tẠp chÍ lỘ ĐỀ sỐ 2 [ trƯỜng hỌc sỐ ]

2. 2 3. TRUONGHOCSO.COM TUYN TP THI TH I HC NM HC 2012 - 2013 M S A6Mn thi: TON; Khi: A ( thi gm 01 trang, 09 cu) Thi gian lm bi: 180 pht, khng k thi gian pht I. PHN CHUNG CHO TT C TH SINH (7,0 im) x 1Cu 1 (2,0 im). Cho hm s y . x 11. Kho st v v th (C) ca hm s cho.2. Tm ta im M thuc (C) tng khong cch t M n hai trc ta l nh nht.Cu 2 (1,0 im). Gii phng trnh sin 2 x cos8x cos7 x cos6x sin x . 24x2 1 2 x 3 4 x 2 2 yx 2 3 2 y xCu 3 (1,0 im). Gii h phng trnh x, y . 2 3 2 y 2x x x 2 3 2 3 2x 1 3 2 x 1 tan x x 2 tan 2 x x Cu 4 (1,0 im). Tnh tch phn I dx . x 2 tan x x 4Cu 5 (1,0 im). Cho hnh lng tr ng ABCD.ABCD c y hnh thoi cnh a 3 . Bit BAD 120o v gc giang thng AC v mt phng ADDA bng 30 . Gi M, N ln lt l trung im ca AD v BB. Tnh th tch khi olng tr v khong cch t im N n mt phng (MAC).Cu 6 (1,0 im). Cho x, y, z l cc s thc dng tha mn x z . Tm gi tr nh nht ca biu thc sau 2 x22z 2 y z 3zP 2 . x y y zzx 2 2II. PHN RING (3,0 im): Th sinh ch c lm mt trong hai phn (phn A hoc phn B)A. Theo chng trnh ChunCu 7.a (1,0 im). Trong h trc ta Oxy cho tam gic ABC c ba gc u nhn. Bit ta chn ng cao h tcc nh A, B, C ln lt l A 1; 2 , B 2;2 , C 1;2 . Vit phng trnh ng thng cha cnh AC ca tam gic.Cu 8.a (1,0 im). Trong khng gian vi h trc ta Oxyz cho mt phng (P) cha ng thng (d) c phngx 1 yztrnh . Bit (P) to vi mt phng Q : 2 x 2 y z 1 0 mt gc 60o , hy tm ta giao im ca1 1 2(P) vi trc Oz.82 Cu 9.a (1,0 im). Tm s hng khng cha x trong khai trin Newton P x 3 .x B. Theo chng trnh Nng cao5 1Cu 7.b (1,0 im). Trong h trc ta Oxy cho tam gic ABC c trng tm G ; v ng trn i qua trung 3 3im ca ba cnh l (C): x y 2 x 4 y 0 . Vit phng trnh ng trn ngoi tip tam gic ABC.2 2Cu 8.b (1,0 im). Trong khng gian vi h trc ta Oxyz vit phng trnh ng thng d i qua im M 0; 2;1bit d ct hai mt phng P : x y z 0; Q : x 2 y z 6 0 ln lt ti hai im A, B sao cho M l trung imAB v on thng AB c di ngn nht.Cu 9.b (1,0 im). Gii bt phng trnh 2log 2 x 1 log 2 x 2 2 x .2 ---------------HT----------------Th sinh khng c s dng ti liu. Cn b coi thi khng gii thch g thm. 3H v tn th sinh:...;S bo danh:.. 4. TRUONGHOCSO.COMTUYN TP THI TH I HC NM HC 2012 - 2013M S A7Mn thi: TON; Khi: A( thi gm 01 trang, 09 cu) Thi gian lm bi: 180 pht, khng k thi gian pht I. PHN CHUNG CHO TT C TH SINH (7,0 im)2x 1Cu 1 (2,0 im). Cho hm s y .1 x1. Kho st s bin thin v v th hm s cho.2. Gi (d) l tip tuyn ca th hm s ti im I 0;1 . Tm trn th hm s cho cc im M c honh ln hn 1 v khong cch t M n (d) l nh nht.Cu 2 (1,0 im). Gii phng trnh 8 sin 6 x cos6 x 3 3 sin 4 x 3 3cos2 x 9sin 2 x 11. x sin 2 x 2Cu 3 (1,0 im). Tnh tch phn I dx . 0 1 sin 2 xCu 4 (1,0 im). Cho hnh chp S.ABC c cnh SA vung gc vi y (ABC), tam gic ABC l tam gic cn ti A. Cnhbn SB ln lt to vi mt phng y v mt phng trung trc ca cnh BC cc gc 30 , 45 , khong cch t S n cnhBC bng a. Tnh th tch khi chp S.ABC theo a. x y 3 8 xy 2 x y 8 xy Cu 5 (1,0 im). Gii h phng trnh 1 1 x; y . 2 x y x yCu 6 (1,0 im). Cho cc s thc dng x, y, z tha mn iu kin xyz 1 . Tm gi tr nh nht ca biu thc x y z 8 T . y z x x y y z z x II. PHN RING (3,0 im): Th sinh ch c lm mt trong hai phn (phn A hoc phn B)A. Theo chng trnh ChunCu 7.a (1,0 im). Trong mt phng vi h ta Oxy , cho ba im I 1;1 , E 2;2 , F 2; 2 , tm ta cc nh cahnh vung ABCD, bit I l tm hnh vung, cnh AB i qua im E v cnh CD i qua im F.Cu 8.a (1,0 im). Trong khng gian ta Oxyz , cho ba im A 1;0; 1 , B 2;3; 1 , C 1;3;1 . Tm ta im D z 3thuc ng thng : x y 1 . Tm ta im D thuc ng thng th tch khi t din ABCD bng 1.2Cu 9.a (1,0 im). T cc ch s 1, 2,3, 4,5,6 c th lp c bao nhiu t nhin chn c 5 ch s khc nhau sao chotrong c ng 2 ch s l v hai ch s l ng lin k nhau ?B. Theo chng trnh Nng caoCu 7.b (1,0 im). Trong mt phng vi h ta Oxy , cho ellipse E c cc tiu im F1 3;0 , F2 3;0 , ng thngd i qua F1 ct E ti hai im M, N. Tnh chu vi tam gic F2 MN bit din tch t gic A1B1 A2 B2 bng 40, trong A1 A2 ,B1 B2 ln lt l di trc ln v trc nh ca E .Cu 8.b (1,0 im). Trong khng gian ta Oxyz , lp phng trnh mt cu S i qua im A 2; 2; 2 v ct mt phng P : x y z 3 theo giao tuyn l mt ng trn sao cho ABCD l t din u vi y BCD l tam gic ni tip ngtrn giao tuyn. x y ex e y Cu 9.b (1,0 im). Gii h phng trnh log 2 x 3log y 2 0 x; y . 2 12---------------HT---------------Th sinh khng c s dng ti liu. Cn b coi thi khng gii thch g thm. 4H v tn th sinh:...;S bo danh:. 5. Truonghocso.com thi th i hc nm hc 2012-2013M s A8 Mn thi: ton; Khi: A thi gm 01 trang Thi gian lm bi: 180 pht, khng k thi gian pht I. Phn chung cho tt c cc th sinh (7,0 im)Cu 1 (2,0 im). Cho hm s y = x3 3x2 + mx + 2a. Cho m = 3, v th v kho st hm s.b. Tm m hm s c hai cc tr M, N tha mn trng tm tam gic AM N nm trn ngthng my x = 0 vi A(1; 2). 3 + sin x + cos xCu 2 (1,0 im). Gii phng trnh sin x + cos x sin x cos x = 1 lg4 + sin x cos x Cu 3 (1,0 im). Gii phng trnhx2 + x 1 + 3(x + 1) = 2 x2 + x + 2. (x x)(1 + x)Cu 4 (1,0 im). Tnh tch phn I =dx.3xCu 5 (1,0 im). Cho tam gic nhn ABC, ng thng (d) i qua A v vung gc vi mtphng (ABC). Trn (d) ly im S vi AS = x > 0. Gi I, K ln lt l trc tm tam gicSBC, ABC. ng thng IK ct (d) ti Q, AK ct BC ti P .a. Chng minh rng P Q vung gc SK.b. Gi s ABC l tam gic u cnh a. Tnh th tch V ca hnh chp S.QBC theo a v x.Cu 6 (1,0 im).Cho x, y l cc s thc. Tm gi tr nh nht ca: (x 1)2 + (x 2)2 + (x 2)2 + (x 5)2 +(x 5)2 + (x 1)2II. Phn ring(3,0 im): Th sinh ch c lm mt trong hai phn (phn A hocphn B)A. Theo chng trnh ChunCu 7.a (1,0 im). Trong mt phng vi h ta Oxy, cho tam gic ABC vi A(1; 4). imH(2, 1), G(3; 2) ln lt l trc tm v trng tm ca tam gic ABC. Tm ta cc nh catam gic ABC.Cu 8.a (1,0 im). Gii phng trnh: 3 25x2 + (3x 10) 5x2 + 3 x = 0Cu 9.a (1,0 im).T 1 ch s 1, 2 ch s 2, 3 ch s 3, 4 ch s 4, 5 ch s 5, c th lpc bao nhiu s c 15 ch s khng chia ht cho 5.B. Theo chng trnh Nng cao 2 +2x62 +2x5Cu 7.b (1,0 im). Gii phng trnh: 2x+3 3x = 3x 2x x2 y2Cu 8.b (1,0 im). Trong mt phng vi h ta Oxy, cho elip(E) : 16+ 9 = 1. Tm ta im M trn (E) sao cho M nhn hai tiu im mt gc 600 .Cu 9.b (1,0 im). Rt gn biu thc:12n232 A = Cn + Cn + Cn + 2(Cn + Cn + Cn ) + + 2n2 (Cn + Cn ) + 2n1 Cnn1n n HtTh sinh khng c s dng ti liu. Cn b coi thi khng gii thch g thm H v tn th sinh:....................................................; S bo danh:................................... 5 6. Truonghocso.com thi th i hc nm hc 2012-2013M s A9 Mn thi: ton; Khi: A thi gm 01 trang Thi gian lm bi: 180 pht, khng k thi gian pht I. Phn chung cho tt c cc th sinh (7,0 im)Cu 1 (2,0 im). Cho hm s y = x4 + 2mx2 + m2 + m (C)a. Kho st s bin thin v v th hm s khi m = 2.b. Vi nhng gi tr no ca m th th (C) c ba im cc tr ng thi ba im cc tr tovi nhau mt tam gic uCu 2 (1,0 im). Gii phng trnh sin x cos 2x + cos2 x + sin x cos 6x = 2 Cu 3 (1,0 im). Gii phng trnh (x 1) x + 2 = x 3 + (x + 1) x 1. Cu 4 (1,0 im). Tnh tch phn:x2 + adxCu 5 (1,0 im). Cho hnh chp S.ABCD ABCD l hnh ch nht, SA vung gc vi mtcphng (ABCD). AB = a 3, AD = a, SA = a 2. Dng hnh bnh hnh BCED. Gi G l trngtm tam gic CED.a. Tnh d(G, (SBD)).b. Tnh th tch V ca hnh chp S.DEC. T tnh d(BD, SC).Cu 6 (1,0 im). Cho cc s thc a, b, c [0, 1] tha mn (a + b + c 2)2 = abc. Tm gi trln nht ca:a b c ++2a2b2cII. Phn ring(3,0 im): Th sinh ch c lm mt trong hai phn (phn A hocphn B)A. Theo chng trnh ChunCu 7.a (1,0 im). Trong mt phng vi h ta Oxy, cho hai ng thng d1 : 2x + y 3 =0, d2 : 2y + x 3 = 0 ct nhau ti A. im M (3, 1). Vit phng trnh ng thng d ct d1 , d2ti B, C sao cho M l trng tm tam gic ABC.Cu 8.a (1,0 im).Tnh n bit:8192 0 2 2 2 42 2n2 2 2n = 2C2n + C2n + C2n + +C2n +C2n , n > 4, n Z 133 52n 1 2n + 1 (x + 2y)xy = 25Cu 9.a (1,0 im). Gii h phng trnh: 2 log5 (x + 2y) + x y = 4B. Theo chng trnh Nng cao 3 2x2y 2x 2y = 24 xCu 7.b (1,0 im).Gii h phng trnh:2x2y + 2 2x 2y = 2x + 8Cu 8.b (1,0 im).Cho ng trn (C) : (x + 1)2 + (y 2)2 = 4 v ng thng (d) :3x + 4y + m = 0. Tm m trn d c duy nht im A m t k c hai tip tuyn AT1 , AT2ti (C) sao cho tam gic AT1 T2 l tam gic u (T1 , T2 l tip im).Cu 9.b (1,0 im). Cho khai trin a thc (1 3x)20 = a0 + a1 x + a2 x2 + + a20 x20 . Tnhtng S = |a0 | + 2|a1 | + 3|a2 | + + 21|a20 | HtTh sinh khng c s dng ti liu. Cn b coi thi khng gii thch g thm H v tn th sinh:....................................................; S bo danh:................................... 6 7. Truonghocso.com thi th i hc nm hc 2012-2013M s A10Mn thi: ton; Khi: A thi gm 01 trang Thi gian lm bi: 180 pht, khng k thi gian pht I. Phn chung cho tt c cc th sinh (7,0 im)Cu 1 (2,0 im).Cho hm s y = x4 + 2mx2 + m2 + m (C)a. Kho st s bin thin v v th hm s khi m = 2.b. Cho T (0; 2). Tm m sao cho A v 3 im cc tr ca hm s thuc mt ng trn.Cu 2 (1,0 im). Gii phng trnh: sin x cos 2x + cos2 x + sin x cos 6x = 2Cu 3 (1,0 im). Gii phng trnh: (x2 + x + 1)(x4 + x2 + 4) = x2 + 2x + 3 /4 sin xCu 4 (1,0 im). Tnh tch phn: I =/4dxx2+1+xCu 5 (1,0 im). Cho hnh lng tr ng ABCA B C vi BAC = v K, L, M l cc im3trn AA , BB , CC tha mn gc to bi KL v AB l ; gc to bi KM v AC l .4 3a. Tnh gc gia mt phng (KLM ) v (ABC).b. Tnh th tch hnh lng tr ABCKLM .Cu 6 (1,0 im). Cho cc s thc dng a, b, c tha mn a 1, a + b 3, a + b + c 6. Tmgi tr ln nht ca biu thc: 3 3 a+ b+ 3cII. Phn ring(3,0 im): Th sinh ch c lm mt trong hai phn (phn A hocphn B)A. Theo chng trnh ChunCu 7.a (1,0 im). Cho A(1; 0) v ng trn (C) : (x 1)2 + (y 1)2 = 9. Lp phng trnhng thng qua A v ct (C) ti hai im E, F sao cho EF nh nht.Cu 8.a (1,0 im). Gii phng trnh:log2 (4x + 1) log5 (4x + 4) + log3 (4x + 2) log4 (4x + 3) = 2 log3 (4x + 2) log5 (4x + 4)Cu 9.a (1,0 im).Tm h s ca s hng cha x9 trong khai trin nh thc Newton ca n 1nn+1+ x3 . Cho bit: 2(Cn+2 + Cn+2 ) = 29n 138. x3B. Theo chng trnh Nng caoCu 7.b (1,0 im). Gii bt phng trnh: 2 (3 x) log2 (1 + 7)x +3x+2 2 x log3 (8 + 2 7)(x+1) x+1Cu 8.b (1,0 im). Cho A(1; 0) v ng trn (C) : (x 2)2 + (y 1)2 = 9. Lp phng trnhng thng qua A v ct (C) ti hai im M, N sao cho A l trung im ca M N .Cu 9.b (1,0 im).Tnh h s ca x16 trong khai trin (x + 2x2 3x3 )8 HtTh sinh khng c s dng ti liu. Cn b coi thi khng gii thch g thm H v tn th sinh:....................................................; S bo danh:................................... 7 8. TRUONGHOCSO.COM TUYN TP THI TH I HC NM HC 2012 - 2013 M S B4 Mn thi: TON; Khi: B( thi gm 01 trang, 09 cu) Thi gian lm bi: 180 pht, khng k thi gian pht I. PHN CHUNG CHO TT C TH SINH (7,0 im) x2Cu 1 (2,0 im). Cho hm s y . x 11. Kho st s bin thin v v th hm s cho.2. Lp phng trnh tip tuyn ca th hm s bit tip tuyn ct hai trc ta ti hai im A, B sao cho bn knh ng trn ni tip tam gic IAB ln nht (vi I l giao im hai ng tim cn).Cu 2 (1,0 im). Gii phng trnh 6cos3x 1 8sin2 xcos3x . x4Cu 3 (1,0 im). Gii bt phng trnh 3x 2 6 x 2 x . 