sismorresistente n° g.d.l varios - modificado
DESCRIPTION
CORTANTE BASALTRANSCRIPT
70 w2=
k2=4 k2= 3 Tn/cm
70 w1=
k1= 4 k1= 7 Tn/cm
a). MATRIZ DE RIGIDEZ b). MATRIZ DE MASA
10 -3 0.0710 0.0000K= -3 3 ton/cm M= 0.0000 0.0710
c). ECUACIONES DE EIGENVALORES
0.071 0.0000 ф110= 10 -3 - Wn²* 0.0000 0.071 * ф21
-3 3
21 - 0.923 W²n + 0.0050
Wn= -5.16Wn= 5.155Wn= -12.57Wn= 12.571
d). CALCULO DE FRECUENCIA NATURAL *PERIODO NATURAL CORRESPONDIENTEWn1 = 5.155 T1 = 1.219wn2 = 12.571 T2 = 0.500
*ANALISIS DEL ESPECTRO (T) *ACELERACION ESPECTRALA1 = 0.230 T1= 225.630A2 = 0.830 T2= 814.230
e). DETERMINACION DE MODOS DE VIBRACION
((K)-Wn²*(M))*(ф1n)=0
*FRECUENCIA NATURAL Wn1= 5.155
8.113 -3 * ф110= -3 1.113 ф11
*FRECUENCIA NATURAL Wn2= 12.571
-1.220 -3 * ф120= -3 -8.220 ф22
ф= 1.00 1.002.704 -0.4070
f). DETERMINACION DE MODOS *MATRIZ NORMALIZADA
M1= 0.7682 ф= 1.302 3.476M2= 0.2877 3.520 -1.415
g). VECTOR DE FACTORES DE PARTICIPACION (P)= (ф)^T*(M)*(1)la anterior transpuesta
P = 1.302 3.520 * 0.0710 0.0000 *3.476 -1.415 0.0000 0.0710
P = 0.3424 0.34200.1463 0.1460
h). MATRIZ DE DESPLAZAMIENTO U= (ф)*(P)*(A)/(Ω^2)
U= 1.302 3.476 * 0.342 0 *3.520 -1.415 0 0.146
U= 3.781 2.61510.221 -1.064
Uc= 4.59710.277
i). MATRIZ DE FUERZAS LATERALES Fs= K * U
10 -3 * 3.781 2.615Fs= -3 3 10.221 -1.064
7.143 29.341Fs= 19.322 -11.038
j). FUERZA LATERAL EN CADA NUDO
Fsc= 30.19822.252
k). VECTOR CORTANTE BASAL
V= 7.143 19.322 * 129.341 -11.038 1
26.464854852 = 26.465 18.30318.303390925
luego el srss aplicado a la cortante basal 32.17
V(TRANSP)=
70 Tn
70 Tn
ton.s²/cm
Wn^4 = 0
*PERIODO NATURAL CORRESPONDIENTEseg.seg.
*ACELERACION ESPECTRAL
ф11= 1.00ф21= 2.704
ф12= 1.00ф22= -0.407
*MATRIZ NORMALIZADA
11
hoja225.63 0
÷26.574 26.574
0 814.23 158.03 158.03
W3= 7.5 Tn
k3= 18.52 Tn/cm
W2= 8.75 Tn
k2= 58.54 Tn/cm
W1= 10.5 Tn
k1= 47.60 Tn/cm
a). MATRIZ DE MASA
0.010703 0 0M = 0 0.00891946992864 0 Tn*s²/cm
0 0 0.0076453
b). MATRIZ DE RIGIDEZ
106.138 -58.5418 0K= -58.542 77.0648 -18.522994392108 Tn/cm
0 -18.523 18.5229943921083
c). ECUACION EIGENVALORES
106.138 -58.5418 0 0.0107033640= -58.542 77.0648 -18.522994392108 - Wn² 0
0 -18.523 18.5229943921083 0
7.298802E-07 Wn^6 - 0.01531233 Wn^4 + 65.47540959
Wn= -32.02 FRECUENCIA NATURALWn= 32.02 Wn1= 32.02Wn= -67.16 Wn2= 67.16Wn= 67.16 Wn3= 125.07
Wn= -125.07Wn= 125.07
d). PERIODO NATURAL
T1= 0.19623T2= 0.09356T3= 0.05024
e). ANALISIS ESPECTRAL (POR TABLA)
A1= 25.654 cm/SA2= 12.7 cm/sA3= 7.62 cm/s
F). CALCULO DE (ф)*PARA FRECUENCIA Wn1= 32.02
95.1645 -58.5418 0 ф110= -58.542 67.91985 -18.522994392108 * ф21
0 -18.523 10.6844592239126 ф31
ф11 = 1ф21 = 1.62558ф31 = 2.80017
*PARA FRECUENCIA Wn2= 67.16
57.8613 -58.5418 0 ф120= -58.542 36.83384 -18.522994392108 * ф22
0 -18.523 -15.960687565078 ф32
ф12= 1ф22= 0.98838ф32= -1.1951
*PARA FRECUENCIA Wn3= 125.07
