scpy155_lec5_บทที่ 11_ไฟฟ้ากระแส
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SCPY155_lec5_บทที่ 11_ไฟฟ้ากระแสTRANSCRIPT
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11 :
SCPY 155 Basic physics for medical and health science
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(electric current)
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(I) Q
A
(A) 1 A = 1 C/s
t
t
QI
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(A) (V)
0.0003 3 10-20 10,000 10 120 0.1 3
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1 0.2 mA 1 ( 1.6x10^-19 C)
I=Q/t N=Q/e
N=4.5x10^18
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R (V)
()
R
VI
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(L) (A)
(resistivity)
A
LR
m
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1.59x10^-8 2.44x10^-8 2.82x10^-8 1.7x10^-8 3.5x10^-5 10^10 10^14 10^13
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2 0.5 1
r
A
LR
m 8107.1 2rA
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3 50 cm 2 cm 500 16
A
LR
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(direct current, DC)
(alternating current, AC)
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() R V=IR
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4 15 3 V
V=IR 0.2 A
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5 3 V 0.3 mA
R=10 k
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(equivalent resistance) Req = R1+R2
R1 R2 V Vab+Vbc =IR1+IR2
V = IReq
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1/Req = 1/R1+1/R2
R1 R2
V Itotal =I1+I2=V /R1+V /R2=V /Req
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(Kirchoffs rules)
I1= I2+I3 09/09/56 http://www.sc.mahidol.ac.th/scpy/courses/
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6 6 V R1, R2, R3 8, 8, 4
, , ,
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1 2
3
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7 I, I1, I2
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8 R = 5
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R a b
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VQU
Q
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(P) (W)
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t
t
UP
t
VQ
t
U
t
QI
RIVIt
UP 2
RVP /2
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40 W, 60W 100 W 220 V 0.18 A
40 W R= 40 W/(0.18 A)^2 = ??
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8 9 V 0.5mA
P = 4.5 mW
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50 Hz
(Vac) (Iac)
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(AC) (DC)
Veff (effective voltage)
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(effective current)
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2
0VVeff
2
0IIeff
effeffVIP
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