32Cu 4 (1,0 im). Tnh tch phn I e x x3 4 x 2 1 dx .1 1Cu 5 (1,0 im). Cho hnh chp S.ABCD c y ABCD l hnh thang vung (vung ti A v B), AB BC AD a , 2cnh SA vung gc vi y v SA 2a . Gi A1 , D1 theo th t l trung im ca SA v SD. Tnh bn knh mt cu ngoitip v th tch hnh chp S. A1BCD1 .111Cu 6 (1,0 im). Cho cc s thc x, y, z 2 tha mn 2 . Chng minh rngx 1 y 1 z 1 x y z 3 x 2 y 2 z 2 .II. PHN RING (3,0 im): Th sinh ch c lm mt trong hai phn (phn A hoc phn B)A. Theo chng trnh Chunx y z 1 0Cu 7.a (1,0 im). Trong khng gian vi h ta Oxyz , cho ng thng d : v A 2; 1;1 , B 1; 1;0 .2 x y 1 0Tm ta im T trn ng thng d sao cho din tch tam gic TAB t gi tr nh nht.Cu 8.a (1,0 im). Trong mt phng vi h ta Oxy , cho hnh thoi ABCD c nh A 1;0 v ng cho BD cphng trnh x 1 y . Tm ta cc nh ca hnh thoi bit di on BD bng 4 2 . log y log y 3 x log3 y log3 y x Cu 9.a (1,0 im). Gii h phng trnh x x; y . cotx coty log yB. Theo chng trnh Nng caoCu 7.b (1,0 im). Trong khng gian vi h ta Oxyz , lp phng trnh mt phng P cha trc Ox v ct mt cu41 S : x2 y 2 z 2 2x 4 y 6z 22 theo mt ng trn c bn knh bng .2 5Cu 8.b (1,0 im). Trong mt phng vi h ta Oxy , cho hypebol H : 4 x 2 y 2 4 , tm ta im N trn hypebolsao cho N nhn hai tiu im di mt gc 120 .4 x 2 5 x m m2Cu 9.b (1,0 im). Tm gi tr thc ca m ng thng : y 2m 3x ct th hm s y tix2hai im phn bit A x1; y1 , B x2 ; y2 x1 x2 sao cho 2 x12 3x2 4 x1 x2 5x1 6 x2 150 3 y12 4 y2 5 y1 y2 6 y1 7 y2 .2 2---------------HT---------------Th sinh khng c s dng ti liu. Cn b coi thi khng gii thch g thm.8H v tn th sinh:...;S bo danh:. 9. TRUONGHOCSO.COM TUYN TP THI TH I HC NM HC 2012 - 2013 M S B5 Mn thi: TON; Khi: B ( thi gm 01 trang, 09 cu)Thi gian lm bi: 180 pht, khng k thi gian pht I. PHN CHUNG CHO TT C TH SINH (7,0 im)x 2m 3 x 2 m2 3m x 2 (1), vi m l tham s thc.1 3 1Cu 1 (2,0 im). Cho hm s y 3 21. Kho st s bin thin vi m 0 .2. Tm m hm s (1) t cc tr ti x1 , x2 sao cho 2 x1 3 3 x2 x1 1 x1 6m 3 . Cu 2 (1,0 im). Gii phng trnh 4sin 2 5 x 4sin 2 2 x 4sin 2 3x 7 .6 4 x 2 5 y 2 6 15 xy Cu 3 (1,0 im). Gii h phng trnh x; y 2 x 3 y 4 9 xy2 2 4x2Cu 4 (1,0 im). Tnh tch phn I xsinx cosx 02dx .Cu 5 (1,0 im). Cho lng tr tam gic u ABCABC c di cnh y bng a . Gi M, N ln lt l trung im ca cc onthng AA, AB. Bit gc gia hai mt phng (CAI) v (ABC) bng 60 . Tnh th tch khi chp NACI v khong cch gia haing thng MN, AC theo a .Cu 6 (1,0 im). Cho tam gic ABC c di 3 cnh ln lt l a, b, c . Tm gi tr nh nht ca biu thc13a 3 b 3 c P . cosA cosB cos C 2 b c 2 a c 2 a b II. PHN RING (3,0 im): Th sinh ch c lm mt trong hai phn (phn A hoc phn B)A. Theo chng trnh ChunCu 7.a (1,0 im). Trong khng gian vi h ta Oxyz , lp phng trnh mt phng P cha ng thng d1 : x 2 y zv hp vi ng thng d2 : x 2 2 y 3 2 z 5 mt gc 30 .Cu 8.a (1,0 im). Trong mt phng vi h ta Oxy , cho ng trn C : x 2 y 2 4 x 2 y 1 0 v im M 3; 4 . T imM k hai tip tuyn MA, MB n ng trn C . Tm ta im N thuc ng thng AB sao cho di on ON ngn nht. log 4 x y 1 log 4 y 222 1Cu 9.a (1,0 im). Gii h phng trnh x; y . log 5 x 2 3xy 3 y 2 2 log 5 y B. Theo chng trnh Nng caox 2 m 3 x 3m 1Cu 7.b (1,0 im). Tm m hm s y c cc i v cc tiu sao cho cc gi tr cc i v cc tiu ca x 1hm s u m.57 11 Cu 8.b (1,0 im). Trong khng gian vi h ta Oxyz , cho ng trn c tm I ; ; , bn knh bng 2 v nm333trong mt phng : x 2 y 2z 1 0 . Lp phng trnh mt cu S cha ng trn v c tm thuc mt phng : x y z 3 .Cu 9.b (1,0 im). Trong mt phng vi h ta Oxy , cho hai ng thng d1 : x 3 ; d2 : x y 2 0 . Gi s T l ng1trn tip xc vi ng thng d 2 ti M v ct ng thng d1 ti hai im N, P sao cho PMN MNP . Lp phng trnh2ng trn T bit chu vi tam gic MNP bng 4 2 2 v im N c tung dng.---------------HT---------------Th sinh khng c s dng ti liu. Cn b coi thi khng gii thch g thm.9H v tn th sinh:...;S bo danh:. 10. TRUONGHOCSO.COM TUYN TP THI TH I HC NM HC 2012 - 2013 M S B6 Mn thi: TON; Khi: B ( thi gm 01 trang, 09 cu)Thi gian lm bi: 180 pht, khng k thi gian pht I. PHN CHUNG CHO TT C TH SINH (7,0 im)Cu 1 (2,0 im). Cho hm s y x3 3 3m x 2 3m2 6m 2 x m3 3m2 2m (1), vi m l tham s thc.1. Kho st s bin thin v v th hm s vi m 1 .2. Tm m th hm s (1) ct trc honh ti 3 im phn bit c honh x1 , x2 , x3 x3 x2 x1 tha mn iukin x12 2 x1 x2 x3 1 x3 10 . 3 2 x y 3 3x 2 y 2Cu 2 (1,0 im). Gii h phng trnh x; y .2 3 3x 2 y 5 x y 8Cu 3 (1,0 im). Gii phng trnh cotx cot 3x 4cos 2 x 3 2 .1Cu 4 (1,0 im). Tnh tch phn I 2 x 1 ln x3 1 dx .0Cu 5 (1,0 im). Cho hnh lp phng ABCD.ABCD c di cnh bng a . Gi M, N, P ln lt l trung im cacc on AB, CC, AD. Tnh gc gia hai ng thng DP, MN v th tch khi t din DMNP theo a .Cu 6 (1,0 im). Cho ba s thc dng x, y, z tha mn x y z xy yz xz . Chng minhx2 1 y2 1z2 1 x yz .2 2 2II. PHN RING (3,0 im): Th sinh ch c lm mt trong hai phn (phn A hoc phn B)A. Theo chng trnh ChunCu 7.a (1,0 im). Trong khng gian vi h ta Oxyz , cho im H 1; 2;1 . Lp phng trnh mt phng P ct cctrc ta ti A, B, C sao cho H l trc tm tam gic ABC.Cu 8.a (1,0 im). Tm gi tr thc ca m phng trnh sau c nghim duy nht log 1 6 x m log 2 3 2 x x 2 0 x . 2Cu 9.a (1,0 im). Trong mt phng vi h ta Oxy , cho hai ng trn c phng trnh ln lt l: C1 : 2 x 1 2 y 2 1; C2 : x 2 2 y 4 . Lp phng trnh ng thng d tip xc vi ng trn C1 v ct 22 2ng trn C2 ti hai im M , N sao cho MN 2 2 .B. Theo chng trnh Nng cao esin x cos xCu 7.b (1,0 im). Tnh gii hn I lim .x 0xCu 8.b (1,0 im). Trong mt phng vi h ta Oxy , cho ellipse E : 4 x 2 9 y 2 36 . Lp phng trnh tip tuyn caellipse hp vi ng thng l : y 3x mt gc 60 .Cu 9.b (1,0 im). Trong khng gian vi h ta Oxyz , cho ba im A 1;3;1 , B 0;1; 1 , C 1; 1;1 . Xc nh ta im M trn mt phng P : 2 x y z 2 0 sao cho biu thc F 2MA 3MB 4MC t gi tr nh nht. ---------------HT---------------Th sinh khng c s dng ti liu. Cn b coi thi khng gii thch g thm. 10H v tn th sinh:...;S bo danh:. 11. TRUONGHOCSO.COM TUYN TP THI TH I HC NM HC 2012 - 2013 M S B7 Mn thi: TON; Khi: B( thi gm 01 trang, 09 cu) Thi gian lm bi: 180 pht, khng k thi gian pht I. PHN CHUNG CHO TT C TH SINH (7,0 im) 3x 1Cu 1 (2,0 im). Cho hm s y .x 1 1. Kho st s bin thin v v th (C) ca hm s cho. 2. Xc nh ta hai im B v C thuc hai nhnh ca th (C) sao cho tam gic ABC vung cn ti A 2;1 . 4 5 x 2 2 y 1 x y 5 x 2 y 2 3x 2 Cu 2 (1,0 im). Gii h phng trnh 2 3x 2 5 5 x x; y . 4 x 5 y yyCu 3 (1,0 im). Gii phng trnh cos3 3x cos 2 x 3cos 2 2 x cos2 x 2 .2Cu 4 (1,0 im). Tnh tch phn I 2 x 1 cos x dx . 20Cu 5 (1,0 im). Cho hnh chp t gic u S.ABCD c di cnh y bng a . Gi M, N theo th t l trung im ca SA v BC.Bit gc gia ng thng MN v mt phng (ABCD) bng 60 . Tnh th tch khi chp S.ABCD v gc gia ng thng MN vmt phng (SBD). 7 16 y 2 x 1 x 6 Cu 6 (1,0 im). Gii h phng trnh x; y . x 2 2 y 4 9 2 2 II. PHN RING (3,0 im): Th sinh ch c lm mt trong hai phn (phn A hoc phn B)A. Theo chng trnh ChunCu 7.a (1,0 im). Trong khng gian vi h ta Oxyz , cho hai im A 2;3;2 , B 6; 1; 2 v ng thng c phng trnh x 1 y 4 z 3: . Tm ta im M trn ng thng sao cho chu vi tam gic MAB nh nht. 1 5 4Cu 8.a (1,0 im). Trong mt phng vi h ta Oxy , lp phng trnh ng thng d i qua gc ta O v ct ng trnC : x 4 y 2 40 ti hai im A, B sao cho AB 4BO .2 4 9 11Cu 9.a (1,0 im). Tm s hng nguyn dng trong khai trin Newtonx 23 x 3 24 y 5 y 66 ybit cp y 4 4 x 2 xy 2 x 4 5 x; y tha mn h phng trnh 2 x; y . 8 x 3xy 4 y xy 4 y2B. Theo chng trnh Nng caoCu 7.b (1,0 im). Trong khng gian vi h ta Oxyz , lp phng trnh mt cu c tm nm trn ng thng4 2 x y 1 z 8 v ng thi tip xc vi hai mt phng P : x 2 y 2 z 2 0 ; Q : x 2 y 2 z 4 0 .Cu 8.b (1,0 im). Trong mt phng vi h ta Oxy , cho ng trn C : x 2 y 1 9 v ng thng c phng 22trnh : m 1 x my 1. Chng minh rng lun ct C ti hai im phn bit A, B. Tm m di on AB nh nht.x x mCu 9.b (1,0 im). Tm gi tr thc ca m hm s y c cc i, cc tiu sao cho khong cch gia im bng 10. 1 x---------------HT---------------Th sinh khng c s dng ti liu. Cn b coi thi khng gii thch g thm.11H v tn th sinh:...;S bo danh:. 12. TRUONGHOCSO.COM TUYN TP THI TH I HC NM HC 2012 - 2013 M S B8 Mn thi: TON; Khi: B( thi gm 01 trang, 09 cu) Thi gian lm bi: 180 pht, khng k thi gian pht I. PHN CHUNG CHO TT C TH SINH (7,0 im) mxCu 1 (2,0 im). Cho hm s y (1), vi m l tham s thc.x21. Kho st s bin thin v v th hm s (1) vi m 1 . 1 2. Xc nh m th hm s cho ct ng thng x y ti hai im A, B phn bit sao cho din tch tam 2 1 gic OAB bng (O l gc ta ). 86 x2 8Cu 2 (1,0 im). Gii bt phng trnh 1 x .x4 x 6 xCu 3 (1,0 im). Gii phng trnh cos 2 x sinx cos3 x cosx sinx . 2 2012 cos x 2011sin xCu 4 (1,0 im). Tnh tch phn I dx . cos x sin x 3 0Cu 5 (1,0 im). Cho hnh chp tam gic u S.ABC c di cnh y bng 2a 6 , chiu cao SH a . Gi M, N lnlt l trung im ca AC v AB. Tnh th tch khi chp S.AMN v tnh din tch mt cu ngoi tip khi chp S.AMN. ab bc ca 3 3 2Cu 6 (1,0 im). Cho ba s thc dng a, b, c 0;1 . Chng minh abc 2 a b2 c2 9 23 .II. PHN RING (3,0 im): Th sinh ch c lm mt trong hai phn (phn A hoc phn B)A. Theo chng trnh ChunCu 7.a (1,0 im). Trong khng gian vi h ta Oxyz , cho hai im A 0;0; 3 , B 2;0; 1 v mt phng (P) cphng trnh 3x 8 y 7 z 1 0 . Xc nh ta im C trn mt phng (P) sao cho tam gic ABC l tam gic u.Cu 8.a (1,0 im). Trong mt phng vi h ta Oxy , cho tam gic ABC c hai nh A, B nm trn ng phn gic thnht ca h trc, im I 2;1 l trung im ca on thng BC. Tm ta trung im K ca on thng AC bit rng tamgic ABC c din tch bng 2. x2 x 2 2 xy y 2 y2 y 4 2 xyCu 9.a (1,0 im). Gii h phng trnh 5.2 x x; y .log 3 x log 5 y log 3 y.log 5 xB. Theo chng trnh Nng caoCu 7.b (1,0 im). Trong khng gian vi h ta Oxyz , cho ba im A 1;1;2 , B 2;1; 1 , C 2; 2; 1 v mt phng P : 2 x y 2 z 1. Tm ta im M trn mt phng (P) sao cho biu thc T MA2 2MB2 MC 2 t gi tr nh nht.Cu 8.b (1,0 im). Trong mt phng vi h ta Oxy , cho hai ng thng d1 : 2 x y 2; d2 : 2 x y 2 0 . Lp16phng trnh ng trn tm I 2; 4 ct hai ng thng ln lt theo hai dy cung AB, CD sao cho AB CD . 53Cu 9.b (1,0 im). Tm gi tr thc ca m ng thng d : y 2 x m ct th y 3 x ti hai im M, Nx 1phn bit sao cho trng tm tam gic IMN nm trn ng thng x 2 y 11 0 (vi I l giao im hai ng tim cn). ---------------HT---------------Th sinh khng c s dng ti liu. Cn b coi thi khng gii thch g thm. 12H v tn th sinh:...;S bo danh:. 13. TRUONGHOCSO.COM TUYN TP THI TH I HC NM HC 2012 - 2013 M S B9Mn thi: TON; Khi: B ( thi gm 01 trang, 09 cu) Thi gian lm bi: 180 pht, khng k thi gian pht I. PHN CHUNG CHO TT C TH SINH (7,0 im)Cu 1 (2,0 im). Cho hm s y x 4 4m 2 x 2 4m2 (1), vi m l tham s thc.1. Kho st s bin thin v v th hm s cho vi m 0 .2. Tm m th hm s (1) ct trc honh ti 4 im phn bit c honh x1 , x2 , x3 , x4 tha mn h thc x14 x2 x3 x4 17 .44410 x 4 y 5 xyCu 2 (1,0 im). Gii h phng trnh x; y . 12 x 2 2 xy y 2 13x 2 y xy 28Cu 3 (1,0 im). Gii phng trnh 3 cot x tan 3 x . sin 2 x4 e x 2 sin2 x Cu 4 (1,0 im). Tnh tch phn I dx . 01 cos 2 xCu 5 (1,0 im). Cho lng tr ng ABC.ABC c y ABC l tam gic vung ti B. Gi K l hnh chiu vung gcca im A ln ng thng AC. Bit gc gia ng thng AK v mt phng (CAB) bng 30 v AB a, AC a 5 , tnh th tch khi t din KABC.Cu 6 (1,0 im). Cho cc s thc khng m a, b, c tha mn a 2b 3c 4 . Chng minh b a c ca 2 .II. PHN RING (3,0 im): Th sinh ch c lm mt trong hai phn (phn A hoc phn B)A. Theo chng trnh ChunCu 7.a (1,0 im). Gii phng trnh log 3 x 2 2 x log 1 x 3 log 313 x .2 3x 1Cu 8.a (1,0 im). Trong mt phng vi h ta Oxy , cho tam gic ABC c nh B 1; 2 , phng trnh ng phngic trong ca gc A l d : 2 x y 1 0 . Tm ta cc nh A v C bit rng im C nm trn trc tung v khong ccht C n d bng hai ln khong cch t B n d.Cu 9.a (1,0 im). Trong khng gian vi h ta Oxyz , lp phng trnh ng thng i qua A 1;0; 2 ct mt x 3 y 2phng P : 2 x y z 3 0 ti C v ct ng thng d : z 6 ti B sao cho AB AC . 