series/parallel circuits. i1i1 + - vr2r2 r3r3 i2i2 i3i3 itit r1r1
TRANSCRIPT
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Series/Parallel Circuits
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Series/Parallel CircuitsI1
+
-V R2 R3
I2 I3
IT
R1
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Series/Parallel Circuit 1.Reduce the Parallel Branches into
One Series Resistor.2.This resistor is called an
Equivalent Resistance.3. Do this for all the Parallel Paths.
4. Do your calculation on the Series Circuit.
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}1
R23
1R2
1R3
= +
1R23
14
14= +
R23 = 2Ω
+
-V=10v R3 =4Ω
R1=8Ω
R2=4Ω
Block
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+
-V=10v
R1=8Ω
R23=2Ω
R23 is an equivalent resistor to
R2 and R3.RT= R1 + R23
RT= 8Ω + 2Ω = 10Ω
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Comp R I VR1
R2
R3
R23
Total
8Ω4Ω4Ω
10v
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IT = V/ RT
IT = 10v / 10ΩIT = 1AIT = I1 = I23 = 1A
V1 = I1 X R1
V1 = 1A X 8ΩV1 = 8v
V23 = I23 X R23
V23 = 1A X 2ΩV23 = 2v
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}+
-V=10v
R1=8Ω
R23=2Ω V23 = 2v
V2 = V3 = 2v
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V2 = V3 = 2v
I2 = V2 / R2
I2 = 2v / 4ΩI2 = 0.5A
I3 = V3 / R3
I3 = 2v / 4ΩI3 = 0.5A
+
-V=10v R3 =4Ω
R1=8Ω
R2=4Ω
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+
-V=60v
R1= 10kΩ
R2= 15kΩR3= 30kΩ
R5 =
24kΩ
R4=24kΩ
R6= 3kΩ
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R1= 10kΩ
R2= 15kΩR3= 30kΩ
1R 123
1R1
1R2
= +1
R3
+
1R 123
110
115
= +1
30
+
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1R 123
110
115
= +1
30
+
1R 123
330
230
= +1
30
+
1R 123
630
=
R123 306
= 5kΩ =
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R123 5kΩ =
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+
-V=60v R5 =
24kΩ
R4=24kΩ
R6= 3kΩ
R123= 5kΩ
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R5 =
24kΩ
R4=24kΩ
1R 45
1R4
1R5
= +
1R 45
124
124
= +
1R 45
224=
R45 242
= 12kΩ =
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R45 12kΩ =
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V=60v
R6= 3kΩ
R123= 5kΩ
+
- R45=12kΩ
RT= R123 + R45 + R6
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RT= R123 + R45 + R6
RT= 5kΩ + 12kΩ + 3kΩ
RT= 20kΩ
IT =60v
20kΩ
IT =ET
RT
IT = 3mA
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V=10v
R6= 3kΩ
R123= 5kΩ
+
- R45=12kΩIT = 3mA
V123 = I123 X R123
= 3mA X 5kΩV123 = 15v
V45 = I45 X R45
=3mAX 12kΩV45 = 36v
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V6 = I6 X R6
= 3mA X 3kΩ
V6 = 9v
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I1 =E1
R1
=10v10kΩ
I1 = 1mA
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I2 =E2
R2
=15v10kΩ
I2 = 1.5mA
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I3 =E3
R3
=15v30kΩ
I3 = 0.5mA
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I4,5 =E4
R4
=36v24kΩ
I4,5 = 1.5mA
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I6 =E6
R6
=9v3kΩ
I3 = 3mA