tinh toan ve dien trong he thong cung cap dien

7/25/2019 Tinh Toan Ve Dien Trong He Thong Cung Cap Dien

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LL VitVit TinTin

EPSDEPSD, SEE,, SEE, HUSTHUST


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1.1. GiiGii thiuthiu chungchung

ChngChng tata lmlm gg?? XcXc nhnh cccc thngthng ss chch caca hh

thngthng cungcung cpcp inin vv tnhtnh tonton nhnh hnghng nn cccchh thngthng cungcung cpcp inin vv trongtrong thitthit kk..

TnhTnh tonton cici gg??

TnhTnh tonton inin pp titi cccc ntnt vv dngdng cngcng sutsut trntrn tttt cccccc nhnhnhnh caca ss cungcung cpcp inin..

TnhTnh tonton lala chnchn thitthit dindin dydy dndn vv cpcp..

KimKim tratra tntn thttht inin pp,, iuiu chnhchnh inin pp vv bb cngcng sutsutphnphn khngkhng trongtrong lili vv cccc bibi tonton khckhc..

SS thaythay thth hh thngthng vv ngng gigi cccc thngthng ss chch..


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2.2. SS thaythay thth caca liliinin2.1.2.1. SS thaythay ththdydy dndn

ThngThng ss ngng dydy cc trngtrng chocho ququ trnhtrnh vtvt ll xyxy

rara trongtrong dydy dndn khikhi cc inin pp tt lnln hochoc dngdng ininxoayxoay chiuchiu ii qua.qua.

PhtPht nngnng dodo hiuhiu ngng Joule:Joule: inin trtr

DngDng inin XCXC gygy nnnn tt trngtrng tt cmcm caca tngtng dydydndn vv hh cmcm giagia cccc dydy dndn vivi nhaunhau.. inin khngkhng

inin pp caocao pp gygy rara inin trngtrng lnln trntrn bb mtmt dydydndn ((hinhin tngtng ionion haha khngkhng khkh quanhquanh dydy dndn,, hinhintngtng vngvng quangquang)) gygy rara tntn haohao:: inin dndn

inin pp xoayxoay chiuchiu gygy nnnn inin trngtrng giagia cccc dydy dndnvivi nhaunhau vv vivi tt nhnh cccc bnbn tt inin: Dung: Dung dndn..


5/30

2.2. SS thaythay thth caca liliinin2.1.2.1. SS thaythay ththdydy dndn

inin trtr

inin trtr mtmt chiuchiu (():):

F

Rdc =

: in tr sut ca dy dn(.m)

inin trtr thaythay ii theotheo nhitnhit ::

inin trtr xoayxoay chiuchiu:: mtmt dngdng inin phnphn bb khngkhng uu dodohiuhiu ngng bb mtmt,, RxcRxc >> RdcRdc. . tntn ss 50Hz,50Hz, ss khckhc nhaunhau

khngkhng ngng kk (~1%)(~1%) nunu coicoi Rxc~RdcRxc~Rdc

F: Thit din dy dn (m2)

)]t(t[1RR 00t

+=

t0: Nhit thit k(20oC)R0: in tr khi t0(): H s nhit ca in tr


6/30

inin khngkhng

0.779r

Dln102

r

D4ln1

8

L m4m0 =

+

=

00:: HH ss dndn tt caca vtvt liuliu chch toto dydy (4(4.10.10--44H/km)H/km)r:r: BnBn knhknh n oin oi caca dd d nd n mm

0.779r

D

ln0.1213fL2X m

L ==

(H/km)

(/km)

DDmm:: KhongKhong cchcch trungtrung bnhbnh hnhhnh hchc giagia cccc dydy dndn(m)(m)

DDabab,, DDbcbc,, DDacac:: KhongKhong cchcch phapha vivi phapha( )1/3acbcabm DDDD =

r

D

a

b c

r

Dbc

cba

Dab

Dac

DDDm 26.123

==

DDm =


7/30

DungDung dndn

r

D

ln18

10

r

D

ln

2C

m

9

m

0

=

=

0: Khong cch khng gian ( F/m)r: Bn knh n oi ca d d n m

fC2

1Xc

=(F/km) ; (/km)

90 1036

1

=

Dm: Khong cch trung bnh hnh hc gia cc dy dn (GMD) (m)

inin dndn

2

0

n

c

U

P

G

=

Pc0: Sut tn tht vng quang (W/km)

Un: in p nh mc (kV)(1/km)


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9/30

2.2. SS thaythay thth caca liliinin2.1.2.1. SS thaythay ththmymy binbin pp

SS thaythay thth caca mymy binbin pp

TngTng dndn mymy binbin pp (Z(ZTT))

SS thaythay thth

2

2

. rlTU

PR =

r

rI

r

ITT

S

Uu

I

uZX

2%.

