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    Submitted by:

    Gianne Denise C. Dueas

    IV-Vanadium

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    Trigonometry is the study and solution of

    Triangles. Solving a triangle means findingthe value of each of its sides and angles. The

    following terminology and tactics will be

    important in the solving of triangles.

    Pythagorean Theorem (a2+b2=c2). Only for right angle triangles

    Sine (sin), Cosecant (csc or sin-1)

    Cosine (cos), Secant (sec or cos-1)

    Tangent (tan), Cotangent (cot or tan-1)

    Right/Oblique triangle

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    A trigonometric function is a ratio of certain parts of a triangle. The

    names of these ratios are: The sine, cosine, tangent, cosecant, secant,

    cotangent.

    Let us look at this triangle

    a c

    b

    A

    B

    C

    Given the assigned letters to the sides and

    angles, we can determine the following

    trigonometric functions.

    The Cosecant is the inversion of thesine, the secant is the inversion of

    the cosine, the cotangent is the

    inversion of the tangent.

    With this, we can find the sine of the

    value of angleA by dividing side aby side c. In order to find the angle

    itself, we must take the sine of the

    angle and invert it (in other words,

    find the cosecant of the sine of the

    angle).

    Sin=

    Cos =

    Tan =

    Side Opposite

    SideAdjacent

    SideAdjacentSide Opposite

    Hypothenuse

    Hypothenuse

    =

    =

    = a

    b

    ca

    b

    c

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    Try finding the angles of the following triangle from the

    side lengths using the trigonometric ratios from the

    previous slide.

    610

    8

    A

    B

    C

    The first step is to use the trigonometric

    functions on angle A.

    Sin =6/10

    Sin =0.6

    Csc0.6~36.9

    Angle A~36.9

    Because all angles add up to 180,

    B=90-11.537=53.1

    C

    2

    34A

    B

    The measurements have changed. Find side BA and sideAC

    Sin34=2/BA

    0.559=2/BA

    0.559BA=2

    BA=2/0.559

    BA~3.578

    The Pythagorean theorem

    when used in this triangle states

    that

    BC2+AC2=AB2

    AC2=AB2-BC2

    AC2=12.802-4=8.802

    AC=8.8020.5~3

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    When solving oblique triangles, simply using

    trigonometric functions is not enough. You need

    The Law of Sines

    C

    c

    B

    b

    A

    a

    sinsinsin

    !!

    The Law of Cosines

    a2=b2+c2-2bc cosA

    b2=a2+c2-2ac cosB

    c2=a2+b2-2ab cosC

    It is useful to memorize theselaws. They can be used to

    solve any triangle if enough

    measurements are given.

    a

    c

    bA

    B

    C

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    When solving a triangle, you must remember to choose

    the correct law to solve it with.

    Whenever possible, the law of sines should be used.

    Remember that at least one angle measurement must be

    given in order to use the law of sines.

    The law of cosines in much more difficult and time

    consuming method than the law of sines and is harder to

    memorize. This law, however, is the only way to solve a

    triangle in which all sides but no angles are given.

    Only triangles with all sides, an angle and two sides, or a

    side and two angles given can be solved.

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    a=4

    c=6

    b

    A

    B

    C

    28

    Solve this triangle

    Because this triangle has an angle given, we can use the law of sines to solve it.

    a/sinA = b/sin B = c/sin C and subsitute: 4/sin28 = b/sin B = 6/C. Because we know nothing about

    b/sin B, lets start with 4/sin28 and use it to solve 6/sin C.

    Cross-multiply those ratios: 4*sin C = 6*sin 28, divide 4: sin C = (6*sin28)/4.

    6*sin28=2.817. Divide that by four: 0.704. This means that sin C=0.704. Find the Csc of 0.704 .

    Csc0.704 =44.749. Angle C is about 44.749. Angle B is about 180-44.749-28=17.251.

    The last side is b. a/sinA = b/sinB, 4/sin28 = b/sin17.251, 4*sin17.251=sin28*b,

    (4*sin17.251)/sin28=b. b~2.53.

