoanng 2A150 v ng ho l18-50 t bng Rz6,3 cp bng 7 v

cp chnh xc 2a.22. Nguyn cng 22:Doa tinh 2 l ln 70 ca tay bin dng my

doa ngang v ng hdo l50-120 t bng Rz6,3 cp bng7 v cpchnh xc 2a.

23. Nguyn cng 23:Phay hai mt u nhdng my phay 6H12 vdao phay mt u 125 t bng4 v cp chnh xc 3a.

24. Nguyn cng 24:Cn trng lng,tin v phay nhng chkhngcn thit ng trng lng yu cu,dng my phay 6P82,dao tin

R10TK,dao phay mt u 100.Sa ngui v lm sach dng da mn,gilauv vi nn kh.

25.

Nguyn cng 25:Kim tra nghim thu dng cc thit bnhngho l18-50 v 50-120,thc cp 250-1/120,cn trng lng 10kg,ng ho cao v bcn mu.


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4.Thit knguyn cng:

Nguyn tc chung khi thit knguyn cng l m bo c nng sut v chnh xc yu cu.Nng sut v chnh xc phthuc vo chct,lngd,sbc v thtcc bc cng ngh.

Ta da vo dng sn xut v phng php phn tn nguyn cng chn csnguyn cng (sg t, k hiu nh v,kp chn, chn my,chndng cct, k hiu chiu chuyn ng ca dao,ca chi tit v ct.)

Trc khi gia cng v phi dp xong cn phi ti ci thin t 2630HRCsau kim tra vcng v kch thc m bo lng dgia cng.

Yu cu kthut:

1/ cng 2630 HRC

2/ Kim tra cc kch thc m bo lng dgia cng.

3/ Sai lch gii hn khng ghi ca cc kch thc ltheo H16, trc H16 cnli JT6/2.

Ni dung nguyn cng:


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18

R32,5

114

H

35

43

1. Kim tra cc kch thc ca phi dp,m bo lng d giacng

2. Phi ti ci thin cng 26..30HRC.

3. Phi dp cc vt nt,chy,ngm x.


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19

70,28

43

29

H

54

94

43

R32,5

4.1/Nguyn cng 1:Phay hai mt phng thn ca tay bin.

Yu cu kthut:Phn bu lng d2 mt gia phay.Ni dung nguyn cng:1. nh vkp cht chi tit trn g.2. Phay thng t kch thc 19,65(mm)3. Lp chi tit 180o.4. Phay thng t kch thc 39,30-0,4.

5. Tho chi tit kim tra.Sg t c thhin nhhnh v:


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19,6

5

Rz40W

S

R32,5

39,3

0-0,4

n

--nh v:chi tit c nh v trn g hn ch 3 bc t do mtphng y,khi V hn ch2 bc tdo,cht thn ch1 bc tdo cnli.--Kp cht:chi tit c kp cht nhlc bulong hng ca lc kp tngoi hng vo mt nh vv c phng vung gc vi phng kchthc thc hin. Chn my:--Mt lm vic ca bn my 400x600mm.--Cng sut ng c(KW):10,hiu sut my =0,75.-svng quay trc chnh:30;37;47,5;60;75;95;118;150;190;235;300;375;475;600;900;1180;1500vng/pht

-lung chadao dc v ngang19;23;30;37,5;47,5;60;75;95;118;150;190;235;300;375;475;600;750;900vng/phtLc ct chiu trc ln nht cho php tc dng ln bn myPxmax=19650N. Chn dao:


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21

Dng dao phay mt u c gn mnh ct hp kim cng.--Theo bng 7 sch thit kn cng ngh{1}ta c kch thc lnnht ca dao l D=3009(mm),tui bn ca dao l T=240(pht)--Tra bng(4.95) s tay cng ngh ch to my tp 1{2} ta chn kchthc ca dao l D=120mm,B=50mm,d(H7)=40mm,srng Z=6.

D

B

d

Lng d gia cng:theo bng (3.17){2} vi chi tit dng cngdp trn ba my c trng lng 40kg v kch thc di 8009mm tac lng dvmt pha Zb=2,5(mm) Chct:Nguyn cng c chia lm hai bc:phay mt mt,sau lt chi titphay tip mt kia cng chct.-Chiu su ct f=1,85(mm)

-Tra bng (5.125) stay cng nghchto my tp 2{3} vi thp c>600Mpa,cng sut ca my N=10KW v mc hp kim cng T15K6c lng chy doa rng :Sz=0,1(mm/rng).

-Tra bng (5.126) {3} vi D=120(mm) ,srng Z=0,tui bn ca daoT=1809(pht) lng chy dao Sz=320(m/pht)-Tc tnh ton:Vt=Vb.K1.K2.K3.K4.K5.K6-Theo bng (5.126){3} ta c:K1:hsphthuc vo ctnh ca thp,K1=1,12


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22

K2:h s ph thuc vo chu k bn ca daoT/Th=240/180=1,33;K2=0,96.K

3:hsiu chnh phthuc vo mc hp kim,K

3=1,0

K4:hsphthuc vo trng thi ca bmt gia cng,K4=0,9K5:hsphiu chnh phthuc chiu rng phay:B/D>0,8,K5=0,89K6:h s iu chnh ph thuc vo goc nghing chnh =60-90 cK6=1,0

Vy Vt=320.1,12.0,96.1,0.0,9.0,89.1,0=275,59(m/pht)=>Svng quay trc tnh ton l

Nt=1000.Vt.D

=1000.275,59

.120=731,4 vng/pht

Chn theo my:Nmy=750 vng/pht

Vn tc ct thct:Vtt=.120.750

1000=450mm/pht

=>Chn theo my: Sm=474(mm/pht)-Cng sut ct:NcTheo bng (5.129){3} vi cc thng s tn ta c cng sut ct

Nc=4(Kw)My chn cng sut ct

Bng thng s

T(mm) N(v/ph) S(mm/ph) Cpchnhxc

bngRz

Phay 1,85 750 475 3 40

4.2.Nguyn cng 2:Phay hai mt phng np ca tay bin:Yu c

u k

thu

t:phn b

u l

ng d

hai mt phay

Ni dung nguyn cng:1. nh vv kp cht chi tit ln eeto.2. Phay phng t kch thc 19,65(mm)3. Lt chi tit 180.4. Phay thng t kch thc 39,30-0,45. Tho chi tit kim tra. Sg t c th hin trn hnh v:


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23

n

Rz40

19,6

5

39,3

0 -0,4

S

--Chi tit c nh vtrn g hn ch3 bc tdo mt phng yv m cnh kha nhm ca hn ch2 bc tdo.--Chi tit c kp cht nh lc kp ca bulong,hng ca lc kp tngoi hng vo mt nh vv vung gc vi phng cua kch thcthc hin. Chn my:gia cng mt phng ca np bin ta dng my phayng 6H12 vi cc thng snhnguyn cng phay thng hai mt thnca tay bin.

Lng dgia cng:theo bng(3.17){2} vi chi tit dng cng dptrn my ba c trng lng di 40 kg v kch thc di 800mm tac lng dvmt pha Zb=2,5mm.

Ch ct:nguyn cng c chia lm hai bc:phay mt mtsau lt chi tit li phay mt kia vi cng chct.Ta chn chct nhnguyn cng phay phng hai mt ca thn bin.

--Chiu su ct:t=1,85(mm)


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24

--Chn theo my Nmy=750(vng/pht)

--Lng chy dao pht :Sm=475(mm/pht)

Bng thng sT(mm) N(v/ph) S(mm/ph) Cp

chnhxc

bngRz

Phay 1,85 750 475 3 40

4.3/Nguyn cng 3:mi phng hai mt thn ca thn bin

Ni dung nguyn cng:

1. G chi tit trn bn t2. Mi phng chi tit t kch thc 19,3(mm)3. Lt chi tit 180o4. Mi phng chi tit t kch thc 38,60,02(mm)5. Tho chi tit kim tra.

Sg t thhin nhtrn hnh v:


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25

2,5

Sd

n

V

38

,60

,02

0,030,05 A

A0,03

nh vv kp cht chi tit trn bn t:

Chn my:gia cng phng hai mt ca tay bin,ta dng mymi phng 3B732 vi cc thng s:

--Bmt lm vic cua bn:320x800(mm)--Tc dch chuyn ca bn my:3-30(m/pht)

--Chy dao ngang sau mt hnh tnh kp ca bn my:0,3-30(mm)--Gii hn chy dao ng:0,005-0,05(mm)--Chiu rng 50-150(mm)--Svng quay ca :1450(vng/pht)--Cng sut ng c:13Kw,hiu sut =0,8--Kch thc my:1645x3450(mm) Chn mi:Dng mi 5C50M28 CT16K5 320x100x100Trong :


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26

+ ng knh mi:D=320(mm)+chiu rng:H=100(mm)+ng knh lp :d=100(mm)+vt liu mi cacbit silic:5C+ht:50M28+cng:CT1+shiu cu trc:6+cht kt dnh kenamit:K5 Lng dgia cng:ta c lng dvmt pha Zb=0,35(mm) Chct: gia cng c hai mt phng ca tay bin ta chianguyn cng lm hai bc l mi mt mt sau lt v mi mt kiavi sg v chct nhct bc mt.