==

R X 20

c

PR

=

UX rm =

r

RcXm

ZT= RT+ jXT

S0

r 0

RT, XL: in tr v in khng vng dyRc: in tr do tn tht trong cc cun dy

Xm: in khng do t trngSr , Ur: Dung lng MBA v in pPI, P0: Tn tht c ti v khng tiuI: in p ngn mch (%)

I0: Dng in khng ti (t trng)

rUjIPQjPS 00000 +=+=


10/30

MyMy binbin pp 33 cuncun dydy SS thaythay thth

ZP

S0

ZS1

ZS2 )ZZ(ZZ

)ZZ(ZZ

SPSSSPS

SSSPSPP

22111

2121

12

12

1

+=

+=

TngTng trtr cuncun dydy

SPSSSPS 12122

2

r

rSP

r

rSPSPSPSP

S

%.Uuj

S

.UPjXRZ

2

1

2

2

1111

+=+=

RP-S1, XP-S1: Tng tr cun s cp th cp th 1Sr , Ur: Dung lng MBA v in pPI, uI : Tn tht c ti v in p c ti khi cun s cp v th

cp th 1 kt ni vi h thng. Cun th cp th 2 m.


11/30

3.3. TnTn thtthtinin pp vv cngcng sutsut3.1.3.1. TnTn thtthtinin pp

TnTn thttht inin pp trntrn ngng dydy

)Im()Re().(3 ZIjZIjXRIVVV LS +=+== &&&&

QXPRQXPRXRIZIV +

+

=+= )sincos(3)Re(rL

R, X: Tng tr mt phaVr: in p dy (L-L)V

S: in p ngun (L-L)

VL: in p ph ti (L-L)I: Dng tiP, Q: cng sut ti 3 pha kW v kVar

PL+jQL

R+jX VLVS


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HH ss tntn thttht KKdd:: TnTn thttht inin pp phnphn trmtrm ((V%)V%) trntrn

ngng dydy tnhtnh vivi 1 km1 km ngng dydy vv cpcp chocho titi 33 phapha 11 kVAkVA..

)sincos(100

1002

XRV

Kd +

=

%

KKdd TraTra cucu trongtrong ss taytay tratra cucu ((hh ss cngcng sutsut).).rr

m.

TnTn thttht inin pp trntrn ngng dydy ii vivi ngng dydynhiunhiu phph titi

( )=

+=n

i

iiii

r

XQRPV

V1

1 RiXi: Tng tr trn on ng dyth iVr: in p (L-L)Pi, Qi: Cng sut tc dng kW v phn

khng kVar chy trn onng dy th i.


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TnTn thttht inin pp ii vivi ngng dydy cc phph titi phnphn bbuuXc nh tn tht in p do cngsut tc dng gy trn on ngdy dx ti chiu di ng dy x

l

xdx

Ngun

L / 2 L / 2

P = P0.l

rr

xxPx

VdxrxP

VdRPVd .... 00==

rr

l

r

PVRP

VlrP

VdxxrPV

.2.

.2.....

2

00

0

00 ===

Tng tn tht in p do cng sut tc dng

Tng t,

r

Q

V

XQV

.2

.=

r

QPV

XQRPVVV

.2

.. +=+=


14/30

TngTng thttht cngcng sutsut trntrn ngng dydy

RV

SRIP LL

=

2

2

33..3

PL+jQL

R+jX VLVS TnTn thttht cngcng sutsut tctc dngdng::

3.3. TnTn thtthtinin pp vv cngcng sutsut3.1.3.1. TnTn thttht cngcng sutsut vvinin nngnng

XV

QPQ

r

LL

+=

2

22

R, X: Tng tr 1 phaVr: in p dyVS: in p ngun

VL: in p tiIL: Dng in tiP, Q: Cng sut tc dung v

phn khng ca ph ti 3pha

RV

QPR

V

S

r

LL

L

L

+=

2

22

2

2

TnTn thttht cngcng sutsut phnphn khngkhng


15/30


TnTn thttht cngcng sutsut caca ngng dydy cc phph titi phnphn bbuu

MtMt phph titi II00(A/m),(A/m), chiuchiu didi l (m)l (m)

TnTn thttht cngcng sutsut trntrn vivi phnphn dxdx caca ngng dydy22

== xx

TnTn thttht trntrn tonton tuyntuyn::

RIlrIdxxrIP

l

.......3 23

0

2

0

0

2

0

2

0 ===


16/30

PhnPhn bb titi trntrn lili

DngDng inin (( )) vv tngtng trtr ((Z=z0.l))

PhnPhn bb hnhhnh chch nhtnht ::

Ti phn b ti v tr 1/3 chiu

=

2

3

13 TIZP

r

T.V3

D.l.wI =

di ng dy PhnPhn bb hnhhnh tamtam gicgic ::

Ti phn b ti v tr 8/15 trongkhong cch t nh n dy catam gic.