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    a=2.4

    c=5.2

    b=3.5A

    B

    C

    Solve this triangle:Hint: use the law of cosines

    Start with the law of cosines because there are no angles given.

    a2=b2+c2-2bc cosA. Substitute values. 2.42=3.52+5.22-2(3.5)(5.2) cosA,

    5.76-12.25-27.04=-2(3.5)(5.2) cos A, 33.53=36.4cosA, 33.53/36.4=cos A, 0.921=cos A, A=67.07.

    Now forB.

    b2=a2+c2-2ac cosB, (3.5)2=(2.4)2+(5.2)2-2(2.4)(5.2) cosB, 12.25=5.76+27.04-24.96 cos B.

    12.25=5.76+27.04-24.96 cos B, 12.25-5.76-27.04=-24.96 cos B. 20.54/24.96=cos B. 0.823=cos B.

    B=34.61.

    C=180-34.61-67.07=78.32.

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    Trigonometric identities are ratios

    and relationships between certain

    trigonometric functions.

    In the following few slides, you

    will learn about different

    trigonometric identities that take

    place in each trigonometric

    function.

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    What is the sine of 60? 0.866. What is the cosine of30?

    0.866. If you look at the name of cosine, you can actually

    see that it is the cofunction of the sine (co-sine). The

    cotangent is the cofunction of the tangent (co-tangent), andthe cosecant is the cofunction of the secant (co-secant).

    Sine60=Cosine30

    Secant60=Cosecant30

    tangent30=cotangent60

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    Sin =1/csc

    Cos =1/sec

    Tan =1/cot

    Csc =1/sin

    Sec =1/cos

    Tan =1/cot

    The following trigonometric identities are useful to remember.

    (sin )2

    + (cos )2

    =1

    1+(tan )2=(sec )2

    1+(cot )2=(csc )2

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    Degrees and pi radians are two methods of

    showing trigonometric info. To convert

    between them, use the following equation.

    2 radians = 360 degrees

    1 radians= 180 degrees

    Convert 500 degrees into radians.

    2 radians =360 degrees, 1 degree = 1 radians/180,500 degrees = radians/180 * 500

    500 degrees = 25 radians/9

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    Write out the each of the trigonometric functions (sin, cos, and tan) of the followingdegrees to the hundredth place.

    (In degrees mode). Note: you do not have to do all of them

    1. 45

    2. 38

    3. 22

    4. 18

    5. 95

    6. 63

    7. 90

    8. 152

    9. 112

    10. 58

    11. 345

    12. 221

    13. 47

    14. 442

    15. 123

    16. 53

    17. 41

    18. 22

    19. 75

    20. 34

    21. 53

    22. 92

    23. 153

    24. 1000

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    Solve the following right triangles with the dimensions given

    5

    c

    22A

    B

    C

    9 20

    18A

    B

    C

    A

    a

    c

    13

    B

    C

    52

    c

    12

    8 A

    B

    C

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    Solve the following oblique triangles with the dimensions given

    12

    22

    14A

    B

    C

    a

    25

    b

    28

    A

    B

    C

    31

    15

    c

    24

    35 A

    B

    C

    5

    c

    8A

    B

    C

    168

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    1. 45

    2. 38

    3. 22

    4. 18

    5. 95

    6. 63

    7. 90

    8. 152

    9. 112

    10. 58

    11. 345

    12. 221

    13. 47

    14. 442

    15. 123

    16. 53

    17. 41

    18. 22

    19. 75

    20. 34

    21. 53

    22. 92

    23. 153

    24. 1000

    Find each sine, cosecant, secant, and cotangent using different

    trigonometric identities to the hundredth place

    (dont just use a few identities, try all of them.).

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    Convert to radians

    52

    34

    35

    46

    74

    36

    15

    37

    94

    53

    174

    156

    376

    324

    163

    532

    272

    631

    856

    428

    732

    994

    897

    1768

    2000

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    Convert to degrees

    3.2 rad

    3.1 rad

    1.3 rad

    7.4 rad

    6.7 rad

    7.9 rad

    5.4 rad

    9.6 rad

    3.14 rad

    6.48 rad

    8.23 rad

    5.25 rad

    72.45 rad

    93.16 rad

    25.73 rad

    79.23 rad

    52.652 rad

    435.96 rad

    14.995 rad

    745.153 rad

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