Team Flying SheepEngineering Analysis

Mark BerkobinJohn NevinJohn Nott

Christian YaegerMichelle Rivero

System Review: Solid Edge Model

Possible Points of Failure for Analysis Welds between horizontal supports and tilt

mechanism

Horizontal Supports in Bending and Shear

Vertical Supports in bending and shear

Bike Interface in bending and shear

Ratcheting Mechanism

Load Bearing Bolts

Not Analyzed Stability: System is Constrained by AISI 1018 HR Low

Carbon Steel parts, stability should not be an issue

Fatigue Analysis: It is not expected that the system will be used more than once every several hours. Fatigue should not be an issue

Human interface: Is built into the mechanism of a popular, proven jack system incorporated into the system

All failure points on the jack itself: The jack is a proven commercial product that we are incorporating into the system, we assume it will continue not to fail

Welds Between Horizontal Supports and the Tilt Mechanism on the Base

FBD For Welds in Torsion FBD for Welds in Shear

Weld Analysis in Torsion Maximum length of from point of force application to weld: 8.75 inches

Length of Weld: 14 inches = 1.17 ft

Height of welded part (D): 1.5 inches = 0.125 in

Maximum Force at point of application = 600 lb

Maximum possible moment: 600 lb * 8.75 = 5250 lb-in

Weld thickness (a value) = 5/16 inch = 0.0260 ft

Bending Stress = (Normal Stress)/(2)0.5

Bending Stress = M/(W*a*(a+D)) = 5250/(14*0.3125*(.3125+1.5)) = 662 psi

Assume: Welds are Equivalent Strength to Steel: Max Allowable Stress = 36 Kpsi

Safety Factor = 36,000 psi/662 psi = 54.4

Weld Analysis in Shear Maximum length of from point of force application to weld: 8.75

inches Length of Weld: 14 inches = 1.17 ft Height of welded part (D): 1.5 inches = 0.125 in Maximum Force at point of application = 600 lb Maximum possible moment: 600 lb * 5.75 = 3450 lb-in Weld thickness (a value) = 5/16 inch = 0.0260 ft Bending Stress = (Normal Stress)/(2)0.5

Bending Stress = M/(W*a*(a+D)) = 3450/(14*0.3125*(.3125+1.5)) = 435 psi

Assume: Welds are Equivalent Strength to Steel: Max Allowable Shear Stress = 24.1 kpsi

Safety Factor = 24,100 psi/435 psi = 55.4

Horizontal Supports Solid Edge Model

Horizontal Support Bending Analysis

For the frame sliders side bar600 lbs

17 inches, from center point;

Assume system is symmetrical around the midpoint

Max stress = M*c/I

M = r X F =17 in x 600 lbs = 10,200 lb-in

c = 0.75

I = ((Loutter) 4 –(Linner)4)/3 = ((1.5)4-(1.25)4)/3

= .873 in4

Max stress = (10,200*.75)/.873 = 8,762 psi

Max allowable Stress = 36 kpsi

Safety Factor = Max Stress/Maximum Allowable Stress

= 36,000/8,762 = 4.11

Horizontal Support Shear Stress Analysis

At the support beams600 lbs

Cross Sectional Area

Side of square tube: 1.25 in

Thickness:1/8 inches

Area affected in shear:

A=(1.25)2-(1.25-2(.125*2))2

A=.5625 in2

Maximum Allowable Shear Stress = 24.1 KpsiMoment

Max stress = P/A = 600/.5625 = 1,066

Safety Factor = Max Stress/Maximum Allowable Stress = 24,100/1,066 = 22.6

Vertical Support Solid Edge Model

Bike Interface Description Solid Edge Model Free Body Diagram

Vertical Support Bending Analysis For purposes of this analysis the bike interface with the foot pegs (half tube) and the

frame sliders (whole tube) will be treated as the same in terms of failure

Max stress = M*c/I

M = r X F = 3.25 in x 600 lbs = 1,950 lb-in

c = 0.75 I = ((Loutter) 4 –(Linner)4)/3 = ((1.5)4-(1.25)4)/3

= .873 in4

Max stress = (1,950*.75)/.873 +600/(.2*.5) = 7,675 psi

Max allowable Stress = 36 kpsi

Safety Factor = Max Stress/Maximum Allowable Stress

= 36,000/7,675 = 4.69

Description of Ratcheting Mechanim Solid Edge Model Free Body Diagram

Ratcheting Analysis

Design Characteristics

Tooth height is .2 inches due to the need for adjustability

Tooth width is variable to meet requirements, currently planned at 0.5 inches

Mode of failure

Pressure of bike will be straight down on the tooth, tooth likely to fail in shear

Worst Case scenario: all of the bike’s weight resting on one “tooth”

Ratcheting Analysis-Continued Maximum Shear Stress: = F/A =

600/(.2*.5) = 6000 psi = 6 kpsi

Maximum Allowable Shear Stress for AISI 1018 HR Low Carbon Steel: 32 kpsi

Safety Factor: (32 kpsi)/(6kpsi) = 5.34

Description of Load Bearing Bolts Solid Edge Model

In Tension

In shear

Free Body Diagram

Bolt Analysis Bolts Used throughout this project have been

chosen as ½” diameter SAE Grade 8 bolts

Grade 8 bolts have the following properties:

Minimum Proof Strength

Minimum Tensile Strength

Minimum Yield Strength

120 kpsi 150 kpsi 130 kpsi

Bolt Analysis-Shear For Coarse ½” diameter bolt

At=0.1419 in2

Proof Load

Fp=AtSp

Fp=17028 lbs

Maximum expected Fp = 600 lb (weight of the motorcycle)Safety factor: 17028/600 = 23.4

Bolt Analysis-Tension

T=FL/HA

L= 1.90 inches H = 3.99 inches

T = (600*1.90)/(3.99*0.1419) = 2,013 psi

Safety Factor = 150/2.013 = 74.5

Questions?