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Aptitude (http://mrunal.org/category/aptitude) / 3 years Ago /54 Comments (http://mrunal.org/2012/11/speed-time-work-two-men-can-finish-work-3x-efficient-b-b-leaves-completion-variety-cases.html#comments)

1. Case: A & B work start together but B leaves2. Case: A started work, B joined after 4 days, how days work lasted?3. Case: A starts, B joins, How long did B work?4. Case: A and B start together but A leaves5. Case: Efficiency given: A is thrice good than B

Case: A & B work start together but B leaves

Q.Kalmadi can build a stadium in 14 days, while Raja can do the same in 21 days. They startedworking together.

Case #1: 3 days before the completion of work, Kalmadi was sent to Tihad jail. So find outTotal Number of days to complete the work?Case #2: Same question but Raja goes to jail.

Step 1: Draw the STD Table

Whether it is Pipes and Cistern problem or it is Time and Work problem, draw the STD table,fill up the values

Kalmadi Raja Kalmadi + Raja

Speed

Time 14 21

Distance

[Speed Time Work] Two Men can nish a work, A is 3x more ecientthan B, B leaves before completion & variety of cases

English: SP Bakshi(http://www.flipkart.com/objective-general-

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Step 2: Take LCM, update Table

Now well take the LCM of 14, 21

14=27

21=37

LCM (14,21)= 2x3x7=42

Lets just visualize this stadium has just 42 seats. And these fine gentlemen have to place theseats, and drill the bolts.So 42 seats is the Total work to be done or Total Distance to be covered.

Fill up the table


Speed

Time 14 21

Distance 42 42

Now the speed of Kalmadi

Sx T= D

S x 14=42 ; because we know Kalmadi takes 14 days to finish this work

Speed of Kalmadi= 42/14= 3 seats a day

Same way Raja can fit 2 seats a day (because 21 x 2 = 42)

Update the Table


Speed 3 2

Time 14 21

Distance 42 42

Step 3: Kalmadi + Raja Together?

What if Kalmadi + Raja work together? Obviously their speed will increase.

Now they can fit 3+2 = 5 seats per day.


Speed 3 2 3+2=5

Time 14 21 ??

Distance 42 42 ??

BUT we dont know for how many days did they work together?

So we cannot find how many seats they fixed. (STD formula requires two known values!)

So leave the (Kalmadi+Raja) column and move ahead.

Step 4: Kamadi goes to Jail, Raja Works Alone

We are given that 3 days before the completion of work, Kalmadi was sent to Tihad jail.

It means for the last three days, Raja worked alone, right ?

So, Expand the table, create one more column for Raja Alone

Kalmadi Raja Kalmadi + Raja Raja alone

Speed 3 2 3+2=5 2

Time 14 21 ?? 3

Distance 42 42 ?? 6

So, how many seats did Raja fix in last three days?

Speed x time = distance

2 x 3 = 6. ; Because Rajas speed Is 2 and he works for 3 days.

Step 5: Remaining seats

We know that total seats= 42, and Raja fixed 6.

Meaning 42 minus 6 = 36 seats were fixed by Kalmadi +Raja together.

Plug the value back in the Table


Speed 3 2 3+2=5 2

Time 14 21 ?? 3

Distance 42 42 36 6

Again STD formula to find how many days did they work together ?

Speed (Kalmadi + Raja) x Time = Distance

5 x Time = 36

Time = 36/5=7.2

Thus, our final table looks like this


Speed 3 2 3+2=5 2

Time 14 21 7.2 3

Distance 42 42 36 6

Were about to solve the problem now.

What is the Total time taken by these two fine gentlemen of impeccable integrity, to build thisstadium?

Look at the finished table.

7.2 days they worked together

Plus 3 days Raja worked alone.

=7.2+3=10.2 days.

Final answer= 10.2 days

Similarly you do for case#2 when Raja is sent to Jail, 3 days before the completion of work.

Case: A started work, B joined after 4 days, how days work lasted?

Abdul and Bhide can do a piece of work in 20 days and 12 days respectively. Abdul startedthe work alone and then after 4 days Bhide joined him till the completion of the work.How long did the work last?

Step1: Create STD table

Abdul Bhide

Speed

x Time 20 12

= distance

Step2: Take LCM of time

LCM (20,12)

in other words, which is the first number that comes in multiplication table of both 12 and 20?