-61.289 -58.5418 ф130= -58.542 -62.458 -18.522994392108 * ф23
-18.523 -101.06802166294 ф33
ф13= 1ф23= -1.0469ф33= 0.36966
F). CALCULO DE MODOS DE VIBRACION
*MATRIZ MODAL
1 1 1ф= 1.625582 0.9883759067351 -1.0469262
2.800167 -1.1950620635148 0.3696571
*MATRIZ MODAL NORMALIZADA
3.25784 5.741494 6.81609481710324ф= 5.29589 5.674754 -7.1359482059165
9.12251 -6.86144 2.51961817706278
g). VECTRO CORTANTE BASAL
*PRIMER MODO v= 25.654
A1= 821.441
NIVEL Wi фi Wi*фi Wi*фi² Fi1 10.5 3.257844 34.2073612262354 111.44224 4.34953552 8.75 5.295893 46.3390627055783 245.40671 5.89210613 7.5 9.122507 68.4188046363823 624.15104 8.6995901
148.965228568196 981
W^E= 22.6204V= 18.9412
*SEGUNDO MODO v= 12.7
A2= 852.932
NIVEL Wi фi Wi*фi Wi*фi² Fi1 10.5 5.741494 60.2856840703289 346.12988 3.12457042 8.75 5.674754 49.6540980467975 281.77479 2.57354183 7.5 -6.86144 -51.46081000392 353.09533 -2.6671826
58.4789721132068 981
W^E= 3.48602V= 3.03093
*TERCER MODO v= 7.62
A3= 953.033
NIVEL Wi фi Wi*фi Wi*фi² Fi1 10.5 6.816095 71.568995579584 487.82106 1.98639322 8.75 -7.13595 -62.439546801769 445.56537 -1.73300593 7.5 2.519618 18.8971363279708 47.613568 0.5244889
28.0265851057856 981
W^E= 0.8007V= 0.77788
J). CORTANTE BASAL
(V) = 18.9412 3.03093 0.77787618453336
0.777876
3.03093
18.94123175
Alturasf´c= 280 Kg/cm2 C1 300 Altura Losa Ali. Peso PropioEconcreto 250998.008 C1 280 h=0.20 300 Kg/m2C1 40X40 C2 280 h=0.25 350 Kg/m2
40 40 213333.333 h=0.30 420 Kg/m2C2 30X30 L 5 A
30 30 67500.000 Area Losa 25w1 10.5 Tn
K1= 47.60 w2 8.75 TnK2= 58.54 w3 7.5 TnK3= 18.52
981
0 00.0089195 0
0 0.00764526
Wn² - 51612.37077 .= 0
MODO1= 0.306951475MODO2= 0.174170703MODO3= 0.146711574
5
w4= 5 Tn
K4= 5 Tn/cmW3= 6 Tn
K3= 7 Tn/cmW2= 8 Tn
K2= 9 Tn/cm
W1= 8 Tn
K1= 12 Tn/cm
a). MATRIZ DE MASA
0.00815 0 0 0M = 0 0.00815 0 0 Tn*s²/cm
0 0 0.00612 00 0 0.00510
b). MATRIZ DE RIGIDEZ
21 -9 0 0K= -9 16 -7 0 Tn/cm
0 -7 12 -50 0 -5 5
c). ECUACION EIGENVALORES
21 -9 0 00= -9 16 -7 0 - Wn²
0 -7 12 -50 0 -5 5
0.= 2.0731*10^-9 Wn^8 - 1.5507*10^-5 Wn^6 +
Wn= -13.53 FRECUENCIA NATURALWn= 13.53 Wn1= 13.53Wn= -32.61 Wn2= 32.61Wn= 32.61 Wn3= 50.23Wn= -50.23 Wn4= 60.91
Wn= 50.23Wn= -60.91Wn= 60.91
d). PERIODO NATURAL
T1= 0.46439T2= 0.19268T3= 0.12509T4= 0.10316
e). ANALISIS ESPECTRAL (POR TABLA)
A1= 60.96 cm/SA2= 20.32 cm/sA3= 12.7 cm/sA4= 6.2 cm/s
F). CALCULO DE (ф)*PARA FRECUENCIA Wn1= 13.53
19.50715 -9 0 0 ф110= -9 14.50715 -7 0 * ф21
0 -7 10.88036 -5 ф310 0 -5 4.06697 ф41
ф11 = 1ф21 = 2.16746ф31 = 3.20624ф41 = 3.94256
*PARA FRECUENCIA Wn2= 32.61
12.32793 -9 0 0 ф120= -9 7.32793 -7 0 * ф22
0 -7 5.49595 -5 ф320 0 -5 -0.42004 ф42
ф12= 1ф22= 1.36977ф32= 0.14823
ф42= -1.75475
*PARA FRECUENCIA Wn3= 50.23
0.4246450561 -9 0 0 ф130= -9 -4.57535494 -7 0 * ф23
0 -7 -3.43151621 -5 ф330 0 -5 -7.85959684 ф43
ф13= 1ф23= 0.047182784ф33= -1.316553998ф43= 0.8374993788
