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Advanced Mathematics Training Class Notes Chapter 8: Trigonometry
46
Chapter 8
Trigonometry
Trigonometry (三角學三角學三角學三角學)
Trigonometry is a branch of geometry that studies the relationship of triangles. Take a
simplest triangle – a right-angled triangle as example:
A
b
c
θ B a C
If we fix point B and C (the value of a), and vary the size of BCA∠ (value of θ), the value of b and c also changes. Actually, the value c/b is a function of θ. Trigonometry defined the
function “sine” (正弦) as followed:
sinc
bθ =
Similarly, there are also five other functions – cosine (餘弦), tangent (正切), cotangent (餘
切), secant (正割) and cosecant (餘割), together called the trigonometric functions (三角
函數):
cos , tan , cot , sec , csca c a b b
b a c a cθ θ θ θ θ= = = = =
For practical use, only sine, cosine and tangent are more useful.
A
Hypotenuse
Opposite
θ B Adjacent C
Respecting to θ, the side opposite to it is called the “opposite” (對邊), the one which is
longest is called “hypotenuse” (斜邊), and the one next to θ is called “adjacent” (鄰邊).
Therefore, the sine, cosine and tangent can also be defined as:
Opposite Adjacent Oppositesin , cos , tan
Hypotenuse Hypotenuse Adjacentθ θ θ= = =
It can be memorized by the mnemonic “oh, ah, oh-ah”, which represents, sin θ is opposite over hypotenuse, cos θ is adjacent over hypotenuse, tan θ is opposite over adjacent.
Definition of Angle
In plane geometry, the range of angle is 0° to 360°. However, this is not enough for practical
use. For example, a clock rotates more than 360°. It is necessary for us to redefine what is
angle.
In trigonometry, we interpret angle as rotation of rays (射線). When a ray OA rotates about O
to the position OB, the amount of rotation is defined as the angle AOB and is denoted by
AOB∠ . The angle is positive if it is rotated anti-clockwise, and is negative if is rotated
clockwise.
B
420° -75°
45°
O A
Base on the “new” definition of angle, we also have a more generalized definition of
trigonometric functions.
Advanced Mathematics Training Class Notes Chapter 8: Trigonometry
47
In a coordinate plane, take a point P (x, y). Let r denotes the distance from this point (P) to
the origin O (0, 0). (So 2 2r x y= + .) Let θ be the angle from the x-axis to OP.
P (x, y)
r
θ O
Then we define:
sin cos
tan cot
sec csc
y x
r r
y x
x y
r r
x y
θ θ
θ θ
θ θ
= =
= =
= =
These are the definition of the trigonometric functions of general angles θ.
Radians (弧度弧度弧度弧度)
In elementary mathematics, we measure angles in degrees (角度). Say, a right angle is 90°.
However, it is sometimes more convenient to use another measure: radians.
A
r s
θ O r B
In the figure, O is the center of a circle with radius r. A and B are two points on the
circumference. θ is the size of AOB∠ . s is the length of arc AB.
The radian measure of an angle is the ratio of the arc, which subtends the angle at the center
of a circle, and the radius of the circle. Or in formula,
s
rθ =
The following angle has a size of 1 radian.
r r
1 rad.
r
Usually the unit “rad.” is omitted, i.e., the size of the angle is 1.
Note that:
π radians = 180°
s
r θ
r
In a sector (扇形), if θ is measured in radian, then:
s = rθ
Area = 21 12 2r rsθ =
Advanced Mathematics Training Class Notes Chapter 8: Trigonometry
48
Basic Trigonometric Relations
Base on the definition of trigonometric functions, it is always true that:
1.
1csc
sin
1sec
cos
1cot
tan
θθ
θθ
θθ
=
=
=
(Reciprocal relations 倒數關係)
2.
sintan
cos
coscot
sin
θθ
θθ
θθ
=
= (Quotient relations 商數關係)
3.
2 2
2 2
2 2
sin cos 1
1 tan sec
1 cot csc
θ θ
θ θ
θ θ
+ =
+ =
+ =
(Squares relations 平方關係)
The last relations can be proved by Pythagoras’ theorem.