Well, we know that

12 x 5 =60 and

20 x 3 = 60

Therefore, 60 is the least common multiple of (12, 20)

Assume total distance = 60

Update table

Abdul Bhide

Speed

Time 20 12

distance 60 60

Step3: Take ratio of speed

now we know that total distance is 60. and if Abdul took 20 minutes to finish, what is his speed?


Speed x 20 = 60

Therefore, Abduls speed is 3; similarly Bhides speed is 5.

Update the table.

Abdul Bhide

Speed 3 5

x Time 20 12

= distance 60 60

in the exam, just do it in your head. you took LCM so youd already know that 203=60 and125=60 so automatically 3:5 is the ratio

Step 4: start the work

Given: Abdul started the work alone and then after 4 days Bhide joined him till the completionof the work

Means, for the first four days, Abdul worked alone.

Abdul Bhide Abdul started

Speed 3 5 3

Time 20 12 4

distance 60 60 34=12

In 4 days, he covered 12 kms.

So remaining work = 60 minus 12 =48.

Which was completed by X+Y

Abdul Bhide Abdul started Abdul + Bhide

Speed 3 5 3 3+5=8

Time 20 12 4 ??

distance 60 60 34=12 48

Run std on last column


8 x time = 48

Time =48/ 8 =6 days

Final table looks like this

Abdul Bhide Abdul started Abdul + Bhide

Speed 3 5 3 3+5=8

Time 20 12 4 6

distance 60 60 34=12 48

Question: How long did the work last?

X started and X+Y finished.

Look at the time cells of their respective columns. (i.e. last column and second last column)

Total time= 4 + 6=10 days.

Final Answer: work lasted for 10 days.

Case: A starts, B joins, How long did B work?

Q. Abdul & Bhide can do a job alone in 10 days and 12 days respectively. Abdul starts thework & after 6 days Bhide also joins to finish the work together. For how many daysBhide actually worked on the job ?

Take LCM of (10,12)=60

After 6 days, Bhide also joins. That means for the first 6 days, Abdul worked alone.

Fill up the table.

Abdul Bhide Abdul starts Abdul+Bhide

Speed 6 5 6 (6+5)=11

Time 10 12 6 days ??

Distance 60 36 (60-36)=24

In the first 6 days, Abdul finished 6 x 6 = 36 kilometers. Hence remaining work= 60 minus 36= 24

This 24 kilometers were done by Abdul+Bhide together. (last column)

Run the STD on last column


11 x Time =24

Time =24/11= approx. 2.18

Final answer: Bhide worked for 2.18 days.

Case: A and B start together but A leaves

Abdul and Bhide can do a job in 15 days & 10 days respectively. They began the work togetherbut Abdul leaves after some days and Bhide finishes the remaining job in 5 days. After howmany days did p leave?

Take LCM of (15, 10)=30 and fill up the table

Abdul Bhide A+B work together only Bhide

Speed 2 3 3+2=5 3

xTime 15 10 ?? 5

Distance 30 ?? 15

According to last column, Bhide covered 3x 5= 15 kilmeteres out of total 30 km.

Hence the remaining 30 minus 15 = 15 kilometers were covered by A+B together

their combined speed is (3+2)= 5.

Run the STD formula on (A+B) column

5 x time = 15

Time = 15/5=3

Means P+Q worked together for 3 days. And then P left.

Final answer: P left after 3 days.

Case: Eciency given: A is thrice good than B

Q. Abdul is thrice as good as workman as Bhide and therefore is able to finish a job in 60days less than Bhide. Working together, they can do it in how many days?

Abdul is thrice as good means if speed of Bhide is b, then

Speed of Abdul = 3b

Given: Abdul can finish job in 60 days less than Bhide

Means if B can do work in t days, then A can do it in t-60 days

Fill up the table

A B

Speed 3b b

Time (t-60) t

distance

The distance covered in each column is same, therefore

(Speed x time)As column = (speed x time) Bs column

3b x (t-60)=b x t

3(t-60)=t

t=90

Update the table with this value of t

A B

Speed 3b b

Time 90-60=30 90

distance

In Bs column apply STD formula so you get

b x 90 =90b that is our total distance.