24B. Theo chng trnh Nng cao 31 1 4x Cu 7.b (1,0 im). Tm h s ca s hng cha a trong khai trin Newton 36 3 a 2 y 4 a bit x, y tha mn h 7 6 log 7 6 x 5 1 x 1phng trnh y 2 x; y . C y 4 C yy 2 3 y 1 4 x 2Cu 8.b (1,0 im). Trong khng gian vi h ta Oxyz , lp phng trnh ng thng i qua im A 3; 1;1 , nmtrong mt phng P : x y z 5 v to vi ng thng d : 2 x y 2 z mt gc 45 .Cu 9.b (1,0 im). Trong mt phng vi h ta Oxy , cho hypebol H : 8x 2 y 2 8 . Tm m sao cho hypebol trn ctng thng d : 2 x y m 0 ti hai im A, B tha mn 2AF1 BF2 (A, B ln lt thuc nhnh tri v nhnh phi cahypebol, F1 , F2 l hai tiu im ca (H) v F1 c honh m). ---------------HT---------------Th sinh khng c s dng ti liu. Cn b coi thi khng gii thch g thm. 13H v tn th sinh:...;S bo danh:. 14. TRUONGHOCSO.COMTUYN TP THI TH I HC NM HC 2012 - 2013 M S B10Mn thi: TON; Khi: B( thi gm 01 trang, 09 cu) Thi gian lm bi: 180 pht, khng k thi gian pht I. PHN CHUNG CHO TT C TH SINH (7,0 im) 2x 1Cu 1 (2,0 im). Cho hm s y .x21. Kho st s bin thin v v th (C) ca hm s cho.2. Tm ta im M trn th (C) sao cho tam gic MAB vung ti M vi A 5;1 , B 1;3 . sin x cos x 2sin 2 x21 Cu 2 (1,0 im). Gii phng trnh sin 4 x sin 4 3x .1 cot x 2 2 xy x 2 y Cu 3 (1,0 im). Gii h phng trnh x; y . 7 x 7 2y 3 e 1Cu 4 (1,0 im). Tnh tch phn I x2 sin x e x x 2 dx . 1Cu 5 (1,0 im). Cho hnh chp S.ABCD c y ABCD l hnh thoi cnh a, SA SB a v mt phng (SBD) vung gcvi mt phng (ABCD). Tnh theo a th tch khi chp S.ABCD v khong cch gia hai ng thng AC v SD.Cu 6 (1,0 im). Cho ba s thc dng a, b, c tha mn a b c 1. Chng minh 11a 9b 11b 9c 11c 9a 10 .9a a b 9b b c 9c c a II. PHN RING (3,0 im): Th sinh ch c lm mt trong hai phn (phn A hoc phn B)A. Theo chng trnh ChunCu 7.a (1,0 im). Chng minh ng thc Cn 3n1 2Cn 3n2 3Cn 3n3 ... nCn n4n1 .12 3 nCu 8.a (1,0 im). Trong khng gian vi h ta Oxyz , lp phng trnh ng thng nm trong mt phng c x2 y2phng trnh P : x y 2 z 5 0 , song song v cch ng thng d : z 3 mt khong bng 14 . 43Cu 9.a (1,0 im). Trong mt phng vi h ta Oxy , lp phng trnh ng trn (C) c tm I 1;3 ct ng thng : 3x 4 y 10 0 ti hai im M, N phn bit sao cho MIN 120 .B. Theo chng trnh Nng caoCu 7.b (1,0 im). Trong khng gian vi h ta Oxyz , lp phng trnh mt phng i qua im M 1; 3; 2 ct mtcu S : x 1 y 2 z 3 14 theo giao tuyn l mt ng trn c bn knh nh nht.22 2Cu 8.b (1,0 im). Trong mt phng vi h ta Oxy , cho im A 2; 2 . Tm ta cc im B, C ln lt thuc ccng thng d1 : x y 2 ; d2 : x y 8 0 sao cho tam gic ABC vung cn ti A.Cu 9.b (1,0 im). Tm gi tr thc ca a h phng trnh sau c nghim vi mi gi tr thcca b : 2b log3 x b a 1 log 2 y a 2 2 x; y . a 1 log3 x log 2 y 122 ---------------HT---------------Th sinh khng c s dng ti liu. Cn b coi thi khng gii thch g thm. 14H v tn th sinh:...;S bo danh:. 15. TRUONGHOCSO.COMTUYN TP THI TH I HC NM HC 2012 - 2013 M S D3Mn thi: TON; Khi: ( thi gm 01 trang, 09 cu)Thi gian lm bi: 180 pht, khng k thi gian pht I. PHN CHUNG CHO TT C TH SINH (7,0 im)Cu 1 (2,0 im). Cho hm s y x3 3x 2 m , m l tham s thc.1. Kho st s bin thin v v th hm s vi m 0 .2. Tm m tip tuyn ti ti im c honh bng 1 ca th hm s (1) to vi hai trc ta mt tam gic OAB c 3din tch bng (O l gc ta ). 2 x 1 x 1 y 1Cu 2 (1,0 im). Gii h phng trnh 4 x; y .2 x 9 x y 2 y 5 x 022 2Cu 3 (1,0 im). Gii phng trnh sin 2 x tan x cos2 x cos2 x 2 tan x .1Cu 4 (1,0 im). Tnh tch phn I 2 x 2 x 1 e x x 12 dx .0Cu 5 (1,0 im). Cho lng tr ng ABC.ABC c AC 2 AB 2a; AA 2a 5; BAC 120 . Gi M l trung im cacnh CC, chng minh MB vung gc vi MA v tnh khong cch t A ti mt phng ABM.Cu 6 (1,0 im). Cho cc s thc x, y tha mn ng thi 2 y x 2 ; y 2 x 2 3x . Tm gi tr ln nht ca biu thcN 6 x2 6 y 2 7 .II. PHN RING (3,0 im): Th sinh ch c lm mt trong hai phn (phn A hoc phn B)A. Theo chng trnh ChunCu 7.a (1,0 im). Trong khng gian vi h ta Oxyz , vit phng trnh ng thng i qua im A 8;0; 23 ,nm trong mt phng P : 2 x 2 y z 7 0 v tip xc vi mt cu S : x 1 y 2 z 3 17 . 2 22Cu 8.a (1,0 im). Trong mt phng vi h ta Oxy , cho ba im A 1; 1 , B 0;2 , C 0;1 . Lp phng trnh ngthng d i qua A sao cho tng khong cch t B v C n d t gi tr ln nht. 2 x 2 2 xy 3x y 1 0 Cu 9.a (1,0 im). Gii h phng trnh 2 2 x y x; y . 2 x y 2 22 4 B. Theo chng trnh Nng caoCu 7.b (1,0 im). Trong khng gian vi h ta Oxyz , cho hai im A 3;5;4 , B 3;1;4 , tm ta im C nm trongmt phng P : x y z 1 0 sao cho tam gic ABC cn ti C v c din tch bng 2 17 .x2 y 2Cu 8.b (1,0 im). Trong mt phng vi h ta Oxy , cho ellipse E : 1 . Lp phng trnh ng thng10 54 6vung gc vi ng thng d : x y 2013 0 v ct ellipse cho ti hai im M, N sao cho MN . 3Cu 9.b (1,0 im). Mt hp ng 40 vin bi, trong c 20 vin bi , 10 vin bi xanh, 6 vin bi vng v 4 vin bi trng.Ly ngu nhin 2 vin bi, tnh xc sut hai vin bi ly ra c cng mu. ---------------HT---------------Th sinh khng c s dng ti liu. Cn b coi thi khng gii thch g thm. 15H v tn th sinh:...;S bo danh:. 16. TRUONGHOCSO.COM TUYN TP THI TH I HC NM HC 2012 - 2013M S D4Mn thi: TON; Khi: D( thi gm 01 trang, 09 cu) Thi gian lm bi: 180 pht, khng k thi gian pht I. PHN CHUNG CHO TT C TH SINH (7,0 im) x3Cu 1 (2,0 im). Cho hm s y . x21. Kho st s bin thin v v th hm s cho.2. Tm gi tr thc ca m ng thng d : y 2 x 3m ct th hm s trn ti hai im phn bit P, Q tha mn h thc OP.OQ 4 0 (O l gc ta ). 2 y x 2 3 x 1 Cu 2 (1,0 im). Gii h phng trnh 2 x; y . x 4 y 2 9 y 12 x 2 7 y 6 Cu 3 (1,0 im). Gii phng trnh 2cos 3x cos x 3 sin 2 x 1 2 3cos 2 2 x . 4 2xCu 4 (1,0 im). Tnh tch phn I 2 cos 2 x cos x esin x dx . 02Cu 5 (1,0 im). Cho hnh chp S.ABC c y ABC l tam gic u, cc cnh bn u bng a, gc gia cnh bn v mtphng y bng 30 . Tnh th tch khi chp S.ABC theo a.Cu 6 (1,0 im). Cho cc s thc x, y, z tha mn x y z 6 . Chng minh 8x 8 y 8z 4x1 4 y 1 4z 1 .II. PHN RING (3,0 im): Th sinh ch c lm mt trong hai phn (phn A hoc phn B)A. Theo chng trnh Chun a 20Cu 7.a (1,0 im). Tnh t s bit a, b ln lt l h s ca cc hng t cha x 2 , x3 trong khai trin 5 3 x . bCu 8.a (1,0 im). Trong mt phng ta Oxy , cho tam gic ABC ni tip ng trn tm I 6;6 v ngoi tip ngtrn tm K 4;5 , lp phng trnh cc cnh ca tam gic bit ta nh A 2;3 .Cu 9.a (1,0 im). Trong khng gian vi h ta Oxyz , cho im J 1; 2;1 . Lp phng trnh mt cu tm I ct mtphng P : 2 x y 2 z 15 0 theo giao tuyn l mt ng trn c chu vi bng 8 (I l im i xng vi J qua mtphng (P)).B. Theo chng trnh Nng caoCu 7.b (1,0 im). Trong mt phng vi h ta Oxy , cho parabol y 2 x , tm ta hai im A v B thuc parabolsao cho tam gic AOB l tam gic u. x 1 z4Cu 8.b (1,0 im). Trong khng gian vi h ta Oxyz , cho ng thng d : y 7 v mt phng (P) c 2 4phng trnh 3x 2 y z 5 0 . Gi l hnh chiu vung gc ca d trn mt phng (P), tm ta im F trn ngthng sao cho di OF ln nht.x 2 m 5 x mCu 9.b (1,0 im). Tm gi tr thc ca m th hm s y ct trc honh ti hai im phn bit sao x 1cho khong cch gia hai im ngn nht. ---------------HT---------------Th sinh khng c s dng ti liu. Cn b coi thi khng gii thch g thm. 16H v tn th sinh:...;S bo danh:. 17. TRUONGHOCSO.COMTUYN TP THI TH I HC NM HC 2012 - 2013M S D5 Mn thi: TON; Khi: D ( thi gm 01 trang, 09 cu) Thi gian lm bi: 180 pht, khng k thi gian pht I. PHN CHUNG CHO TT C TH SINH (7,0 im)x2Cu 1 (2,0 im). Cho hm s y .x 11. Kho st s bin thin v v th (C) ca hm s cho.2. Xc nh ta im T trn th (C) sao cho tip tuyn ti T to vi hai ng tim cn mt tam gic c chu vi bng 8 2 10 . Cu 2 (1,0 im). Gii phng trnh 2cos x cos x 4sin x 2 . 34 5xCu 3 (1,0 im). Gii bt phng trnh 9 0 x .2 x 3 x 2 3 3Cu 4 (1,0 im). Cho hnh chp t gic u S.ABCD, H l tm ca y, I l trung im ca on SH, khong cch t I n mt phnga(SBC) bngv mt phng (SBC) to vi y (ABCD) mt gc . Tnh th tch khi chp S.ABCD theo a v .2 2xCu 5 (1,0 im). Tnh tch phn I dx . 0 2 x 2 xCu 6 (1,0 im). Cho hai s thc dng x, y tha mn x y 2 . Tm gi tr ln nht ca biu thcT x3 y 3 x3 y 3 3 x 3 y .II. PHN RING (3,0 im): Th sinh ch c lm mt trong hai phn (phn A hoc phn B)A. Theo chng trnh Chunn n2 x 1 Cu 7.a (1,0 im). Tm s hng cha x trong khai trin Newton ca 3 10 6 trong n l s nguyn dng nh nht tha n x mn iu kin Cn Cn Cn ... Cn 512 .0 12 nCu 8.a (1,0 im). Trong mt phng vi h ta Oxy cho tam gic ABC vi ta ba trung im ca cc cnh AB, BC, CA lnlt l M 1;1 , N 3;2 , P 2; 1 . Lp phng trnh ng trn ngoi tip tam gic ABC.Cu 9.a (1,0 im). Trong khng gian vi h ta Oxyz , lp phng trnh mt phng cha trc Ox v ct mt cu c phngtrnh S : x 2 y 2 z 2 2 x 4 y 4 z 0 theo mt giao tuyn l ng trn c bn knh ln nht.B. Theo chng trnh Nng caox2Cu 7.b (1,0 im). Trong mt phng vi h ta Oxy cho ellipse E : y 2 1 , lp phng trnh ng thng d song song4vi trc honh v ct ellipse ti hai im A, B sao cho OA vung gc vi OB. y 3Cu 8.b (1,0 im). Trong khng gian vi h ta Oxyz , cho ng thng d :1 x 3 z v mt phng (P) c 2phng trnh 2 x y 2 z 9 0 . Gi A l giao im ca d v mt phng (P), lp phng trnh ng thng nm trongmt phng (P) sao cho i qua A v vung gc vi d.1Cu 9.b (1,0 im). Tm gi tr thc ca m hm s y mx c cc tr sao cho khong cch t im cc tiu n tim cn ca x 2th bng . 5 ---------------HT---------------Th sinh khng c s dng ti liu. Cn b coi thi khng gii thch g thm. 17H v tn th sinh:...;S bo danh:. 18. TRUONGHOCSO.COM TUYN TP THI TH I HC NM HC 2012 - 2013M S D6Mn thi: TON; Khi: D ( thi gm 01 trang, 09 cu)Thi gian lm bi: 180 pht, khng k thi gian pht I. PHN CHUNG CHO TT C TH SINH (7,0 im)Cu 1 (2,0 im) Cho hm s y x 4 8 m 2 x 2 m3 1 (1), m l tham s thc.1. Kho st s bin thin v v th hm s (1) vi m 1 .2. Tm m th hm s c ba im cc tr sao cho ba im lp thnh mt tam gic vung cn.9 6 cos2 x 2 Cu 2 (1,0 im). Gii phng trnh sin 2 x sin 2 x 4cos2 x 3 0 . 81 9 x 2 y 1 3x3 24 Cu 3 (1,0 im). Gii h phng trnh x; y . ( x 2) y 14 25cos x 4sin xCu 4 (1,0 im). Tnh tch phn I (s inx cos x)03dx .Cu 5 (1,0 im). Cho tam gic ABC vung cn ti A, AB=a. Trn ng thng qua C v vung gc vi mt phng (ABC) ly im Dsao cho CD a . Mt phng qua C vung gc BD ct BD ti F v ct AD ti E. Tnh th tch khi t din CDEFCu 6 (1,0 im). Cho cc s thc dng a, b, c tha mn iu kin a b c 1.Chng minh a b3 1 b c3 1 c a3 1 5 .II. PHN RING (3,0 im): Th sinh ch c lm mt trong hai phn (phn A hoc phn B)A. Theo chng trnh ChunCu 7.a (1,0 im). Trong mt phng vi h ta Oxy ,cho tam gic ABC c ta nh A 1; 3 , phng trnh cc ng caoBH v CK theo th t l 5x 3 y 25;3x 8 y 12 . Bit phng trnh ng trung trc ca on AB l 3x 4 2 y v trng tmG 4; 2 , lp phng trnh ng trn bng tip gc B ca tam gic ABC.Cu 8.a (1,0 im). Trong khng gian vi h ta Oxyz , lp phng trnh mt cu (S) c tm thuc ng thngx 1z2d1 l giao tuyn ca hai mt phng x 3 y 4 0 , x y 2 z 1 0 ng thi tip xc vi ng thng d 2 : 1 y 23ti im H 3;1;3 .Cu 9.a (1,0 im). Tm hng t cha x 4 trong khai trin v rt gn tng sau f ( x) (1 x)4 (1 x)5 ... (1 x)15 .B. Theo chng trnh Nng caoCu 7.b (1,0 im). Trong mt phng vi h ta Oxy , cho ellipse c phng trnh E :16 x 2 25 y 2 400 . ng thng d c hs gc k ct cc ng chun ca ellipse ti M v N. Tnh din tch tam gic FMN theo k trong F l tiu im c honh dngca ellipse.x 1 y 3 zCu 8.b (1,0 im). Trong khng gian vi h ta Oxyz , tm ta im M thuc ng thng d1 : v im N2 3 2x 5 y x 5thuc ng thng d 2 : sao cho ng thng MN song song v cch mt phng P : x 2 y 2 z 1 0 mt645khong bng 2.Cu 9.b (1,0 im). Gii bt phng trnh 16x 3x 4 x 9 x x . ---------------HT---------------Th sinh khng c s dng ti liu. Cn b coi thi khng gii thch g thm. 18H v tn th sinh:...;S bo danh:. 19. TRUONGHOCSO.COMTUYN TP THI TH I HC NM HC 2012 - 2013 M S D7Mn thi: TON; Khi: D( thi gm 01 trang, 09 cu)Thi gian lm bi: 180 pht, khng k thi gian pht I. PHN CHUNG CHO TT C TH SINH (7,0 im)Cu 1 (2,0 im). Cho hm s y x 4 x 2 1 .1. Kho st s bin thin v v th (C) ca hm s cho.2. Tm ta cc im A nm trn th (C) sao cho tip tuyn ti A ct th (C) ti hai im B, C khc A v B, C nm v hai pha i vi A. 10Cu 2 (1,0 im). Gii phng trnh 5 5 x 2 1 x x .xCu 3 (1,0 im). Gii phng trnh 8cos3 x cos3x .3 aCu 4 (1,0 im). Tnh th tch khi chp S.ABC bit AB AC a, BC , SA a 3 v SAB SBC 30 . 