Some special angles
1 2 3 2
45° 60° 1 1
For 30°, 45° and 60°, their corresponding trigonometric functions will give some special
results. They are thus called the special angles. The results should be memorized, and is
summarized in the following table:
30° (ππππ/6) 45° (ππππ/4) 60° (ππππ/3)
sin 1
2
2 1or or 0.5
2 2
3or 0.75
2
cos 3
or 0.752
2 1
or or 0.52 2
1
2
tan 3 1
or3 3
1 3
Together with 0° and 90°, the value of sine and cosine shows an interesting pattern.
0° (0) 30° (ππππ/6) 45° (ππππ/4) 60° (ππππ/3) 90° (ππππ/2)
sin 0
2
1
2
2
2
3
2
4
2
cos 4
2
3
2
2
2
1
2
0
2
The followings should also be memorized:
0° (0) 90° (ππππ/2) 180° (ππππ) 270° (2ππππ/3) 360° (2ππππ) sin 0 1 0 -1 0
cos 1 0 -1 0 1
tan 0 / 0 / 0
“/” means undefined.
Extension: 1
sin181 5
° =+
Advanced Mathematics Training Class Notes Chapter 8: Trigonometry
49
Ranges of Trigonometric Functions
The output ranges of some trigonometric functions are constrained:
1 sin 1
1 cos 1
sec 1 or sec 1
csc 1 or csc 1
θθ
θ θ
θ θ
− ≤ ≤
− ≤ ≤
≤ − ≥
≤ − ≥
But tangent and cotangent are not. Their output range is any real numbers.
When 2
n πθ π= + , tangent and secant do not exist. When θ = nπ, cotangent and cosecant are
not defined.
In addition, their signs are also arranged in a special pattern:
0° < θθθθ < 90° 90° < θθθθ < 180° 180° < θθθθ < 270° 270° < θθθθ < 360°
0 < θθθθ < ππππ /2 ππππ/2 < θθθθ < ππππ ππππ < θθθθ < 3ππππ/2 3ππππ/2 < θθθθ < 2ππππ sin, csc + + – –
cos, sec + – – +
tan, cot + – + –
It can be simplified as:
90°
S A
180° 0° / 360°
T C
270°
“S” means “sine in positive”, “C” means “cosine is positive”, “T” means “tangent is
positive”, “A” means “all are positive”. This is known as the “CAST Diagram”.
Note: the part 0° to 90° is called quadrant I (第一象限), 90° to 180° is called quadrant II
(第二象限), and so on.
Transformation Formulae
Any angles can actually transformed into angles within range of 0° to 90° when dealing with
trigonometric functions.
Negative angles
( )( )( )
sin sin
cos cos
tan tan
θ θ
θ θ
θ θ
− = −
− =
− = −
Complementary angles
( )( )( )
2
2
12 tan
sin cos
cos sin
tan cot
π
π
πθ
θ θ
θ θ
θ θ
− =
− =
− = =
(Recall: π/2 = 90°)
Multiple revolutions
( ) ( )2f n fπ θ θ+ =
Where f can be sin, cos, tan, cot, sec or csc. n can be any integers.
Moreover, tan(πn + θ) = tan θ, cot(πn + θ) = cot θ.
Others
90° - θθθθ 90° + θθθθ 180° - θθθθ 180° + θθθθ 270° - θθθθ 270° + θθθθ 360° - θθθθ θθθθ
ππππ/2 - θθθθ ππππ/2 + θθθθ ππππ - θθθθ ππππ + θθθθ 3ππππ/2 - θθθθ 3ππππ/2 + θθθθ 2ππππ - θθθθ sin s c c s -s -c -c -s
cos c s -s -c -c -s s c
tan t k -k -t t k -k t
Here, “s” means “sin θ”, “c” means “cos θ”, “t” means “tan θ” and “k” means “cot θ”.