When A+B work together, theyve to cover the same distance (90b)

A B A+B

Speed 3b b 3b+b=4b

Time 90-60=30 90 ??

distance b x 90=90b 90b

Apply STD in last column

4b x time =90b

Time =22.5 days

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R E P L Y ( / 2 0 1 2 / 1 1 / S P E E D - T I M E - W O R K - T W O - M E N - C A N - F I N I S H - W O R K - 3 X - E F F I C I E N T - B - B - L E A V E S -C O M P L E T I O N - V A R I E T Y - C A S E S . H T M L ? R E P L Y T O C O M = 2 0 4 8 9 5 # R E S P O N D )

SHOURABH JOSHIThank you so much for ur constructive support and all ur efforts


ashishI think answer to 1st case,1 subquestion I.e Kalamadi left the work 3daysbefore should be..12.9 days.Check and correct me , if I m wrong

R E P L Y ( / 2 0 1 2 / 1 1 / S P E E D - T I M E - W O R K - T W O - M E N - C A N - F I N I S H - W O R K - 3 X - E F F I C I E N T - B - B -L E A V E S - C O M P L E T I O N - V A R I E T Y - C A S E S . H T M L ? R E P L Y T O C O M = 2 0 4 9 5 2 # R E S P O N D )

Akhil@Ashish, you have mis-read the question, like I did in first attemptand ended up with the same answer. You must have calculatedtotal time as 42/5 and substracted 3 from that. There is theproblem, the time is given considering he already left 3 daysbefore. So equation would be like this,[(t-3)/14]+[t/21] = 1t = 10.2


Basistthe answer (10.2) is correct.If raja goes to jail, the answer would be 9.6 days


Rajesh

Question 1 can also be interpreted in this manner that they weresupposed to finish the work together in three days, but one was requiredto go to jail three days before project completion?


ArunA does half as much work as B in three fourth of the time. IF togetherthey take 18 days to complete the work, how much time shall B take todo it?


anand kumartime 2.18 of q 3 is of both not only of bhind


sunny kumarkindly help with below question-my answer- 48.actual answer-24

twenty four men can complete a work in 16 days.thirty two women can complete the same work in 24 days.sixteen men & sixteen women started working and worked for twelvedayshow many more men are to be added to complete the remaining work in2 days?

thanks.


Ronit will be better if u could also write ur procedure of solving this Q.Nevertheless,I think u made mistake by not subtracting 48(men reqto complete work in 4 days)-24(men already present)=24(men req).hope this will help

R E P L Y ( / 2 0 1 2 / 1 1 / S P E E D - T I M E - W O R K - T W O - M E N - C A N - F I N I S H - W O R K - 3 X - E F F I C I E N T -B - B - L E A V E S - C O M P L E T I O N - V A R I E T Y - C A S E S . H T M L ?R E P L Y T O C O M = 2 4 7 3 4 0 # R E S P O N D )

sunny kumar24M*16=32W*24M=2WSo 16*2W+16W = 48(Total work)w= 1m=2now no work left to be done as m again getting 48.please help

R E P L Y ( / 2 0 1 2 / 1 1 / S P E E D - T I M E - W O R K - T W O - M E N - C A N - F I N I S H - W O R K - 3 X -E F F I C I E N T - B - B - L E A V E S - C O M P L E T I O N - V A R I E T Y - C A S E S . H T M L ?R E P L Y T O C O M = 3 2 6 4 2 7 # R E S P O N D )

divyaM=2W16M+16W=24Mwe already know 24M can complete work in 16 days24M work for only for 12days and remaining needs to

be completed by additional men + existing men tocomplete in 2 days24Mx4=nx2n=48(this is existing men of 24 + additional men)


Lakhan JadejaA B C together do work in 10 days. B C together work thrice as much as Aand A and B together work four time as much as C in what time thay cando each other ?sir i follow your method to solve time work quesiton but in this methodhow to put your method plz guide me


AJHow to solve this one with STD approach:A pump can fill a tank with water in 2 hours. Because of a leak, it took 2hours to fill the tank. The leak can drain all the water of the tank in:


AJHow to solve this one also with STD approach:A tank is filled by three pipes with uniform flow. The first two pipesoperating simultaneously fill the tank in the same time duringwhich the tank is filled by the third pipe alone. The second pipe fillsthe tank 5 hours faster than the first pipe and 4 hours slower than

the third pipe. The time required by the first pipe is:A. 6 hours B. 10 hoursC. 15 hours D. 30 hours