2 ex ex 1 ln 7Cu 5 (1,0 im). Tnh tch phn I 3 e2 x 7e x 8 dx .lnCu 6 (1,0 im). Cho cc s thc dng x, y, z tha mn iu kin xy yz zx 1 . Tm gi tr ln nht cax y z P .x2 1 y2 1 z2 1II. PHN RING (3,0 im): Th sinh ch c lm mt trong hai phn (phn A hoc phn B)A. Theo chng trnh ChunCu 7.a (1,0 im). Trong mt phng vi h ta Oxy , cho tam gic ABC c phng trnh ng phn gic trong gc Al x 2 y 5 0 , ng cao qua A c phng trnh 4 x 13 y 10 0 , ta nh C 4;3 . Tm ta nh B ca tam gic.Cu 8.a (1,0 im). Trong khng gian vi h ta Oxyz , cho hai im A 2;0; 2 , B 0;3; 3 , lp phng trnh mtphng i qua im A sao cho khong cch t B n mt phng t gi tr ln nht.Cu 9.a (1,0 im). T cc ch s 0,1, 2,3, 4,5 lp c bao nhiu s t nhin c bn ch s khc nhau sao cho cc s u chia ht cho 4 ?B. Theo chng trnh Nng caoCu 7.b (1,0 im). Trong khng gian vi h ta Oxyz , cho hai im A 3;5; 5 , B 5; 3;7 v mt phng c phngtrnh P : x y z 0 . Xc nh ta im M trn mt phng (P) sao cho MA2 MB2 t gi tr nh nht. x2 y 2Cu 8.b (1,0 im). Trong mt phng vi h ta Oxy , cho ellipse c phng trnh E : 1 , mt gc vung 9 4 11MON quay xung quanh gc ta O ( M v N thuc ellipse). Chng minh 2 khng i.OM ON 2n 1Cu 9.b (1,0 im). Vi mi s nguyn dng n, khai trin nh thc x theo th t ly tha ca x gim dn, tm hng 3t chnh gia ca khai trin bit h s ca hng t th ba l 5. ---------------HT---------------Th sinh khng c s dng ti liu. Cn b coi thi khng gii thch g thm. 19H v tn th sinh:...;S bo danh:. 20. TRUONGHOCSO.COM TUYN TP THI TH I HC NM HC 2012 - 2013M S D8Mn thi: TON; Khi: D( thi gm 01 trang, 09 cu) Thi gian lm bi: 180 pht, khng k thi gian pht I. PHN CHUNG CHO TT C TH SINH (7,0 im)Cu 1 (2,0 im). Cho hm s y x 4 2 m 2 x 2 m2 5m 5 (1), vi m l tham s thc.1. Kho st s bin thin v v th hm s vi m 1 .2. Tm m th hm c ba im cc tr sao cho ba im lp thnh mt tam gic u.5 x 2 3x 1Cu 2 (1,0 im). Gii bt phng trnh 5 x . x 1 x3 1 7 x Cu 3 (1,0 im). Gii phng trnh 2cos cos x . 24 3 8 ln 2Cu 4 (1,0 im). Tnh tch phn I x 2 e x 1 e e x dx . 22x 2x0 e2 x e x 1Cu 5 (1,0 im). Cho cc s thc x, y, z tha mn iu kin x2 y 2 z 2 2 x 4 y 4 z 0 . Tm gi tr ln nht v gi trnh nht ca biu thc F 2 x y 2 z .Cu 6 (1,0 im). Cho hnh chp S.ABCD c y ABCD l hnh bnh hnh , cnh AB a, ABC 60 . Hai mt bn (SAD)v (SBC) l hai tam gic vung ln lt ti A v C, ng thi cc mt phng ny nghing u trn y mt gc . Tnh thtch khi chp S.ABCD theo a v .II. PHN RING (3,0 im): Th sinh ch c lm mt trong hai phn (phn A hoc phn B)A. Theo chng trnh Chun 1 5 log x y2 2 y x 5Cu 7.a (1,0 im). Gii h phng trnh 3y x; y . 1 log x 1 log x 4 x Cu 8.a (1,0 im). Trong mt phng vi h ta Oxy , cho hai im A 1; 2 , B 4;3 , xc nh ta im M nm trntrc honh sao cho AMB 45 .Cu 9.a (1,0 im). Trong khng gian vi h ta Oxyz , cho ba im A 0;1;1 , B 1; 2; 3 , C 1;0; 3 v mt cu cphng trnh S : x 2 y 2 z 2 2 x 2 z 2 . Xc nh ta im D thuc mt cu sao cho th tch t din ABCD t gitr ln nht.B. Theo chng trnh Nng caoCu 7.b (1,0 im). Trong khng gian vi h ta Oxyz , cho hai im A 0;1;2 , B 1;1;0 v mt phng (P) c phngtrnh x y z 0 . Xc nh ta im M trn mt phng (P) sao cho tam gic MAB l tam gic vung cn ti B.Cu 8.b (1,0 im). Trong mt phng vi h ta Oxy , lp phng trnh ng thng d i qua gc ta O v ct haing thng d1 : x y 2 0 ; d2 : 2 x y 5 theo th t ti hai im A, B sao cho OAOB 10 ..Cu 9.b (1,0 im). Mt hp cha 20 vin bi gm 5 vin bi xanh, 7 vin bi v 8 vin bi vng. Ly ngu nhin 8 vin bi,hy tnh xc sut ly c 8 vin bi sao cho c c ba mu. ---------------HT---------------Th sinh khng c s dng ti liu. Cn b coi thi khng gii thch g thm. 20H v tn th sinh:...;S bo danh:. 21. TRUONGHOCSO.COM TUYN TP THI TH I HC NM HC 2012 - 2013 M S D9 Mn thi: TON; Khi: D( thi gm 01 trang, 09 cu) Thi gian lm bi: 180 pht, khng k thi gian pht I. PHN CHUNG CHO TT C TH SINH (7,0 im) 2x 1Cu 1 (2,0 im). Cho hm s y .x 11. Kho st s bin thin v v th (C) ca hm s cho.2. Gi I l giao im hai ng tim cn ca (C). Tm ta im M thuc th (C) sao cho tip tuyn ca (C) ti im M vung gc vi ng phn gic gc phn t th nht ca h trc ta .Cu 2 (1,0 im). Gii phng trnh 25sin 2 x 14 33sin x 4cos x . 6 cos xCu 3 (1,0 im). Tnh tch phn I dx . 0 cos x cos2 x20Cu 4 (1,0 im). Gii phng trnh 6 x 4 x 1 x . xCu 5 (1,0 im). Cho hnh hp ABCD.ABCD c y ABCD l hnh vung. Bit rng AA a v khong cch t im aA n mt phng (ABD) bng . Tnh th tch khi chp CABD v gc gia hai mt phng (ABC) , (ACD).2Cu 6 (1,0 im). Cho cc s thc dng x, y, z c tng bng 3. Chng minh x 2 y 2 z 2 6 xyz 9 .II. PHN RING (3,0 im): Th sinh ch c lm mt trong hai phn (phn A hoc phn B)A. Theo chng trnh ChunCu 7.a (1,0 im). Trong mt phng vi h ta Oxy , lp phng trnh ng thng d i qua im M 6;3 v ctng trn C : x 1 y 1 9 ti hai im A, B sao cho tam gic IAB c din tch bng 2 2 v AB 2 (I l tm2 2ng trn).Cu 8.a (1,0 im). Trong khng gian vi h ta Oxyz , cho hai im M 0; 1;2 , N 1;1;3 , lp phng trnh mtphng (P) i qua hai im M, N v to vi mt phng Q : 2 x y 2 z 2 mt gc nh nht.2 1 x 3 8 xCu 9.a (1,0 im). Tnh gii hn I lim. x 0 xB. Theo chng trnh Nng caoCu 7.b (1,0 im). Trong khng gian vi h ta Oxyz , cho cc im A 1;1;0 , B 0;0; 2 , C 1;1;1 . Vit phngtrnh mt phng (P) i qua hai im A, B sao cho khong cch t C ti mt phng (P) bng 3 .Cu 8.b (1,0 im). Trong mt phng vi h ta Oxy , lp phng trnh ng thng d i qua im A 9;6 ct ngtrn C : x 2 y 2 8x 2 y theo mt dy cung c di 4 3 .Cu 9.b (1,0 im). C bao nhiu s t nhin gm 4 ch s nh hn 2707 sao cho cc ch s ca n u khc nhau ? ---------------HT---------------Th sinh khng c s dng ti liu. Cn b coi thi khng gii thch g thm. 21H v tn th sinh:...;S bo danh:. 22. TRUONGHOCSO.COM TUYN TP THI TH I HC NM HC 2012 - 2013M S D10 Mn thi: TON; Khi: D ( thi gm 01 trang, 09 cu)Thi gian lm bi: 180 pht, khng k thi gian pht I. PHN CHUNG CHO TT C TH SINH (7,0 im)Cu 1 (2,0 im). Cho hm s y x 4 2mx 2 1 (1), m l tham s thc.1. Kho st s bin thin v v th ca hm s (1) vi m 1 .2. Tm gi tr ca m th hm s c ba im cc tr to thnh mt tam gic cn sao cho di cnh y gp i bn knh ng trn ngoi tip tam gic .Cu 2 (1,0 im). Gii bt phng trnh x 3 4 x x 2 10 x 22 x .ln 2 x 3ln x 3eCu 3 (1,0 im). Tnh tch phn I dx .1x ln x 2 Cu 4 (1,0 im). Gii phng trnh sin x cos 2 x cos 2 x tan 2 x 1 2sin 3 x 0 .Cu 5 (1,0 im). Cho cc s thc dng x, y, z tha mn x y z 6 . Tm gi tr ln nht ca P x yz y xz z x y .Cu 6 (1,0 im). Cho hnh chp S.ABCD c y l hnh thang vung ti A v D, CD 2 AB 2 AD 2a . Cnh bn SDvung gc vi y (ABCD) v SD a . Gi E l trung im ca CD, xc nh tm v tnh bn knh mt cu ngoi tip tdin S.BCE.II. PHN RING (3,0 im): Th sinh ch c lm mt trong hai phn (phn A hoc phn B)A. Theo chng trnh Chunn 1Cu 7.a (1,0 im). Tm s hng t do trong khai trin x x 2 bit n l s nguyn dng tha mn Cn 2n An1 . 3 n x Cu 8.a (1,0 im). Trong khng gian vi h ta Oxy , cho hnh thoi ABCD c A 1; 2 , phng trnh ng thng BDl x y 1 0 . Tm ta cc nh cn li ca hnh thoi bit rng BD 2 AC v nh B c tung m.Cu 9.a (1,0 im). Trong khng gian vi h ta Oxyz , cho ba im A 5;3; 1 , B 2;3; 4 , C 1;2;0 . Chng minhtam gic ABC l tam gic u v tm ta im D sao cho ABCD l t din u.B. Theo chng trnh Nng caoCu 7.b (1,0 im). Trong khng gian vi h ta Oxyz , cho im A 3; 2;3 v hai ng thng c phng trnh lnlt l d1 : 4 2 x 6 2 y z 3; d2 : 2 2 x y 4 6 2 z . Chng minh im A v hai ng thng cho ng phng,tm ta cc nh B v C bit hai ng thng trn theo th t cha ng cao k t B v trung tuyn k t C ca tamgic ABC.22 x y 2 x 21 yCu 8.b (1,0 im). Gii h phng trnh x; y .log 2 x. log 4 y 1 4Cu 9.b (1,0 im). Trong khng gian vi h ta Oxy , cho hnh vung ABCD c nh A 2; 1 v phng trnh ngcho BD : x 2 y 5 . Lp phng trnh cnh AB ca hnh vung bit ng thng AB c h s gc dng. ---------------HT---------------Th sinh khng c s dng ti liu. Cn b coi thi khng gii thch g thm. 22H v tn th sinh:...;S bo danh:. 23. 23 24. S 1Cu 1: Mt mch dao ng in t, in dung ca t in C = 2.10-8 F. Biu thc nng lng ca cun cm lWL = 10-6sin2(2.106t) J. Xc nh cng dng in trong mch ti thi im nng lng dao ng in ttrong mch chia u cho t in v cun cm ? A. 0,238 mAB. 0,238 A C. 0,466AD. 0,466 mACu 2: i vi con lc l xo treo thng ng dao ng iu ho: A. Lc n hi tc dng ln vt khi l xo c chiu di ngn nht c gi tr nh nht. B. Lc n hi tc dng ln vt khi l xo c chiu di cc i c gi tr ln nht. C. Lc n hi tc dng ln vt cng chnh l lc lm vt dao ng iu ho. D. C ba cu trn u ng.Cu 3: Ti 2 im A,B trn mt cht lng cch nhau 16cm c 2 ngun pht sng kt hp dao ng theo phngtrnh: u1= acos(30t) , u2 = bcos(30t +/2 ). Tc truyn sng trn mt nc l 30cm/s. Gi C, D l 2 imtrn on AB sao cho AC = DB = 2cm . S im dao ng vi bin cc tiu trn on CD l: A. 12B. 11C. 13D. 10Cu 4: Chn pht biu sai: Mt my bin p l tng c cun s cp mc vi ngun in xoay chiu, cun thcp mc vi in tr thun. Nu gim gi tr ca in tr xung cn mt na gi tr ban u th: A. Cng dng in hiu dng trong cun th cp v cun s cp u tng hai ln. B. in p hiu dng hai u cun s cp v th cp u khng i. C. Sut in ng cm ng cc i trong cun s cp v th cp u khng i. D. Cng sut tiu th in mch s cp v th cp u khng i.Cu 5: Sng dng trn mt si dy do s chng cht ca hai sng truyn theo chiu ngc nhau: u1 = u0cos(kx+ t) v u2 = u0cos(kx - t). Biu thc no sau y biu th sng dng trn dy y? A. u = 2u0sin(kx).cos(t) C. u = u0sin(kx).cos(t) B. u = 2u0cos(kx).cos(t) D. u = 2u0sin(kx - t)Cu 6: Mt con lc n dao ng iu ho theo phng trnh li gc = 0,1cos(2t + /4) ( rad ). Trongkhong thi gian 5,25s tnh t thi im con lc bt u dao ng, c bao nhiu ln con lc c ln vn tcbng 1/2 vn tc cc i ca n? A. 11 ln. B. 21 ln. C. 20 ln. D. 22 ln.Cu 7: Cho mt chum nh sng trng pht ra t mt n dy tc truyn qua mt ng thu tinh cha kh hidro p sut thp ri chiu vo khe ca mt my quang ph. Trn mng quan st ca knh quang ph trong bung tis thu c: A. Mt quang ph lin tc. B. Quang ph lin tc nhng trn c mt s vch ti. C. Bn vch mu trn mt nn ti. D. Mn quan st hon ton ti. 1104Cu 8: Trong on mch RLC mc ni tip c R 50 , L ( H ), C ( F ) . t vo hai u on mch mt in p xoay chiu c U=100 V v tn s gc thay i c. Khi 1 200 (rad / s) th cng sut tiuth ca mch l 32W. cng sut trong mch vn l 32W th tn s gc l 2 bng:24 25. A. 100 (rad/s) B. 50 (rad/s)C. 200 (rad/s)D. 300 (rad/s)Cu 9: Mt con lc l xo treo thng ng, u di l xo treo ln lt vt c khi lng m1 2m2 100 g (haivt c ni vi nhau bng mt dy treo nh khng gin). Khi h cn bng l xo dn mt on l 12cm. Ct ttc thi dy ni gia hai vt, khi con lc l xo to bi l xo v vt c khi lng m1 s dao ng iu hovi c nng bng bao nhiu? Ly g 10 m / s 2 A. 0,09 JB. 0,01 J C. 0,04 JD. 0,08 JCu 10: Treo mt vt trong lng 10N vo mt u si dy nh, khng co dn ri ko vt khi phng thngng mt gc 0 v th nh cho vt dao ng. Bit dy treo ch chu c lc cng ln nht l 20N. dykhng b t, gc 0 khng th vt qu:A. 150. B. 300. C. 450. D. 600.Cu 11: Mt dao ng lan truyn trong mi trng lin tc t im M n im N cch M mt on 7/3(cm).Sng truyn vi bin A khng i. Bit phng trnh sng ti M c dng uM = 3cos2t (uM tnh bng cm, ttnh bng giy). Vo thi im t1 tc dao ng ca phn t M l 6 (cm/s) th tc dao ng ca phn t Nl A. 3 (cm/s).B. 0,5 (cm/s). C. 4(cm/s). D. 6(cm/s).Cu 12: Trong thang my treo mt con lc l xo c cng 25N/m, vt nng c khi lng 400 g. Khi thangmy ng yn ta cho con lc dao ng iu ho, chiu di con lc thay i t 32cm n 48cm. Ti thi im mgvt v tr thp nht th