*PARA FRECUENCIA Wn3= 0.00
-9.25487 -9.00000 0 0 ф130= -9.00000 -14.25487 -7.00000 0 * ф23
0 -7.00000 -10.69115 -5.00000 ф330 0 -5.00000 -13.90930 ф43
ф13= 1ф23= -1.028319163ф33= 0.8083655027ф43= -0.288825244
F). CALCULO DE MODOS DE VIBRACION
*MATRIZ MODAL
1 1 1 1ф= 2.16746 1.36977 0.04718 -1.02832
3.20624 0.14823 -1.31655 0.808373.94256 -1.75475 0.83750 -0.28883
*MATRIZ MODAL NORMALIZADA
2.30287 5.04535 6.68910 6.86800ф= 4.99138 6.91097 0.31561 -7.06250
7.38356 0.74786 -8.80656 5.551869.07922 -8.85333 5.60211 -1.98365
g). VECTOR CORTANTE BASAL
*PRIMER MODO v= 60.96
A1= 824.7888
NIVEL Wi фi Wi*фi Wi*фi² Fi1 8 2.30287 18.42297 42.42575 2.337642 8 4.99138 39.93108 199.31138 5.066743 6 7.38356 44.30136 327.10169 5.621274 5 9.07922 45.39610 412.16118 5.76018
148.05151 981
W^E= 22.343781312V= 18.785831372
*SEGUNDO MODO v= 20.32
A2= 662.6352
NIVEL Wi фi Wi*фi Wi*фi² Fi1 8 5.04535 40.36282 203.64464 1.552762 8 6.91097 55.28780 382.09254 2.126933 6 0.74786 4.48714 3.35573 0.172624 5 -8.85333 -44.26664 391.90709 -1.70294
55.87111 981
W^E= 3.182039758V= 2.1493695733
*TERCER MODO v= 12.7
A3= 637.921
NIVEL Wi фi Wi*фi Wi*фi² Fi1 8 6.68910 53.51277 357.95208 1.107042 8 0.31561 2.52488 0.79688 0.052233 6 -8.80656 -52.83934 465.33263 -1.093114 5 5.60211 28.01057 156.91841 0.57947
31.20888 981
W^E= 0.992858714V= 0.64563244
*CUARTO MODO v= 6.2
A3= 377.64076
NIVEL Wi фi Wi*фi Wi*фi² Fi1 8 6.86800 54.94403 377.35575 0.47082
2 8 -7.06250 -56.49999 399.03117 -0.484153 6 5.55186 33.31114 184.93869 0.285444 5 -1.98365 -9.91826 19.67439 -0.08499
21.83691 981
W^E= 0.48609V= 0.18712
J). CORTANTE BASAL (V) = 2.14937 2.14937 0.64563
CORTANTE BASAL MAS PROBABLE* COMO : T4/T3 = 0.8247 < 0.75 NO CUMPLE
T3/T2 = 0.6492 < 0.75 CUMPLE T2/T1 = 0.4149 < 0.75 CUMPLE
solo si todas las proposiciones cumplenVc = 18.92034
0.00815 0 0 00 0.00815 0 00 0 0.00612 00 0 0 0.00510
3.59221*10^-2 Wn^4 - 26.7125 Wn^2 + 3780
MODO1= 0.43424MODO2= 0.19820MODO3= 0.14950MODO4= 0.14560
0.18712
w3= 7.5 Tn
k3= 18.523
w2= 8.75 Tn
k2= 58.543
w1= 10.5 Tn
k1= 47.6
a). MATRIZ DE MASA
0.01070336 0 0M = 0 0.00891947 0 Tn*s²/cm
0 0 0.00764526
b). MATRIZ DE RIGIDEZ
106.143 -58.543 0K= -58.543 77.066 -18.523 Tn/cm
0 -18.523 18.523
c). ECUACION EIGENVALORES
106.143 -58.543 00= -58.543 77.066 -18.523 - Wn²
0 -18.523 18.523
7.298802E-07 Wn^6 - 0.01531274 Wn^4 +
Wn= -15.64 FRECUENCIA NATURALWn= 32.02 Wn1= 32.02Wn= -38.44 Wn2= 67.16Wn= 67.16 Wn3= 125.07Wn= -53.55Wn= 125.07
d). PERIODO NATURAL
T1= 0.20T2= 0.09T3= 0.05
e). ANALISIS ESPECTRAL (POR TABLA) ACELERACION ESPECTRAL
A1= 1.756 g T1= 1722.636A2= 0.869 g T2= 852.489A3= 0.971 g T2= 952.551
f). DETERMINACION DE MODOS DE VIBRACION*PARA FRECUENCIA Wn1= 32.02
95.169050765 -58.543 ф110= -58.543 67.9210423 -18.523 * ф21
-18.523 10.6844648 ф31
