wind energy basics
DESCRIPTION
Wind Energy Basics. Outline. What is a wind plant? Power production Wind power equation Wind speed vs. height Usable speed range Problems with wind; potential solutions. 1. What is a wind plant? Overview. 1. What is a wind plant? Tower & Blades. - PowerPoint PPT PresentationTRANSCRIPT
Wind Energy Basics
Outline1. What is a wind plant?2. Power production
a. Wind power equationb. Wind speed vs. heightc. Usable speed range
3. Problems with wind; potential solutions
1. What is a wind plant?Overview
1. What is a wind plant? Tower & Blades
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1. What is a wind plant? Towers, Rotors, Gens, Blades
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Manu-facturer
Capacity Hub Height Rotor Diameter
Gen type Weight (s-tons)
Nacelle Rotor Tower
0.5 MW 50 m 40 m
Vestas 0.85 MW 44 m, 49 m, 55 m, 65 m, 74 m
52m DFIG/Asynch 22 10 45/50/60/75/95, wrt to hub hgt
GE (1.5sle) 1.5 MW 61-100 m 70.5-77 m DFIG 50 31
Vestas 1.65 MW 70,80 m 82 m Asynch water cooled 57(52) 47 (43) 138 (105/125)
Vestas 1.8-2.0 MW 80m, 95,105m 90m DFIG/ Asynch 68 38 150/200/225
Enercon 2.0 MW 82 m Synchronous 66 43 232
Gamesa (G90) 2.0 MW 67-100m 89.6m DFIG 65 48.9 153-286
Suzlon 2.1 MW 79m 88 m Asynch
Siemens (82-VS) 2.3 MW 70, 80 m 101 m Asynch 82 54 82-282
Clipper 2.5 MW 80m 89-100m 4xPMSG 113 209
GE (2.5xl) 2.5 MW 75-100m 100 m PMSG 85 52.4 241
Vestas 3.0 MW 80, 105m 90m DFIG/Asynch 70 41 160/285
Acciona 3.0 MW 100-120m 100-116m DFIG 118 66 850/1150
GE (3.6sl) 3.6 MW Site specific 104 m DFIG 185 83
Siemens (107-vs) 3.6 MW 80-90m 107m Asynch 125 95 255
Gamesa 4.5 MW 128 m
REpower (Suzlon) 5.0 MW 100–120 m Onshore90–100 m Offshore
126 m DFIG/Asynch 290 120
Enercon 6.0 MW 135 m 126 m Electrical excited SG 329 176 2500
Clipper 7.5 MW 120m 150m
1. What is a wind plant?Electric Generator
6
generator
full power
PlantFeeders
actodc
dctoac
generator
partia l power
PlantFeeders
actodc
dctoac
generator
Slip poweras heat loss
PlantFeeders
PF controlcapacitor s
actodc
generator
PlantFeeders
PF controlcapacitor s
Type 1Conventional Induction Generator (fixed speed)
Type 2Wound-rotor Induction
Generator w/variable rotor resistance
Type 3Doubly-Fed Induction
Generator (variable speed)
Type 4Full-converter interface
1. What is a wind plant?Type 3 Doubly Fed Induction Generator
7
generator
partia l power
PlantFeeders
actodc
dctoac
• Most common technology today• Provides variable speed via rotor freq control• Converter rating only 1/3 of full power rating• Eliminates wind gust-induced power spikes• More efficient over wide wind speed• Provides voltage control
1. What is a wind plant?Collector Circuit
• Distribution system, often 34.5
8
POI or connection to the grid Collector System
Station
Feeders and Laterals (overhead and/or underground)
Individual WTGs
Interconnection Transmission Line
1. What is a wind plant?Offshore
• About 600 GW available 5-50 mile range• About 50 GW available in <30m water• Installed cost ~$3000/MW; uncertain because US cont. shelf deeper than N. Sea
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2. Power productionWind power equation
v1 vt v2
v
x
Swept area At of turbine blades:The disks have larger cross sectional area from left to right because• v1 > vt > v2 and• the mass flow rate must be the same everywhere within the streamtube.