cho thang my i xung nhanh dn u vi gia tc a . Ly g = 2 = 10 m/s2. Bin 10 dao ng ca vt trong trng hp ny l A. 17 cm. B. 19,2 cm.C. 8,5 cm.D. 9,6 cm.Cu 13: My bin th gm cun s cp N1=1000 vng, r1=1 (m); cun th cp vi N2=200 vng, r2=1,2 (m).Ngun s cp c hiu in th hiu dng U1, ti th cp l tr thun R=10 (m); hiu in th hiu dng U2. Bqua mt mt nng lng li t. Tnh hiu sut ca my. A. 80%B. 82%C. 69% D. 89%Cu 14: Con lc l xo c cng k, chiu di l , mt u gn c nh, mt u gn vo vt c khi lng m.lKch thch cho l xo dao ng iu ho vi bin A trn mt phng ngang khng ma st. Khi l xo ang2dao ng v b dn cc i, tin hnh gi cht l xo ti v tr cch vt 1 on l , khi tc dao ng cc ica vt l:k k kk A. lB. l C. lD. lm6m2m 3mCu 15: Mt tia sng trng chiu ti bn hai mt song song vi gc ti i = 600. Bit chit sut ca bn mt ivi tia tm v tia ln lt l 1,732 v 1,70. B dy ca bn mt e = 2 cm. rng ca chm tia khi ra khibn mt l: A. 0,146 cm. B. 0,0146 m.C. 0,0146 cm. D. 0,292 cm.Cu 16: Da vo tc dng no ca tia t ngoi m ngi ta c th tm c vt nt trn b mt sn phm bngkim loi?25 26. A. kch thch pht quang.B. nhit. C. hy dit t bo. D. gy ra hin tng quang in.Cu 17: Trong th nghim Y-ng v giao thoa nh sng, mn quan st E cch mt phng cha hai khe S1S2 mtkhong D 1, 2 m. t gia mn v mt phng hai khe mt thu knh hi t, ngi ta tm c hai v tr ca thuknh cch nhau 72 cm cho nh r nt ca hai khe trn mn, v tr nh ln hn th khong cch gia hai khe nhS1 S2 4 mm. B thu knh i, ri chiu sng hai khe bng ngun im S pht bc x n sc 750nm th khong vn thu c trn mn lA. 0,225 mm. B. 1,25 mm. C. 3,6 mm.D. 0,9 mm.Cu 18: Pht biu no sau y l sai v nhc m. A. Si dy n c th pht ra y cc ha m bc chn v bc l. B. ng so mt u kn, mt u h ch pht ra cc ha m bc l. C. m thoa ch pht ra mt m, chnh l m c bn. D. th ca nhc m c tnh iu ha (theo qui lut hnh sin).Cu 19 : Trong dao ng in, i lng tng ng vi lc phc hi ca dao ng c l A. iB. ucC. uLD. QCu 20 : Trong thng tin lin lc bng sng v tuyn, ngi ta s dng cch bin iu bin , tc l lm chobin ca sng in t cao tn (gi l sng mang) bin thin theo thi gian vi tn s bng tn s dao ngm tn. Cho tn s ca sng mang l 1000 (kHz). Khi dao ng m tn c tn s 800 (Hz) thc hin mt daong ton phn th dao ng cao tn thc hin c s dao ng ton phn l A. 1000B. 800C. 1250D. 1600Cu 21 : Mch dao ng LC ang thc hin dao ng in t t do vi chu k T. Ti thi im no dngin trong mch c cng 8 (mA) v ang tng, sau khong thi gian 3T / 4 th in tch trn bn t c ln 2.109 C. Chu k dao ng in t ca mch bngA. 0,5ms.B. 0,25ms.C. 0,5 s.D. 0,25 s.Cu 22 : Cho mch in xoay chiu RLC khng phn nhnh, R = 50 (), C = 300/ (F), L = 2/ (H). t inp xoay chiu u = U0cos(2ft + ) vo hai u mch, gi nguyn Uo, thay i tn s f th thy mi gi tr ca ULch tm c mt gi tr ca tn s f tng ng. Tn s f khng th nhn gi tr A. 13 Hz. B. 15 Hz. C. 17 Hz. D. 11 Hz.Cu 23 : Mt con lc l xo thng ng gm vt nng c khi lng l 100g v mt l xo nh c cng100N/m. Ko vt xung di theo phng thng ng n v tr l xo dn 4 cm ri truyn cho n mt vn tc l 40 cm / s theo phng thng ng hng xung. Chn chiu dng hng xung. Coi vt dao ng iu hotheo phng thng ng. Tc trung bnh khi vt chuyn ng t v tr thp nht n v tr l xo b nn 1,5 cmln th hai l ? A.93,75 cm/s B.-93,75 cm/sC.-56,25 cm/s D. 56,25 cm/sCu 24 : t in p u = U 2 cos(t + ) (V) vo hai u mch RLC ni tip, cun dy thun cm, in dungC thay i c. Khi in dung c C = C1, o in p hai u cun dy, t in v in tr ln lt UL = 310Vv UC = UR = 155V. Khi thay i C = C2 UC2 = 155 2 V th in p hai u cun dy khi bng A. 175,3V. B. 350,6V.C. 120,5V. D. 354,6VCu 25: mt cht lng c hai ngun sng A, B cch nhau 19 cm, dao ng theo phng thng ng viphng trnh l uA = uB = acos20t (vi t tnh bng s). Tc truyn sng ca mt cht lng l 40 cm/s. Gi Ml im mt cht lng gn A nht sao cho phn t cht lng ti M dao ng vi bin cc i v cng phavi ngun A . Khong cch AM l26 27. A. 5 cm.B. 2 cm.C. 4 cm.D. 2 2 cm.Cu 26: Dao ng ca mt cht im l tng hp ca hai dao ng iu ha cng phng, c phng trnh li2 2 ln lt l x1 = 3cos(t - ) v x2 =3 3 cost (x1 v x2 tnh bng cm, t tnh bng s). Ti cc thi im3 2 3x1 = x2 li ca dao ng tng hp lA. 5,79 cm. B. 5,19cm.C. 6 cm.D. 3 cm.Cu 27: Trong th nghim giao thoa Y-ng, khong cch gia hai khe l 0,9 mm, khong cch t mt phng hai khen mn l 1 m. Khe S c chiu bng nh sng trng c bc sng 0,38 m 0,76 m . Bc x n sc no sauy khng cho vn sng ti im cch vn trung tm 3 mm?A. 0,65 m .B. 0,45 m .C. 0,675 m . D. 0,54 m .Cu 28: Mt khung dy dn phng c din tch 20 cm2 gm 1000 vng quay u vi tn s gc 3000 vng/phtquanh mt trc c nh nm trong mt phng khung dy, trong mt t trng u B = 1 T, vect cm ng tvung gc vi trc quay ca khung. Ban u vect php tuyn ca mt phng khung dy hp vi vect cmng t mt gc bng . Sut in ng cm ng trong khung c biu thc 3 A. e 200 cos(100 t ) VB. e 200 cos(100 t ) V6 6 C. e 100 cos(100 t ) VD. e 100 cos(100 t ) V3 3Cu 29: Thc hin th nghim Y-ng v giao thoa vi nh sng n sc mu ta quan st c h vn giaothoa trn mn. Nu thay nh sng n sc mu bng nh sng n sc mu lc v cc iu kin khc ca thnghim c gi nguyn thA. khong vn tng ln. B. v tr vn trung tm thay i.C. khong vn khng thay i. D. khong vn gim xung.Cu 30 : t in p xoay chiu u = U 2 cos(t ) ( U v khng i) vo hai u on mch gm in trthun R, cun cm thun c t cm L thay i c v t C mc ni tip. Khi L = L0 th in p hiu dnggia hai u cun dy t gi tr cc i. Khi L = L1 v L = L2 th in p hiu dng gia hai u cun dy cgi tr bng nhau. Lin h gia L0, L1, L2 lL1 L2 2L1 L22 L1 L2 L1 L2A. L0 . B. L0 . C. L0 . D. L0 . 2L1 L2 L1 L2 L1 L2Cu 31: Mt on mch AB gm hai on mch AM v MB mc ni tip. on mch AM gm in tr thunR mc ni tip vi t in C c in dung thay i c, on mch MB l cun dy thun cm c t cm L.Thay i C in p hiu dng ca on mch AM t cc i th thy cc in p hiu dng gia hai uin tr v cun dy ln lt l UR = 100 2 V, UL = 100V. Khi in p hiu dng gia hai u t in l:A. U C 100 3V B. U C 100 2V C. U C 200V D. U C 100VCu 32: Bin php no sau y khng gp phn tng hiu sut ca my bin p?A. Dng li thp c in tr sut nh.27 28. B. Dng li thp gm nhiu l thp mng ghp cch in vi nhau. C. Dng dy c in tr sut nh lm dy qun bin p. D. Thay li thp bng nhng kim loi khc c in tr sut nh, nh: ng, nhm, .Cu 33: Mch dao ng LC l tng gm cun dy cm thun L 0,39H v t in C 18,94nF . Thi gianngn nht gia hai ln in tch trn cng bn t khc du nhau nhng nng lng t trng bng nhau v bngWt 15.104 J l t 1,8.104 s . Tnh in tch cc i trn t in.A. 5,3.106 C B. 8,7.106 CC. 4,8.106 CD. 6, 2.106 CCu 34: Mt cht im dao ng iu ha khng ma st. Khi va qua khi v tr cn bng mt on S ngnng ca cht im l 1,8J. i tip mt on S na th ng nng ch cn 1,5J v nu i thm on S na thng nng by gi lA. 0,9J B. 1,0JC. 0,8J D. 1,2JCu 35: Bng n dy tc 220V-100W mc ni tip vi cun cm thun v t in. t vo hai u mch inp xoay chiu n nh. Ban u n hot ng ng nh mc, sau t b nh thng v ngn mch nn cngsut n gim mt na. Dung khng ca t ch c th nhn gi tr no sau y?A. 200 B. 264C. 345D. 310Cu 36: Nu ni hai u on mch gm cun cm thun L mc ni tip vi in tr thun R = 1 vo haicc ca ngun in mt chiu c sut in ng khng i v in tr trong r th trong mch c dng inkhng i cng I. Dng ngun in ny np in cho mt t in c in dung C = 2.10-6 F. Khi intch trn t in t gi tr cc i, ngt t in khi ngun ri ni t in vi cun cm thun L thnh mtmch dao ng th trong mch c dao ng in t t do vi chu k bng .10-6 s v cng dng in cci bng 8I. Gi tr ca r bng: A. 2 B. 0,25C. 1 D. 0,5Cu 37: Trn mt nc c hai ngun sng ging nhau A v B, cch nhau khong AB = 12cm dao ng vung gcvi mt nc to ra sng c bc sng = 1,6cm. C v D l hai im khc nhau trn mt nc, cch u hai ngunv cch trung im O ca AB mt khong 8(cm). S im dao ng cng pha vi ngun trn on CD l : A. 3. B. 6. C. 10.D. 5.Cu 38: Hai t C1 = 3C0 v C2 = 6C0 mc ni tip.Ni 2 u b t vi pin c sut in ng E = 3 V np incho cc t ri ngt ra v ni vi cun dy thun cm L to thnh mch dao ng in t t do.Khi dng introng mch dao ng t cc i th ngi ta ni tt 2 cc ca t C1.Hiu in th cc i trn t C2 ca mchdao ng sau l:A.2 V B.1V C. 3 V D.3VCu 39: Bn khung dao ng in t c cc cun cm ging ht nhau, cn cc t in th khc nhau. in dung cat in trong khung th nht l C1, ca khung th hai l C2 < C1, ca khung th ba l b t in gm C1, C2 ghp nitip, ca khung th t l b t in gm C1, C2 ghp song song. Tn s dao ng ring ca khung th ba lf3=5MHz, ca khung th t l f4= 2,4MHz. Hi khung th nht v th hai c th bt c cc sng c bc sng lnlt l 1 v 2 bng bao nhiu? Cho c = 3.108m/s. A. 1 = 75m; 2= 100m.B. 1 = 100m; 2= 75m. 28 29. C. B. 1 = 750m; 2= 1000m.D. 1 = 1000m; 2= 750m.Cu 40: Mt con lc l xo c t trn mt phng nghing nh hnh v.Cho bit vt m = 100g , cng l xo k = 10N/m, gc nghingk 600 . a vt ra khi v tr cn bng 5cm ri bung nh. m Do c ma st nn sau 10 dao ng vt ngng li. Ly g =10 m/s . H s ma st gia vt v mt phng nghing l: 2A.0,025 B. 0,25 C. 0,125 D.0,0125Cu 41: Trn mt h rt rng, vo bui ti, mt ngn sng dao ng vi phng trnh u 5cos(4 t / 2) . Mtci phao ni trn mt nc. Ngi ta chiu sng mt h bng nhng chp sng u n c 0,5s mt ln. Khi ngi quan st s thy ci phao.A. Dao ng vi bin 5cm nhng li gn ngun. B. Dao ng ti mt v tr xc nh vi bin 5cm.C. ng yn. D. Dao ng vi bin 5cm nhng tin dn ra xa ngun.Cu 42: Dng cc chp sng tun hon chu k 2s chiu sng mt con lc n ang dao ng. Ta thy, conlc dao ng biu kin vi chu k 30 pht vi chiu dao ng biu kin cng chiu dao ng tht. Chu k daong tht ca con lc l:A. 2,005sB. 1,978sC. 2,001sD. 1,998sCu 43: Mt ngi nh qun mt my h p t in p U1 = 220 (V) xung U2 =110 (V) vi li khng phnnhnh, xem my bin p l l tng, khi my lm vic th sut in ng hiu dng xut hin trn mi vng dyl 1,25 Vn/vng. Ngi qun ng hon ton cun th cp nhng li qun ngc chiu nhng vng cuica cun s cp. Khi th my vi in p U1 = 220V th in p hai u cun th cp o c l 121(V). Svng dy b qun ngc l: A. 9 B. 8C. 12D. 10Cu 44: Khi my pht in xoay chiu 3 pha v ng c khng ng b 3 pha hot ng th hin tng cmng in t xy ra (cc) b phn no?A. cc cun dy ca stato my pht in 3 phaB. cc cun dy ca stato my pht in 3 pha v rto ca ng c khng ng b 3 phaC. cc cun dy ca stato ng c khng ng b 3 phaD. cc cun dy ca stato my pht in 3 pha v cc cun dy ca stato ng c khng ng b 3 phaCu 45: Mt t xoay c in dung bin thin lin tc v t l thun vi gc quay t gi tr C1 = 10pF n C2 =370pF tng ng khi gc quay ca cc bn t tng dn t 00 n 1800. T in c mc vi mt cun dy ch s t cm L = 2H to thnh mch chn sng ca my thu. thu c sng c bc sng = 18,84mphi xoay t mt gc bng bao nhiu k t khi t c in dung nh nht?A. = 900 B. = 200C. = 1200 D. = 300Cu 46: Mt my bin th li i xng gm ba nhnh c tit din bng nhau, hai nhnh c cun hai cundy. Khi mc mt hiu in th xoay chiu vo mt cun th cc ng sc do n sinh ra khng b thot rangoi v c chia u cho hai nhnh cn li. Khi mc cun 1 vo mt hiu in th xoay chiu c gi tr hiu29 30. dng l 240V th cun 2 h c hiu in th U2. Hi khi mc vo cun 2 mt hiu in th U2 th cun 1 h c hiu in th bao nhiu? Bit rng in tr ca cc cun dy khng ng k. A. 60VB. 30V C. 40V D. 120V Cu 47: ngten s dng mt mch dao ng LC l tng thu sng in t, trong cun dy c t cm L khng i, cn t in c in dung C thay i c. Mi sng in t u to ra trong mch mt sut in ng cm ng. Xem rng cc sng in t c bin cm ng t u bng nhau. Khi in dung ca t in l C1= 2.10-6 F th sut in ng cm ng hiu dng trong mch do sng in t to ra l E1= 4V. Khi in dung ca t in l C2 = 8.10-6F th sut in ng cm ng hiu dng do sng in t to ra l: A. 0,5 V B. 2 VC. 1,5 VD. 1 V Cu 48: Trong th nghim giao thoa nh sng nu lm cho 2 ngun kt hp lch pha th vn sng chnh gia s thay i nh th no? A. Vn nm chnh gia ( khng thay i ).B. X dch v ngun sm pha hn. C. Khng cn vn giao thoa na.D. X dch v ngun tr pha hn. Cu 49: Mt con lc n gm mt dy kim loi nh c u trn c nh, u di c treo qu cu nh bng kim loi. Chiu di ca dy treo l l=1 m. Ly g = 9,8 m/s2. Ko vt nng ra khi v tr cn bng mt gc 0,1 rad ri th nh vt dao ng iu ho. Con lc dao ng trong t trng u c vect B vung gc vi mt phng dao ng ca con lc. Cho B = 0,5 T. Sut in ng cc i xut hin gia hai u dy kim loi l bao nhiuA. 