AJHow to solve this one with STD approach:A pump can fill a tank with water in 2 hours. Because of a leak, it took(7/3) hours to fill the tank. The leak can drain all the water of the tank in:


AJHow to solve this one also with STD approach:A tank is filled by three pipes with uniform flow. The first two pipesoperating simultaneously fill the tank in the same time during which thetank is filled by the third pipe alone. The second pipe fills the tank 5hours faster than the first pipe and 4 hours slower than the third pipe.The time required by the first pipe is:A. 6 hours B. 10 hoursC. 15 hours D. 30 hours


AryaI would like to ask one question, for which i am not able to get thesolution from above cases. Please help me in solving the question.

Ques: Two workers A and B working together completed a job in 5 days.If A worked twice as efficiently as he actually did and B worked 1/3 asefficiently as he actually did, the work would have been completed in 3days. To complete the job alone A would require how many days?

Reply ASAP.


AanyaSuppose A alone can do the work in a days.Suppose B alone can do the work in b days.

By First statement - 1/a + 1/b = 1/5

Second statement A works twice as efficiently as he did means ifearlier he was taking a days now he will take only a/2 days.Similarly B will take 3b days .Thus,2/a + 1/(3b) = 1/3

Solve above two to get value of a.


AanyaSuppose A alone can do the work in a days.Suppose B alone can do the work in b days.

By First statement - 1/a + 1/b = 1/5

Second statement A works twice as efficiently as he did means ifearlier he was taking a days now he will take only a/2 days.Similarly B will take 3b days .Thus,2/a + 1/(3b) = 1/3

Solve above two to get value of a.


PreetiThanks Mrunal


Sajal Sinhaperson A can do a job in x daysperson B can do a job in y dayspart of job done by person A alone in one day is 1/x th partpart of job done by person B alone in one day is 1/y th partpart of job done by A and B together in one day is 1/x + 1/y th partSo total days required to do the job is 1/(1/x +1/y) { Suppose I can do1/5th part of job in one day so I will need 1/(1/5) days i.e 5 days tocomplete the job}This is the only theory there are no other rules or tricksThe origin to this theory is that you cannot add inversely proportionalrelations


sneha

snehamukul and vipin together do a work in 6 days. if mukul does 1/5 part ofthe work in 2 days, in how many days will vipin alone do the remainingwork ?


RaviMukul does 1/5 work in 2days therefore in one day he can do 1/10work. So he alone can complete work in 10 days

Vipin and mukul together= 1/6

Vipin alone= 1/6 1/10 = 1/15So vipin alone can do in 15 days.

But 1/5 work has already been done by Mukul so the remainingwork is 4/5

Vipin does 1 work in 15 days.He can do 4/5 work in 15X4/5 days = 12 days


Abhay12??Total combined efficiency= 100/6= 16.67Mukul can do 100 percent wrk in = 5*2=10Mukul efficiency= 100/10=10therefore Vipin efficiency= 16.67-10= 6.67

Work left=4/5=80%therefore numberbof days for vipin to complete= 80/6.67= 12days??


Praveenms 1day work= 1/10(m+v)s 1day work=1/6vs 1day work= 1/6-1/10 = 4/60v takes to complete the work alone= 60/4=15 days.

hope im clear


ASHISHi think 7 days


sunny kumarThe shape of a garden is rectangular in the middle and semi circularat the both ends . Find the area and the perimeterof this garden.total length of garden- 20 mbredth of garden- 7 m

i got the area right( 91+38.5)but not getting perimeter.my answer- perimeter of rectangl portion=40 & perimtr of circle=22, so intotal =62but answer is 48kindly help with thisthanks


AanyaYou are getting the area right so you are clear that garden is arectangle of 7*13 and 2 semi circles of radius 3.5 . These semicircles are adjacent to the sides of length 7.

Now perimeter 13*2 (free sides) + 2*22/7*3.5 (2*22/7*r) = 48


sunny kumar24M*16=32W*24M=2WSo 16*2W+16W = 48(Total work)w= 1m=2now no work left to be done as m again getting 48.please help


kiran

kiransunny complete que liko plz y tnw ka


sunny kumargot it.i was double counting the perimeter.thanks!


niharikapermiter of the garden is 76m


sunny kumar1 more for you-

kindly help with below question-my answer- 48.actual answer-24

twenty four men can complete a work in 16 days.thirty two women can complete the same work in 24 days.sixteen men & sixteen women started working and worked for twelvedayshow many more men are to be added to complete the remaining work in2 days?

thanks.