Therefore, A 1 < At < A 2
2. Power productionWind power equation
ttt
t vAt
xA
t
mQ
3. Mass flow rate at swept area:
22
212
1vvmKE
1. Wind velocity:t
xv
xAm 2. Air mass flowing:
4a. Kinetic energy change:
5a. Power extracted: 2
221
22
21 2
1
2
1vvQvv
t
m
t
KEP t
6a. Substitute (3) into (5a):)()2/1( 2
221 vvvAP tt
4b. Force on turbine blades:
21 vvQvt
m
t
vmmaF t
5b. Power extracted:
21 vvvQFvP ttt
6b. Substitute (3) into (5b):)( 21
2 vvvAP tt
ttttt vvvvvvvvvvvvvvvvv ))(2/1()())(()2/1()()()2/1( 12212
21211222
122
7. Equate
8. Substitute (7) into (6b): ))((4
)()))(2/1(( 2122
2121
221 vvvv
AvvvvAP t
t
9. Factor out v13: )1)()(1(
4 1
22
1
231
v
v
v
vvAP t
2. Power productionWind power equation
10. Define wind stream speed ratio, a: 1
2
v
va
)1)(1(4
231 aavA
P t 11. Substitute a into
power expression of (9):
12. Differentiate and find a which maximizes function:
1,3/10)1)(13(
0123122
0)1()1(24
222
231
aaaa
aaaaa
aaavA
a
P t
This ratio is fixed for a given turbine & control condition.
13. Find the maximum power by substituting a=1/3 into (11):
27
8
3
4
9
8
4)
3
4)(
9
11(
4
31
31
31 vAvAvA
P ttt
2. Power productionWind power equation
14. Define Cp, the power (or performance) coefficient, which gives the ratio of the power extracted by the converter, P, to the power of the air stream, Pin.
)1)(1(4
231 aavA
P t
31
211
211
21 2
1
2
1
2
10
2
1vAvvAvQv
t
m
t
KEP ttin
power extracted by the converter
power of the air stream
)1)(1(2
1
21
)1)(1(4 2
31
231
aavA
aavA
P
PC
t
t
inp
15. The maximum value of Cp occurs when its numerator is maximum, i.e., when a=1/3:
5926.027
16)
3
4)(
9
8(
2
1
inp P
PC
The Betz Limit!
312
1vACPCP tPinp
2. Power productionCp vs. a
2. Power productionCp vs. λ and θ
Tip-speed ratio:11 v
R
v
u u: tangential velocity of blade tip
ω: rotational velocity of blade
R: rotor radiusv1: wind speed
Pitch: θ
GE SLE 1.5 MW
2. Power productionCp vs. λ and θ
Tip-speed ratio:11 v
R
v
u u: tangential velocity of blade tip
ω: rotational velocity of blade
R: rotor radiusv1: wind speed
Pitch: θ
GE SLE 1.5 MW
2. Power productionWind Power Equation
31),(
2
1vACPCP tPinp
So power extracted depends on 1.Design factors:
• Swept area, At 2.Environmental factors:
• Air density, ρ (~1.225kg/m3 at sea level)• Wind speed v3
2. Control factors: • Tip speed ratio through the rotor speed ω• Pitch θ
2. Power productionControl
In Fig. a, a dotted curve is drawn through the points of maximum torque. This curve is very useful for control, in that we can be sure that as long as we are operating at a point on this curve, we are guaranteed to be operating the wind turbine at maximum efficiency. Therefore this curve, redrawn in Fig. b, dictates how the machine should be controlled in terms of torque and speed.
2. Power productionEffects on wind speed: Location
Wind Wind Speed(b) Wind Speed(b)
Power Power m/s (mph) Power m/s (mph)
Class Density Density
(W/m2) (W/m2)
1 <100 <4.4 (9.8) <200 <5.6 (12.5)
2 100 - 1504.4 (9.8)/5.1 200 - 300
5.6 (12.5)/6.4
3 150 - 2005.1 (11.5)/5.6 300 - 400
6.4 (14.3)/7.0
4 200 - 2505.6 (12.5)/6.0 400 - 500
7.0 (15.7)/7.5
5 250 - 3006.0 (13.4)/6.4 500 - 600
7.5 (16.8)/8.0
6 300 - 4006.4 (14.3)/7.0 600 - 800
8.0 (17.9)/8.8
7 >400 >7.0 (15.7) >800 >8.8 (19.7)
Classes of Wind Power Density at 10 m and 50 m(a)
10 m (33 ft) 50 m (164 ft)
2. Power productionEffects on wind speed: Location
2. Power productionEffects on wind speed: Height
“In the daytime, when 10 m temperature is greater than at 80 m, the difference between the wind speeds is small due to solar irradiation, which heats the ground and causes buoyancy such that turbulent mixing leads to an effective coupling between the wind fields in the surface layer. During nighttime the temperature DIFFERENCE changes sign because of the cooling of the ground. This inversion dampens turbulent mixing and, hence, decouples the wind speed at different heights, leading to pronounced differences between wind speeds.”