0,3915 V B. 1,566 V C. 0,0783 VD. 2,349 V Cu 50: Xt hai mch dao ng in t l tng. Chu k dao ng ring ca mch th nht T1, ca mch th hai T2 = 2T1 .Ban u in tch trn mi bn t c ln cc i Qo.Sau mi t phng in qua cun cm ca mch. Khi in tch trn mi bn t ca hai mch u c ln bng q ( 0 < q < Qo ) th t s ln cng dng in trong mch th nht v th hai bng bao nhiu ? A. 1/4 B. 2C. 1/2 D. 2/3 S 2Cu 1 : vt thc hin ng thi hai dao ng iu ha cng phng c cc phng trnh sau: (li x tnh bngMtcm, thi gian t tnh bng giy s) x1 = 12cos(20t + /3) v x2 = 16cos(20t + 2). Bin ca dao ng tnghp A = 20 (cm). Pha ban u 2 l:A.2 = - /6. B.2 = /6.C. 2 = /3. D. 2 = -/2.Cu 2 : Mt cht im M chuyn ng vi tc 0,75 m/s trn ng trn c ng knh bng 0,5m. Hnhchiu M ca im M ln ng knh ca ng trn dao ng iu ho. Ti t = 0, M i qua v trcn bng theo chiu m. Khi t = 8 s li ca M l:A.22,64 cm.B. 45,38 cm.C.-22,64 cm. D. -45,38 cm.Cu 3 : on mch xoay chiu gm t in c in dung thay i c mc ni tip vi in tr thunR = 100 . t vo hai u mch in p xoay chiu c biu thc: u = 200cos(100t) (V). cng30 31. sut tiu th trong mch t gi tr cc i, in dung ca t in l: 10 - 4 10 4 2.10- 4 10- 4A.CF. B. C F.C. C F.D. C F5 2Cu 4 : Mch dao ng in t ring vi cun dy thun cm c h s t cm l L = 4mH v ti thi im t 10 6in tch trn t q = 36 sin( t ) nC. in dung ca t in (C) v cng dng in hiu dng 6(I) ti thi im c gi tr l:A.C = 9 F v I = 3 2 A.B. C = 9 F v I = 3 2 mA.C.C = 9 nF v I = 3 2 mA. D. C = 9 nF v I = 3 2 A. LCCu 5 : Cho on mch RLC ni tip nh hnh v.R A BCho cc in p hiu dng: UAM = UMN = 13V; M NUNB = UAB = 65V. Tn s ca mch in f = 50HzH s cng sut ca mch l :A.0,518 B. 0,385C.0,452 D. 0,355Cu 6 : iu no sau y l sai khi ni v ng c khng ng b ba phaA.Hot ng da trn c s hin tng cm ng B. T trng quay trong ng c l kt qu cain t v s dng t trng quay. vic s dng dng in xoay chiu mt pha.C.Bin i in nng thnh nng lng khc. D. C hai b phn chnh l Stato v Rto.Cu 7 : Chn cu sai khi ni v bin sng :A.Bin sng l bin dao ng ca ngun sng.B.Khi sng ch truyn theo phng mt ng thng th bin sng mi im nh nhau.C.Bin sng l bin dao ng ca cc phn t vt cht ni c sng truyn qua.D.Khi sng truyn t ngun im trn mt phng, bin sng gim theo qung ng truyn sng.Cu 8 : Khong cch gia hai ngn sng lin tip l 5 (m). Mt thuyn my i ngc chiu sng th tn sva chm ca sng vo thuyn l 4 Hz. Nu i xui chiu th tn s va chm l 2 Hz. Tnh Tc truyn sng. Bit tc ca sng ln hn Tc ca thuynA.5m/s. B. 13m/s. C. 14m/s. D. 15m/s.Cu 9 : Trong th nghim Ing v giao thoa nh sng, khong cch gia hai khe sng S1 v S2 l a = 1,56(mm), khong cch t S1, S2 n mn quan st l D = 1,24 m. o c khong cch gia 12 vnsng lin tip l 5,21 mm. Bc sng nh sng dng trong th nghim l:A. = 0,596.10-6 m.B. = 0,596 m.C. = 0,596.10-6 mm.D. = 0,596 mm.31 32. 2Cu 10 : Vt dao ng iu ha c vn tc cc i bng 3m/s v gia tc cc i bng 30 (m/s ). Thi im ban u vt c vn tc 1,5m/s v th nng ang tng. Hi vo thi im no sau y vt c gia tc bng 15 (m/s2):A. 0,10sB. 0,05sC. 0,15sD. 0,2sCu 11 : Cho mch in gm in tr R = 30 ni tip vi t in C. in p hiu dng gia hai bn cc t in l 60 V. in p t vo hai u mch c biu thc: u = 120cos100t (V). in dung ca t in l: -3-3A. C = 10 F. B. C = 10 F.3310 -3 3.10 -3C. C= F.D. C= F. Cu 12 : M t v t phat ra tia h ng ngoa i vao mi trng xung quanh phai co nhi t :A. trn 1000C.B.trn 0 K.C. trn 00C. D. cao hn nhi t mi trng.Cu 13 : Mt vt khi lng m dao ng iu ho vi chu k T = 1s. Khi i qua v tr cn bng, vt c vn tc l v = 0,628m/s. Chn gc thi gian ti thi im vt qua v tr c li x = -5cm theo chiu dng. Thi im th nng bng ng nng l:11 k11 kA. t (s) Vi k = 0; 1; 2; .. B. t (s) Vi k = 0; 1; 2; ..24 424 2k 11k 11C. t (s) Vi k = 1; 2; .. D. t (s) Vi k = 1; 2; ..2 244 24Cu 14 : Pht biu no sau y l ng khi ni v dao ng tng hp ca hai dao ng iu ha cng phng, cng tn s c pha ban u khc nhau?A. Tn s gc ca dao ng tng hp bng tn s gc ca cc dao ng thnh phn.B. Tn s ca dao ng tng hp bng tng cc tn s ca cc dao ng thnh phn.C. Bin ca dao ng tng hp bng tng cc bin ca cc dao ng thnh phn.D. Chu k ca dao ng tng hp bng tng cc chu k ca cc dao ng thnh phn.Cu 15 : Trong th nghim giao thoa sng, ngi ta to ra trn mt nc hai ngun sng A,B dao ng vi phng trnh uA = uB = 5cos 10t cm.Tc truyn sng trn mt nc l 20cm/s.Mt im N trn mt nc vi AN BN = - 10cm nm trn ng cc i hay cc tiu th my, k t ng trung trc ca AB?A. Cc tiu th 3 v pha A.B. Cc tiu th 4 v pha A.C. Cc tiu th 4 v pha B.32 33. D. Cc i th 4 v pha A.Cu 16 : Si dy n hi OA = l, u A c nh, u O dao ng vi phng trnh u = acos2ft. Sng phn x ti A c phng trnh:l 1 lA. upxA = acos2(ft - ). B.upxA = acos2(ft - ) . 2 l lC. upxA = acos2(ft - ).D.upxA = acos2(ft - ). 2Cu 17 : Mch dao ng LC ang thc hin dao ng iu ha, nng lng tng cng c chuyn hon ton t in nng trong t in thnh nng lng t trng trong cun cm mt 2 ms. Tn s dao ng ca mch l:A. 500HzB. 250HzC. 125HzD.1000Hz.Cu 18 : Con lc n gm dy khng dn chiu di l, khi lng qu cu m dao ng iu ho vi chu k T. Truyn in lng q cho qu cu v t con lc trong in trng u E c phng thng ng, con lc dao ng vi chu k T. Hy chn nhn xt ng:A. Nu q < 0 v E hng ln trn th T < T.B. Nu q > 0 v E hng xung di th T > T.C. Nu q < 0 v E hng xung di th T < T.D. Nu q > 0 v E hng ln trn th T < T.Cu 19 : t in p xoay chiu c gi tr hiu dng khng i vo mch RLC ni tip, tn s f thay i c .Khi f = fo = 100Hz th cng sut tiu th trong mch cc i. Khi f = 160Hz th cng sut trong mch bng P. Gim lin tc f t 160Hz n gi tr no th cng sut tiu th trong mch li bng P? Chn p n NG.A. 125Hz. B.40HzC. 62,5Hz D.90HzCu 20 : Mt con lc n c khi lng 100g, dao ng ni c g = 10m/s2, khi con lc chu tc dng mt lc F khng i hng t trn xung th chu k dao ng gim i 75%. ln ca lc F l:A. 20N. B. 15N. C. 5N.D.7,8N.Cu 21 : Mt on mch AB gm hai on mch AM v MB mc ni tip. on mch AM ch c bin tr R, on mch MB gm in tr thun r mc ni tip vi cun cm thun c t cm L. t vo AB mt in p xoay chiu c gi tr hiu dng v tn s khng i. iu chnh R n gi tr 80 th cng sut tiu th trn bin tr t cc i v tng tr ca on mch AB chia ht cho 40. Khi h s cng sut ca on mch MB v ca on mch AB tng ng lA. 3 5B. 33113 v . v . 8 811816033 34. C.1 2D.13v.v 172 84Cu 22 : iu no sau y l khng ng khi ni v quang ph lin tc?A. Quang ph lin tc ph thuc vo nhit ca ngun sng.B. Quang ph lin tc khng ph thuc vo thnh phn cu to ca ngun sng.C. Quang ph lin tc l nhng vch mu ring bit hin trn mt nn ti.D. Quang ph lin tc do cc vt rn, lng hoc kh c p sut ln khi b nung nng pht ra.Cu 23 : Vn tc truyn dao ng t A n M l 0,6m/s. Phng trnh dao ng ti M, cch A mt on d = 1,2m l: uM = acos(2t - 3). Coi bin sng khng i. Phng trnh dao ng ti A l:A. uA = acos(2t +).B. uA = acos(2t - ).C. uA = acos2t. D. uA = acos(2t + 2).Cu 24 : Chn cu ng. Trong qu trnh lan tuyn sng in t, vct cm ng t v vect cng in trng lun lun:A. Dao ng ngc pha nhau. B.Dao ng vung pha vi nhau.C. Cng phng v vung gc vi phng truyn sng. D.Dao ng cng pha vi nhau.Cu 25 : Hai vt thc hin hai dao ng iu ho theo cc phng trnh: x1 = 4cos(4t +) (cm) v 2 x2 = 2sin(4t + ) (cm). lch pha ca vn tc ca hai dao ng lA. 12 = - .B. 12 = 0.2C. 12 = . D. 12 =.2Cu 26 : Cho sng lan truyn dc theo mt ng thng. im M cch ngun mt khong d = /4, thi im t = T/3 c dch chuyn 6mm. Vi l bc sng v T l chu k. Coi bin sng khng i. Bin a ca sng bng:A. a = 4 3 mm.B. 3mm.C. a = 4 2 mm. D.a = 6mm.Cu 27 :10 4 1 t vo hai u on mch R, L, C: R = 50; C F v L H mc ni tip, hiu in th 22 xoay chiu u = 200cos100t (V). cng sut tiu th trn on mch t cc i th phi ghp thm vi t in C ban u mt t in C0 c in dung bao nhiu v cch ghp nh th no?10 410 4A. C0 F, ghp song song. B. C0 F, ghp ni tip. 2 3 10 43 10 4C. C0 .F, ghp ni tip. D. C0 .F, ghp song song. 2 2 34 35. Cu 28 : on mch xoay chiu gm cun dy c in tr thun R, t cm L mc ni tip vi t in c in dung C. in p t vo hai u mch c tn s f v gi tr hiu dng 37,5V. Khi dng in qua mch c cng hiu dng I = 0,1A; in p hiu dng gia hai u cun dy l 50V, gia hai bn cc t in l 17,5V. Nu cho tn s f thay i n gi tr f = 330Hz th cng dng in hiu dng t gi tr cc i. Tn s f c gi tr l:A. f 500 HzB. f 1000 Hz C. f 1000 HzD. f 500 HzCu 29 : Mt cht im chuyn ng thng dc theo trc xOx vi ta x = - 4cost (cm). Pht biu no sau y l sai?A. Cht im bt u dao ng t gc ta .B. Dao ng ca cht im l dao ng iu ha.C. Dao ng ca cht im l dao ng tun hon.D. Dao ng ca cht im c di qu o l 8cm.Cu 30 : Mt my pht in ba pha mc hnh sao c in p hiu dng pha 127 V v tn s 50Hz. Ngi ta a dng ba pha ny vo ba ti nh nhau mc hnh tam gic, mi ti c in tr thun 15 v t cm 51,3 mH. Cng dng in i qua cc ti l:A. 2,5A.B. 5A .C. 8A.D. 10A.Cu 31 : Mch in xoay chiu no sau y c h s cng sut ln nht ?A. T in C ni tip vi cun dy thun cm L.B. in tr thun R ni tip vi t in C.C. in tr thun R ni tip vi cun dy thun cm L.D. in tr thun R ni tip vi in tr thun R.Cu 32 : Trong on mch RLC ni tip ang xy ra hin tng cng hng. in p hiu dng gia hai u on mch khng i. Khi gim dn tn s dng in v gi nguyn cc thng s khc ca mch, pht biu no sau y l ng ?A. H s cng sut ca on mch tng.B. Cng hiu dng ca dng in gim.C. in p hiu dng trn in tr tng.D. in p hiu dng gia hai bn t in tng.Cu 33 : Nguyn nhn gy ra hin tng tn sc nh sng mt tri trong th nghim ca Niutn l:A. gc chit quang ca lng knh trong th nghim cha ln.B. chm nh sng mt tri b nhiu x khi i qua lng knh.C. chit sut ca lng knh i vi cc nh sng n sc l khc nhau.D. b mt ca lng knh trong th nghim khng nhn.Cu 34 : Ngi ta thc hin th nghim Y-ng v giao thoa nh sng, hai khe cch nhau 0,5mm vi nh sng n sc c bc sng = 0,5 m v quan st hin tng trn mn E cch mt phng cha hai khe 2 m. B rng vng giao thoa quan st trn mn l 26 mm v th nghim c thc hin trong nc35 36. c chit sut n = 4/3. S vn ti v vn sng quan st c trn mn l :A.16 vn ti, 17 vn sng. B. 16 vn ti, 15 vn sng.C.18 vn ti, 17 vn sng. D. 14 vn ti, 13 vn sng.Cu 35 :Vt nh c khi lng 200 g trong mt con lc l xo dao ng iu ha vi chu k T v bin 4cm. Bit trong mt chu k, khong thi gian vt nh c ln gia tc khng nh hn 500 2cm/s2 l T/2. cng ca l xo lA.20 N/m.B.30 N/m. C. 40 N/m.D. 50 N/m.Cu 36 :Trong th nghim Hcx, nu chiu nh sng hng ngoi vo l km tch in m th:A.in tch m ca l km mt i.B. tm km s trung ha v in.C.in tch ca tm km khng thay i D. tm km tch in dng.Cu 37 :Mt mch dao ng gm cun dy c t cm L = 0,2H v t in c in dung C = 10 F thchin dao ng in t t do vi cng dng in cc i trong mch I0 = 0,012A. Khi in pgia hai bn t l 0,94 V th cng dng in tc thi trong mch l:A.i = 0,1A.B.i = 0,01A.C. i = 0,01A D. i = 0,01mA.Cu 38 : 10 4on mch xoay chiu gm in tr thun R = 60, t in c in dung C (F), cun dy 0,2thun cm c t cmL = (H) mc ni tip . in p t vo hai u mch: u = 50 2 cos100t (V). Biu thc in p gia hai u in tr R l:37 53A.uR = 50 2 cos(100t - ) (V). B. uR = 30 2 cos(100t - ) (V).180 180 37uR = 30 2 cos(100t + 53 ) (V).C.uR = 10 2 cos(100t +) (V).D. 180 180Cu 39 :Cho mch in xoay chiu ch c t in. t vo hai u on mch mt in p xoay chiu nnh c biu thc u U 2 cos(100t / 3) (V) . th ca in p tc thi hai u on mchtheo cng dng in tc thi trong mch c dng lA.Hnh trnB.Hnh Elip C. Hnh sin