Anurag16x24M=32x24W => M=2W .Now the total work is 16x24M .16M+16W = 24M work completed 24x12M remaining 24x4M means96M work still remaining , 24M can do 24M work per day,means they willcomplete 48M work,remaining is 48M it needs 24 more Men or 48 morewomen.


shivangican any1 plzz help me with this ques?20 women can finish a job in 20 days.after each day, a woman is replacedby a man and a man is twice as efficient as a woman.on which day doesthe job get completed?ans is 18th day.


rahulIn question, 20 women can finish a job in 20 days. assume everywomen has 2 units then total unit of work is 20*2*20=800 unit(20women has 2 unit each and work for 20 days).Second term of question, After each day a women is replaced by aman and a man is twice as efficient as a women,hence, man unit is 4 (because it is twice as efficient as a women)

so a woman does 2 units of work in a day and man does 4 units ofwork in a day

starting with 20 women initially

day 140 units completedday 238 + 4 = 42 units (1 women replace by 1 men)day 3 ..36 + 8 = 44 units (2 women replace by 2 men)day 4 ..34 +12 = 46 units(3 women replace by 3) men) etc.. etc

now we have to find in how many days this will add to 800 uniteasy way to do this,adding each dayday1+day2+day3+day4..=800 unit.

in 15 days total work done = 810 unit.

so work gets over on the 15th day

Answer is 15th days not 14th day


shivangisorry typeing errroranswer to above question is 14th day..


samikssha

A can do a piece of work in 36 days, B in 54 days and C in 72 days. All thethree began the work together but A left 8 days and B 12 days before thecompletion of the work. How many days in all did C put in till the entirework was finished?pls solve it in STD method


rahulin last question why a and b work together for 90 days,in rest of thequestions its not like that


AbhishekTwo pipes L and M can fill a tank in 15 and 12 h respectively and a 3rdpipe N can empty it in 4 h. If the pipes are opened at 8 am 10 am and 11am respectively find the time the tank will be emptied.


Santhe answer is 16.50.


muralithanku mrunal sir


mrunal fanBhai thanksItna bhadiya concept samjhane k liye


Anas MMrunal Bhai, I am expert in Time and Work type question. all because ofyou.Thank you so much.


Sai DattaMrunal sir.. Im deaf man. I understand your explanation clearly. Now Ivesome doubts. Please clear my doubts before having bank exam nextweek.

Here some questions :

1) A and B can do a piece of work in 30 days, while B and C can do thesame work in 24 days and C and A in 20 days. They all work together for10 days when B and C leave. How many days more will A take to finishthe work?

2) 4 men can complete a piece of work in 2 days. 4 women can completethe same piece of work in 4 dayswhereas 5 children can complete the same piece of work in 4 days. If 2men, 4 women and 10 childrenwork together, in how many days can the work be completed?


Parul10 men and 15 women can finish a work in 6 days. One man can alonefinish a work in 100 days. In how many days will a woman finish the work?sir how will it be solved by Std table?


RashiCan someone solve this question with the above mentioned technique:Two pipes A and B can fill a tank in 24mins and 32 mins. If both pipes areopened together,after how much time B should be closed so that tank isfull in 18 mins. [Ans. 8mins]


deepak(18/24)+(x/32)=1


vipin

vipinits very easy. speed of a comes out to be 4 . speed of b= 3 . totaldistance or time = 96. a+b = 7 . now take time of a+b = x and aalone to be 18 x . now the equation will be 7x + 4 ( 18 x ) = 96 .solve it and you will get the value of x = 8 min .

R E P L Y ( / 2 0 1 2 / 1 1 / S P E E D - T I M E - W O R K - T W O - M E N - C A N - F I N I S H - W O R K - 3 X - E F F I C I E N T -B - B - L E A V E S - C O M P L E T I O N - V A R I E T Y - C A S E S . H T M L ?R E P L Y T O C O M = 3 2 8 7 8 2 # R E S P O N D )

vipintotal distance =96 and not time


rakeshFOR MPPSC ADMIT CARD PLEASE GO TO APPLY ONLINE LINK CLICKSTATE SERVICES EXAM 2014 AMD DWLD ADMIT CARD


SANTHOSH S KSir, how to solve using STD table A can do a work in 15 days and B in 20days. If they work on it together for 4 days, then the fraction of the workthat is left is?


siddharth

Write your message!

please tell me ho to solve by std approacha and b can do a job in 16 and 12 days respectively 4 days beforecompletion of job a joins b find out how many days b has worked alone ifb has started work alone ???????a 6b 4c5d7


tejaswiA can do a piece of work in 80 days.he works at it for 10days and then Balone finishes the remaining work in 42 days .in how much time will Aand B working together , finish the work????

pls solve this using STD method ..