ф11= 1ф21= 1.6256264757ф31= 2.8003695202
*PARA FRECUENCIA Wn2= 67.16
57.86584526 -58.543 0 ф120= -58.543 36.8350377 -18.523 * ф22
0 -18.523 -15.960682 ф32
ф12= 1ф22= 0.9884332074ф32= -1.194948201
*PARA FRECUENCIA Wn3= 125.07
-61.28442248 -58.543 0 ф130= -58.543 -62.4568521 -18.523 * ф23
0 -18.523 -101.068016 ф33
ф12= 1ф22= -1.046827502ф32= 0.3691923802
*MATRIZ MODAL NORMALIZADA *DETERMINACION DE MODOS
1 1 1 M1=ф= 1.6256264757 0.98843321 -1.0468275 M2=
2.8003695202 -1.1949482 0.36919238 M3=
*MATRIZ NORMALIZADA
3.2576718443 5.741595 6.81680243ф= 5.2957575991 5.67518316 -7.13601627
9.1226849397 -6.86090862 2.51671152
g). VECTOR DE FACTORES DE PARTICIPACION
(P)= (ф)^T*(M)*(1)
3.2576718443 5.2957576 9.12268494 0.0107033639(P)= 5.741595 5.67518316 -6.86090862 * 0
6.8168024348 -7.13601627 2.51671152 0
0.1518486956(P)= 0.0596205765
0.0285541484
h). MATRIZ DE DESPLAZAMIENTO
U= (ф)*(P)*(A)/(Ω^2)
3.2576718443 5.741595 6.81680243 0.1518486956
U= 5.2957575991 5.67518316 -7.13601627 * 09.1226849397 -6.86090862 2.51671152 0
0.831130584 0.06469879 0.0118531U= 1.351107882 0.06395043 -0.01240815
2.3274727546 -0.0773117 0.00437607
0.8337292585Uc= 1.3526773926
2.3287605442
i). MATRIZ DE FUERZAS LATERALES Fs= K *
106.143 -58.543 0 0.83113Fs= -58.543 77.066 -18.523 * 1.35111
0 -18.523 18.523 2.32747
9.12078 3.12347 1.98453Fs= 12.35582 2.57279 -1.73122
18.08521 -2.61660 0.31089
*FUERZA LATERAL EN CADA NUDO SRSS
9.8429251308
Fsc= 12.73902489518.276157631
j). VECTOR CORTANTE BASAL V= F^T *
9.12078 12.35582 18.08521 1V= 3.12347 2.57279 -2.61660 * 1
1.98453 -1.73122 0.31089 1
39.56182V= 3.07966 VTRANSP= 39.5618158 3.0796622372
0.56421SRSS = 39.68551
0.01070336 0 00 0.00891947 00 0 0.00764526
65.4789778 Wn² - 51617.0587 .= 0
*DETERMINACION DE MODOS
0.306967690.174167630.14669634
0 0 10.00891947 0 * 1
0 0.00764526 1
0 0 1722.636 0 0 1025.2804
0.05962058 0 * 0 852.489 0 ÷ 4510.46560 0.02855415 0 0 952.551 15642.5049
1.68016086 0 00 0.18900244 00 0 0.06089504
U
0.06470 0.011850.06395 -0.01241-0.07731 0.00438
1
0.56420744
1025.2804 1025.2804
4510.4656 4510.465615642.5049 15642.5049
W4= 6 Tn
k4= 8 Tn/cm
W3= 8 Tn
k3= 6 Tn/cm
W2= 12 Tn
k2= 5 Tn/cm
W1= 16 tn
k1= 4 Tn/cm
a). MATRIZ DE MASA
0.016309888 0 0 0M= 0 0.01223242 0 0 Tn*s²/cm
0 0 0.00815494 00 0 0 0.00611621
b). MATRIZ DE RIGIDEZ
9 -5 0 0K= -5 11 -6 0 Tn/cm
0 -6 14 -80 0 -8 8
c). ECUACION EIGENVALORES
9 -5 0 00= -5 11 -6 0 - Wn²
0 -6 14 -80 0 -8 8
2.3564 Wn^8 - 25.3014 Wn^6 + 12354
Wn= -15.64 FRECUENCIA NATURALWn= 20.625 Wn1= 20.625Wn= -38.44 Wn2= 42.97Wn= 42.97 Wn3= 42.97Wn= -53.55 Wn4= 42.97Wn= 42.97Wn= -25.36Wn= 42.97
d). PERIODO NATURAL
T1= 0.30464T2= 0.146222946T3= 0.146222946T4= 0.146222946
e). ANALISIS ESPECTRAL (POR TABLA) ACELERACION ESPECTRAL
A1= 2.4 g T1= 2354.4A2= 1.04 g T2= 1020.24A3= 0.65 g T3= 637.65A4= 0.68 g T4= 667.08