D. on thngCu 40 :Chn p n ng. Trong th nghim Ing v giao thoa nh sng, a = 1mm; D = 1m. nh sng dngtrong th nghim l nh sng trng. hai vn ti ca hai bc x c bc sng 1 = 0,50m v2 = 0,75m trng nhau ln th nht ( k t vn sng trung tm) ti im cch vn trung tm mtkhong l:A.1 mm B.2 mmC. 2,5 mm D. Cc p n trn u sai. Cu 41Mt thanh g hnh hp ni trn mt nc c khi lng 200g din tch y s = 50cm2 .Ngi ta nhn n chm xung mt cht ri bung ra cho dao ng t do .Tnh tn s dao ng ca n .Cho bit khi36 37. lng ring ca nc =1000kg/m3 v g = 9,8 m/s2A. f = 50 HzB. f = 5,2 HzC. f = 25 HzD.f = 2,5 HzCu 42 Khi t in p xoay chiu 220V vo mt dng c P, th thy dng in trong mch c gi tr hiu dng bng 0,25A v sm pha so vi in p t vo l . Nu cng in p trn mc vo dng c Q2 th cng dng in cng bng 0,25A nhng cng pha vi dng in t vo. Cho P v Q ch cha 1 trong 3 linh kin: in tr thun, cun dy thun cm hoc t in. Khi t in p trn vo mch c P mc ni tip vi Q th dng in trong mch s c cng v lch pha so vi in p hai u mch l : 1 1 A. I= (A) v sm pha . B. I= (A) v tr pha .4 22 4 241 1C. I= (A) v sm pha . D. I= (A) v sm pha.4 44 2 4Cu 43 Trong k thut truyn thng bng sng in t, trn dao ng m thanh v dao ng cao tn thnh cao tn bin iu ngi ta phiA. bin tn s ca dao ng cao tn thnh tn s ca dao ng m tn.B. bin tn s ca dao ng m tn thnh tn s ca dao ng cao tn.C. lm cho bin ca dao ng cao tn bin i theo nhp iu (chu k) ca dao ng m tn.D. lm cho bin ca dao ng m tn bin i theo nhp iu (chu k) ca dao ng cao tn.Cu 44 Cho on mch xoay chiu gm hai phn t X v Y mc ni tip. Khi t vo hai u mch hiu in th xoay chiu c gi tr hiu dng U th hiu in th hiu dng gia hai u phn t X l 3 U, gia hai u phn t Y l 2U. Hai phn t X, Y tng ng l:A. T in v cun dy khng thun cm.B. T in v cun dy thun cm.C. Cun dy v in tr thun. D. T in v in tr thun.Cu 45 iu no sau y l ng khi ni v mi lin h gia in trng v t trng?A. T trng bin thin lun lm xut hin in trng bin thin.B. Tc bin thin ca t trng ln th in trng sinh c tn s cng ln.C. in trng bin thin u th t trng cng bin thin u.D. in trng bin thin u th sinh ra t trng khng i.Cu 46 Mt sng ngang dng sin truyn trn mt si dy theo chiu dng ca trc Ox, vi bc sng10 cm, tn s 400 Hz, bin 2 cm v pha ban u ti O bng 0. Coi bin sng khng i trong qu trnh truyn sng. Tm hiu ta ca hai im gn nht c lch pha l .2A. x = 10 cm.B. x = 5,0 cm C. x = 2,5 cm. D.x = 7,5 cm37 38. Cu 47 Mt con lc l xo c cng 100N/m, vt nng c khi lng m = 100g dao ng trn mt phng nm ngang. Cho g = 10m/s2. Ko vt khi v tr cn bng mt on 10 cm ri th nh. Qung ng m vt i cho n khi dng hn l 25m. H s ma st gia vt v mt phng ngang l :A. = 0,02. B. = 0,15. C. = 0,01.D. = 0,03.Cu 48 Mch dao ng li vo ca mt my thu thanh c th bt c cc sng ngn v sng trung c bc sng t 10 m n 1km. Bit in dung C ca t in bin thin trong khong t 15 pF n 860 pF ; vn tc nh sng trong chn khng c = 3.108m/s. t cm L ca mch bin thin trong khong :A. 1,87 H L 328 H B. 1,87 H L 328 mH.C. 1,87 mH L 328 mH D. 1,87 H L 328 HCu 49 Trong th nghim Y-ng, hai khe cch nhau 1,5mm c chiu bi nh sng trng (c bc sng 0,38 m 0,76 m). Mn M quan st vn giao thoa cch mt phng cha hai khe mt khong 1,2m. im A trn mn M, cch vn chnh gia 2 mm. Bc x no c bc sng sau y khng cho vn sng ti A ?A. = 500 nm. B. = 525 nm. C. = 625 nm.D. 417 nm.Cu 50 Trong th nghim Y-ng ngi ta chiu ng thi hai bc x mu v mu tm vo cnh ca mt lng knh c gc chit quang A = 80 theo phng vung gc vi mt phng phn gic ca gc chit quang. Bit chit sut ca lng knh i vi nh sng v nh sng tm l 1,61 v 1,68. Sau lng knh t mn nh M song song v cch mt phng phn gic ca gc chit quang mt khong 1m. Khong cch gia hai vt sng trn mn m l:A. 1,22cmB. 1,04cmC. 0,97cm.D. 0,83cm. S 3Cu 1: Khi t mt in p xoay chiu vo hai u mch gm in tr thun R = 30 mc ni tip vi mt t2in C th biu thc dng in c dng1 = 3 cos 100 + 3 .Mc ni tip thm vo mch in cun dythun cm L ri mc vo in p xoay chiu ni trn th biu thc dng in c dng 2 = 3(100 + ).Biu thc in p hai u mch l:6 A. = 45cos (100 + ) VC. = 180cos(100 + ) V2 22 B. = 90cos (100 +)VD. = 60 3cos (100 + 2 ) V3 Cu 2: Mt vt dao ng iu ha vi phng trnh x = 10cos( 6t + 3 ) cm. Hy xc nh tc trung bnh lnnht ca vt trong mt phn ba chu k dao ng? A. 180 30 cm/s B. 90 cm/sC. 50 cm/s D. 90 30 cm/sCu 3: To ra sng dng trn mt si dy c u B c nh, ngun sng c phng trnh x = 3cos( 2t + 3 ) cm.Bc sng trn si dy l 30 cm. Gi M l mt im trn si dy dao ng vi bin A = 3 cm. Hy xc nhkhong cch BM nh nht? A. 5 cm B. 15 cm C. 2,5 cmD. 7,5 cm 38 39. Cu 4: Mt hc sinh thc hnh o in tr(r1,r2) ca dy qun cun s cp v th cp ca my bin p, c t svng dy ca cun s cp v s vng dy ca cun th cp l 2, hc sinh mc vo hai u cun th cp mtin tr R = 30. u tin hc sinh mc vo hai u cun s cp mt in p U1 = 131V th o c in p hai u cun th cp l 60V, sau hc sinh thay in p U1 bng in p U2 = 262V th o c in phai u cun th l 120V, tnh r1,r2? A. r1 = 3, r2 = 2C. r1 = 0, r2 = 2 B. r1 = 4, r2 = 0D. r1 = 2, r2 = 3Cu 5: Mt khe F hp pht nh sng trng chiu sng hai khe F1, F2 song song vi F v cch nhau 1,2mm. Mnquan st M song song vi mt phng cha F1, F2 v cch n 3m. Cho bit bc sng nh sng nhn thy c giihn t 380nm n 760nm. Ti im A trn mn M cch vn trng trung tm 4mm c my vn sng? Ca nhngbc x no?A. C 3 vn sng ca 1 = 380nm, 2 = 570nm v 3= 760nm.B. C 2 vn sng ca 1 = 600nm v 2 = 480nm.C. C 3 vn sng ca 1 = 600nm, 2 = 480nm v 3 = 400nm.D. C 3 vn sng ca 1 = 380nm, 2 = 600nm v 3 = 760nm.Cu 6: Cho phn ng ht nhn: p + 3 2 + 16,3MeV. Cho NA = 6,023.1023 mol-1. Tnh nng lng ta 7ra khi to c 2g Hli ?A. 24,54.1024 MeV. B. 2,454.1023 MeV. C. 24,54.1023 MeV. D.13,02.1023 MeVCu 7: Cho A,M,N,B l 4 im lin tip trn mt on mch xoay chiu khng phn nhnh, on mch AMcha R, on mch MN cha cun dy thun cm L v on mch NB cha t inC. Bit biu thc hiu inth trn cc on AN v MB ln lt l:uAN= 40cos(t+/6) (V); uMB=50cos(t - /2) (V). Xc nh biu thcin p gia hai u on mch AB? 5536 A. = 10 37 cos 180 C. = 5 74 cos 180 B. = 40 41 cos D . = 10 3 cos 180180Cu 8: on mch RLC mc ni tip, in tr c th thay i c. Cho Zc = 121 , khi R1 = 108 v R2 =147 th mch cho cng 1 cng sut P < Pmax . Tnh ZLA. ZL = 5 B. ZL = 247 C. p n khc D. C A v CCu 9: Mt con lc l xo nm ngang gm 1 l xo c cng k(N/m) v vt c khi lng m(g) . Ti 1 thiim t no vt ang c ln lc hi phc bng F = 2N. Hi sau T/4 vt c ln vn tc bng baonhiu ? A. v = F/ . (m/s)B. F. . (m/s) C. F/10 . (m/s)D. F.10/ . (m/s)Cu 10: Mt vt dao ng iu ha vi phng trnh x = A.cos( 10t + ) cm.Gia tc t cc i ti u ? A: Ti v tr ng nng cc i B: Ti v li cc tiu C: ti v tr li cc i D: Khng phi cc p n trnCu 11: Hai ngun sng S 1, S 2 dao ng cung pha v cch nhau 8 cm.Trn mt cht lng c mt im Mkhng thuc S 1S 2 c tng khong cch ti hai ngun bng 15cm . khong cch ln nht t M ti S2 l ( bitkhong cch l mt s nguyn )A . 11cm `B:12 cm C: 9 cm D: 13cmCu 12: Chiu nh sng trng i qua lng knh c gc chit quang 30o th thy nh sng tm c gc lch cctiu. Hy tm gc lch ca tia bit n d = 1,54; n t = 1,58.A: 16o 50B: 16,5oC: 15o 6 D: 15,6o39 40. Cu 13: Mt qu cu c lm bng kim loi c gii hn quang in 0,39, bn knh bng 20cm, c chiubng nh sang t ngoi c bc sng 0,25 (th nghim c thc hin trong khng kh) cho k = 9.109N.m2/C2. Hy xc nh in tch cc i m qu cu c th tch c?A.39,6pC B. 7,93pC C. 3,96pCD. 79,3pCCu 14: Cho ng so c mt u bt kn v mt u h. Bit rng ng so pht ra m to nht ng vi hai gitr tn s ca hai ha m lin tip l 150 Hz v 250 Hz. Tn s m nh nht khi ng so pht ra m to nht bngA. 50 Hz.B. 75 Hz. C. 25 Hz.D. 100 Hz.Cu 15: Cho on mch in xoay chiu RLC(cun dy thun cm) mc ni tip trong t in c indung thay i c bit in p hai u on mch l u = 200cos100t (V) khi C = C1 = 2,5.105 F v C = C2= 5.105 F th mch cho cho cng mt gi tr hiu dng ca t in , tnh cm khng?A: 300B: 200 C: 100D: 400/3Cu 16: Dung dch Fluorxin hp th nh sng c bc sng 0,55m v pht ra nh sng c bc sng0,59m. ngi ta gi hiu sut ca s pht quang l t s gia nng lng nh sng pht quang v nng lngnh sng hp th. Bit hiu sut ca s pht quang ca dung dch Fluorxin l 62,5%. S phn trm ca phtnb hp th dn n s pht quang ca dung dch lA: 62,92%B: 79,6%C: 67,05%D: 77,8%Cu 17: on mch ni tip gm 3 phn t: in tr thun R, cun cm thun L v t in C mc vo mngin xoay chiu c tn s f1 th cm khng l 36 v dung khng l 144 . Nu mng in c tn s f2 = 120Hz th cng dng in cng pha vi in p hai u on mch. Gi tr f1 lA: 240 Hz. B: 60 Hz. C: 30 Hz.D: 480 Hz. Cu 18: Mt toa xe trt khng ma st trn mt ng dc xung di, gc nghing ca dc so vi mt phngnm ngang l = 450. Treo ln trn toa xe mt con lc n gm dy treo chiu di l = 1,2 m ni vi mt qucu nh. Trong thi gian xe trt xung, kch thch cho con lc dao ng iu ho vi bin gc nh. B quama st, ly g = 10 m/s2. Chu k dao ng ca con lc l : 2,59 s. :2,19 s.: 1,83s. : 1,38 s.Cu 19: Mc on mch gm cun dy thun cm ni tip vi mt in tr thun vo ngun in xoay chiuth h s cng sut ca mch bng 0,5. Nu ch gim t cm ca cun dy i 3 ln th khi h s cng sutca mch s bng 3 2 A. 2 B. 0,4 C.D. 0,6 2 2Cu 20: Mt vt dao ng vi phng trnh x = 10cos(2 + ) . Thi gian ngn nht vt i qua v tr c 3tc 10 cm/s v c ln li ang tng l ? 7171 A: 12 B: 4 C: D: 12 12Cu 21: Ngi ta a mt con lc n t mt t ln mt ni c cao 1,344 km. Hi nhit ca n phithay i nh th no chu k dao ng khng thay i( R = 6400Km, h s n di = 1,4. 104 1 )A:tng nhit thm 60C B:gim nhit i 30CC. tng nhit thm 30CD: gim nhit i 60C40 41. Cu 22: Chiu chm sng gm 3 nh sng n sc vng, lam, chm vo lng knh c gc chit quang 45o theophng vung gc vi mt bn AB. Bit chit sut ca tia vng vi cht lm lng knh l 2 . Xc nh s bcx n sc c th l ra khi mt bn kia ca lng knh.A: 0 B: 1 C: 2 D: 3Cu 23: Trn mt si dy n hi AB ang c sng dng vi hai u l nt ,AB = 20cm bc sng trn dybng 2cm, tm im gn nht vi B dao ng cng pha vi im M cch B 15,76cm v c bin bng bin dao ng ti ngun?A.0,76cm B. 1,33cmC. 0,33cmD. 1,76cm84Cu 24: Ht nhn 210 phng x v bin i thnh ht nhn ch bn. Ban u trong mu Po cha mt lng1,23 (g). B qua nng lng ca photon gama. Khi lng ht nhn con to thnh sau bn chu k bn r l ? A: 1,207gB:1,131gC: 0,075gD: 1,153gCu 25: Trong mt khng gian ang c sng cu vi ngun t ti O , trn im A cch ngun mt khong RAc bin 7cm, bin ti mt im B ( O,A,B thng hng ) l 2cm, tnh bin ti mt im C l trung imca AB A: 28/9cm B: 9/2cm C:371/8cmD. t = 53/14Cu 26: Dng in trong mch LC l tng c dng i = 0,02cos(2000t) (A). Thi gian ngn nht k t lc banu, dng in c ln bng dng in hiu dng lA.1,25.104 s B.1,25 C.2,5 D.2,5.104Cu 27: Mt nh my pht in gm n t my c cng cng sut P hot ng ng thi. in sn xut ra ca ln ng dy v truyn n ni tiu th vi hiu sut truyn ti l H. Hi khi ch cn mt t my hotng bnh thng th hiu sut truyn ti H l bao nhiu? Coi in p truyn ti, h s cng sut truyn ti vin tr ng dy khng i.A.H = H/n B. H = HC. H = (n +H-1)/nD. H = nHCu 28: Cho c h nh hnh vmCon lc l xo c cng k = 100N/m v khi lng m = 250g. Vt M ang ng yn ti VTCB cch tng 1khong 9cm. ngi ta ko vt m vo v tr l xo nn 3cm sau truyn cho n mt vn tc 60 11cm/s chovt giao ng iu ha. Tnh chu k dao ng ca vt , bit trong qu trnh dao ng vt va chm n hi vitng A: 10 (s)B: 24 (s) C: 15 (s)D: 12 (s)Cu 29: Mt vt c khi lng ngh m o. khi chuyn ng vi vn tc v = 0,8c th khi lng ca n l baonhiu?A: khng i B: 1,25m oC: 1,66m o D: 0,6m oCu 30: Nu quan nim nh sng ch c tnh cht sng th khng th gii thch c hin tng no di y?A: Khc x nh sng. B: Giao thoa nh sng.C: Quang in. D: Phn x nh sng.41 42. Cu 31: Trong th nghim Ing v giao thoa nh sng, khong cch gia hai khe l a=1,5mm, khong cch thai khe n mn l D=1,5m v ngun sng pht hai bc x c bc sng 1=480nm v 2=640nm. Kch thcvng giao thoa trn mn l L=2cm (chnh gia vng giao thoa l vn sng trung tm) S vn sng quan st ctrn mn lA: 54. B: 72.C: 61. D: 51.Cu 32: Cho mch in xoay chiu LRC mc ni tip, cun dy c t cm L in tr thun r . in dung Cbin thin. iu chnh C n gi tr no sau y th in p hiu dng hai u on mch cha t in v intr thun R t gi tr nh nht?2 + 2 + 2 2 . 