=

2

15

83 TIZP


17/30

TnTn thttht cngcng sutsut trongtrong mymy binbin pp

TnTn thttht cngcng sutsut tctc dngdng vv phnphn khngkhng

IPS

PnP

+=

2

max0

1


r

r

IT

S

Su

n

SInQ

100

%1

100

% 2max0 +

=

Sr : Dung lng my bin p

Smax: Cng sut ti cc i ca trm bin p.PI, P0: Tn tht ngn mch v khng tiuI: in p ngn mch (in %)I0: Dng in khng ti (%)n: S my bin p trong trm (lm vic song song)


18/30

TnhTnh tonton tntn thttht inin nngnng

nhnh nghangha ((A)A) ::

=T

dttPA )( P(t) :Tn tht cng sut ca li in

T: Khong thi gian trn th ph ti


0

TnTn thttht inin nngnng::

= maxPA Pmax: Tn tht cng sut cc i

: Thi gian tn tht cng sut ln nht


19/30

TnhTnh thithi giangian tntn thttht cngcng sutsut lnln nhtnht (())

SS dngdng biubiu phph titi cccc ii TTmmQuanQuan hh giagia vv TTmm


.=m

==T

m dttPPP

AT

0maxmax

)(1

1 : th ph ti h thng2 : vng giao gia Pmaxv Tm

Tm: Tra trong s tay thit k.


20/30

TTP

A

P

PF avS

=

=

=

maxmax

Pav: Tn tht cng suttrung bnh

SS dngdng hh ss tntn thttht (Fs)(Fs)


TFS= TnhTnh hh ss tntn thttht cngcng sutsut (Fs)(Fs)

QuanQuan hh giagia FFSSvv FFLL

2)1( LLS FcFcF += FL: H s ph tic = 0.2 (Anh v c)c = 0.3 (M, th)c = 0.16 (M, nng nghip)

FL: Tra trong s tay thit k.


21/30

TnTn thttht inin nngnng caca ngng dydy

= .maxPA Pmax: Tn tht cng sut cc i: Thi gian tn tht cng sutln nht


TFP s..max=

nn thttht inin nngnng trongtrong trmtrm binbin ppTFP

S

S

nPnP

S

S

nTPnA sI

r

I

r

+=

+= ...

1....

1..

2

max0

2

max0

Sr : Cng sut ca my bin pSmax: Cng sut cc i ca trm.PI, P0:Tn tht c ti v khng tin : S lng my bin p trong trm (lm vic song song)

T : Thi gian ng in my bin p (1 nm: 8760h)


22/30

V d 2. Xt trm bin p trung gian c 2 my bin p vi cc thng s

SmB = 10MVA, cp in p 132/11kV. Tn tht khng ti 18kW v cti 60kW, in p ngn mch % l 10.5%, dng in khng ti % l0.9%. Xc nh tn tht cng sut v tn tht in nng ca trm binp vi ph ti 12+j7.2MVA, Tm=5000h/nm.

p n: My bin p lm vic song song

)(75.946010

2.712

2

1182..

1.

2

222

max0 kWP

S

S

nPnP I

r

=

++=

+=

)(1208 kVAr=

34116010

2.712

2

18760182...

1..

2

222

max0

++=

+= I

r

PS

S

nTPnA

)(34118760)105000124.0(8760)10124.0( 2424

hTm =+=+=

x

)(5083854 kWh=

10.10010)2.712(5.10

21

10010109.02

.100%1

100%.

32232

max0 +

+

=+=r

IT

S.Su.

n.SInQ


23/30

cc imim lili inin hh LiLi inin cc mtmt ngunngun cpcp,,

SS cc dngdng hnhhnh tiatia,, linlin thngthng ((phnphn nhnhnhnh)) hochoc hnhnhphp..