--Theo bng mi bn knh v chiu dy ca 100(mm) ta c lngchy dao ngang :Sng=2550(mm/htrkep).Chn Sng32(mm/htrkep)

--Theo bng (5.126) {3} vi tc chuyn ng ca phi Vph=20mm/pht v lng chy dao ngang Sng=32 mm/htrkep ta c lng chydao theo chiu su :Sd=0.016 (mm/htrkep)--Lng chy dao theo chiu su c tnh:Std=S.K1.K2.K3Trong :

K1:hsiu chnh phthuc vo vt liu gia cng v ng knh mi.Theo bng (5.216) {3} vi ng knh mi D=320(mm) v chitit l thp ti ta c :K1=0,8K2:hsiu chnh ph thuc vo chnh xc gia cng .Theo bng(5.126){3} vi lng d gia cng Z=0,35mm v chnh xc kchthc 0,04mm,ta c K2=1,125.K3:h s iu chnh ph thuc vo h s in y bn.Theo bng(5.126){3} vi hsin y bn l K=1St=0,016.0,8.1,125.0,71=0,0102(mm/htkep)

Cng sut ct yu cu N c ta theo bng (5.127) {3} vi Vph=20vng/pht,Sng=32(mm/htkep),S=0,01(mm/htrkep) ta c:N=4,8Kw


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27

4.4/Nguyn cng 4:Mi phng hai mt np ca tay bin.

Ni dung nguyn cng:

1. G chi tit trn bn t2. Mi phng chi tit t kch thc 19,3(mm)3. Lt chi tit 18004. Mi phng chi tit t kch thc 38,30-0,055. Tho chi tit v kim tra.

Sg t c thhin nhhnh v:

2,5

Sd

n

19,3

38

,6

0-0,0

5

3

V

0,03

0,05 A

A0,03


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28

nh vv kp cht chi tit trn bn t. Chn my:gia cng phng hai mt ca tay bin ta dng mymi phng 3B372 vi cc thng s nhnguyn cng mi phng haimt ca thn bin.

Chn mi:dng 5C50M28 CT1 6K5 320x100x100 Lng dgia cng:lng dvmt pha Zb=0,35(mm) Chct

gia cng c hai mt cu ca tay bin ta chia nguyn cng lm

hai bc l:mi mt mt sau lt v mi mt kia vi sg tv ch ct nh bc 1.V cng yu cu k thut nn tin chovic gia cng ta chn ch ct nhnguyn cng mi phng haimt ca thn bin.

Ta c:

--Lng chy dao ngang:Sng=32(mm/htrkep)--Tc chuyn ng ca phi:Vph=20(mm/phut)--Lng chy dao theo chiu su:S=0,01(mm/htrkep)

--Cng sut ct yu cu:N=4,8(Kw)


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29

4. Vt ln lt hai mp t kch thc 1,5x4505. Tho chi tit v kim tra.

Sg t c thhin nhtrn hnh v

1,5x452 mp

W

n

S

Rz40

A37 +0,39-0

--nh v:chi tit c nh vmt y bng phin t hn ch3 bc tdo ,dng hai cht kha nhm thay cho khi V hn ch2 bc tdo,v

dng mt cht kha nhm chng xoay.--Kp cht:dng mkp bulong ai c kp cht chi tit c phnglc kp thng ng v chiu cua lc kp hng ttrn xung .

Chn my:chn my khoan ng 2A150 vi cc thng s:-ng knh mi khoan ln nht khi gia cng thp c bn trung

bnh max=50(mm)-Cng sut ng c:N=7Kw,hiu sut my =0,85


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30

-svng quay ca trc chnh:32;47;63;89;125;185;240;351;500;735;900;1400 (v/ph)-Lng chy dao:0,12;0,19;0,28;0,3;0,62;1,17;1,8;2,0;2,4(mm/vng)-Lc khoan chiu tc ln nht cho php cc c cu chydao:Pmax=24580N. Chn mi khoan:-Theo bng (4.40) {2} ta chn mi khoan rut g bng thp gi kiuui cn loi ngn c ng knh d=5260 mm.

-Ta dng mi khoan c ng knh 37 mm,tra bng 7{1} ta c tuibn ca dao T=75(pht) Lng dgia cng:Nguyn cng ny chia lm ba bc

--Khoan l37(mm) vi zb=18,5 mm--Vt mp l1,5x450--Lt chi tit 1800vt mp ming kia ca l1,5x450 Chct:Khoan l37(mm)-Chiu su ct :t=18,5(mm)-Theo bng (5.225) {3} ta c nhm thp gia cng l 6.-Tra bng (5.87) {3} vi 37 ,nhm thp gia cng 6 v lng chy dao:S=0,45(mm/vng) ta c tc ct Vb=25(mm/pht)-Tc ct tnh ton:V

t=V

b.K

1.K

2.K

3.K

.3

Theo bng (5.86) ta c:K1:hsphthuc chiu su lkhoan LSvng quay trc chnh tnh ton l:

nt =1000.Vt.D

=1000.23,73

.37=204,32(vng/pht)

Chn theo my :nmy=40(vng/pht)

Vn tc ct thc t:Vtt= .D.Nmy

1000=

.37.2401000

=27,9(m/pht)

-Lng chy dao chn theo my c:Sm=0,4(mm/pht)-Cng sut ct :Nc

Nc=5,5kwvy my chn cng sut ct. Vt mp u thnht-Chn lng chy dao theo bc khoan bc trc S=0,4(mm/vng)


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31

-Tc vng quay trc dao chn theo bc khot nguyn cng trcta c:N=240(vng/pht)Sau khi vt mp xong mt u ta lt chi tit v vt mp u cn li ccchcng tng t.

Bng thng skhi khoan lu nh37

t(mm) n(v/ph) S(v/ph) Cpchnh

xc

Rz

Khoanl37

18,5 240 0,4 5 40

Vtmp

240 0,4

4.6/Nguyn cng 6:Chut lu nhtay bin:

Yu cu kthut :- khng vung gc gia l 38 so vi mt A khng ln hn0,05/100Ni dung nguyn cng:1. nh vchi tit trn g2. Lp dao vo chi tit v bu cp3. Chut lt kch thc 380-0,054. Tho chi tit kim tra

Sg t c thhin nhhnh v:


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32

380-0.05S

2.5

A38 0-0,05

nh v:chi tit c nh vmt y ca phin thn chba bc t

do trn g ,do trong qu trnh tut dao tla do hn chhai bctdo.

--Kp cht:Do dao chut c ng knh ln dn v tn u lng dgia cng nn li dng lc chut kp cht chi tit xung thn g

phng ca lc vung gc vi mt nh chiu p chi tit vo mt nhv.

Chn mychut lu nhm bo c yu cu kthut ta dng my chutnm vi cc thng ssau:-Lc chut:20(tn)-Chiu di hnh trnh bn trt+Ln nht:1600(mm)+Nhnht:100(mm)-Tc chut(min-max):1,511(m/pht)-Tc chy khng:25(m/pht)


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33

-Cng sut ng c:30(kw).Hiu sut my =0,8Kch thc my 1500x6800(mm)

Chn dao:Dng dao chut thp gi trn c ng knh thay i t36,8 n360-0,05.Sau khi chut song nhm bmt gia cng R-a=2,5m.

Lng dgia cng:Ta c lng dgia cng vmt pha Zb=0,5(mm) Chct:

-Cc phn tct:Cc phn tkhi chut l:Chu vi ct (vnh ct)B=B.Z1/BTrong :B:Chu vi ct phthuc vo hnh dng ,kch thc bmt gia cng v

s ct ,phi hoc ln hn c mt i lng 1/cos,khi b tr rngnghing mt gc =1/cos;B=.d=3,14x38=119,32(mm)Z0:srng trong on dao chut khi theo sct tin tin (khi theo sct profin hay theo sct theo sng th Z0=1)Z1:srng ln nht ng thi ct c xc nh theo biu thc:Z=1/tVi 1 :l chiu di bmt gia cng 1=38,6(mm)T:bc rng dao t=6(mm)=>Srng ln nht ng thi c ct Z1.38,6/6=6,43=>=6Vy chu vi ct B =119.32x6/1=715,92(mm)

--Lng chy dao Sz:Lng chy dao khi chut Sz l chnh kch thc gia cc rng daolin nhau chnh l yu tto nn dao chut.Ta chn lng dao Sz=0,01(mm)--Tc ct V:Tc ct c xc nh theo yu cu ca chnh xc gia cng v nhm bmt.Theo bng (5.53){3} v (5.52) {3} ta c nhm tc ctkhi chut thp.Tc ct ln nht ca my l:Vmax=11(m/pht)


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34

A2

Sz

A1

V Sz=A2 - A1

Tc ct cho thp ng cca my chut l Vm=61200

NPz

(m/pht)

Trong :N:cng sut ng cmy N=30(KN)Pz:lc ct khi chut ca my Pz=200(KN):Hiu sut ca my =0,8

Vm=61200.30

200000.0,8=7,344(m/pht)

-Lc ct Pz(N)

Khi chut lc ct c xc nh theo cng thc:Pz=P.=71.715,92=50830(N)Bng thng skhi chut l380-0,05

Lungchydao Sz

Tc ctV(m/ph)

Lckhi ctPz(N)

Cpchnhxc

bngRz

Chut

l

0,01 7 50830 2 10

4.7/Nguyn cng 7:Phay thng vu lm chun ca tay bin:Ni dung nguyn cng:1. nh vv kp cht chi tit trn g.2. Phay chi tit t kch thc 510,2.3. Tho v ly chi tit ,kim tra. Sg t c thhin nhhnh vsau:


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35

Rz20

W W

S

510

,2

270

,2

-nh v:chi tit c nh vmt y bng phin dn hn ch3 bc tdo,cht trngn hn chhai bc tdo ti lu nho v chtchng xoay hn chbc quay quanh lu nh.-Kp cht:Dng mo kp bulong ai c kp cht chi tit c phnglc kp vung gc vi phin tv chiu ca lc hng vo nh v. Chn my:Phay chun tinh ta dng my phay ngang 6H82T vithng s:

-Mt lm vic ca bn my 320x1250 mm-Cng sut ng c:(Kw):N=7.Hiu sut my =0,75.-svng quay ca trc chnh:30;37,5;47,5;60;75;95;118;150;190;235;300;375;475;600;750;900mm/ph-lung chy dao dc v ngang:19;23,5;30;37,5;47,5;60;75;95;190;235;300;375;475;600;750;900mm/ph


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36

-Lc ct chiu trc ln nht cho php tc dng ln bnmy:Pxmax=14720N.