ANS: 30 DAYS

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VIMAL { product of two number is 600.Lcm of thease number 10.What is the HCF of those two number? } [Aptitude] LCM, HCF, GCD: Basic concept, calculation, applications explained(http://mrunal.org/2013/03/aptitude-lcm-hcf-gcd-basic-concept-calculation-applications-explained.html/comment-page-2#comment-340559)

HARSHADNARKAR { What is your Message? Search before asking questions & confine discussions to exams related matter only. sir,history lectures kab honge. } [Economy Lecture]GS2: UNFCCC Lima Summit, Paris Summit Post-2020... (http://mrunal.org/2015/06/economy-lecture-paris-summit-post-2020-climate-finance-framework.html/comment-page-1#comment-340552)

JOHNSSWARGIARY { ist true that double the money plz ans me } [Financial Inclusion]Kisan Vikas Patra (KVP): Features, Money Laundering,... (http://mrunal.org/2014/12/kisan-vikas-patra-kvp-features-money-laundering-black-money-tax-benefit.html/comment-page-1#comment-340548)

NAVEEN { Prateek even i got.....291 marks.....what about the reserved list??? Whts the procedure?? } [CAPF-2014] Final result out, 105 selected, marksheets in 15...(http://mrunal.org/2015/02/upsc-capf-2014-final-result-marksheet.html/comment-page-2#comment-340545)

VacanciesEntire List shifted to bottom. Scroll down

(http://www.alexa.com/siteinfo/mrunal.org)

Mega Jobs

23-Jul: IBPS Rural PO & Asst. (http://ibps.in/html/cwe_rrb.htm)

17-Aug: IGNOU PG Admission (https://onlineadmission.ignou.ac.in/Login.aspx)

17-Jul: NDA Officers (http://upsconline.nic.in/mainmenu2.php)

13-Jul: SSC 10+2 (http://www.ssconline.nic.in/)

09-Jul: APFC Provident Fund Comm.

(http://www.upsc.gov.in/recruitment/advt/2015/Spl.Advt.52-15%20Web%20Cell.pdf)

09-Jul: Punjab Corp Engineer (http://202.164.52.147/serv1/docs/dysecyrect121017527.pdf)

09-Jul: Punjab Corp Clerks (http://202.164.52.147/serv1/docs/dysecyrect121017527.pdf)

07-Jul: RBI Assistants (504) (https://opportunities.rbi.org.in/Scripts/bs_viewcontent.aspx?

Id=3024#AN)

02-Jul: FCI MT (1Lakh Bond,3yr) (https://fcijobsportal.com/fcimt2015/pages/index.aspx)

01-Jul: Haryana Health Services (http://haryanahealth.nic.in/)

30-Jun: LIC ADO (25k Bond,4yr) (http://www.licindia.in/careers_pop0022.htm)

24-Jun: Haryana Gramin Bank Assiatant (http://www.shgb.co.in/RecruitmentsandPromotions)

24-Jun: IDBI Manipal Banking Admission (http://www.idbi.com/idbi-bank-careers-current-

openings.asp)

Rural Banks

23-Jul: IBPS Rural PO & Asst. (http://ibps.in/html/cwe_rrb.htm)

25-Jun: Odisha Gramya (http://www.odishabank.in/Recruitment.aspx)

25-Jun: Assam Gramin (http://www.agvbank.co.in/recruitment.php)

24-Jun: Haryana Gramin Bank PO (http://www.shgb.co.in/RecruitmentsandPromotions)

IT Jobs

20-Jul: CDAC Noida (http://www.cdac.in/index.aspx?id=ca_noida_may_2015)

Engineers

02-Jul: BEL Ghaziabad (http://bel-india.com/recruitment)

02-Jul: ISRO Scientists (http://isro.gov.in/careers)