Advanced Mathematics Training Class Notes Chapter 8: Trigonometry
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Compound Angle Formulae (複角公式複角公式複角公式複角公式)
We often encounter expressions like sin(A + B) or cos(A – B). If A is a multiple of π/2, then we can use the transformation formulae. But it’s not that easy. Fortunately, there are general
expressions of the trigonometric functions of sum or differences of angles.
( )( )
( )
( )
sin sin cos cos sin
cos cos cos sin sin
tan tantan
1 tan tan
cot cot 1cot
cot cot
A B A B A B
A B A B A B
A BA B
A B
A BA B
A B
± = ±
± =
±± =
± =±
∓
∓
∓
These are called the “Compound Angle Formulae”. The first three formulae should be
memorized.
Example: Express tan 15° in surd form (根式) (with root signs)
Notice that tan 15° = tan (60° - 45°). Therefore,
( )tan15 tan 60 45
tan60 tan 45
1 tan60 tan 45
3 1
3 1
3 1 3 1
3 1 3 1
2 3
° = ° − °
° − °=
+ ° °
−=
+
− −=
+ −
= −
Double angle formulae (倍角公式倍角公式倍角公式倍角公式)
Replacing B with A, and use “+” for the “+” signs, we get the double angle formulae:
2 2
2
2
sin 2 2sin cos
cos2 cos sin
2 tantan 2
1 tan
cot 1cot 2
2cot
A A A
A A A
AA
A
AA
A
=
= −
=−
−=
For cosine, if we replace either cos2 A by 1 – sin2 A or sin2 A by 1 – cos2 A, we get two other
forms of double angle formulae for cosine:
cos 2A = 1 – 2 sin2 A = 2 cos2 A – 1
Triple angle formulae (三倍角公式三倍角公式三倍角公式三倍角公式)
Again, using compound angle formulae, we get the triple angle formulae: 3
3
sin3 3sin 4sin
cos3 4cos 3cos
A A A
A A A
= −
= −
The triple angle formulae can also be: 2 3
3 2
sin3 3cos sin sin
cos3 cos 3cos sin
A A A A
A A A A
= −
= −
But these are not as important as the two formulae given above.
Half angle formulae (半角公式半角公式半角公式半角公式)
Finally, the half angle formulae states that:
1 cossin
2 2
1 coscos
2 2
A A
A A
− = ±
+ = ±
The sign is determined by which quadrant does A/2 lie.
Advanced Mathematics Training Class Notes Chapter 8: Trigonometry
51
Product and Sum of Sine and Cosine
When solving trigonometric equations, we often come across with products or sums of sine
and cosine, which we may not be able to do easily. The product-to-sum formulae,
sum-to-product formulae and subsidiary angle form help us to tackle them.
Product-to-sum formulae (積化和差公式積化和差公式積化和差公式積化和差公式)
( ) ( )( )( ) ( )( )( ) ( )( )( ) ( )( )
12
12
12
12
sin cos sin sin
cos sin sin sin
cos cos cos cos
sin sin cos cos
A B A B A B
A B A B A B
A B A B A B
A B A B A B
= + + −
= + − −
= + + −
= − + − −
Sum-to-product formulae (和差化積公式和差化積公式和差化積公式和差化積公式)
( ) ( )( ) ( )( ) ( )( ) ( )
2 2
2 2
2 2
2 2
sin sin 2sin cos
sin sin 2cos sin
cos cos 2cos cos
cos cos 2sin sin
A B A B
A B A B
A B A B
A B A B
A B
A B
A B
A B
+ −
+ −
+ −
+ −
+ =
− =
+ =
− = −
The product-to-sum and sum-to-product formulae can be summarized as:
A B A+B A–B
2
2
2
2
s c s s
c s s s
c c c c
s s c c
= +
= −
= +
− = −
2
A B+ 2
A B− A B
Here, “s” means “sin”, “c” means “cos”.
Subsidiary angle form
Product-to-sum and sum-to-product mainly deal with sum or difference of two sines or
cosines. The subsidiary angle form is much difference. It changes expression in form of
sin cosa bθ θ+ to r cos(θ – α). Suppose ( )cos sin cosr a bθ α θ θ− = + . By expanding the left-hand-side, comparing
coefficients, we get:
sin
cos
a r
b r
αα
=
=
And therefore:
2 2
tan
r a b
a
bα
= +
=
Example: If ( )sin 3cos cosrθ θ θ α+ = − , find r and α.