f). DETERMINACION DE MODOS DE VIBRACION*PARA FRECUENCIA Wn1= 20.625
2.061926606 -5 0 0 ф110= -5 5.79644495 -6 0 * ф21
0 -6 10.5309633 -8 ф310 0 -8 5.39822248 ф41
ф11= 1ф21= 0.412385321ф31= -0.43493853ф41= -0.8818292
*PARA FRECUENCIA Wn2= 42.97
-21.1149178 -5 0 0 ф12
0= -5 -11.5861884 -6 0 * ф220 -6 -1.05745892 -8 ф320 0 -8 -3.29309419 ф42
ф12= 1ф22= -4.22298357ф32= 7.321380523ф42= 2.199480284
*PARA FRECUENCIA Wn3= 42.97
-21.1149178 -5 0 0 ф130= -5 -11.5861884 -6 0 * ф23
0 -6 -1.05745892 -8 ф330 0 -8 -3.29309419 ф43
ф13= 1ф23= -4.22298357ф33= 7.321380523ф43= -41.5413614
*PARA FRECUENCIA Wn4= 42.97
-21.1149178 -5 0 0 ф140= -5 -11.5861884 -6 0 * ф24
0 -6 -1.05745892 -8 ф340 0 -8 -3.29309419 ф44
ф14= 1ф24= -4.22298357ф34= 7.321380523ф44= 2.199480284
*MATRIZ MODAL NORMALIZADA
1 1 1 1ф= 0.412385321 -4.22298357 -4.22298357 -4.22298357
-0.43493853 7.32138052 7.32138052 7.32138052-0.8818292 2.19948028 -41.5413614 2.19948028
*MATRIZ NORMALIZADA
6.364272878 1.19422882 0.29845786 1.19422882ф= 2.624532714 -5.0432087 -1.26038264 -5.0432087
-2.7680675 8.74340365 2.18512356 8.74340365
-5.61220169 2.62668275 -12.3983458 2.62668275
g). VECTOR DE FACTORES DE PARTICIPACION
(P)= (ф)^T*(M)*(1)
6.364272878 2.62453271 -2.7680675 -5.61220169 0.01630989(P)= 1.194228824 -5.0432087 8.74340365 2.62668275 * 0
0.29845786 -1.26038264 2.18512356 -12.3983458 01.194228824 -5.0432087 8.74340365 2.62668275 0
0.079006125(P)= 0.045154416
-0.068561010.045154416
h). MATRIZ DE DESPLAZAMIENTO
U= (ф)*(P)*(A)/(Ω^2)
6.364272878 1.19422882 0.29845786 1.19422882 0.07900612U= 2.624532714 -5.0432087 -1.26038264 -5.0432087 * 0
-2.7680675 8.74340365 2.18512356 8.74340365 0-5.61220169 2.62668275 -12.3983458 2.62668275 0
2.782927472 0.0297961 -0.00706662 0.01948207U= 1.147638439 -0.12582844 0.02984223 -0.08227244
-1.21040239 0.21814859 -0.05173743 0.14263561-2.45406672 0.06553593 0.29355712 0.04285042
2.783164136Uc= 1.157828181
1.2392273492.472802127
i). MATRIZ DE FUERZAS LATERALES Fs= K * U
9 -5 0 0Fs= -5 11 -6 0 *
0 -6 14 -80 0 -8 8
25.04847723 -5.7891409 0 0Fs= -13.9158207 12.73611 -7.4353641 0
0 -6.94696909 17.3491829 -19.782417
0 0 -9.91381879 19.782417
*FUERZA LATERAL EN CADA NUDO SRSS
25.70876045Fsc= 20.27666645
27.2139403522.12753547
j). VECTOR CORTANTE BASAL V= F^T * 1
25.04847723 -13.9158207 0 0 1V= -5.7891409 12.73611 -6.94696909 0 * 1
0 -7.4353641 17.3491829 -9.91381879 10 0 -9.91381879 19.782417 1
11.13265654V= 0 VTRANSP= 11.1326565 0 0
09.868598222
0.01630989 0 0 00 0.01223242 0 00 0 0.00815494 00 0 0 0.00611621
Wn4 - 124.354 Wn² + 960 .= 0
*DETERMINACION DE MODOS
M1= 0.15712714M2= 0.83736046M3= 3.35055676M4= 0.83736046
0 0 0 10.01223242 0 0 * 1
0 0.00815494 0 10 0 0.00611621 1
0 0 0 2354.4 0 0 00.04515442 0 0 * 0 1020.24 0 0
0 -0.06856101 0 0 0 637.65 00 0 0.04515442 0 0 0 667.08