SS liuliu banban uu

4.4. TnhTnh tonton dngdng cngcng sutsut4.1.4.1. ThitThit lplp bibi tonton

SS lili inin,, CcCc thngthng ss caca ngng dydy vv mymy binbin pp,, inin pp ngunngun UoUo CngCng sutsut cccc ntnt phph titi..

NhimNhim vv tnhtnh tonton DngDng inin vv cngcng sutsut chychy trntrn cccc nhnhnhnh TnTn thttht cngcng sutsut trntrn cccc nhnhnhnh

TnTn thttht inin pp cccc nhnhnhnh vv inin pp cccc ntnt trntrn lili..


24/30

TnhTnh tonton lili inin khngkhng xtxt nn tngtng dndn ngng dydy ((lili phnphnphiphi inin))

CcCc gigi thitthit tnhtnh tonton:: SS thaythay thth chch xtxt thnhthnh phnphn inin trtr vv inin khngkhng ngng

dydy ((ngng dydy trntrn khngkhng trungtrung vv hh pp U


25/30

V d 3.

S thay th Dng cng sut trn cc nhnh:

V0

S1.

S2.

S5.

S6.

S7. S3.

S4.

10 2

3

4

5

6

7

323 SS && = 424 SS

&& =

4322422212 SSSSSSS &&&&&&& ++=++=656 SS

&& =757 SS

&& =

7655756515 SSSSSSS &&&&&&& ++=++=

&&&&&&&&&&&76543211512101

Tn tht cng sut v in p trn cc on ng dy:

( ) ( )ijij2r

2ij

2ij

ijij2r

2ij

ijijij j.XR.U

QPj.XR.

U

SQj.PS +

+=+=+=&

r

ijijijijij

U

.XQ.RPU

+=

in p nt:ijij UUU =


26/30

TnhTnh tonton lili inin hh cc xtxt nn dungdung dndn ngng dydy

CcCc gigi thitthit tnhtnh tonton:: SS thaythay thth cc xtxt thnhthnh phnphn inin trtr,, inin khngkhng vv

dungdung dndn ((ngng dydy trntrn khngkhng U=U=110kV110kV vv cpcp U=22U=22--36kV36kV

4.4. TnhTnh tonton dngdng cngcng sutsut

4.2.4.2. PhngPhng phpphp gngnngng

KhiKhi xcxc nhnh phnphn bb dngdng cngcng sutsut,, coicoi inin pp cccc ntntbngbng inin pp nhnh mcmc caca lili inin..

TrnhTrnh tt tnhtnh tonton:: TnhTnh phnphn bb cngcng sutsut trntrn cccc nhnhnhnh XcXc nhnh tntn thttht inin pp vv inin pp titi cccc ntnt..


27/30

V d 4.

S thay th Dng cng sut v tn tht

trn cc nhnh

i j

2

Qj ij

i

S& ijS& '

ijS&

jS&

2

Qj ij

ijS&

ijZ

2QjSS ijj

'ij =

&& 2

rijij .UBQ =

ij'ijij SSS &&& += )j.X.(R

QP)j.X.(R

)S(S ii

2ij

2ij

ii

2'ij

i ++

=+=

&&

;

;rr

2QjSS ijiji = &&

Tn tht in p trn cc nhnh v in p ti cc nt

0

01010101

0

0101010101U

.RQ.XPjU

.XQ.RPU

+

+

=&

0101 UUU &&& =

i

ijijijij

i

ijijijij

ijU

.RQ.XPj

U

.XQ.RPU

+

+=&

ijij UUU &&& =


28/30

TnhTnh tonton vv inin trongtrong lili inin knkn nn gingin



0.ZI.ZI.ZI 020212120101 =+ &&&

0101 SS

& 02S

& 12S

&

Dng cng sut trn cc nhnh

p dng lut Kirchhoff xc nh in p:

0

1 2

1S&

2S&

01S&

02S&

12S&

r0

01

U3U3 =

0.ZS.ZS.ZS 020212120101 =+

r

02

U3

r

12

U3

0 1 2 001S& 02S&12S&

1S

&

2S&

rong ; ;

(1)


29/30

0SSS 11201 = &&&

0SSS 21202 =+ &&&

Tnh dngin theo Kirchhoff ti nt ph ti 1 v 2



(2)

(3)

021201

0220212101

ZZZ

ZS)ZZ(SS

++

++=

&&&

021201

0111201202

ZZZ

ZS)ZZ(SS

++

++=

&&&

20210112 SSSSS &&&&& +==

T (1), (2) v (3), ta c

;


30/30

tinh toan ve dien trong he thong cung cap dien

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