( )221 3 2r = + =
( )6
1tan
3
30π
α
α
=
∴ = = °
Advanced Mathematics Training Class Notes Chapter 8: Trigonometry
52
Graphs of Trigonometric Functions (三角函數的圖像三角函數的圖像三角函數的圖像三角函數的圖像)
x
y
−π 0 π 2π
-1
1
y = sin x
x
y
−π 0 π 2π
-1
1
y = cos x
x
y
−π 0 π 2π
-2
2
y = tan x
x
y
−π 0 π 2π
-2
2
y = cot x
x
y
−π 0 π 2π
-2
2
y = sec x
x
y
−π 0 π 2π
-2
2
y = csc x
Advanced Mathematics Training Class Notes Chapter 8: Trigonometry
53
The previous page shows the graphs of the six trigonometric functions. In their graphs, we
see that they have repeating patterns. They are then called “periodic functions” (週期函數).
A function f(x) is periodic if and only if, there exists a real constant T > 0 such that:
f(x + T) = f(x) for all real values of x.
The smallest possible value of T is called the “period” (週期) of that function.
For sine, cosine, secant and cosecant, their periods are 2π. For tangent and cotangent, their periods are π.
Sine curve (正弦曲線正弦曲線正弦曲線正弦曲線)
The graph of y = sin(x) is exactly the same as the shape of waves. By this, we will go depth in
this type of curve.
The sine curve can be generalized as sinx d
y a cT
− = +
. In this expression, a is called the
“amplitude” (振幅) of the wave, T is the period, c presents the horizontal translation (橫
移), and d illustrates the vertical translation (縱移).
Note: The reciprocal (倒數) of T, 1/T, is sometimes called “frequency” (頻率)
The following graphs show how these four variables control the outlook of the curve.
x
y
−π 0 π 2π
-2
2
(Green curve: y = sin x. Red curve: y = 2 sin x. Pink curve: 12siny x= − )
x
y
0 π 2π 3π 4π
-1
1
(Blue curve: y = sin x. Green curve:2
sin xy = . Purple curve: y = sin 2x)
x
y
0 π 2π
-1
1
(Blue curve: y = sin x. Green curve: ( )4siny x π= − . Yellow curve: ( )5siny x π= + .)
x
y
0 π 2π
-2
2
(Blue curve: y = sin x. Green curve: y = sin x – 1. Purple curve: 32
siny x= + .)
Advanced Mathematics Training Class Notes Chapter 8: Trigonometry
54
Inverse Trigonometric Functions (反三角函數反三角函數反三角函數反三角函數)
Inverse function (反函數反函數反函數反函數)
For any function f(x), if y = f(x), there is a corresponding “inverse function” F(x) such that
x = F(y).
For example, if f(x) = 5x – 6, then its inverse function is ( ) 6
5
yF y
+= .
An inverse function of f(x) is usually denoted as f-1(x). In the above example,
( )1 6
5
xf x− +
= .
Inverse trigonometric function
Being functions, trigonometric functions also have their inverse functions. They are denoted
as sin-1 x, cos-1 x, etc. However, since trigonometric functions are all periodic, if y = f(x) (f is
a trigonometric function), there are multiple solutions of x. For example, if 12
sin x= , then
5 5 2 7 4 133 6 3 6 3 6 3 6, , , , , , , ,x π π π π π π π π= − − − … . But recall that a function can have one and only one
corresponding value of dependant variable. So we must take only one value out of so many
values. Which should we take? First, we define the principle value intervals (主值區間) of
these inverse functions. 1
2 2
1
1
2 2
sin
0 cos
tan
x
x
x
π π
π π
π
−
−
−
− ≤ ≤
≤ ≤
− < <
As π/6 is the only value inside range –π/2 to π/2, so 1 12 6
sin π− = .