5.53467769 0 0 00 0.55255007 0 00 0 0.34534379 00 0 0 0.36128274
2.78316414 0 0 00 1.15782818 0 00 0 1.23922735 00 0 0 2.47280213
9.86859822
425.390625 425.390625 425.390625 425.390625÷ 1846.4209 1846.4209 1846.4209 1846.4209
1846.4209 1846.4209 1846.4209 1846.42091846.4209 1846.4209 1846.4209 1846.4209
970 k/m2
75 k/m2
L= m 3.5
50 k/m2
L= m 3.5
6 m
6 m
a). DETERM. CARGA MUERTA TRIBUTARIA DATOS DEL PROBLEMARazon de amortiguamiento=
Piso 1: Desplazamiento =
Losa = 34.92 ton Esfuerzo cortante=
4 muros = 4.2 ton4 columnas = 1.05 ton DATO ASUMIDO
T1= 0.5peso total = w1 40.17 ton ф2= 1
ф1= 0.66piso 2:
Losa = 34.92 ton4 muros = 2.1 ton4 columnas = 0.525 ton
peso total = w2 37.545 ton
b). DETRMINACION DE LA RIGIDEZ DE CADA PISO
K1 = K2 = 15 ton/cm
c). MODELO DINAMICO DEL PORTICO
ESTRUCTURA MODELO DINAMICO
k2= 15 Tn/cm
k1= 15 Tn/cm
d). DETRMN. DE LA FORMA MODAL Y EL PERIODEO FUNDAMENTAL DE VIBRACION POR ITERACION
u2 = 1u1 = 0.66
Piso
2 37.545 /g 15 1 37.545 w²/g 37.545
1 40.170 /g 15 0.66 26.512 w²/g 64.057
2 37.545 /g 15 1 37.545 w²/g 37.5451 40.170 /g 15 0.63 25.307 w²/g 62.852
2 37.545 /g 15 1 37.545 w²/g 37.5451 40.170 /g 15 0.64 25.709 w²/g 63.254
e). DETERMINACION DE LA FRECUENCIA CIRCULAR NATURAL
6.720 w²/g = 1w = 12.082 rad/seg
f). DETERM. DEL PERIODO
T = 0.52 seg
g). DETERMINACION DE LAS FUERZAS LATERALES
A = 0.18 *g
h). DETERMINACION DEL FACTOR DE PARTICIPACION
NIVEL Wi ф1 Wi*ф1 Wi*ф1² Fi Vi2 37.545 1 37.545 37.545 7.923 7.9231 40.17 0.64 25.6094 16.326636 5.404 13.327
BASESUMATORIA 63.154 53.872
masa de piso m
Rigidez del piso k
Modo inicial u
Fuerza de inercia m*w²*u
Fuerza de corte k*∆
P = 1.172
i). DTERMINACION DE LA ACELERACION PICO t=0 seg
A = 0.2 *g
DATOS DEL PROBLEMA7 %
0.3 cm4.5 ton
DATO ASUMIDO seg
MODELO DINAMICO FORMA MODAL1
w2= 37.545
w1= 40.17 0.64
d). DETRMN. DE LA FORMA MODAL Y EL PERIODEO FUNDAMENTAL DE VIBRACION POR ITERACION
Modo del piso
w²/g 2.503 w²/g 6.773 w²/g 1
w²/g 4.270 w²/g 4.270 w²/g 0.63
w²/g 2.503 w²/g 6.693 w²/g 1w²/g 4.190 w²/g 4.190 w²/g 0.64
w²/g 2.503 w²/g 6.720 w²/g 1w²/g 4.217 w²/g 4.217 w²/g 0.64
Fi=Fuerzas laterales Vi=cortante basal
Fuerza de corte k*∆
Derivada del piso ∆
Despl. Del pison ∑∆
DATOS PROPORCIONADOS DE LA PREGUNTA
0.939 3.159 3.135EIGENVECTORES: ф= 2.181 2.871 -4.084
3.491 -3.129 1.226
ф^T * M * ф = I
w3k3=
4.0 mw2
k2=4.0 m
w1
4.0 m k1=
PROCEDIMIENTO:* EMPEZAMOS DE LA MATRIZ DE PARTICIPACION (dato matriz modal normalizada)se cumple:
P = ф^T * M * 1
*matriz de masa
55 0 0M= 0 35 0 *Tn/g
0 0 35
0.939 2.181 3.491 55 0P= 3.159 2.871 -3.129 * 0 35
3.135 -4.084 1.226 0 0
250.165P= 164.715 *1/g
72.395
a). VERIFICACION DE LOS FACTORES DE PARTICIPACION SI SON CORRECTOS O NOSe cumple:∑Pn*фm =1
250.165 * 0.939 + 164.715 * 3.159
POR LO TANTO: 1.00 = 1
b). CALCULO DE DESPLAZAMIENTOS UTILIZANDO EL ESPECTRO DE ACELERACION
