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SWBAT: Solve quadratic equations with complex roots.

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  • SWBAT: Solve quadratic equations with complex roots.

  • SWBAT: Solve quadratic equations with complex roots.

  • SWBAT: Solve quadratic equations with complex roots.

    6𝑖

    βˆ’πŸ = βˆ’πŸ‘π’Š

  • SWBAT: Solve quadratic equations with complex roots.

  • SWBAT: Solve quadratic equations with complex roots.

  • SWBAT: Solve quadratic equations with complex roots.

    π‘₯2 βˆ’ 8π‘₯ +βˆ’8

    2

    2

    = βˆ’17 +βˆ’8

    2

    2

    π‘₯2 βˆ’ 8π‘₯ + 16 = βˆ’17 + 16

    π‘₯2 βˆ’ 8π‘₯ + 16 = βˆ’1

    π‘₯ βˆ’ 4 2 = βˆ’1

    π‘₯2 βˆ’ 8π‘₯ = βˆ’17

    π‘₯ βˆ’ 4 = ±𝑖

    𝒙 = πŸ’ Β± π’Š

    π‘₯ βˆ’ 4 2 = βˆ’1

  • SWBAT: Solve quadratic equations with complex roots.

    Denominators: 𝒙: 𝒙 + 𝟏 𝑳π‘ͺ𝑫 = x(x+1)

    πŸ’

    π’™βˆ™

    𝒙+𝟏

    𝒙+𝟏 βˆ’

    πŸ‘

    (𝒙+𝟏)βˆ™

    𝒙

    𝒙 =

    7

    1

    4 π‘₯+1 βˆ’ 3π‘₯

    π‘₯(π‘₯+1) =

    7

    1

    4π‘₯+4 βˆ’3π‘₯

    π‘₯(π‘₯+1) =

    7

    1

    π‘₯+4

    π‘₯(π‘₯+1) =

    7

    1βˆ™

    π‘₯(π‘₯+1)

    π‘₯(π‘₯+1)

    π‘₯ + 4 = 7π‘₯2 + 7π‘₯

    7π‘₯2 + 6π‘₯ βˆ’ 4 = 0

    x = βˆ’ πŸ” Β± (πŸ”)πŸβˆ’πŸ’(πŸ•)(βˆ’πŸ’)

    𝟐(πŸ•)

    x = βˆ’πŸ” Β± πŸπŸ’πŸ–

    πŸπŸ’

    x = βˆ’πŸ” Β± πŸ’ πŸ‘πŸ•

    πŸπŸ’

    x = βˆ’πŸ” Β± 𝟐 πŸ‘πŸ•

    πŸπŸ’

    x = βˆ’πŸ‘ Β± πŸ‘πŸ•

    πŸ•

    Divide by GCF of 2

  • SWBAT: Solve quadratic equations with complex roots.

  • SWBAT: Solve quadratic equations with complex roots.

    𝒙+πŸ‘

    πŸ‘βˆ™

    𝒙

    𝒙 +

    𝒙+ πŸ‘

    π’™βˆ™

    πŸ‘

    πŸ‘ =

    2

    1βˆ™

    πŸ‘π’™

    πŸ‘π’™

    Denominators: πŸ‘: 𝒙 𝑳π‘ͺ𝑫 = 3x

    π‘₯ π‘₯+3 + 3(π‘₯+3)

    3π‘₯ =

    6π‘₯

    3π‘₯

    π‘₯2+3π‘₯+3π‘₯+9

    3π‘₯ =

    6π‘₯

    3π‘₯

    π‘₯2 + 6π‘₯ + 9 = 6π‘₯

    π‘₯2 + 9 = 0

    π’™πŸ = βˆ’πŸ—

    𝒙 = Β±πŸ‘π’Š

    π‘₯2 + 9 = 0

    1.

  • SWBAT: Solve quadratic equations with complex roots.