02-Jul: FCI Engg.Trainee (http://www.fcijobsportal.com)

30-Jun: Hindustan Latex Biomed. Engg (300) (http://www.hlfppt.org/)

26-Jun: RBI JE (https://rbi.org.in/scripts/Bs_viewcontent.aspx?Id=3020)

26-Jun: Bharat Dynamics (http://bdl.ap.nic.in/bdlrecruit.htm)

25-Jun: Raipur Civil Engg (http://www.aiimsraipur.edu.in/Career.aspx)

25-Jun: MP Electricity

(https://www.mponline.gov.in/Portal/Services/Recruit_MPKVV/Indore/notification.aspx)

24-Jun: KRIBHCO Noida (http://kribhco.indiainformative.com/Post4.aspx)

Legal

10-Jun: AAI Law (http://www.aai.aero/employment_news/Employee_Recruitment_new.jsp)

Specialists

31-Jul: IIIT Allahabad Gr. A & B (http://www.iiita.ac.in/announcements.php)

20-Jul: State Trading corp. (http://www.stc.gov.in/careers/current-openings.aspx)

20-Jul: NISER APO (http://www.niser.ac.in/drupal_new/)

15-Jul: Jammu Univ. (http://www.cujammu.ac.in//Default.aspx?

option=article&type=single&id=32&mnuid=734&prvtyp=site)

15-Jul: MoEF Scientists (http://envfor.nic.in/advertisements)

09-Jul: Allahabad Bank (https://www.allahabadbank.in/english/Recruitment.aspx)

12-Jul: Mumbai Metro (https://mmrda.maharashtra.gov.in/tenders-notices)

12-Jul: GBPUAT (http://www.gbpuat.ac.in/)

09-Jul: Punjab Corp Law (http://202.164.52.147/serv1/docs/dysecyrect121017527.pdf)

07-Jul: NBCC Building (http://www.nbccindia.com/nbccindia/nroot/njsp/Career.jsp)

01-Jul: NIELIT Spec. (http://www.nielit.gov.in/recruitments.aspx)

30-Jun: Rajendra Agro. (http://www.mangaldhwani.com/pusa/wp-

content/uploads/2014/09/Advt_-01_2015.pdf )

30-Jun: IIT Kanpur (http://www.iitk.ac.in/new/vacancies-in-administrative-and-technical-

cadre )

28-Jun: ONGC Rajbhasha (NET)

(http://ongcindia.ongc.co.in/wps/wcm/connect/ongcindia/home/career/recruitment+notices/recruitment-

of-olo-2015)

25-Jun: Raj. Industrial Development (http://www.riicorecruitment.org/)

25-Jun: HSCC Noida (http://www.hsccltd.com/)

24-Jun: Haryana Gramin Agro (http://www.shgb.co.in/RecruitmentsandPromotions)

24-Jun: Haryana Gramin Law Officer (http://www.shgb.co.in/RecruitmentsandPromotions)

Medics

14-Jul: MP medical officer (http://www.mppsc.nic.in/)

30-Jun: HAL Medical officer (http://www.hal-

india.com/Common/Uploads/Resumes/144_CareerPDF1_Med-advt-AC.pdf)

ParaMedics

Not At the moment

Deskjobs

05-Aug: NBE Assistants (http://natboard.edu.in)

31-Jul: IIIT Allahabad Gr.C (http://www.iiita.ac.in/announcements.php)

20-Jul: NISER Clerks (http://www.niser.ac.in/drupal_new/)



07-Jul: NBCC Building (http://www.nbccindia.com/nbccindia/nroot/njsp/Career.jsp)

01-Jul: NIELIT Deskjobs (http://www.nielit.gov.in/recruitments.aspx)

13-Jun: Bank Note Press (http://www.jobapply.in/bnpdewas/)

30-Jun: Lucknow Law univ. (http://rmlnlu.ac.in/recruitment-notification-process.html)

30-Jun: Rashtriya Sanskrit Sansthan (http://sanskrit.nic.in/advt_22_05_2015.pdf)

25-Jun: Pawan Hans Limited (http://pawanhans.co.in/site/Careern.aspx)

24-Jun: SJVN (PH) (http://sjvn.nic.in/careerdetail.htm?10/jobdetail)

Faculty

31-Jul: IIIT Allahabad (http://www.iiita.ac.in/announcements.php)