T1= 0.73240841 seg A1= 0.15 *gT2= 0.32402418 seg A2= 0.6 *gT3= 0.21562729 seg A3= 0.77 *g
* MATRIZ DE DESPLAZAMIENTO
U = ф * P * A
0.939 3.159 3.135 250.165U = 2.181 2.871 -4.084 * 0
3.491 -3.129 1.226 0
0.478773731 0.830288714 0.205818579U = 1.112039943 0.754592877 -0.26812219
1.779977736 -0.82240373 0.080489179
* SRSS PPARA CADA NUDO DE DESPLAZAMIENTO
0.980288183Uc = 1.370376866
1.962433985
c). CALCULO DE LA DERIVA ENTRE CADA PISO O DESPLAZAMIENTOS ENTRE PISOS
-0.63326621 0.075695837 0.473940772A = -0.66793779 1.576996608 -0.34861137
1.779977736 -0.82240373 0.080489179
0.7945916A = 1.747738278
1.962433985
8.5788FRECUENCIAS: w= 19.3911
29.1391
w3= 35 Tn
3 Tn/cmw2= 35 Tn
3 Tn/cm
w1= 55 Tn
7 Tn/cm
0 10 * 1
35 1
+ 72.395 * 3.135 *1/g = 1
÷ Ω²
0 0 0.15 0 0164.715 0 * 0 0.6 0 ÷
0 72.395 0 0 0.77
73.59580944 73.5958094 73.5958094376.0147592 376.014759 376.014759849.0871488 849.087149 849.087149
METRADOS:V4
w= 1.5 tn/m3 m
c2 c2V3
w= 1.5 tn/m3 m
c2 c2V2
w= 2 tn/m COLUMNA 1 :3 m COLUMNA 2 :
c1 c2V1
w= 2 tn/m4 m
c1 c1
6.5
a) C1 = 2520 b) C1 = 1080V = 3276 C2 = 648
M = 2275 V = 2808W = 13000 M = 1950
21071 kg W = 1300019486 kg
f'C = 210 KG/cm2S/C muro = 100 Kg/m2 m= 13245
LARGO ANCHOVIGA 1 : 0.3 0.7 m= 14868VIGA 2 : 0.3 0.6VIGA 3 : 0.3 0.4VIGA 4 : 0.3 0.4
COLUMNA 1 : 0.3 0.5 m= 19486COLUMNA 2 : 0.3 0.3
m= 21071
c) C2 = 1296 d) C2 = 648V = 1872 V = 1872
M = 1950 M = 975W = 9750 W = 9750
14868 kg 13245 kg
Q3 = 1000 kg/m RESUMEN
NIVEL 3 k3= 13.042m3
Q2 = 1200 Q2 = 1200 kg/mNIVEL 2 k2= 8.253
4 Q1 = 1400 Q1 = 1200 kg/m
NIVEL 1 k1= 3.169
5
5 m 5 m
ANALISIS DE LA RIGIDEZ DE ELEMENTOS
NIVEL 1 - EMPOTRAMIENTO NIVEL 1 - EMPOTRAMIENTO
fc = 210 kg/cm2 fc = 210 0E = 217370.65119 ton/m2 E = 217370.6512 ton/m2
b = 0.3 m b = 0.3 m 6.521h = 0.3 m h = 0.3 mI = 0.000675 m^4 I = 0.000675 m^4A = 0.09 m^2 A = 0.09 m^2
2.751L= 5 m L= 5 mK= 1.4085618197 ton/cm K= 0.352140455 ton/cm
1.409NIVEL 2 - EMPOTRAMIENTO NIVEL 3 - EMPOTRAMIENTO
fc = 210 0 fc = 210 0E = 217370.65119 ton/m2 E = 217370.6512 ton/m2
b = 0.3 m b = 0.3 mh = 0.3 m h = 0.3 mI = 0.000675 m^4 I = 0.000675 m^4A = 0.09 m^2 A = 0.09 m^2
L= 4 m L= 3 mK= 2.7510973042 ton/cm K= 6.521119536 ton/cm
a). MATRIZ DE MASA
0.01325 0.00000 0.00000M= 0.00000 0.01223 0.00000 Tn*s²/cm
0.00000 0.00000 0.00510
b). MATRIZ DE RIGIDEZ
11.423 -8.253 0.000 K1 +K2 -K2K= -8.253 21.296 -13.042 Tn/cm K= -K2 K2+K3
0.000 -13.042 13.042 0 -K3
c). ECUACION EIGENVALORES
11.42256 -8.25329 0.00000 0.01325 0.000000= -8.25329 21.29553 -13.04224 - Wn² 0.00000 0.01223
0.00000 -13.04224 13.04224 0.00000 0.00000
11.42256 - 0.01325 Wn² -8.25330= -8.2533 21.2955 - 0.01223
0.0000 -13.0422
8.264E-07 Wn^6 - 14.690643797 Wn^4 + 4.141398 Wn²
resolver en HP50g SOLUCION DE LA ECUACIONx1 = -9.523x2 = 9.523 Wn1= 9.523x3 = -34.143 Wn2= 34.143x4 = 34.143 Wn3= 62.483x5 = -62.483
