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Pressure Vessel Engineering, Ltd.120 Randall Dr. Waterloo, Ontario N2V 1C6
Date Printed: 11/12/2009
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Pressure Vessel Design Summary
Customer
Vessel
Job & Rev
Calculations by
Reviewed by
UG-22 Loadings Considered
Yes (a) Internal pressure
No (a) External pressure
No (b) Vessel weight full, empty and at hydro test
No (c) Weight of attached equipment and piping
No (d)(1) Attachment of internals
No (d)(2) Attachment of vessel supports
No (d) Cyclic or dynamic reactions
Yes (f) Wind
No (f) Snow
Yes (f) SeismicNo (g) Fluid impact shock reactions
No (h) Temperature gradients
No (h) Differential thermal expansion
No (i) Abnormal pressures like deflagration
NO (j) Hydrotest Loads
Sample 13
Sample 13
Brian Munn
Laurence Brundrett P. Eng.
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Pressure Vessel Engineering, Ltd.Shell 1
Customer: Pressure Vessel Engineering LtdJob No: PVE-3602 Sample 13 Vessel Number: Sample 13
Number: 1 Mark Number: S1
Date Printed: 11/12/2009
Cylindrical Shell Design Information
Design Pressure: 250.00 PSI Design Temperature: 550 F
Static Head: 34.00 PSI Long. Joint Efficiency: 85 %Shell Material: SA-516 Gr. 70 Factor B Chart: CS-2
Material Condition: Normalized Material Stress (hot): 19700 PSIShell Length: 98.0000 in. Material Stress (cold): 20000 PSI
Compressive Stress: 11431 PSICorrosion Allowance: 0.1250 in. Actual Circumferential Stress: 16286 PSI
External Corrosion Allowance: 0.0000 in. Actual Longitudinal Stress: 7976 PSI
Outside Diameter (new): 86.0000 in.Outside Diameter (corroded): 86.0000 in. Specific Gravity: 1.00
Shell Surface Area: 183.87 Sq. Ft. Weight of Fluid: 19643.09 lb.Shell Estimated Volume: 2351.32 Gal. Total Flooded Shell Weight: 26970.54 lb.
Circ. Joint Efficiency: 85 % Shell Weight: 7327.45 lb.
Minimum Design Metal Temperature Data
Min. Temperature Curve: D Pressure at MDMT: 250.00 PSIUCS-66(b) reduction: No Minimum Design Metal Temperature: -20 FUCS-68(c) reduction: No Computed Minimum Temperature: -30 F
External Pressure Data
Design Pressure (Pa): 15.00 PSI Design Temperature: 550 FDimension L: 294.0000 in.
Ext. Minimum t: 0.5830 in. Ext. Nominal t: 1.0000 in.Minimum L/Do: 3.4186 Nominal L/Do: 3.4186Minimum Do/t: 187.7730 Nominal Do/t: 98.2857
Minimum Factor A:0.0001627 Nominal Factor A:0.0004162Minimum Factor B: 2112 PSI Nominal Factor B: 5414 PSI
Design Thickness Calculations
Longitudinal Stress Calculations per Paragraph UG-27(c)(2)
t =PR
2SE + 0.4P=
284.00 * 42.1250
2 * 19700 * 0.85 + 0.4 * 284.00= 0.3560 + 0.1250 (corrosion) + 0.0000 (ext.corrosion) = minimum of 0.4810
Circumferential Stress Calculations per Appendix 1-1(a)(1)
t =PRo
SE + 0.4P=
284.00 * 43.0000
19700 * 0.85 + 0.4 * 284.00= 0.7244 + 0.1250 (corrosion) + 0.0000 (ext.corrosion) = minimum of 0.8494
Maximum External Pressure Calculation per Paragraph UG-28
Pa (using nominalt) =4B
3(Do / t)=
4 * 5414
3 * ( 86.0000 / 0.8750 )= maximum external pressure of 73.45 P
Extreme Fiber Elongation Calculation per Paragraph UCS-79
Elongation =50t
Rf=
50 * 1.0000
42.5000= elongation of 1.18
External loads do not control design.
Advanced Pressure Vessel version: 10.1.5 Computer Engineering, Inc. Section VIII, Division 1, 2007 Edition, 2008 AddenPage 1 of 95
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Pressure Vessel Engineering, Ltd.Shell 1
Job No: PVE-3602 Sample 13 Vessel Number: Sample 13Number: 1 Mark Number: S1
Date Printed: 11/12/2009
Nominal Shell Thickness Selected = 1.0000 in.