Source: M. Lange and U. Focken, “Physical approach to Short-Term Wind Power Prediction,” Springer, 2005.
T80m < T10m Ground heatingAir riseTurbulent mixingCoupling v80m ~ v10m
2. Power productionEffects on wind speed: Height
Source: M. Lange and U. Focken, “Physical approach to Short-Term Wind Power Prediction,” Springer, 2005.
“The mean values of the wind speed show a pronounced dirunal cycle. At 10 m, the mean wind speed has a maximum at noon and a minimum around midnight. This behavior changes with increasing height, so that at 200 m, the dirunal cycle is inverse, with a broad minimum in daytime and maximum wind speeds at night. Hence, the better the coupling between the atmospheric layers during the day, the more horizontal momentum is transferred downwards from flow layers at large heights to those near the ground.”
Daytime peak occurs at 10 m.
Nighttime peak occurs at 200 m.
Almost flat at 80 m.
Average wind speed increases with height.
2. Power productionEffects on wind speed: Height
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1
Height Hub
refref H
UUWind shear exponent differs locationallyU: wind speed estimate at Hub HeightHref is height at which reference data was takenUref is wind speed at height of Href
“The atmosphere is divided into several horizontal layers to separate different flow regimes. These layers are defined by the dominating physical effects that influence the dynamics. For wind energy use, the troposphere which spans the first five to ten km above the ground has to be considered as it contains the relevant wind field regimes.”
Source: M. Lange and U. Focken, “Physical approach to Short-Term Wind Power Prediction,” Springer, 2005.
2. Power productionEffects on wind speed: Contours
Wind profile at top of slope is fuller than thatof approaching wind.
2. Power productionEffects on wind speed: Roughness
2. Power productionUsable speed range
Cut-in speed (6.7 mph) Cut-out speed (55 mph)
3. Problems with wind; potential solutionsDay-ahead forecast uncertainty
• Fossil-generation is planned day-ahead• Fossil costs minimized if real time same as plan• Wind increases day-ahead forecast uncertainty
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Hourly Load Variability and Load-Wind Variability When Wind Penetration is 10%
0
500
1000
1500
2000
2500
3000
3500
4000
-800
-700
-600
-500
-400
-300
-200
-100
0 100
200
300
400
500
600
700
800
Load and Load-Wind Hourly Variability (MW)
Fre
qen
cy
Load Hourly Variability Load-Wind Hourly Variability
Solutions:• Pay increased fossil costs from fossil energy displaced by wind• Use fast ramping gen• Distribute wind gen widely• Improve forecasting• Smooth wind plant output
• On-site regulation gen• Storage
3. Problems with wind; potential solutionsDaily, annual wind peak not in phase w/load
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Solutions:• “Spill” wind• Shift loads in time• Storage
• Pumped storage• Pluggable hybrid vehicles• Batteries• H2, NH3 with fuel cell• Compressed air• …others
• Daily wind peaks may not coincide w/ load• Annual wind peaks occur in winter
Midwestern Region
3. Problems with wind; potential solutionsWind Power Movies
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JULY2006JANUARY2006
Notice January has a lot more high-wind power than July.Also notice how the waves of wind power move through the entire EI.
3. Problems with wind; potential solutionsCost
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3. Problems with wind; potential solutionsCost
•$1050/kW capital cost• 34% capacity factor• 50-50 capital structure• 7% debt cost; 12.2% eqty rtrn• 20-year depreciation life• $25,000 annual O & M per MW20-year levlzd cost=5¢/kWhr
• Existing coal: <2.5¢/kWhr• Existing Nuclear: <3.0¢/kWhr• New gas combined cycle: >6.0¢/kWhr• New gas combustion turbine: >10¢/kWhr
Solution:• Cost of wind reduces with tower height
• Tower designs, nacelle weight reduction, innovative constructn• Carbon cost makes wind good (best?) option
3. Problems with wind; potential solutions Wind is remote from load centers
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Transmission cost: a small fraction of total investment & operating costs.…And it can pay for itself:• Assume $80B provides 20,000 MW delivery system over 30 years, 70% capacity factor, for Midwest wind energy to east coast.• This adds $21/MWh.• Cost of Midwest energy is $65/MWh. • Delivered cost of energy would then be $86/MWh.•East coast cost is $110/MWh.
Conclusions
Source: European Wind Energy Association, “Wind Energy – The Facts,” Earthscan, 2009.
• High penetration levels require solution to cost, variability, and transmission.• Wind economics driven by wind speed, & thus by turbine height.• Solutions to variability and transmission problems could increase growth well beyond what is not being predicted.