20-Jul: Raipur Univ. (http://www.prsu.ac.in:8010/Univ_Req.aspx)

15-Jul: NIT Puducherry (http://www.nitpy.ac.in/assets/teaching.pdf)

16-Jul: RPSC Home Science (http://rpsconline.rajasthan.gov.in/)



12-Jul: GBPUAT (http://www.gbpuat.ac.in/)

10-Jul: NITTTR Chandigarh (http://www.nitttrchd.ac.in )

07-Jul: Palampur, Himachal asst. (http://www.ihbt.res.in/recruit/recruitNotice.php)

06-Jul: PEC Chandigarh (http://pec.ac.in/~pecac/new/jobs)

03-Jul: SKHM Government Medical College (http://www.gmcmewat.ac.in)

30-Jun: IIT Roorkee (http://www.iitr.ernet.in/administration/pages/Openings+Faculty.html)

30-Jun: Ambedkar Uni. Delhi (http://aud.ac.in/careerataud)

30-Jun: NEIGRIHMS (http://neigrihms.gov.in)

30-Jun: Lucknow Law (http://rmlnlu.ac.in/recruitment-notification-process.html)

30-Jun: AIIMS Raipur (http://www.aiimsraipur.edu.in/Career.aspx)

28-Jun: Ranchi Agro (http://www.bauranchi.org/application-for-the-post-of-teachers-2/)

22-Jun: DIATPune (http://14.139.111.180/admin.html)

22-Jun: IGIT (http://www.igitsarang.ac.in/careers.php)

22-Jun: Himachal Central Univ. (http://www.cuhimachal.ac.in/job_emp.aspx)

Uniform

19-Jul: Navy Officers (http://www.irfc-nausena.nic.in/hindi/join_indiannavy.htm)

17-Jul: NDA Officers (http://upsconline.nic.in/mainmenu2.php)

15-Jul: Army Dental (23) (http://indianarmy.nic.in)

10-Jul: Army 10+2 (http://joinindianarmy.nic.in/)

30-Jun: BSF Constable (http://bsf.nic.in/en/recruitment.html)

15-Jun: Navy Sailers (SSR) (http://nausena-bharti.nic.in/forthcomingSailor.php)

15-Jun: Daman Diu Constables (http://daman.nic.in/jobs/2015/616-12-05-2015.PDF)

B.Com,CA,HR,MBA

20-Jul: Pawan Hans Audit (http://pawanhans.co.in/site/Careern.aspx)

06-Jul: GBPUAT Accountant (http://www.gbpuat.ac.in/)

01-Jul: NIELIT Accounts (http://www.nielit.gov.in/recruitments.aspx)

25-Jun: MP Electricity Accounts

(https://www.mponline.gov.in/Portal/Services/Recruit_MPKVV/Indore/notification.aspx)

21-Jun: Lucknow Metro Accounts

(https://www.digialm.com/EForms/html/form2399/index.html)

RESULT /MARKSHEET

SSC 2014 T2

NCLAT

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uri=CivilServiceExam)HOME (HTTP://MRUNAL.ORG/) ECONOMY (HTTP://MRUNAL.ORG/ECONOMY)

DOWNLOAD (HTTP://MRUNAL.ORG/DOWNLOAD) CONTACT ME (HTTP://MRUNAL.ORG/CONTACT)

The work of Mrunal (http://mrunal.org/) is under the Creative Commons Attribution-Non Commercial-ShareAlike 4.0License (http://creativecommons.org/l icenses/by-nc-sa/4.0/deed.en_US).Permissions beyond the scope of this l icense

may be available at Mrunal.org/contact (http://mrunal.org/contact).

1. Online Form Part-I stops few days before deadline, so don't wait till last date. Dont forget

reg.id & roll no.Note'em in Google Drive (https://www.google.com/drive/)

2. I usually update vacancies every Monday.Purple link= newly added,Blue= existing.Last

updated Mon. Jun 22, at 9:04PM

Hotel Management

TENTATIVE NOTIFICATIONS

IAS-IPS-IFoS: 16 May

IES: 7 Feb

SSC CGL: 2 May

SSC 10+2: 6 June

SSC Sub insp: 28 Mar

CAT: Aug 2015

RBI Officer / Assistant: ??

IBPS PO / Clerk / RRB: ??

ACIO 2015: ??

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