Advanced Pressure Vessel version: 10.1.5 Computer Engineering, Inc. Section VIII, Division 1, 2007 Edition, 2008 AddenPage 2 of 95
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Pressure Vessel Engineering, Ltd.Shell 2
Customer: Pressure Vessel Engineering LtdJob No: PVE-3602 Sample 13 Vessel Number: Sample 13
Number: 2 Mark Number: S2
Date Printed: 11/12/2009
Cylindrical Shell Design Information
Design Pressure: 250.00 PSI Design Temperature: 550 FStatic Head: 17.00 PSI Long. Joint Efficiency: 85 %
Shell Material: SA-516 Gr. 70 Factor B Chart: CS-2Material Condition: Normalized Material Stress (hot): 19700 PSI
Shell Length: 88.0000 in. Material Stress (cold): 20000 PSICompressive Stress: 10819 PSI
Corrosion Allowance: 0.1250 in. Actual Circumferential Stress: 19075 PSIExternal Corrosion Allowance: 0.0000 in. Actual Longitudinal Stress: 9380 PSI
Outside Diameter (new): 122.2500 in.Outside Diameter (corroded): 122.2500 in. Specific Gravity: 1.00
Shell Surface Area: 234.70 Sq. Ft. Weight of Fluid: 35997.33 lb.Shell Estimated Volume: 4308.96 Gal. Total Flooded Shell Weight: 46545.50 lb.
Circ. Joint Efficiency: 85 % Shell Weight: 10548.16 lb.
Minimum Design Metal Temperature Data
Min. Temperature Curve: D Pressure at MDMT: 250.00 PSIUCS-66(b) reduction: No Minimum Design Metal Temperature: -20 FUCS-68(c) reduction: No Computed Minimum Temperature: -26 F
External Pressure Data
Design Pressure (Pa): 15.00 PSI Design Temperature: 550 F
Dimension L: 294.0000 in.Ext. Minimum t: 0.6939 in. Ext. Nominal t: 1.1250 in.Minimum L/Do: 2.4049 Nominal L/Do: 2.4049Minimum Do/t: 214.8880 Nominal Do/t: 122.2500
Minimum Factor A:0.0001862 Nominal Factor A:0.0004285Minimum Factor B: 2418 PSI Nominal Factor B: 5573 PSI
Design Thickness Calculations
Longitudinal Stress Calculations per Paragraph UG-27(c)(2)
t =PR
2SE + 0.4P=
267.00 * 60.1250
2 * 19700 * 0.85 + 0.4 * 267.00= 0.4778 + 0.1250 (corrosion) + 0.0000 (ext.corrosion) = minimum of 0.6028
Circumferential Stress Calculations per Appendix 1-1(a)(1)
t =PRo
SE + 0.4P=
267.00 * 61.1250
19700 * 0.85 + 0.4 * 267.00= 0.9685 + 0.1250 (corrosion) + 0.0000 (ext.corrosion) = minimum of 1.0935
Maximum External Pressure Calculation per Paragraph UG-28
Pa (using nominalt) =4B
3(Do / t)=
4 * 5573
3 * ( 122.2500 / 1.0000 )= maximum external pressure of 60.78 P
Extreme Fiber Elongation Calculation per Paragraph UCS-79
Elongation =50t
Rf=
50 * 1.1250
60.5625= elongation of 0.93
External loads do not control design.
Advanced Pressure Vessel version: 10.1.5 Computer Engineering, Inc. Section VIII, Division 1, 2007 Edition, 2008 AddenPage 3 of 95
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Pressure Vessel Engineering, Ltd.Shell 2
Job No: PVE-3602 Sample 13 Vessel Number: Sample 13Number: 2 Mark Number: S2
Date Printed: 11/12/2009
Nominal Shell Thickness Selected = 1.1250 in.
Advanced Pressure Vessel version: 10.1.5 Computer Engineering, Inc. Section VIII, Division 1, 2007 Edition, 2008 AddenPage 4 of 95
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Pressure Vessel Engineering, Ltd.Shell 3
Customer: Pressure Vessel Engineering LtdJob No: PVE-3602 Sample 13 Vessel Number: Sample 13
Number: 3 Mark Number: S3
Date Printed: 11/12/2009
Cylindrical Shell Design Information
Design Pressure: 250.00 PSI Design Temperature: 550 FStatic Head: 17.00 PSI Long. Joint Efficiency: 85 %
Shell Material: SA-516 Gr. 70 Factor B Chart: CS-2Material Condition: Normalized Material Stress (hot): 19700 PSI
Shell Length: 144.0000 in. Material Stress (cold): 20000 PSICompressive Stress: 10819 PSI
Corrosion Allowance: 0.1250 in. Actual Circumferential Stress: 19075 PSIExternal Corrosion Allowance: 0.0000 in. Actual Longitudinal Stress: 9380 PSI
Outside Diameter (new): 122.2500 in.Outside Diameter (corroded): 122.2500 in. Specific Gravity: 1.00
Shell Surface Area: 384.06 Sq. Ft. Weight of Fluid: 58904.73 lb.Shell Estimated Volume: 7051.03 Gal. Total Flooded Shell Weight: 76165.36 lb.
