sinx=5/13

11
Sinx=5/13 T a n x = 3 / 5 . 1 9 tanx=1 Sinx=3/5 sinx=12.69/1 5 cosx=12/13 sinx=0.5 x = 2 2 . 6 2 o tanx=5/12 cosx=8/15 c o s x = 4 / 5 x=45 0 x 5 3 4 x 13 5 12 x 4.24 3 3 x 6 3 5.1 9 x 15 12.6 9 8

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x. x. x. x. x. 6. 4.24. tanx=1. 3. 3. 5.19. 3. Tanx=3/5.19. Sinx=5/13. x=45 0. sinx=0.5. 13. 5. cosx=12/13. x=22.62 o. 12. Sinx=3/5. sinx=12.69/15. tanx=5/12. 15. cosx=8/15. 5. 12.69. 3. cosx=4/5. 8. 4. 1 km. 500 m. 0.5 km. 1000 m. 1000mm. 250cm. 25 mm. 1 m. - PowerPoint PPT Presentation

TRANSCRIPT

Page 1: Sinx=5/13

Sinx=5/13

Ta

nx=

3/5

.19

tan

x=1

Sinx=3/5 sinx=12.69/15cosx

=1

2/1

3

sinx=0.5 x=2

2.6

2o

tanx=5/12

cosx

=8

/15

cosx=

4/5

x=450

x

53

4

x

135

12

x

4.243

3x

63

5.19

x

1512.69

8

Page 2: Sinx=5/13

250cm1

00

0 m

1 k

m90 cm

128 cm

0.9

cm

1 m

0.6

5 km

128 mm

65

0m

m4

0 m

2.5 cm

0.9 m

40

00

cm

2.5 m9

mm

12.8 cm

25 mm1000mm

0.5

km

50

0 m

65

0 m

1.28 m

0.6

5 m

Page 3: Sinx=5/13

250kg

10

00

g

1 k

g

900 g128 g

0.9

t

1 t

0.6

5 kg

12800 kg

65

g4

kg

0.25 kg

0.9 kg

40

00

g

0.25 t

90

0 k

g

12.8 t

250 g1000kg

0.5

kg

50

0 g

65

0 g

0.128 kg

0.0

65

kg

Page 4: Sinx=5/13

1 year

30

seco

nd

s0.5

min

ute

1 minute365.25 days

3 h

ou

rs

24 hours

45

min

ute

s

168 hours

1 h

ou

r 4

80

seco

nd

s

15 minutes

60 seconds

8 m

inu

tes

52 weeks

18

0 m

inu

tes

1 week

¼ of an hour1 day

30

min

ute

s

½

an

ho

ur

¾ o

f a

n h

ou

r

1 year

36

00

seco

nd

s

Page 5: Sinx=5/13

400500 0.70.8

0.010.02

0 25

3136

1020 010

0

34

12

510

11.1 0.20.3

3.17.

5

0.28

420

1.08

20

1.6

30

11

0.01635

0.74

Page 6: Sinx=5/13

A = r2

P=

2l +

2w

Pe

rime

ter

of

rect

an

gle

Surface area of a cuboid Volume of prism

Are

a o

f tr

ap

ezi

um

Circumference of circle

Vo

lum

e o

f a cu

bo

id

A = bh

Vo

lum

e o

f cy

lind

er

Vo

lum

e o

f con

e

A = ½ bh

V= 2(lw +hw +lh)

V =

r2

h/3

Area of circle

A =

½ (

a+

b)h

Area of parallelogram

Area of triangleC = 2r

A =

lw

Are

a o

f re

cta

ng

le

V =

lwh

V = cross-sectional area x length

V =

r

2h

Page 7: Sinx=5/13

Volume=31.75 cm3

Dia

me

ter =

10

cmAre

a =

35

cm

2

Surface area =94 cm2 Perimeter = 35.08 cm

Su

rfa

ce a

rea

=8

4 c

m2

Perimeter = 40 cm Bird

s eye

view

Length of all edges=44 cm

Are

a =

72

cm

2 V

olu

me

=6

0 cm

3

Perimeter = 26 cm

Le

ng

th o

f a

ll e

dg

es

=3

3cm

Perimeter = 31.42 cm

Are

a =

84

cm

2

Volume = 45 cm3

Circular area =56.55 cm2Perimeter =40 cm

Are

a =

96

cm2

Are

a =

78

.54

cm

2

Cu

rve

d s

urf

ace

a

rea

= 1

31

.95

cm

2

Volume= 197.92 cm3

Su

rface

are

a =

48

cm2

5 cm

12 cm

8 cm

7 cm

6 cm5cm

3cm

7cm

2.65cm

8cm

5cm

10cm

10cm

2cm

2cm

5cm

4cm

3cm

3cm

4cm

3cm

12cm6cm

6cm

8cm8.54cm

5cm

Net of a box with no lid

6cm

Page 8: Sinx=5/13

X x X

5x

8x

– 3

x

x/4 3x – 4(x – 2)

3(x

+ 1

)

5x

2x +

y

x +

5 +

3x

-29

x2

X4

¼ x

(3x)

2

X2

3x

+ 3

x + x3

X x X32x + 3x

3x

5x

+ 2

y –

3x

- y

8 - x

4x+

3 x

+ x

+ x

x + x3

Page 9: Sinx=5/13

3x + 7 = 28

x = 2/3

2 –

3x=

0

x/5 + 2 = 4 4x = -16

9x –

5 =

85

x=2 x = 4.5

x = 2

x =

7

x = 3 or -3

x = -4

x = 10

x2 =

9

x = 7

x =

10

5x + 8 = 18

x + 9 = 52x + 1 = 5

x = 12

x –

2 =

10

x/3

= 1

.5

x =-4

6x + 4 =

46

Page 10: Sinx=5/13

x = 120

x=90

y=11

5

y = 105 w and y = 25

z =

300

y=105 y = 60

w = 60

x =

50

z= 75

w=65

x = 15

x =

40

y=90

y =

75

y = 50

w =72z = 75

x=75

w

=60

y =

288

x and z = 108

z = 90

x

105 y

w

120

y

x25

x

w

15

xy

zx

z

y

w

60

x

w

y z

75x

y

z

40 x

y

z

110x

20130

w

y

Page 11: Sinx=5/13

A = r2

P=

2l +

2w

Pe

rime

ter

of

rect

an

gle

Surface area of a cuboid Volume of prism

Are

a o

f tr

ap

ezi

um

Circumference of circle

Vo

lum

e o

f a cu

bo

id

A = bh

Vo

lum

e o

f cy

lind

er

Vo

lum

e o

f con

e

A = ½ bh

V= 2(lw +hw +lh)

V =

r2

h/3

Area of circle

A =

½ (

a+

b)h

Area of parallelogram

Area of triangleC = 2r

A =

lw

Are

a o

f re

cta

ng

le

V =

lwh

V = cross-sectional area x length

V =

r

2h