Chn dao:Dng hai dao phay trthp gi C120 v

168.-Theo bng 7{1} ta c Dmax=200(mm),tui bn T=120 pht-Chn kch thc ca dao ln :D=168(mm);B=30(mm);Z=10. Lng dgia cng:ta c lng dZb=3(mm) Chct:Ta tnh chct cho dao c ng knh ln.-Chiu su ct:t=3(mm)-Tra bng(5.131){3} vi 168(mm0,srng Z=12,tui bn dao T=180

pht,lng chy dao tinh S0=0,18(mm/rng) v chiu su ct t=39mm)ta c tc ct Vb=57(m/pht)-Tc ct tnh ton:Vt=Vb.K1.K2.K3.K4Theo bng: (5.126){3} ta c :K1:hsphthuc vo ctnh ca thp,K1=1,12K2:hsphthuc vo chu k bn T/Th=240/180=1,33;K2=0,95K3:hsphthuc vo trng thi ca bmt gia cng,K3=0,9K4:hsiu chnh phthuc vo dng gia cng c K4=0,8Vy Vt=57x1,12x0,95x0,8=43,67(m/pht)=>Svng quay ca trc chnh tnh ton l:

Nt= 1000.Vt.D

=1000.43,67

.168=83(vong/phut)

Chn theo my:nmy=95(vng/pht)Vn tc ct thc t:Vt=

.D.Nmy1000

=50,14(m/pht)

-Lng chy dao pht:Sp=Sn.nmy=2,16.95=205,2(mm/pht)=>Chn svng my:Sp=190(mm/pht)


chnhxc

bngRz

Phay 3 95 190 3 20

4.8/Nguyn cng 8:Phay phng mt ghp(thn v np) ca taybin.Yu cu kthut:Cc kch thc m bo bng gi

Ni dung nguyn cng:1. nh vv kp cht chi tit ln g phay2. Phay chi tit t kch thc 149 0,1


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37

3. Tho v ly chi tit4. Kim traSg c t nhtrn hnh v:

45

Rz40

n

s

1490

,1

0,10,05 A

33

3

W

3

WA

nh v: thn bin c nh vmt y bng phin dn hn ch3

bc tdo ,cht trngn hn chhai bc tdo ti lu nhv chtxoay hn chbc quay quanh lu nhti vu chun.Np bin cng c nh vhai mt y bng phin dn hn ch3bc tdo ,hai cht trkha nhm np bin ti hai mt ta bulong hnchhai bc tdo.Kp cht:dng mkp bulong ai c kp cht chi tit c phng lckp vng gc vi phin tv chiu ca lc kp hng vo mt nh v.


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38

Chn my:Phay thng mt ghp thn v np bin dng my phay

ng 6H12 Chn dao:Dng dao phay mt u c gn mnh ct hp kimcng.-Theo bng7{1} ta c Dmax=300(mm),tui bn ca dao l T=240(pht)-Tra bng (4.95){2} ta chn D=80(mm);B=45;d(H7)=30(mm).SrngZ=5 Lng dgia cng:ta c lng dZb=2,5(mm0 Chct:t=2,5(mm)-Chiu su ct:t=2,5(mm)-Tra bng (5.125){3} vi cng sut my N=10kw,b>600Mpa v mc

hp kim T15K6 ta chn lng chy dao T =180(pht),lng chy daoSz=0,1(mm/rng) v chiu su ct t=3(mm) ta c tc ctVb=335(m/pht) Tc tnh ton:Vt=Vb.K1.K2.K3.K4.K5Theo bng (5.126){3} ta c:K1:Hsphthuc vo tnh cca thp,K1=1,12K2:Hsphthuc vo chu kbn dao T/TH=240/180=1,33;K2=0,95.K3:Hsiu chnh phthuc vo mc hp kim,K3=1,0K4:Hsphthuc vo trng thi ca bmt gia cng,K4=0,9

K5:Hsiu chnh phthuc chiu rng phay :B/D=2/8svng quay trc chnh tnh ton l:

Nt=1000.Vt.D

=1136(vng/pht)

Chn nmy=1180(vng/pht)

Vn tc ct thc t:Vtt=.D.Nmy

1000=296,57(vng/pht)

-Lng chy dao:Sp=0,15.1180=590(mm/ph)=>Chn S

m=600(mm/ph)

-Cng sut ct NcTheo bng (5.129){3} tra c cng sut ct Nc=3,5kw


chnhxc

bngRz

Phay 3 95 190 3 20


39/124



39

4.9/Nguyn cng 9:Khoan doa lnh vYu cu kthut:1. khng vung gc ng tm 2 lM12x1,25;ng tm 2 l12,3 v ng tm 4 l16 so vi bmt A khng ln hn 0,05/1002. Cc kch thc m bo g Sg t c thhin nhtrn hnh v:

45

149+0.1

-0.0

5

210,72

0.1

23

.5

25

.5

510.1

15.7+0.15

8.5

w w

3 3

12,3

900,5

19,2

50

,15

450,05

Rz20

S S

-nh v:Thn bin c nh vmt y bng phin dn hn ch3

bc tdo,cht trngn hn chhai bc tdo ti lu nhv chtchng xoay hn chbc quanh lu nho ti vu chun.-Np bin cng c nh vmt y bng phin dn hn ch3 bctdo,hai cht trkha nhm np bin ti hai mt ta bulong hnchhai bc tdo.


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40

-Kp cht:dng mbulong ai c kp cht chi tit c phng lckp vung gc vi phin tv chiu hng vo mt nh v.

Ni dung nguyn cng:1. nh vv kp cht cthn v np trn g.2. Khoan ln lt hai l trn thn t cc kch thc10,7;25,5(mm)3. Khoan ln lt hai ltrn np t kch thc 12,3(mm)4. Khot ln lt hai ltrn thn t kch thc 15,7+0,15;5,5(mm)5. Khot ln lt hai ltrn np t kch thc 15,7+0,15;8,5(mm)6. Doa ln lt hai ltrn thn t kch thc 160

+0,15;5,5(mm)7. Doa ln lt hai ltrn np t kch thc 16-0,003-0,039;8,5(mm)8. Vt ln lt c mp t kch thc 1x450

9. Taro hai ltrn thn t cc kch thc M12x1,25;23,5(mm)10. Tho chi tit kim tra. Chn my:Chn my khoan cn 2H55 vi cc thng s:-ng knh mi khoan ln nht khi gia cng thp c bn trung

bnh max=50(mm)-Cng sut ng c:N=4(Kw),hiu sut my =0,85-Cng sut ng cnng cn:N=2,2(Kw)-Svng quay trc chnh:

:20;32;47;63;89;125;185;240;351;500;735;996;1400;2000(vng/pht)-Lng chy dao::0,056;0,12;0,19;0,28;0,4;0,62;1,17;1,8;2,0;2,4(mm/vng) Chn dao:-Dng mi khoan rut g bng thp gi phi tiu chun10,7;12,3(mm)-Dng mi khot thp gi phi tiu chun 15,7(mm)-Dng mi doa thp gi 16H7;16N8(mm)-Dng mi khot vt 900-Dng taro M12x1,25

Tra bng 7{1} ta c tui bn cua dao T=759phuts) Lng dgia cng:Gia cng trn thn bin:-Khoan lc 10,7(mm) vi zb=5,35(mm)-Khot l15,7 (mm) vi zb=2,5(mm)-Doa l16H7(mm) vi zb=0,15(mm0-Taro M12x1,25-Vt mp 1x450


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41

Gia cng trn np bin:-Khoan lc 12,3(mm) vi zb=1,7(mm)-Khot l 15,7(mm) vi z

b=1,7(mm)

-Doa l16H7(mm) vi zb=0,15(mm) Khoan 2 l16H7(mm) trn thn bin-Chiu su ct:t=5,35(mm)-Theo bng (5.225) ta c nhm thp gia cng l 6-Tra bng (5.87){3} vi 10,7(mm) v thp c Trong :K1:hsphthuc vo chiu su ca khoan Lsvng quay trc chnh tnh ton l:L

Nt=1000.Vt.D

=1000.43,94

.D=1307,15(vng/pht)

Chn theo my nmy=1400(vng/pht)

Vn tc ct thc t:Vt=.D.Nmy

1000=47,06(m/pht)