x6 = 62.483 =ᵹ 5%
ANALISIS DEL ESPECTRO EN FUNCION DE T (diagrama)ANALISIS DEL ESPECTRO (CONVERSION)
V1= 25 pulg/s V1= 63.5 cmV2= 6 pulg/s V2= 15.24 cmV3= 4 pulg/s V3= 10.16 cm
ACELERACION ESPECTRAL - FUNCION DE TA1 = 604.740 cm/s2A2 = 520.339 cm/s2A3 = 634.832 cm/s2
F). CALCULO DE (ф)*PARA FRECUENCIA Wn1= 0.00
10.220827811 -8.2533 0 ф110= -8.2533 20.1863132 -13.0422 * ф21
0 -13.0422 12.579687087 ф31
ф11 = 1ф21 = 1.2383940759
ф31 = 1.28392975
*PARA FRECUENCIA Wn2= Wn1=
-4.023548531 -8.2533 0 ф120= -8.2533 20.1863132 -13.0422 * ф22
0 -13.0422 7.0969460042 ф32
ф12= 1ф22= -0.487508327ф32= -1.387360527
*PARA FRECUENCIA Wn3= Wn2=
-40.30789436 -8.2533 0 ф130= -8.2533 7.03848506 -13.0422 * ф23
0 -13.0422 -6.869104089 ф33
ф13= 1ф23= -4.883856622ф33= -3.268475877
F). CALCULO DE MODOS DE VIBRACION
*MATRIZ MODAL
1 1 1 MODO1=ф= 1.238 -0.488 -4.884 MODO2=
1.284 -1.387 -3.268 MODO3=
*MATRIZ MODAL NORMALIZADA
4.974 6.205 1.668ф= 6.160 -3.025 -8.146
6.387 -8.609 -5.451
g). VECTOR DE FACTORES DE PARTICIPACION
(P)= (ф)^T*(M)*(1)
4.974 6.160 6.387 0.01325 0 0(P)= 6.205 -3.025 -8.609 * 0 0.01223 0
1.668 -8.146 -5.451 0 0 0.00510
0.1738(P)= 0.0013
-0.1053
h). MATRIZ DE DESPLAZAMIENTO
U= (ф)*(P)*(A)/(Ω^2)
4.974 6.205 1.668 0.1738 0.0000 0.0000
U= 6.160 -3.025 -8.146 * 0.0000 0.0013 0.00006.387 -8.609 -5.451 0.0000 0.0000 -0.1053
5.765 0.004 -0.029U= 7.140 -0.002 0.140
7.402 -0.005 0.093
5.765Uc= 7.141
7.403
i). MATRIZ DE FUERZAS LATERALES Fs= K * U
11.423 -8.253 0.000 5.765 0.004 -0.029Fs= -8.253 21.296 -13.042 * 7.140 -0.002 0.140
0.000 -13.042 13.042 7.402 -0.005 0.093
6.9284 0.0577 -1.4777Fs= 7.9196 -0.0020 1.9889
3.4240 -0.0438 -0.6018
*FUERZA LATERAL EN CADA NUDO SRSS
7.0845Fsc= 8.1655
3.4767
j). VECTOR CORTANTE BASAL V= F^T * 1 ^ T
6.9284 7.9196 3.4240 1V= 0.0577 -0.0020 -0.0438 * 1
-1.4777 1.9889 -0.6018 1
18.2720V= 0.0118 VTRANSP= 18.2720 0.0118 -0.0905
-0.0905CORTANTE BASAL - SRSS
18.2722 ton[Vb] =
W3= 5 Tn 1. MATERIALCONCRETO EN VIGAS 210
Tn/cm CONCRETO EN COLUMNAS 210CONCRETO EN PLACAS 210
W2= 12 Tn MODULO DE POISSON µ = 0.172. DIMENSIONES:
Tn/cm COLUMNAS : b x h = 30VIGAS PRINCPALES : b x h = 30
W1= 13 tn 3. ANALISIS :NO CONSIDERAR PESO DE VIGAS
Tn/cm NO CONSIDERAR PESO DE COLUMNAS
6.521 6.521
2.751 2.751 2.751
1.409 0.352 1.409
E : 15000*fc^0.5 kg/cm2
0-K3 Tn/cmK3
0.00000 Ø1n0.00000 * Ø2n0.00510
0.0000Wn² -13.0422
13.0422 - 0.00510 Wn²
- 341.144 .= 0
PERIODO NATURAL CORRESPONDIENTE
T1 = 0.6598 sT2 = 0.1840 sT3 = 0.1006 s
ANALISIS DEL ESPECTRO (CONVERSION)
0.2010 0.01325 0.00000 0.000000.1611 M= 0.00000 0.01223 0.00000 Tn*s²/cm0.5996 0.00000 0.00000 0.00510
1* 1
1
604.740 0 0 90.696 90.696 90.696
* 0 520.339 0 ÷ 1165.744 1165.744 1165.7440 0 634.832 3904.185 3904.185 3904.185
6.667738 0 00 0.44636 00 0 0.162603
kg/cm2kg/cm2kg/cm2
* 30 cm* 60 cm