    4 βˆ™π‘₯2

    4 = 4(x – 2)

    π‘₯2 = 4π‘₯ βˆ’ 8

    π‘₯2 βˆ’ 4π‘₯ = βˆ’8

    π‘₯2 βˆ’ 4π‘₯ +βˆ’4

    2

    2

    = βˆ’8 +βˆ’4

    2

    2

    π‘₯2 βˆ’ 4π‘₯ + 4 = βˆ’8 + 4

    π‘₯2 βˆ’ 4π‘₯ + 4 = βˆ’4

    π‘₯ βˆ’ 2 2 = βˆ’4

    π‘₯ βˆ’ 2 = Β±2𝑖

    𝒙 = 𝟐 Β± πŸπ’Š

    π‘₯ βˆ’ 2 2 = βˆ’4

    2.

  • SWBAT: Solve quadratic equations with complex roots.

    2π‘₯2 = -6x - 9

    2π‘₯2 + 6π‘₯ + 9 = 0 x = βˆ’ πŸ” Β± (πŸ”)πŸβˆ’πŸ’(𝟐)(πŸ—)

    𝟐(𝟐)

    x = βˆ’πŸ” Β± βˆ’πŸ‘πŸ”

    πŸ’

    x = βˆ’πŸ” Β± πŸ”π’Š

    πŸ’

    x = βˆ’πŸ‘ Β± πŸ‘π’Š

    𝟐

    Divide by GCF of 2

    3.

  • SWBAT: Solve quadratic equations with complex roots.

    π‘₯2 βˆ’ 1π‘₯ = 56

    π‘₯2 βˆ’ 1π‘₯ +βˆ’1

    2

    2

    = 56 +βˆ’1

    2

    2

    π‘₯2 βˆ’ 1π‘₯ +1

    4=

    225

    4

    π‘₯2 βˆ’ 1π‘₯ +1

    4=

    225

    4

    π‘₯ βˆ’1

    2

    2

    =225

    4

    π‘₯ βˆ’1

    2= Β±

    15

    2

    βˆ’πŸ•, πŸ–

    π‘₯ βˆ’1

    2

    2

    =225

    4

    π‘₯ =1

    2Β±

    15

    2

    π‘₯1 =1+15

    2 = 8

    π‘₯2 =1βˆ’15

    2 = -7

  • SWBAT: Solve quadratic equations with complex roots.

    π‘₯ + 8 = Β±5

    𝒙 = βˆ’πŸ– Β± πŸ“

    π‘₯ + 8 2 = 25

    βˆ’πŸπŸ‘, βˆ’πŸ‘

    π‘₯1 = βˆ’8 + 5 = -3

    π‘₯2 = βˆ’8 βˆ’ 5 = -13

    5. (x + 8)2 = 25

  • SWBAT: Solve quadratic equations with complex roots.

    (π‘₯ + 3)(π‘₯ + 4) = 5 βˆ™ 6

    π‘₯2 + 3π‘₯ + 4π‘₯ + 12 = 30

    π‘₯2 + 7π‘₯ = 18

    π‘₯2 + 7π‘₯ +7

    2

    2

    = 18 +7

    2

    2

    π‘₯2 + 7π‘₯ +49

    4=

    121

    4

    π‘₯2 + 7π‘₯ +49

    4=

    121

    4

    π‘₯ +7

    2

    2

    =121

    4

    π‘₯ +7

    2= Β±

    11

    2

    π‘₯ =βˆ’7

    2Β±

    11

    2

    π‘₯1 =βˆ’7+11

    2 = 2

    π‘₯2 =βˆ’7βˆ’11

    2 = -9

    βˆ’πŸ—, 𝟐

  • SWBAT: Solve quadratic equations with complex roots.

  • SWBAT: Solve quadratic equations with complex roots.

    π‘₯2 βˆ’ 4π‘₯ +βˆ’4

    2

    2

    = βˆ’9 +βˆ’4

    2

    2

    π‘₯2 βˆ’ 4π‘₯ + 4 = βˆ’9 + 4

    π‘₯2 βˆ’ 4π‘₯ + 4 = βˆ’5

    π‘₯ βˆ’ 2 2 = βˆ’5

    π‘₯2 βˆ’ 4π‘₯ = βˆ’9

    π‘₯ βˆ’ 2 = ±𝑖 5

    𝒙 = 𝟐 Β± π’Š πŸ“

    π‘₯ βˆ’ 2 2 = βˆ’5