Circ. Joint Efficiency: 85 % Shell Weight: 17260.63 lb.
Minimum Design Metal Temperature Data
Min. Temperature Curve: D Pressure at MDMT: 250.00 PSIUCS-66(b) reduction: No Minimum Design Metal Temperature: -20 FUCS-68(c) reduction: No Computed Minimum Temperature: -26 F
External Pressure Data
Design Pressure (Pa): 15.00 PSI Design Temperature: 550 F
Dimension L: 294.0000 in.Ext. Minimum t: 0.6939 in. Ext. Nominal t: 1.1250 in.Minimum L/Do: 2.4049 Nominal L/Do: 2.4049Minimum Do/t: 214.8880 Nominal Do/t: 122.2500
Minimum Factor A:0.0001862 Nominal Factor A:0.0004285Minimum Factor B: 2418 PSI Nominal Factor B: 5573 PSI
Design Thickness Calculations
Longitudinal Stress Calculations per Paragraph UG-27(c)(2)
t =PR
2SE + 0.4P=
267.00 * 60.1250
2 * 19700 * 0.85 + 0.4 * 267.00= 0.4778 + 0.1250 (corrosion) + 0.0000 (ext.corrosion) = minimum of 0.6028
Circumferential Stress Calculations per Appendix 1-1(a)(1)
t =PRo
SE + 0.4P=
267.00 * 61.1250
19700 * 0.85 + 0.4 * 267.00= 0.9685 + 0.1250 (corrosion) + 0.0000 (ext.corrosion) = minimum of 1.0935
Maximum External Pressure Calculation per Paragraph UG-28
Pa (using nominalt) =4B
3(Do / t)=
4 * 5573
3 * ( 122.2500 / 1.0000 )= maximum external pressure of 60.78 P
Extreme Fiber Elongation Calculation per Paragraph UCS-79
Elongation =50t
Rf=
50 * 1.1250
60.5625= elongation of 0.93
External loads do not control design.
Advanced Pressure Vessel version: 10.1.5 Computer Engineering, Inc. Section VIII, Division 1, 2007 Edition, 2008 AddenPage 5 of 95
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Pressure Vessel Engineering, Ltd.Shell 3
Job No: PVE-3602 Sample 13 Vessel Number: Sample 13Number: 3 Mark Number: S3
Date Printed: 11/12/2009
Nominal Shell Thickness Selected = 1.1250 in.
Advanced Pressure Vessel version: 10.1.5 Computer Engineering, Inc. Section VIII, Division 1, 2007 Edition, 2008 AddenPage 6 of 95
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Pressure Vessel Engineering, Ltd.Shell 4
Customer: Pressure Vessel Engineering LtdJob No: PVE-3602 Sample 13 Vessel Number: Sample 13
Number: 4 Mark Number: S4
Date Printed: 11/12/2009
Cylindrical Shell Design Information
Design Pressure: 250.00 PSI Design Temperature: 550 FStatic Head: 34.00 PSI Long. Joint Efficiency: 85 %
Shell Material: SA-516 Gr. 70 Factor B Chart: CS-2Material Condition: Normalized Material Stress (hot): 19700 PSI
Shell Length: 98.0000 in. Material Stress (cold): 20000 PSICompressive Stress: 11431 PSI
Corrosion Allowance: 0.1250 in. Actual Circumferential Stress: 16286 PSIExternal Corrosion Allowance: 0.0000 in. Actual Longitudinal Stress: 7976 PSI
Outside Diameter (new): 86.0000 in.Outside Diameter (corroded): 86.0000 in. Specific Gravity: 1.00
Shell Surface Area: 183.87 Sq. Ft. Weight of Fluid: 19643.09 lb.Shell Estimated Volume: 2351.32 Gal. Total Flooded Shell Weight: 26970.54 lb.
Circ. Joint Efficiency: 85 % Shell Weight: 7327.45 lb.