-Lng chy dao chn theo my c :Sm=0,12(mm/vng)*Khoan 2 l12,3 (mm/np bin)Chiu su ct T=6,15 (mm)-Chn svng quay trc chnh theo my :nmy=1400 (vng/pht)-Lng chy dao chy theo my :Sm=0,12 (mm/pht)*Khot 2 l15,7 (mm) trn thn bin-Chiu su ct :t=2,5(mm)-Tra bng (5.104){3} vi 15,7 (mm) v nhm chy dao II ta c lngchy dao :S=0,40,45 (mm/vng).Lng chy dao


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42

S=0,4(mm/vng),nhm thp gia cng 6 v mi khot lin ta c ctVb=20(vng/pht)-Tc ct tnh ton:V

t=V

b.K

1.K

2

Trong :-K1:hsphthuc vo chu k bnVi 15,7(mm)=>Ttb=30(pht)=>T/Th=30/75=0,4Theo bng (5.104){3} ta c K1=1,25-K2:hsphthuc vo trng thi thp

Theo bng (5.104){3} ta c K2=0,95Vi Vt=20.1,25.0,95=23,75(m/pht)

=>Svng quay trc chnh tnh ton l:Nt=

1000.Vt.D

=1000.23,75.15,7

=481,52(vng/phut)

Chn theo my:ta c n my=500(vng/pht)


1000=47,06(m/pht)

-Lng chy dao ta chn cho my c:Sm=0,12(mm/vng)*Khoan 2 l12,3(mm) trn np bin.-Chiu su ct:t=6,15(mm)

-Chn svng quay trc chnh theo my :nmy=1400 vng/pht-Lng chy dao dc theo my:Sm=0,12(mm/vng)*Khot 2 l15,7 trn thn bin-Chiu su ct :t=2,5(mm)-Tra bng (5.104){3} vi 15,7(mm) v nhm chy dao II ta c lngchy dao:S=0,4 0,45(mm/vng).Chn lng chy daoS=0,42(mm/vng),nhm thp gia cng 6 v mi khot lin ta c tc ct :Vb=20(m/pht)Tc ct tnh ton:Vt=Vb.K1.K2Trong :-K1:hsphthuc vo chu k bnVi 15,7(mm)=>Ttb=30(pht)=>T/Th=30/75=0,4Theo bng (5.104){3} ta c K1=1,25-K2:hsphthuc vo trng thi thp

Theo bng (5.104){3} ta c K2=0,95


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43

Vi Vt=20.1,25.0,95=23,75(m/pht)=>Svng quay trc chnh tnh ton l:

Nt=1000.V

t.D =481,52(vng/phut)Chn theo my:ta c n my=500(vng/pht)


1000=24,66(m/pht)

-Lng chy dao ta chn cho my c:Sm=500(mm/vng)*Khot 2 l15,7 trn np bin-Chiu su ct:t=1,7(mm)-tra bng (5.104){3} vi vi 16 (mm) v nhm chy dao II ta clng chy dao :S=0,8(mm/vng)

*Doa 2 l15,7 trn np bin-Chiu su ct:t=0,15(mm)-tra bng (5.104){3} vi vi 16 (mm) v nhm chy dao II ta clng chy dao :S=0,8(mm/vng) v nhm thp gia cng 6 ta c tc ct Vb=10,6(m/pht)-Tc ct tnh ton Vt=Vb.KTrong :-K:hsphthuc vo chu k bnVi 16(mm)

=>Ttb=40(pht)=>vy Vt=10,6.0,8=8,48(m/pht)=>Svng quay trc chnh tnh ton l:

Nt=1000.Vt.D

=168,7(vng/phut)

Chn theo my:ta c n my=185(vng/pht)


1000=9,3(m/pht)

-Lng chy dao ta chn cho my c:Sm=0,62(mm/vng)*Doa 2 l16N8 trn np bin-Chiu su ct:t=1,7(mm)-Svng quay trc chnh chn theo my:nmy=185(vng/pht)-Lng chy dao chn theo my:Sm=0,62(mm/vng)*Taro lren M12x1,25:-Bc ren:P=1,25(mm/vng)-Tra bng (5.104){3} vi M12 v P=15(mm) ta c tc ctVb=10(m/pht)Tc ct tnh ton:Vt=Vb.K1.K2


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44

Trong :K1:hskn khi ct ren chnh xc,K1=0,8K

2:hsiu chnh phthuc vo vt lih gia cng

Ta c:K2=1,0=>V1=10.0,8.1,0=8(m/pht)=>Svng quay trc chnh tnh ton l:

Nt=1000.Vt.D

=212,21(vng/phut)

*Vt 2 mp 1x450-Chn lng chy dao cho my :Sm=0,12(mm/vng)

4.10/Nguyn cng 10:Mi mt ghp (thn v np) ca tay bin

Yu cu kthut:1. nh vv kp cht cthn v np trn g mi2. Mi phng t kch thc 210 0,05 v 148,490,0353. Tho chi tit kim tra Sg t c thhin nhtrn hnh v

45

149

+0.1

-0.0

5

210,72

0.1

510.1

w w

3 3

A

n

1,25S

V

33

0,010,01 A


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45

nh v:thn bin c xc nh mt y bng phin dn hnch3 bc tdo,cht trngn hn chhai bc tdo ti lu nhvcht xoay hn chbc quay quanh lu nhti vu chun.-Np bin cng c nh vmt bng phin dn hn ch3 bc tdo,cht tru kha nhm np bin ti hai mt ta bulong hn chhai

bc tdo. Kp cht:dng m kp bulong ai c kp cht chi tit c

phng lc kp vung gc vi phin tv chiu ca lc hng vo mtnh v. Chn my:mi phng thn v np bin dng my mi phng

3B732 Chn mi:Dng mi 64C 32H C1 6K3 400x120x100Trong :+ng knh mi D=400(mm)+chiu rng H=100(mm)+ng knh lp d=100(mm)+vt liu mi cacbit silic xanh :64C+ht 40H+cng C1

+shiu cu trc 6+cht kt dnh Keeamit:K3 Lng dgia cng:ta c lng dvmt pha Zb=0,51(mm) Chct:ct gia cng c mt ghp ca thn v np bin ta c chminhsau:-Theo bng (5.126){3} tc chuyn ng ca phi Vph=20(mm/pht)v lng dao ngang Sng=32(mm/htrkp) ta c lng chy dao theochiu su Sd=0,016(mm/htrkep)-Lng chy dao theo chiu su tnh:St=S. .K1.K2.K3Trong :K1:hsiu chnh phthuc vo vt liu gia cng v ng knh miTheo bng (5.126){3} vi ng knh mi D=320(mm) v chi tit lthp ti ta c K1=0,9K2:hsiu chinh phthuc vo chnh xc gia cngTheo bng (5.126){3} vi lng dgia cng z=0,51(mm) v chnhxc kch thc 0,07(mm) ta c K2=1,8K3:hsiu chnh phthuc vo hsin y bn


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46

Theo bng (5.126){3} vi hsiu khin y k=1=>K3=0,71=>St=0,016.0,9.1,8.0,71(mm/htrkep)Chn S

=0,02(mm/htrkep)

-Cng sut yu cu N c tra bng (5.217){3}-Vi Theo bng (5.126){3} viVph=20(m/pht),Sng=32(mm/htrkep) vS=0,02(mm/htrkep) ta c :N=7,5(kw)


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47

24

B

32

0 0.3

4

Rz40

n s

0,05 A

A

-nh v:np bin c nh vmt ghp 3 bc tdo nhphin dnv c nh vbng mt phin dn mt phng hn chhai bc tdo.-kp cht:Np bin c kp cht bng bolong thanh c phng vunggc vi kch thc thc hin v chiu hng vo mt nh v.*Chn my:Chn my khoan cn 2H55 vi cc thng s*Chn dao:dng dao kho mt thp gi 23,c nh tm vi s rngz=5Tra bng 7{1} ta c tui bn ca dao T=75(pht) Lng d gia cng:lng d gia cng khi kha mt bulong lZb=1(mm) Chct:

-Chiu su ct :t=1(mm)-Tra bng (5.146){3} chiu su ct t=1(mm) v srng dao Z=5.Ta cphng dao chy rng:Sz=0,120,07(mm/rng)Chn Sz=0,09(mm/rng)-Tra bng (5.146){3} vi 24(mm),srng dao Z=5,ng knh kha24mm v chiu su ct t =1(mm).Ta c tc ct :Vb=64(m/pht)-Tc ct tnh ton:Vt=Vb. K1.K2.K3


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48

Trong K

1:hsiu chinh phthuc vo chu k bn ca dao

T/Tn=75/60=1,25Theo bng (5.147){3} ta c K1=0,93K2:hsphthuc vo ctnh ca thpTheo bng (5.120){3} ta c K2=1,15K3:hsiu chnh phthuc vo trng thi bmt gia cngTheo bng (5.120){3} ta c K3=0,85K4:hsphthuc vo trng thi thpVy Vt=64.0,93.1,15.0,85=58,18(m/phut)=>Svng quay trc chnh tnh ton l:

Nt=1000.Vt.D =771,6(vng/phut)

Chn theo my:nmy=735(vng/pht)


1000 =55,42(m/pht)

Lng chy dao S=0,09.5=0,45(mm/rng)Chn theo my c :Sm=0,4(mm/rng)Cng sut ct theo yu cu NTheo bng (5.151) vi Sz=0,09(mm/rng)

ng knh khong 24 v lng chy dao S=394(mm/pht) ta ccng sut ct theo yu cu N=1,5kw


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49

1. Kp cht thn bin trn eto2. Lm sch nh vthn v np3. Lp bc nh vthn v np4. Lp bulong bin,xit cht5. ng sthttrn thn v np trng nhau6. Tho v ly chi tit

4.13/Nguyn cng 13:Mi phng hai mt ca tay bin.Yu cu kthut:Phn bu lng dcho hai mt.