Properties of inverse trigonometric function
By the principle of inverse function, there must be:
( ) ( )
( ) ( )
( ) ( )
1 1
1 1
1 1
sin sin sin sin
cos cos cos cos
tan tan tan tan
x x x x
x x x x
x x x x
− −
− −
− −
= =
= =
= =
Deriving from the relation #3 (Squares relations), we get:
( ) ( )( ) ( )( ) ( )
1 1 2
1 1 2
1 1 2
sin cos cos sin 1
sec tan csc cot 1
tan sec cot csc 1
x x x
x x x
x x x
− −
− −
− −
= = −
= = +
= = −
Or summarizing:
x sin cos tan cot sec csc
sin-1 x 21 x− 21
x
x−
21 x
x
− 2
1
1 x− 1
x
cos-1 21 x− x
21 x
x
− 21
x
x− 1
x
2
1
1 x−
tan-1 21
x
x+
2
1
1 x+ x
1
x 2
1 x+
21 x
x
+
cot-1 2
1
1 x+
21
x
x+ 1
x x
21 x
x
+ 2
1 x+
sec-1 2 1x
x
−
1
x 2
1x − 2
1
1x − x
2 1
x
x −
csc-1 1
x
2 1x
x
− 2
1
1x − 2
1x − 2 1
x
x − x
(The order of reading is first function, then inverse function, then “x”, and finally the cell)
Advanced Mathematics Training Class Notes Chapter 8: Trigonometry
55
General Solutions of Trigonometric Functions (三角函數通解三角函數通解三角函數通解三角函數通解)
We have learnt that if 12
sin x= , there are infinitely many solutions for x. Sometimes we are
told to find all of the solutions of the equation. Of course, we can’t list out that infinitely many solutions. We can use an expression with a free variable to represent it. The expression is called the general solution of a trigonometric function.
If s = sin x, then
( ) ( )
( ) ( )
1
1
1 sin In radian measure
180 1 sin In degree measure
n
n
x n s
x n s
π −
−
= + −
= ° + −
If c = cos x, then
( )( )
1
1
2 cos In radian measure
360 cos In degree measure
x n c
x n c
π −
−
= ±
= ° ±
If t = tan x, then
( )( )
1
1
tan In radian measure
180 tan In degree measure
x n t
x n t
π −
−
= +
= ° +
In the above expressions, n is any integer.
Example: 12
sin x= , then ( )6
1n
x n ππ= + − , where n is any integer.
In addition, if a range 0 < x < 2π (i.e., 0° < x < 360°) is specified, then
( )( )( )
1 1 1
1 1 1
1 1 1
sin or sin 180 sin
cos or 2 cos 360 cos
tan or tan 180 tan
x s s s
x c c c
x t t t
π
π
π
− − −
− − −
− − −
= − ° −
= − ° −
= + ° +
Slope and Trigonometry
Recall the definition of slope of a line:
1 2
1 2
y ym
x x
−=
−
C (x1, y1)
A (x2, 0) θ B (x1, 0)
x
If the second point lies on the x-axis (y2 = 0), the equation is reduced to 1
1 2
ym
x x=
−.
In the figure,
1 2
1
AB x x
BC y
= −
=
Therefore, in ∆ABC,
1
1 2
tanBC y
mAB x x
θ = = =−
That means,
tanm θ=
Where θ is the angle between the line and the x-axis, called the inclination (傾角)
Example: If slope of a line is 1, its inclination is 45°.
Advanced Mathematics Training Class Notes Chapter 8: Trigonometry
56
Angle between two lines
Consider two lines L1 and L2 having slopes m1 and m2 and inclination θ1 and θ2. We are
interested in the angle between them.
φ
L1 L2
θ1 θ2
( )( )
1 2
1 2
1 2
1 2
1 2
1 2
ext. of
tan tan
tan tan
1 tan tan
1
m m
m m
φ θ θ
φ θ θ
θ θθ θ
= − ∠
∴ = −
−=
+
−=
+
∵ △
Where φ is the angle between L1 and L2. Thus we got the formula:
1 2
1 2
tan1
m m
m mφ
−=
+
The absolute sign is there to ensure that an acute angle is selected.