2 2 + 2 + 2 . 2 .B. 2 +2 +2 C.D. 2 + 2 + . 22 . 2 2Cu 33: Mt mch dao ng gm mt t in c in dung 1000pF v mt cun cm c t cm 10F, vmt in tr 1 . Phi cung cp mt cng sut bng bao nhiu duy tr dao ng ca n, khi hiu in thcc i hai u t in l U 0 = 2 (V). Hy chn kt qu ng trong cc kt qu sau:A: P = 2.104 WB: P = 4.104 W C: P = 0,0001W D: P = 0,00001WCu 34: Mt con lc l xo dao ng tt dn trn mt phng nm ngang vi cc thng s nh sau: m = 0,1kg, Vmax = 1m/s, = 0,05. Tnh ln vn tc ca vt khi vt i c 10cm. A. 0,95cm/s B: 0,3cm/s C: 0,95m/sD: 0,3m/sCu 35: th biu din mi lin h gia lc hi phc v ng nng ca con lc l xo l :A. Mt ng hnh sinB. mt ng thng C. mt ng elip D. mt ng trnCu 36: Thc hin giao thoa sng c trn mt nc vi hai ngun cng pha S1; S2 cch nhau 12 cm. Bit bcsng ca sng trn mt nc l = 3cm. Trong vng giao thoa c mt im M nm trn ng cc i k = 1 (M gn ngun 2 hn ). C bao nhiu im dao ng cng pha vi hai ngun trn on S2M ?A: 4 imB: 2 imC: 6 imD: 3 im 1 Cu 37: Cho mch in RLC mc ni tip , cun dy thun cm c L = H, t in c in dung C bin thin .t mt in p xoay chiu c gi tr hiu dng khng i vo hai u on mch . iu chnh in dung ca tin , khi C = C1 hoc C = C2 th Uc c cng mt gi tr . Bit C1 = 4C2 . tnh C1 v C2?10 310 3 10 310 3 A:(F) v(F)B.(F) v(F) 4 4 16 10 3 10 310 3 10 3C:(F) v (F)D:(F) v(F)28 3 12 Cu 38: C 3 ngun m c tn s 20Hz, 40Hz v 60Hz khi tng hp chng li thnh mt ngun m th tn sl:A: 60Hz. B: 120Hz.C: 40Hz.D: 20Hz.Cu 39: Chn cu ng. Chiu di ng so cng ln th m pht raA: Cng caoB: Cng trm C: Cng toD: Cng nhCu 40: dao ng c L = 10 mH, c C = 10 pF ang dao ng. Lc t = 0 cng tc thi ca mch c gi trcc i v bng 31,4 mA. Biu thc cng dng in trong mch l:. = 31,4. cos 106 B. = 31,4. cos 107 C. = 31,4. cos 106 D. = 31,4. cos 107 2242 43. Cu 41: Pht biu no sau y l sai khi ni v in t trng?A: in trng v t trng l hai mt th hin khc nhau ca mt loi trng duy nht gi l in t ttrngB: Nam chm vnh cu l mt trng hp ngoi l ch c t trngC: in trng bin thin no cng sinh ra t trng bin thin v ngc liD: Khng th c in trng v t trng tn ti c lpCu 42: Ti im M trn mn c vn sng bc 10. Dch mn i so vi v tr c 10 cm th cng ti M c vn tith 10 k t vn sng trung tm. Khong cch t mt phng cha hai khe n mn trc khi dch chuyn l? A: D = 1,2mB: D = 1,9m C: D = 1,5mD: D = 1mCu 43: Mt ngun sng n sc = 0,6m chiu vo mt mt phng cha hai khe h S1, S2, hp, song song,cch nhau 1mm v cch u ngun sng. t mt mn nh song song v cch mt phng cha hai khe 1m. Nukhng t bn thu tinh m y vo khong gia khe v mn mt cht lng c chit sut n, ngi ta thykhong cch gia hai vn sng lin tip bng 0,45mm. Tnh chit sut n ca cht lng ?A: 1,5B: 1,33 C: 1,4D: 1,6Cu 44: Catt ca t bo quang in chn khng l mt tm kim loi phng c gii hn quang in l o = 0,6 m . Chiu vo catt nh sng c bc sng = 0,5 m. Ant cng l tm lim loi phng cch catt 1cm. Giachng c mt hiu inth 10V. Tm bn knh ln nht trn b mt ant c quang electron p ti.A: R = 4,06 mm B: R = 4,06 cmC: R = 8,1 mmD: R = 6,2 cmCu 45: Trong quang ph hidro, khi e chuyn t qu o L v K s pht ra photon c bc sng o. Gi lbc sng ca tia lam trong dy Banme. Hy xc nh ?A. 5,4 o B: 4 o C: 4,5 o D: 6 oCu 46: Khi chiu ln lt hai bc x in t c bc sng 1 v 2 vi 2 = 2 1 vo mt tm kim loi th ts ng nng ban u cc i ca quang electron bt ra khi kim loi l 9. Gii hn quang in ca kim loi lo. Mi quan h gia bc sng 1 v gii hn quang in o l?A: 1 = 3/ 5 0B: 1 = 5/ 7 oC: = 5/ 16 oD: = 7/16 oCu 47: Nguyn t 13 . Tm khi lng nguyn t ca lu hunh theo n v u? Bit m p = 1,00728u; m n =361,00866u; m e = 5,486.10-4 u.A: 36 uB: 36,29382uC: 36,3009518u D: p n khcCu 48: Ti thi im to t s gia lng cht cn li v lng cht phng x l 1/7 . Bit chu k bn r cacht trn l 12 nm. Hi sau bao nhiu nm th t s trn l 1/31 . A: 20 nmB: 27,3 nm C: 36,8 nm D: 24 nm Cu 49 : Mt song c lan truyn trn mt si dy n hi c bin A khng i , c hai im M,N cng nmtrn phng truyn sng vi M nm gn ngun hn, ti thi im t c = A/2 theo chiu dng, v tip sau thi im t = T/3 th 2 im M,N c cng li , tnh lch pha ca hai dao ng ? 2 A: = B. =C: =D: = 3 3 2643 44. Cu 50: Khng nh no sau y l ng?Ti VTCB :A.ng nng v vn tc t cc i.B.Th nng t cc tiu,lc hi phc t cc tiu.C.Gia tc t cc tiu, vn tc i cc i.D.Th nng cc tiu, tc cc i. S 4Cu 1: Mt vt dao ng iu ha vi bin A, chu k T. Qung ng ln nht m vt i c trong khongthi gian t=3T/4 lA. 3A.B. A(2+ 2 ).C. 3A/2. D. A(2+ 3 ).Cu 2: Con lc l xo treo thng ng, cng k = 80N/m, vt nng khi lng m = 200g dao ng iu ho theophng thng ng vi bin A = 5cm, ly g = 10(m/s2). Trong mt chu k T, thi gian l xo gin l A.(s) B. (s) C.(s) D. (s). 24 1230 15Cu 3: Mt con lc l xo DH theo phng thng ng vi phng trnh x = 10cos( t-/6) (cm). T s ln ca lc n hi cc i v cc tiu ca l xo khi vt dao ng bng 7/3. Cho g = 2 (m/s2). Chu k dao ngca vt lA. 0,25s B. 0,5s C. 1,0sD. 10s.Cu 4: Mt con lc l xo treo thng ng, t v tr cn bng O ko con lc v pha di, theo phng thngng, thm 3cm ri th nh, con lc dao ng iu ha quanh v tr cn bng O. Khi con lc cch v tr cn bng1cm, t s gia th nng v ng nng ca h dao ng lA. 1/8B. 1/9.C. 1/2.D. 1/3.Cu 5: Mt vt m, nu gn vi l xo k1 th dao ng vi chu k 0,6s v nu gn vi l xo k2 th dao ng vichu k 0,8s. Nu cho hai l xo ghp song song ri gn vt vo th vt dao ng vi chu k lA. 1,4sB. 1sC. 0,48sD. 0,24s.Cu 6: Mt vt m gn vi mt l xo th n dao ng vi chu k 2s. Ct l xo ny ra lm hai phn bng nhau rimc song song v treo vt vo th chu k dao ng ca vt lA. 1s .B. 2s . C. 4s. D. 0,5s.Cu 7: Vt nh c khi lng 200 g trong mt con lc l xo dao ng iu ha vi chu k T v bin 4 cm.Bit trong mt chu k, khong thi gian vt nh c ln gia tc khng nh hn 500 2 cm/s2 l T/2. cng ca l xo lA. 20 N/m. B. 50 N/m.C. 40 N/m.D. 30 N/m.Cu 8: Mt con lc l xo gm l xo nh c cng 100 N/m v vt nh khi lng m. Con lc dao ng iuTha theo phng ngang vi chu k T. Bit thi im t vt c li 5cm, thi im t+ vt c tc 50cm/s.4Gi tr ca m bngA. 0,5 kgB. 1,2 kg C.0,8 kg D.1,0 kgCu 9: Con lc l xo treo thng ng, l xo c khi lng khng ng k. Hn bi ang v tr cn bng thc ko xung di theo phng thng ng mt on 3cm ri th ra cho n dao ng. Hn bi thc hin 50dao ng mt 20s. Cho g 2 10m / s2 . T s ln lc n hi cc i v lc n hi cc tiu ca l xo khidao ng l:A. 7 B. 5C. 4 D. 3Cu 10: Trong dao ng iu ho ca con lc n, pht biu no sau y l ng ?A. Lc ko v ph thuc vo chiu di ca con lc.B. Lc ko v ph thuc vo khi lng ca vt nng.44 45. C. Gia tc ca vt ph thuc vo khi lng ca vt. D.Tn s gc ca vt ph thuc vo khi lng ca vt.Cu 11: ni m con lc n m giy (chu k 2 s) c di 1 m, th con lc n c di 3m s dao ngvi chu k l A. T = 6 s B. T = 4,24 sC. T = 3,46 sD. T = 1,5 sCu 12: Mt con lc n c di l, trong khong thi gian t n thc hin c 6 dao ng. Ngi ta gimbt di ca n i 16cm, cng trong khong thi gian t nh trc n thc hin c 10 dao ng. Chiu dica con lc ban u lA. l = 25m. B. l = 25cm. C. l = 9m.D. l = 9cm.Cu 13: Ti mt ni c hai con lc n ang dao ng vi cc bin nh. Trong cng mt khong thi gian,ngi ta thy con lc th nht thc hin c 4 dao ng, con lc th hai thc hin c 5 dao ng. Tngchiu di ca hai con lc l 164cm. Chiu di ca mi con lc ln lt l.A. l1 = 100m, l2 = 6,4m.B. l1 = 64cm, l2 = 100cm.C. l1 = 1,00m, l2 = 64cm. D. l1 = 6,4cm, l2 = 100cm.Cu 14: Mt ngi quan st sng trn mt h thy khang cch gia hai ngn sng lin tip bng 2m v c 6ngn sng qua trc mt trong 8s. Tnh vn tc truyn A. v = 1,25 m/sB. v = 1,5 m/s C. v = 2,5 m/sD. v = 3 m/sCu 15: t 1 m thoa st ming 1 ng nghm thng ng bn trong l khng kh. Cho m thoa rung vi tns f = 850Hz, n pht ra 1 m rt yu. t t nc vo ng n lc ct khng kh trn mt nc c chiu caoh = 50cm th m nghe mnh nht( cng hng m ).Tnh vn tc truyn m trong khng kh.Cho bit 320m/s (3) > (4) > (1) > (5) > (6) D. (3) < (1) < (4) < (2) < (5) < (6)Cu 23: t chy hon ton mt hn hp X (glucoz, fructoz, metanal v etanoic) cn 3,36 lt O2 (iu kinchun). Dn sn phm chy qua bnh ng dung dch Ca(OH)2 d, sau phn ng hon ton thu c m gam ktta. Gi tr ca m lA. 10,0 B. 12,0C. 15,0 D. 20,5Cu 24: in phn 2 lt dung dch cha hn hp gm NaCl v CuSO4 vi in cc tr, c mng ngn n khiH2O bt u in phn c hai cc th dng li. Ti catt thu 1,28 gam kim loi ng thi ti ant thu 0,336 ltkh ( ktc). Coi th tch dung dch khng i th pH ca dung dch sau in phn l:A. 3B. 12C. 13 D. 2Cu 25: Ion R3+ c cu hnh electron phn lp ngoi cng l 3d5. V tr ca R trong bng tun hon l:A. Chu k 4, nhm VIIB B. Chu k 3 nhm VIIIB C. Chu k 4 nhm VIIIB D. Chu k 4, nhm IIBCu 26: Cht bo X c ch s axit l 7. trung ha lng axit c trong 10 kg X cn va m gam NaOH. Gitr ca m l:A. 55 B. 70C. 50 D. 60Cu 27: Khi cho hn hp Fe3O4 v Cu vo dung dch H2SO4 long d thu c cht rn X v dung dch Y. Dyno di y gm cc cht u tc dng c vi dung dch Y?A. KI, NH3, NH4Cl B. BaCl2, HCl, Cl2 C. NaOH, Na2SO4,Cl2 D. Br2, NaNO3, KMnO4Cu 28: Cho cc cht sau: axetilen, axit fomic, fomanehit, phenyl fomat, glucz, anehit axetic, metyl axetat,mantz, natri fomat, axeton. S cht c th tham gia phn ng trng gng l 69 70. A. 8B. 5C. 6D. 7Cu 29: Cho m gam hp cht hu c X c cng thc phn t l C3H6O2 tc dng hon ton vi 200 ml dungdch KOH 0,7M thu c dung dch Y. C cn Y thu c 12,88 gam cht rn khan. Cng thc cu to ca Xv gi tr ca m lA. HCOOCH2CH3 v 8,88 gam.B. CH3COOCH3 v 6,66 gam.C. C2H5COOH v 8,88 gam.D. C2H5COOH v 6,66 gam.Cu 30: t chy 3,2 gam mt este E n chc, mch h c 3,584 lt CO2 (ktc) v 2,304 gam H2O. Nucho 15 gam E tc dng vi 200 ml dung dch NaOH 1M, c cn dung dch sau phn ng thu c 14,3 gamcht rn khan. Vy cng thc ca ancol to nn este trn c th lA. CH2=CH-OHB. CH3OHC. CH3CH2OH D. CH2=CH-CH2OHCu 31: Ancol X, anehit Y, axit cacboxylic Z c cng s nguyn t H trong phn t v u no, n chc,mch h. t hon ton hn hp 3 cht trn (c s mol bng nhau) thu c t l mol gia CO2 v H2O l11:12. Cng thc phn t ca X, Y, Z l:A. CH4O, C2H4O, C2H4O2B. C4H10O, C5H10O, C5H10O2C. C2H6O, C3H6O, C3H6O2 D. C3H8O, C4H8O, C4H8O2Cu 32: S nguyn t ha hc m nguyn t ca n c electron cui cng in vo phn lp 4s l:A. 12 B. 1C. 10 D. 2Cu 33: a mt hn hp kh N2 v H2 c t l 1: 3 vo thp tng hp, sau phn ng thy th tch kh i ragim 1/10 so vi ban u. Hiu sut ca phn ng tng hp NH3 l:A. 10%B. 20%C. 15%D. 25%Cu 34: X l hn hp cc mui Cu(NO3)2, Zn(NO3)2, Fe(NO3)3, Mg(NO3)2. Trong O chim 9,6% v khilng. Nung 50 gam X trong bnh kn khng c oxi n khi phn ng xy ra hon ton thu c m gam oxit.Gi tr ca m lA. 44,6 B. 39,2 C. 17,6 D. 47,3Cu 35: Cho 29,8 gam hn hp 2 amin n chc k tip tc dng ht vi dung dch HCl, lm kh dung dchthu c 51,7 gam mui khan. Cng thc phn t 2 amin lA. C2H5N v C3H7N B. CH5N v C2H7NC. C3H9N v C4H11ND. C2H7N v C3H9NCu 36: Trong cc ho cht Cu, C, S, Na2SO3, FeS2 , O2, H2SO4 c. Cho tng cp cht phn ng vi nhautrong iu kin thch hp th s cp cht c phn ng to ra kh SO2 lA. 6B. 7C. 9D. 8Cu 37: nhn bit ba l mt nhn: phenol, stiren, ancol benzylic, ngi ta dng mt thuc th duy nht lA. Ca(OH)2B. Dung dch NaOH C. Nc bromD. Na 70 71. Cu 38: Ha tan hon ton 6,44 gam hn hp bt X gm FexOy v Cu bng dung dch H2SO4 c nng (d).Sau phn ng thu c 0,504 lt kh SO2 (sn phm kh duy nht, ktc) v dung dch cha 16,6 gam hn hpmui sunfat. Cng thc ca oxit st l:A. FeOB. Fe3O4C

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