Ni dung nguyn cng:1. G chi tit trn bn t2. Mi phng chi tit t kch thc 30-0,17-0,333. Tho dnh v kim tra Sg t c thhin nhhnh v


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50

2,5

Sd

n

V

38-0,1

7

-0,3

3

0,020,03 A

0,02A

nh vv kp cht chi tit trn bn t Chn my:mi phng hai mt ca tay bin ,ta dng my mi

phng 3B732 Chn mi:dng mi 23A40 CT1 6K5 320x100x150Trong : +ng knh mi D=320(mm)+chiu rng H=100(mm)+ng knh lp d=100(mm)+vt liu mi crun in trng:23A+ht 40+cng CT1+shiu cu trc 6

+cht kt dnh Keeamit:K5 Lng dgia cng:ta c lng dvmt pha Zb=0,3(mm) Chct:gia cng c hai mt phng ca tay bin ta chianguyn cng ra lm hia bc l:+Mi mt mt kia vi sg t v chct nhu bc m1-Theo bng (5.126){3} vi mi bn tinh v chiu dy ca 100(mm)ta c lng chy dao ngang Sng=2550(mm/htrkep) .ChnSng=25(mm/htrkep)


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51

-Theo bng (5.126){3} vi tc chuyn ng ca phiVph=16(mm/pht) v lng dao ngang Sng=25(mm/htrkep) ta c lngchy dao theo chiu su S

=0,025(mm/htrkep)

-Lng chy dao theo chiu su tnh:St=S. K1.K2.K3Trong :K1;hsiu chnh phthuc vo vt liu gia cng v ng knh miTheo bng (5.216){3} vi ng knh mi D=320(mm) v chi tit lthp ti ta c:K1=0,8K2:hsiu chnh phvo chnh xc gia cngTheo bng (5.216){3} vi h s in y bnk=72/100=0,62=>K3=0,85=>St=0,025.0,8.1,4.0,85=0,0238(mm/htrkep)

Chn S=0,02(mm/htrkep)-Cng sut yu cu N c tra bng (5.127){3}-Vi Vph=16(m/pht),Sng=25(mm/htrkep) v S=0,02(mm/htrkep) ta c:

N=4,8(kw)


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52

tin lu to ca tay bin ,ta dng my tin R-vn-ve 1K36 vicc thng s:-ng knh ln nht ca phi trn mm cp :440 mm-ng knh ln nht ca thanh vt liu gia cng :60 mm-Sltrn trR-vn-ve:6-Hnh trnh di nht ca R-vn-ve:917 mm-Tit din dao ln nht:25x25mm-Cng sut ng c:10kw-Lc chy dao ln nht:8830N(900kg)-Svng pht ca trc chnh:30;40;54;69;126;222;297;380;515;619.-lng chy dao dc (mm/vng):0,07;0,09;0,13;0,17;0,28;0,31;0,38;0,41;0,52;0,56;0,76;0,92;1,24;1,68;

2,29. Chn dao tin:Dng dao u thng thp gi 16x25 mm c tui

bn 40-50 pht. Lng d gia cng:ta c lng d gia cng v mt phaZb=1,75(mm) Chct: tin lu to ca tay bin ta cn xc nh ccthng sct sau:-Chiu su ct:Ta thy nguyn cng ny l tin th v khng hn ch

bi cng sut ca thit b,cng vng ca hthng cng nghdo

ta ly chiu su ct bng lng dgia cng=>t=1,75(mm) ta c lngchy dao ngang S=0,61,2(mm/vng)So snh vi bng (5.62){3} ta chn lng chy dao S=0,6(mm/vng)-Tc ct V:theo bng (5.63){3} vi chiu su ct t=1.75(mm) lngchy dao S=0,6(mm/vng) v c im gia cng tin trong ta c tc ct V=47(m/pht)-Tc ct tnh ton l Vt= Vb. K1.K2.K3.K4.K5=>Trong :K1:hsiu chnh phthuc vo nhm ctnh ca thpTheo bng (5.63){3} vi thp 45 c HRC 26-30 ,ta c K1=1,28

K2:hsiu chnh phthuc chu kbn T ca daoTheo bng (5.63){3} vi T=40-50 pht,ta c K2=1,04K3:hsiu chnh phthuc vo goc nghing chnh ca daoTheo bng (5.63){3} vi =900ta c K3=0,65K4:hsiu chnh phthuc vo tnh trng bmt phiTheo bng (5.63){3} vi phi dp khng c vo cng ta c K4=1,0K5:hsiu chinh phthuc vo dung dch trn ngui ta c: K5=0,8Vy Vt=47.1,28.1,04.0,65.1,0.0,8=32,53(m/pht)


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53

=>Svng quay trc chnh tnh ton l:

Nt=1000.Vt

.D

=151,16(vng/phut)



1000=35,29(m/pht)

Lng chy dao chn theo my Smy=0,56(mm/vng)Cng sut ct yu cu N c tra theo bng (5.67){3} vi cc thng s xc nh trn ta c:N=2,0(kw)


54/124



54

S

W

2100,05

510

,1

69,5

+0

,1

0

35

0,03

4

0,009

w

n

-nh v:tay bin c nh vmt y bng phin dn hn ch3 bctdo,cht trngn hn ch2 bc tdo ti lu to v cht chng xoayhn chbc quay quanh lu to ti vu chun.-Kp cht:Dng mkp bulong ai c kp cht chi tit c phnglc kp vung gc vi phin t v chiu ca lc kp hng vo mt

nh v. Chn my: Chn my khoan ng 2A150 doa lnh39mm. Chn dao: Dng mi doa thp gi 39mm. Lng dgia cng:Doa l39mm vi lng dgia cng vmt

pha zb=0,5(mm) Chct:- Chiu su ct:t=0,5(mm)


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55

- Tra bng (5.112){3} vi D=39(mm) v nhm chy dao II ta clng chy dao :S=1,2(mm/vng). Chn theo my ta c lng chy daoS

my=1,17(mm/vng)

- Tra bng (5.112){3} vi D=39(mm),lng chy daoSmy=1,17(mm/vng) v nhm thp gia cng 6,ta c tc ctVb=7,5(m/pht)- Tc ct tnh ton:Vt=Vb.KTrong :K:hsphthuc vo chu k bnVi D=39(mm)=>T=80(pht)=>T/Th=80/50Theo bng (5.113){3} ta c K=0,85Vy Vt=7,5.0,85=6,375(m/pht)

=>Svng quay trc chnh tnh ton l:Nt=

1000.Vt.D

=7,72(m/phut)

Lng chy dao dc theo my c Sm=1,17(mm/vng)Bng thng s


bngRz

Doa

l39

0,5 63 1,17 3 10

4.16/Nguyn cng 16:Doa ln 1 lto 69,5 ca tay bin.Yu cu kthut:1. khng song song ng tm 2 l39 v 69,5 ,khng lnhn 0,05/100.2. cn,ovan l69,5 khng ln hn 0,018.

Ni dung nguyn cng: nh vv kp cht chi tit trn g doa Doa lt kch thc 2100,05;510,1;69,5+0,10 Tha chi tit kim tra. Sg c thhin nhtrn hnh v:


56/124



56

S

w

W

2100

,05

39+0,0

25

0

69,5+0,10

510,2

n

-nh v:thn bin c nh vmt y bng phin dn hn chba

bc t do,cht tr ngn hn ch 2 bc t do ti lu nh v chtchng xoay hn chbc quay quanh lu nhti vu chun.-Kp cht:Dng mkp bulong ai c kp cht chi tit c phnglc kp vung gc vi phin tv chiu lc kp hng vo mt nhv.

Chn my:dng my doa ngang 2615 vi cc thng s:- ng knh lc doa :80(mm)- Khong cch tng tm trc chnh ti mt bn:225 (mm)- Gii hn chy dao trc chnh:2,21760 (mm/vng)- Gii hn chy dao ca bn my:1,41110(mm/vng)- Gii hn vng quay trc chnh:201600(vng/pht)- Cng sut ng cin 5 (kw)

Chn dao:dng mnh hp kim cng T15K6 gn trn trc dao doat l69,5(mm) Lng dgia cng:Doa l69,5 vi lng dgia cng vmt pha zb=0m5(mm)


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57

Chct:- Chiu su ct:t=0,5(mm)

- Theo bng (5.116){3} vi ng knh doa

69,5(mm) ta clng chy dao S=1,52,0(mm/vng)- Tra bng (5.116){3} vi vt liu thp cc bon,ng knh doa69,5(mm) vt liu ct T15K6 v nhm bmt Rz10 ta c tc ctV=10(m/pht)

=>Svng quay trc chnh tnh ton l:

Nt=1000.Vt.D

=45,8(vng/phut)


Vn tc ct thc t:Vtt=.D.Nmy1000

= 10,26(m/pht)

Lng chy dao chn theo my Smy=1,68(mm/vng)Bng thng s


bngRz

Doal

69,5

0,5 47 1,68 3 10

4.17/Nguyn cng 17:p bc v khoan lu nhtay binNi dung nguyn cng:1. nh vv kp cht chi tit trn my khoan.2. Vt cc mp t kch thc 05x450;900;75.3. Lm trn ming u lnh.4. Lp bc ng vo chy p bi du bi trn ln mt ngoi bc.5. p bc vo u nhbin t kch thc 2(mm)6. Tho chi tit.7. Khoan lu 5 ,vt mp cc lt kch thc 3(mm);12008. Ly chi tit kim tra.Vt cc ming lu to,u nhv p bc vo u nhca tay bin. Sg c thhin nhtrn hnh v:


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58

0,5x45 0 75 2,5x45 0

-nh v: Chi tit c nh vmt y bng phin thn ch3 bctdo,dng hai cht kha nhm thay cho khi V hn chhai bc tdo vdung 1 cht kha nhm chng xoay.-Kp cht: Dng mkp bulong ai c kp cht chi tit c phnglc kp thng ng v chiu ca lc kp hng ttrn xung di. Chn my: Chn my khoan ng 2A125 vi cc thng s:-ng knh mi khoan vi cc thng sln nht khi gia cng thp c

bn trung bnh max=25(mm)-Cng sut ng c:N=2,8(kw),hiu sut my =0,8-S vng quay trc chnh:99,5; 135; 190; 267; 380; 540; 668; 950;1360(vng/pht)-Lng chy dao:0,1; 0,13; 0,17; 0,22; 0,28; 0,36; 0,48; 0,62;0,81(mm/vng)-Lc khoan chiu trc ln nht cho php ca cc c cu chydao:Pmax=8830N(900kg)


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59

Lng dgia cng:vt mp lnh0,5x450 Chct:

Ta chn lng chy dao v tc ct chungcho hai bc khot lnhv lto ca tay bin .V yu cu bng Rz20 nn ta chn chcttheo my v phi hp l vi yu cu kthut.Lng chy dao chn theo my c:Sm=0,1(mm/vng)Tc ct chn theo my c:nm=190(vng/pht)Sau khi vt mp xong 1 u ta lt chi tit 1800v vt mp u cn livi chct tng tbc trc.Bng thng skhi vt mp:

Zb(mm) N(v/ph) S(mm/v) RzVt mp45

0,5x450 190 0,1 20

Vt mp80

2,5x450 190 0,1 20

Sau khi vt mp cc ming ca l ta p bc vo u nh ca l vitrnh t:lm trn ming lu nhv lp bc ng vo chy p bi dutrn ln mt ngoi ca bc sau p bc vo u nh bin t kchthc 2(mm) nhthhin nhhnh vdi:

34

P


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60

Gia cng lu:

5

-nh v:Chi tit c nh vbi phin tu to v u nhca taybin hn ch3 bc tdo ,cht trngn nh v2 bc tdo lu nhv cht trm nh vbc xoay ti lu to.-Kp cht:kp cht chi tit c thc hin bng ai c v bc chC.Phng ca lc kp vung gc vi mt inh vv chiu hng vo mt

nh v. Chn my:Dng my khoan va sdng bc vt mp trc Chn dao:-Dng mi khoan rut gi bng thp gi 5(mm)-Dng mi khot vt 120012 thp gi.Tra bng 7{1} ta c tui bn ca dao T=25(pht) Lng dgia cngGia cng l5(mm) vi lng dgia cng vmi pha zb=2,5(mm)


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61

Vt mp lvi lng dgia cng 3x600 Chct:

Khoan lu

5-Chiu su ct:t=2,5(mm)-Lng chy dao chn theo my:Sm=0,36(mm/vng)-V gia cng lu 5 khng cn chnh xc cao nn ta chn vntc quay ca trc chnh theo my l nm=950(vng/pht)


1000=14,92(m/pht)

Vt mp lu:-Lng chy dao chn theo my:Sm=0,1(mm/vng)

-Chn vn tc quay ca trc chnh theo my l nm=190(vng/pht)Bng thng skhi vt mp:

Zb(mm) n(v/ph) S(mm/v)Khoan l25

2,5 950 0,36

Vt mp 3x450 190 0,1

4.18/Nguyn cng 18:Phay rnh nh v

Ni dung nguyn cng:1. nh vv kp cht cthn v np theo btrn g phay2. Phay ln lt cc rnh trn thanh v np t kch thc5+0,10;70,1;10,36;2,75.3. Tho chi tit kim tra. Sg t c thhin nhtrn hnh v:


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62

45

510.1

w w

3 3

A

1,25

s

2,75

30

10,6

3

5+0,1

0

70,1

5+0,1

0

70,1

30

-nh v:thn bin c nh vmt y bng phin dn hn ch3

bc tdo,cht trngn hn ch2 bc tdo ti lu nhv cht chngxoay hn chbc quay quanh lu lti vu nhu chun.

Np bin cng c nh vmt y bng phin dn hn ch3 bc tdo,hai cht trkha nhm np bin ti hai mt ta bulong hn ch 2

bc tdo.-Kp cht:Dng mkp bulong ai c kp cht chi tit c phnglc kp vung gc vi phin t v chiu ca lc kp hng vo mtnh v.

Chn my: Phay rnh nh vbc trn thn v np bin dng my phayngang 6H82T. Chn dao:Dng dao phay rnh then thp gi

Theo bng 7{1} ta c Dmax=90(mm),tui bn ca dao l T=70(pht) Chct:-Chiu su ct t=2,75(mm)


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63

-tra bng (5.163){3} vi D=30(mm),v chiu su ct 2,75(mm) ta clng chy dao S=0,080,05(mm/rng)

=>Chn Sz=0,05(mm/rng)-Theo bng (5.163){3} vi D/z =30/10 v chiu rng B=5 (mm) vlng chy dao Sz=0,05(mm/rng),ta c tc ct V=50(m/pht).-Tc ct tnh ton l: Vt= Vb. K1.K2Trong :theo bng (5.120){3}K1:l hsphthuc vo ctnh ca thp,K1=1,15K2:l hsphthuc vo chu k bn ca daoT/Th=70/120=>K2=1,04Vy Vt=50.1,15.1,12=64,4(m/pht)=>Svng quay trc chnh tnh ton l:

Nt=1000.Vt.D

=683,3(vng/phut)



1000=70,68(m/pht)

Lng chy dao chn theo my Smy=375(mm/vng)Cng sut ct Ncc tra theo bng (5.129){3} vi cc thng s xcnh trn ta c:Nc=2,2(kw)Vy my chn cng sut ct

Bng thng st(mm) n(v/ph) S(mm/v) CpCX

bRz

Phay 2,75 750 375 3 20

4.19/Nguyn cng 19:Ngui v lp rpYu cu kthut:1. Chi tt np bin c lp chn vi tay bin2. Sau khi lp rp xit cht bulong.Lc xit bulong =8Kgm

Ni dung nguyn cng:


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64

1. Kp cht thn bin trn eto2. Lm sch bavia cthn v np3. Lp bc nh vthn v np strn thn v np phi trng nhau

4. Lp hai bulong bin,xit cht5. Tho v ly chi tit kim tra.Sg t c thhin nhtrn hnh:


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65

nS

W

2100,05

510

,1

69,5

+0,

1

0

35

0,03

4

0,009

w

4.20/Nguyn cng 20:Doa tinh ln 2 lnhca tay binYu cu kthut:1. khng song song ng tm 2 l35 v 69,5 khng lnhn 0,05/1002. cn,ovan ca cc l35 khng ln hn 0,01

Ni dung nguyn cng:1. nh vv kp cht chi tit trn g doa.2. Doa lt kch thc 210 0,05;35+0,034+0,0093. Tho chi tit v kim tra Sg t c thhin nhhnh vdi.


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66

n

S

W

2100,05

510,1

69,5

+0,

1

0

350,03

4

0,009

w

-nh v: Tay bin c nh vmt y bng phin thn ch3 bctdo,cht trngn hn ch2 bc tdo ti lu to v cht chng xoayhn chbc quay quanh lu to ti vu chun.-Kp cht:Dng mkp bolong ai c kp cht chi tit c phnglc kp vung gc vi phin t v chiu ca lc kp hng vo mtnh v Chn my:Chn my khoan ng 2A150 doa lnh35

Chn dao:Dng mi doa thp gi 35mm Lng dgia cng:-Doa l35(mm) vi lng dgia cng vG45mt pha zb=0,5(mm) Chct:-Chiu su ct:t=0,25(mm)-Tra bng (5.112){3} vi D=35(mm) v nhm chy dao III,ta c lngchy dao S=0,1(mm/vng)


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67

-Vi yu cu cp chnh xc 2 nhm bmt ca lRz6,3 ta c tc ct theo bng (5..11){3} v V=3(m/pht)=>Svng quay trc chnh tnh ton l:

Nt=1000.Vt.D

=27,3(vng/phut)


Vn tc ct thc t:Vtt==.D.Nmy

1000=3,518m/pht)

Lng chy dao chn theo my Smy=0,96(mm/vng)bng thng s

t(mm) n(v/ph) S(mm/v) Cpchnh xc

bng

RzDoal35

0,25 32 0,96 2 6,3

4.21/Nguyn cng 21:Doa tinh ln 2 lln ca tay binYu cu kthut:1. khng song song ng tm 2 l35 v37 khng ln hn

0,03/100

2. cn,ovan ca cc l70 khng ln hn 0,01Ni dung nguyn cng:1. nh vv kp cht chi tit trn g doa2. Doa lt cc kch thc 2100,05;70+0,0190;510,13. Tho chi tit v kim tra Sg t c thhin nhhnh v:


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68

S

w

W

2100

,05

39+0,0

25

0

69,5+0,10

510,2

n

-nh v:Thn bin c nh vmt y bng phin dn hn ch3

bc tdo,cht trngn hn ch2 bc tdo ti lu nhv cht chngxoay hn chbc quay quanh lu nhti vu chun.-Kp cht:Dng mkp bulong ai c kp cht chi tit c phnglc kp vung gc vi phin t v chiu ca lc kp hng vo mtnh v. Chn my:Chn my doa ngang 2615 Chn dao:Dng mnh hp kim cng T15K6 gn trn trc daodoa t l70(mm) Lng dgia cng:Doa l70(mm) vi lng dgia cng vmt pha zb=0,25(mm)

Chct:-Chiu su ct:t=0,25(mm)-Theo bng (5.116){3} vi vt liu thp cc bon ,ng knh doa70(mm),ta c lng chy dao s=1,52,0(mm/vng)-Tra bng (5.116){3} vi vt liu thp cc bon,ng knh doa70(mm),vt liu ct T15K6 v nhm bmt Rz6,3 ta c tc ctV=10(m/pht)=>Svng quay trc chnh tnh ton l:


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69

Nt=1000.Vt.D

=45,47(vng/phut)

Chn theo my:nmy=47(vng/pht)Vn tc ct thc t:Vtt=

.D.Nmy1000

=10,33(m/pht)

Lng chy dao chn theo my Smy=1,68(mm/vng)Bng thng s

t(mm) n(v/ph) S(mm/v) Cpchnh xc

bngRz

Doal70

0,25 47 1,68 3 6,3

4.22/Nguyn cng 22:Phay phng mt u u nhNi dung nguyn cng:1. nh vv kp cht chi tit ln g phay2. Phay chi tit t kch thc 20-0,13;34

0-0,25

3. Tho v ly chi tit kim tra Sg t c thhin nhhnh v


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70

-nh v:Chi tit c nh vtrn thn g hn ch3 bc tdo mt

phng y ,cht trngn hn ch2 bc tdo u to v cht trcnh kha nhm hn ch bc quay quanh l u to. tng cngvng cho chi tit ta dng cht tphc mt t.-Kp cht:Chi tit c kp cht nh lc kp ca bulong phng lckp vung gc vi mt nh v v chiu ca lc kp hng vo mtnh v. Chn my:Dng my phay ng 6H12. Chn dao:Dng dao phay mt u c gn mt ct hp kim cng.-Theo bng 7{1} ta c Dmax=300(mm),tui bn T=240(pht).-Tra bng(4.95){2} ta chn:D=120(mm);B=(mm);d(H7)=40(mm);s

rng Z=6 Lng d gia cng: Ta c lng d gia cng v mt phazb=29mm) Ch ct:Nguyn cng gm 2 bc:Phay mt mt sau ltchi tit li phay tip mt kia cng vi chct.-Chiu su ct:t=2(mm)Tra bng (5.125){3} vi thp c b>600MPa,cng sut ca my N=10Kw v mc hp kim cng T15k6,ta c lng chy dao rng:Sz=0,1(mm/rng).

-Theo bng (5.125){3} vi D=120(mm) ,s rng Z=6,tui bn dao T=180(pht),lng chay dao Sz=0,1(mm/rng) v chiu su ct t=2(mm)ta c tc ct:Vb=320(m/pht)-Tc ct tnh ton: Vt= Vb. K1.K2.K3.K4.K5.K6.Tra bng (5.125){3} ta c:K1:Hsphthuc vo ctnh ca thp K1=1,12K2:H s ph thuc vo chu k bn ca dao T /TH=240/180=1,33,K2=0,96K3:Hsiu chnh phthuc vo mc hp kim,K3=1,0.K4:Hsphthuc vo trng thi ca bmt gia cng,K4=0,9

K5:Hsiu chnh phthuc vo chiu rng phay:B/D>0,8, K5=0,89K6 :H s iu chnh ph thuc o gc nghing chnh =60-90

0,K6=1,0Vy Vt=320.1,12.0,96.1,0.0,9.0,89.1,0=275,59(m/pht)=>Svng quay trc chnh tnh ton l:

Nt=1000.Vt.D

=731,4(vng/phut)



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71

Vn tc ct thc t:Vtt=.D.Nmy1000

=282,74 (m/pht)

-Lng chy dao pht:Sp=Sn.nmy=0,1.6.750=450(mm/pht)=>Chn theo my:Sm=450(mm/ph)-Cng sut ct Nc:Theo bng (5.129){3} ta tra c cng sut ct

Nc=4(Kw) Vy my chn cng sut ct.

Bng thng st(mm) n(v/ph) S(mm/v) Cp

chnhxc

bngRz

Phay 2 750 475 3 40

4.23/Nguyn cng 23:iu chnh chnh xc trng lng ca taybin.Yu cu kthut:1. Trng lng tay bin sau khi lp rp=1,861 Kg22g.2. Cho php tin 84 phay cc vu Q.S v B iu chnh trnglng.Ni dung nguyn cng:


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72

84

1. t chi tit ln cn xc nh trng lng d so vi yu cu kthut.2. G chi tit ln trc g tin,tin bt kim loi u to.3. G chi tit ln g phay,phay bt lng kim loi u nh.4. Tho v ly chi tit.5. Kim tra.

4.24/Nguyn cng 24:Sa ngui v lm sch tay bin.Ni dung nguyn cng:1. Da sch cc bavia cn li tnguyn cng trc.2. Lau chi tit bng gisch,thi bng kh nn ly sch phi trong

ldu v cc rnh.

4.25/Nguyn cng 25:Kim tra nghim thu.


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73

35

+0

,034

+0,009

510

,1

70+0,

019

-0

2100,05


74/124



74

Yu cu kthut:1. khng song song ng tm 2 l35 v 70 khng ln hn003/100.2. cn,ovan ca cc l35 v 70 khng ln hn 0,01.3. o mt mt u to so vi tm l70 khng ln hn 0,1/100.4. Trng lng tng cng ca tay bin sau khi lp=186122g.5. Cc kch thc v cc YCKT cn li tham kho trn bn vchitit.Ni dung nguyn cng:1. Cc YCKT kim tra 3%.2. ng knh hai lu to v u nhkim tra 100%.3. Cc kch thc cn li kim tra 5%.

Trang bcng ngh:1. ng ho l18-502. ng ho l50-1/203. Thc cp 250-1/204. Cn trng lng 10kg5. ng ho cao6. Bcn mu

Nguyn cng kim tra,sau khi gia cng cc bmt ca cc chi tit taphi kim tra cht lng sn phm theo yu cu kthut cho php cachi tit nh v kch thc + cht lng b mt + song song + vung gc,Nu chi tit no t yu cu th vic gia cng honthnh, cn ngc li chng l phphm. Tt hn ht sau mi nguyncng, ta nn c bc kim tra ngay sau nguyn cng ta c th loi

bc cc bc gia cng tip theo.Nu sai skhi gia cng l sai shthng th ta c thloi bgia cng chi tit khc t yu cu nhtacn.Kim tra tay bin gm cc bc kim tra song song ca hai l,kimtra vung gc ca mt u v tm l,kim tra song song gia ccmt phng,kim tra kch thc lv cc kch thc khc.

Kim tra song song ca hai ltay bin.Chi tit kim tra c g ln cht nh v,cht ny c g ln thn g. Lng trc kim tra v l nh ca tay bin nhhnh v. Dng tayquay tay bin cho n khi trc kim tra chm vo ct(quay tay binquanh cht nh v). Hiu sca hai ng ho hai vtr I v II l song song ca hai l bin.Mun o khong cch gia hai l ta okhong cch gia cc cht nh vv trc kim tra ri tri hoc cngthm bn knh ca cht nh vv cht kim tra.


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75

vung gia mt u v lc kim tra bng ng hso khi ngh so ny c g ln trc g mt vng. lch ca kim ng h sochnh l khng vung gc cn o.

Kim tra khng song song ca hai mt phng.

Chi tit kim tra c t trn mt cn mu t trn bn mp.iuchnh ng h so cho u o tip xc vi mt phng cn o v dchng ho theo mi tn(theo vng trn ca mt u).lch ca kimng hchnh l khng song song ca hai bmt.

Ni dung 6:Tnh ton lng dgia cng cho mt sbmt.

Nguyn cng gia cng lnh39 Yu cu kthut.-Vt liu gia cng :thp 45 c HB 195-nhn bng bmt sau khi gia cng Rz=10,cp nhn bng6-Dung sai kch thc ca l=0,025(mm)Vy m bo yu cu kthut ca lcn thc hin qua cc nguyncng sau:1. Khoan rng l372. Chut l383. Doa l39


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76

Tnh ton lng d:Bmt gia cng l mt trong i xng do ta sdng cng thc:

2Zmin=2(Rzi-1+Ti-1+ 2i-1+

2i

Trong : Rzi-1: Chiu cao nhp nh tvi do nguyn cng trc li.