Example: Find the angle between two lines with slope = -2 and 3 respectively.
( )( )2 3
tan1 2 3
1
45
φ
φ
− −=
+ −
=
∴ = °
Revision
In this chapter, we’ve learnt:
1. What are trigonometric functions
2. Definition of general angles
3. Radian measure of angles
4. Basic trigonometric relations
5. Trigonometric functions of some special angles
6. Ranges of trigonometric functions
7. Transformation formulae
8. Compound angle formulae
9. Product-to-sum and sum-to-product formulae, subsidiary angle form
10. Graphs of trigonometric functions
11. Inverse trigonometric functions
12. General solutions of trigonometric functions
13. Relationships between slope and tangent
14. Angle between two lines on coordinates plane
Advanced Mathematics Training Class Notes Chapter 8: Trigonometry
57
Exercise
In the followings, if not specified, x is the variable. Give answer in radians unless otherwise
stated. If general solution is required, use “n” for the free integral variable.
1. Express sin 75° the followings in surd form.
2. Find the general solutions of x in the following equations:
a) sin x + cos x = 1
b) 3 – cos2 x – 3 sin x = 0
c) ( ) ( )123 3
sin 4 cos xx π π −− =
3. Identify the amplitude, period, horizontal and vertical shift of the following sine curve:
x
y
−2π −π 0 π 2π
-2
2
4
4. Given θ = 54°. a) Prove that cos 2θ + sin 3θ = 0. b) Prove the sin 3β = 3 sin β – 4 sin3 β. c) Show that sin 54° is a root of the equation 4x3 + 2x2 – 3x – 1 = 0.
d) Find the exact value of sin 54°.
[Hint: Consider the sign of sin 54°]
5. (HKMO 2000 Heat) How many roots of θ are there in (cos2 θ – 1) (2 cos2 θ – 1) = 0, where 0° < θ < 360°?
6. (HKMO 1998 Heat) The circumference of a circle is 14π cm. Let X cm be the length of
an arc of the circle, which subtends an angle of 1/7 radian at the center. Find X.
7. (HKMO 2002 Heat) Given that A∠ is a right angle in ∆ABC, 2 2 14
sin cosC C− = and
40AB = . Find the length of BC.
8. (PCMSIMC 2001) If sin x° = cos x°, where 0 < x < 360, find the sum of all possible
values of x.
9. (PCMSIMC 2001) Evaluate 89
1
tan
1 tank
k
k=
°+ °∑
10. (HKCEE 1995 Partial) Answer the following questions.
a) Show that cos2 A – cos2 B = sin(A + B) sin(A – B)
b) Show that cos2 x – sin2 y = cos(x + y) cos(x – y)
c) Find the general solutions of 2 2cos 2 cos sin5 sin 3 0x x x x+ − =
11. Prove that (sin x + cos x)2 = 1 + sin 2x
[Note: This identity worth memorizing]
12. Prove that 1
0
2cos 0
n
k
kx
n
π−
=
+ =
∑ .
13. Prove that 1
0
2sin 0
n
k
kx
n
π−
=
+ =
∑
14. If tan a and tan b are roots of x2 + 2x + 3 = 0, find tan (a + b).
15. The vertices of ∆ABC are A (2, -1), B (7, 1) and C (-1, 5). Find tan A + tan B + tan C. 16. (IMO Prelim HK 2003) Find (cos 42° + cos 102° + cos 114° + cos 174°)2.
Advanced Mathematics Training Class Notes Chapter 8: Trigonometry
58
Suggested Solutions for the Exercise
1) 2 6
4
+
2a) 2
2 or 2n nππ π+
b) ( )2
1n
n ππ + −
c) 1 7
4 12n
ππ +
3) a = 3, T = 1/2, c = π/2, d = 1.
4d) 5 1
4
+
5) 5
6) 1
7) 8
8) 270
9) 44.5
10c) 2 5 20
2 or nn π π ππ ± −
14) 1
15) 111/8
16) 3/4