Ti-1: Chiu cao lp khuyt tt do nguyn cng trc li.i-1: Sai svtr khng gian do nguyn cn trc li.i:Sai sg t chi tit nguyn cng ang thc hin

Githit gd=0 => gd= 2c+

2k

Khoan l37:Lc my dp c cht lng bmt :Rzo=150 (mm);T0=200(m)Tra bng (13.14){1} ta c cht lng bmt lsau gia cng:Cp nhn

bng 3.Rzl=50 (m) ;T1=50 (m) ,0= C

20+(y.l)

2


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77

Co

y.l

Tra bng 18 {1} ta c:C0:x dch tm lC0=30(m):lch tm ly=0,7(m)l:Chiu di gia cng l=38,6(mm) 0= 30

2+0,7.38.62=40,37(m)

1=0=40,37(m)Tnh sai sg t:

gd2:gd= 2c+

2k

Trong :c: sai schun khi chi tit lch c=0;ksai skpTra bng 24{1} vi vt liu thp,b mt nh v gia cng tinh vchiu rng 84(mm) ta c:

k=80(m) => gd2= 802+02=80(m)

Lng dtrung gian khoan rng :2Z2min=2(Rz0+T0+ 20+

21)

2Z2min=2(150+200 + 40,372+802=878(m)

Chut l38Tra bng (13){1} ta c:Cht lng bmt sau khi chut l:Rz2=20(m)T2=40(m);2=K.1=0,05.40,37=2,0185(m)Tnh sai sg t: gd2 : gd2= gd1=80(m)Lng dtrung gian chut sau khoan:

2Z2min=2(Rz1+T1+ 20+

21)

2Z2min=2(50+50+ 40,372+802)=380(m)

Doa l39


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78

Tra bng (13){1} ta c cht lng bmt sau doa l:Rz3=10(m);T3=25(m);3==0,8074(m)Sai sg t:

gd3:

gd3=

gd1=80(m)

Tnh lng ddoa sau khi khot:

2Z3min=2(Rz2+T2+ 22+

23)

2Z3min=2(20+40+ 2.01852+802)=280(m)

Tnh ton:-Dung sai kch thc:Doa :doa=25(m)Khot:khot=50(m)Khoan:khoan=390(m)-Kch thc tnh ton:dchut=ddoamax-2Z3min=39,025-0,025=39(mm)

dkhoan=dchut-2Z2min=38,745-0,380=38,65(mm)

ddl =dkhoan-2Z1min=38,365-0,878=37,478(mm)-Kch thc gii hn:Sau doa:dmax=39,025(mm)dmin=dmax-doa=39,025-0,025=39(mm)Sau chut: dmax=38,75(mm)

dmin=dmax-khot=38,75-0,050=38,7(mm)Sau khoan: dmax=38,40(mm)dmin=dmax-khoan=38,40-0,39=38,01(mm)-Lng dgii hn:Doa : 2Zmin=39,025-38,75=0,275(mm)=275(m)2Zmax=39-38,70=0,30(mm)=300(m)Chut:2Zmin=38,75-37,40=0,35(mm)=350(m)2Zmax=38,7-37,01=0,69(mm)=690(m)-Lng dtng cng:2Z0min=275+300=575(m)2Z0max=350+690=1040(m)Kim tra kt qusau khi tnh ton:-Sau doa:2Zmax-2Zmin=300-275=25(m)chut-doa=50-25=25(m)-Sau chut: 2Zmax-2Zmin=690-350=340(m)chut-doa=390-50=340(m)


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79

Nguyn cng gia cng mt ghp:Yu cu kthut:1. Tho 45 c cng HB 1952. nhn bng bmt sau gia cng Rz=6,3 ,cp nhn bng73. Dung sai kch thc =0,07(mm)Vy m bo yu cu k thut ca mt phng ghp quy tnh cngnghgm 2 nguyn cng sau:=>Phay thng mt ghp=>Mi tinh mt ghp

Thn bin c nh v mt y bng phin dn hn ch 3 bc tdo,cht tr ngn hn ch 2 bc t do ti lu nh v cht choonhs

xoay hn chbc quay quanh lti vu chun.Np bin cng c nh vmt y bng phin dn hn ch3 bc tdo,hai cht trnhm np bin ti 2 mt phng ta bulong hn ch2

bc tdo.Cng thc xc nh lng dgia cng;2Zmin=Rzi-1+Ti-1+i-1+iTrong : Rzi-1:Chiu cao nhp nh tvi do nguyn cng trc liTi-1 : Chiu cao lp khuyt tt do nguyn cng trc lii-1:Sai svtr khng gian do nguyn cng trc li

i:Sai sg t chi tit nguyn cng ang thc hin

Gthit gd=0 => gd= 2c+

2k

Theo bng (10){1} ta c cht lng b mt ca phi khi dp :cp1,Rz0=150(m),T0=200(m)Tra bng (12){1} ta c cht lng bmt sau phay :cp chnh xc 3-4;Rz1=5(m);T1=15(m)


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80

45

210

0,05

510.1

w w

3 3

1,25

V

0,010,01 A

A

149+0,1

-0,0

5

Sai lch khng gian c xc nh tng cng theo cng thc:phi= c+ cmTrong : cm=c.c=k.lcm:x dch ca phi,tra bng (17){1} ta c cm=350(m)k: cong gii hn ca phi trn 1 mm chiu di ck=0,4(m/mm)L: chiu di gia cng l=110(m)=>phi=0,4.110+350=394(m)=>1=k.phi=0,06.394=23,64(m)=>2= k.phi=0,02.394=7,88(m)

Tnh sai sg t: gd1= 2c+2kTrong :c:sai schun khi chi tit lch c=0;k:sai skpTra bng (24){1} ta c:k=80(m)=> : gd1= 80

2+02=80(m)Tng tta cng c:gd=80(m)Lng dphay phng mt ghp:Z1min=Rz0+T0+0+ 1=150+200+394+80=824(m)Lng dmi phng mt ghp:


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81

Z2min=Rz1+ T1+1+ 2=50+50+23,64+80=203,64(m) Tnh ton:

-Dung sai kch thc:Mi :mi=70(m)Phay :phay=200(m)-Kch thc tnh ton:lphay=lmimin+Z2min=148,455+0,204=148,659(mm)lbanu=lphaymin+Z1min=148,659+0,824=149,483(mm)-Kch thc gii hn:Sau mi:lmin=148,455(mm)lmax=lmin+mi=148,455+0,07=148,525(mm)Sau phay: lmin=148,65(mm)

lmax=lmin+phay=148,65+0,2=148,85(mm)Phi : lmin=149,48(mm)lmax=lmin+phay=149,48+0,35=149,83(mm)-Lng dgii hn:Mi : Zmax=148,85-148,525=0,325(mm)=325(m)Zmin=148,65-148,55=0,195(mm)=195(m)Phay : Zmin=149,48-148,65=0,83(mm)Zmax=149,83-148,85=0,98(mm)=980(m)-lng dtng cng:

Zomin=195+830=1025(m)Z0max=325+980=1305(m)

Ni dung 7:Tnh ch ct cho mt s nguyn cng(khoan l37,chut l38 ,doa l39,phay phng mt ghp ca tay bin).

7.1.Nguyn cng khoan lrng 37.-Chiu su ct:t=1,5(mm)-Lng chy dao:STra bng (5.25){3} vi 37(mm),HB=195 ta c lng chy dao

S=0,480,58(mm/vng)-Tc ct:V(m/pht)

Vt=Cv.D

q

Tm.tx.Sy.Kv

Theo bng (5.29){3} vi vt liu gia cng l thp cacbon v vt liumi khot l thp gi P6M5 ta c h s Cv=16,2,v cc sm:q=0,4;x=0,2;y=0,5;m=0,2


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Theo bng (5.30)vi vt liu gia cng l thp cacbon,vt liu dng cct l thp gi v ng knh mi khoan d=37(mm) ta c chu kbnT=70(pht)Hsiu chnh chung cho tc ct tnh n cc iu kin ct thct:KV=KMV.KUV.KLVTrong :KMV:Hsphthuc vo vt liu gia cngTheo bng (5.3){3} vi vt liu gia cng thp 45=>KMV=1,06KUV:Hsphthuc vo vt liu ctTheo bng (5.6){3} vi vt liu gia cng thp 45 v vt liu mi khoanthp gi P6M5,ta c KUV=1,0Vy KV:1,06.1,0.1,0=1,06

Thay cc sliu vo cng thc tnh vn tc ta c:Vt= 16,2.37

0,4

700,2.1,50,2.0,50,5 =24,16(m/phut)

Svng quay trc chnh :nt=1000.Vt.D

=208(vng/pht)

Chn vng quay theo my:nmy=240(vng/pht)Chn lng chy dao theo my:Sm=0,4(mm/vng)-Lc ct dc trc PcTheo cng thc:Pc=10.Cp.t

x.Dq.Sy.Kp

Theo bng (5.32){3} vi vt liu gia cng thp C45 BNc=21,43.240

950=0,53(kw)


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7.2 Nguyn cng chut 37Cc phn tct.-Cc phn tct khi chut l:chu vi ct B-tng cng chiu di ct lnnht ca tt ccc rng ng thi lm vic (mm);lng chy dao chomt rng Sz(mm) v tc ct V(m/pht)-Chu vi ctChu vi ct phthuc vo hnh dng,kch thc bmt gia cng v sct,c xc nh bng phng trnh B=B.Z1/Z0Trong :B chu vi ct (mm),va bng chiu di ca ng vin giacng trn phiB=.d=3,14.38=119,32(mm)Z0:srng trong on giao chut khi theo sct profin c Z0=1

Z1:srng ln nht ng thi ct c xc nh thoe biu thc Z1=1/tL:chiu di bmt gia cng l=38,6(mm);t bc rng dao t=6(mm)=>srng ln nht ng thi c ct Z1=38,6/6=6,43=>Z1=6Vy chu vi ct B=119,32.6/1=725,92(mm)Lng d chy dao Sz:lng chy dao khi chut Szl chnh lchkch thc gia cc rng dao li

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