Minimum Design Metal Temperature Data
Min. Temperature Curve: D Pressure at MDMT: 250.00 PSIUCS-66(b) reduction: No Minimum Design Metal Temperature: -20 FUCS-68(c) reduction: No Computed Minimum Temperature: -30 F
External Pressure Data
Design Pressure (Pa): 15.00 PSI Design Temperature: 550 F
Dimension L: 294.0000 in.Ext. Minimum t: 0.5830 in. Ext. Nominal t: 1.0000 in.Minimum L/Do: 3.4186 Nominal L/Do: 3.4186Minimum Do/t: 187.7730 Nominal Do/t: 98.2857
Minimum Factor A:0.0001627 Nominal Factor A:0.0004162Minimum Factor B: 2112 PSI Nominal Factor B: 5414 PSI
Design Thickness Calculations
Longitudinal Stress Calculations per Paragraph UG-27(c)(2)
t =PR
2SE + 0.4P=
284.00 * 42.1250
2 * 19700 * 0.85 + 0.4 * 284.00= 0.3560 + 0.1250 (corrosion) + 0.0000 (ext.corrosion) = minimum of 0.4810
Circumferential Stress Calculations per Appendix 1-1(a)(1)
t =PRo
SE + 0.4P=
284.00 * 43.0000
19700 * 0.85 + 0.4 * 284.00= 0.7244 + 0.1250 (corrosion) + 0.0000 (ext.corrosion) = minimum of 0.8494
Maximum External Pressure Calculation per Paragraph UG-28
Pa (using nominalt) =4B
3(Do / t)=
4 * 5414
3 * ( 86.0000 / 0.8750 )= maximum external pressure of 73.45 P
Extreme Fiber Elongation Calculation per Paragraph UCS-79
Elongation =50t
Rf=
50 * 1.0000
42.5000= elongation of 1.18
External loads do not control design.
Advanced Pressure Vessel version: 10.1.5 Computer Engineering, Inc. Section VIII, Division 1, 2007 Edition, 2008 AddenPage 7 of 95
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Pressure Vessel Engineering, Ltd.Shell 4
Job No: PVE-3602 Sample 13 Vessel Number: Sample 13Number: 4 Mark Number: S4
Date Printed: 11/12/2009
Nominal Shell Thickness Selected = 1.0000 in.
Advanced Pressure Vessel version: 10.1.5 Computer Engineering, Inc. Section VIII, Division 1, 2007 Edition, 2008 AddenPage 8 of 95
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Pressure Vessel Engineering, Ltd.Shell 5
Customer: Pressure Vessel Engineering LtdJob No: PVE-3602 Sample 13 Vessel Number: Sample 13
Number: 5 Mark Number: S5
Date Printed: 11/12/2009
Cylindrical Shell Design Information
Design Pressure: 250.00 PSI Design Temperature: 550 FStatic Head: 34.00 PSI Long. Joint Efficiency: 85 %
Shell Material: SA-516 Gr. 70 Factor B Chart: CS-2Material Condition: Normalized Material Stress (hot): 19700 PSI
Shell Length: 98.0000 in. Material Stress (cold): 20000 PSICompressive Stress: 11431 PSI
Corrosion Allowance: 0.1250 in. Actual Circumferential Stress: 16286 PSIExternal Corrosion Allowance: 0.0000 in. Actual Longitudinal Stress: 7976 PSI
Outside Diameter (new): 86.0000 in.Outside Diameter (corroded): 86.0000 in. Specific Gravity: 1.00
Shell Surface Area: 183.87 Sq. Ft. Weight of Fluid: 19643.09 lb.Shell Estimated Volume: 2351.32 Gal. Total Flooded Shell Weight: 26970.54 lb.
Circ. Joint Efficiency: 85 % Shell Weight: 7327.45 lb.
Minimum Design Metal Temperature Data
Min. Temperature Curve: D Pressure at MDMT: 250.00 PSIUCS-66(b) reduction: No Minimum Design Metal Temperature: -20 FUCS-68(c) reduction: No Computed Minimum Temperature: -30 F
External Pressure Data
Design Pressure (Pa): 15.00 PSI Design Temperature: 550 F
Dimension L: 294.0000 in.Ext. Minimum t: 0.5830 in. Ext. Nominal t: 1.0000 in.Minimum L/Do: 3.4186 Nominal L/Do: 3.4186Minimum Do/t: 187.7730 Nominal Do/t: 98.2857
Minimum Factor A:0.0001627 Nominal Factor A:0.0004162Minimum Factor B: 2112 PSI Nominal Factor B: 5414 PSI
Design Thickness Calculations
Longitudinal Stress Calculations per Paragraph UG-27(c)(2)
t =PR
2SE + 0.4P=
284.00 * 42.1250
2 * 19700 * 0.85 + 0.4 * 284.00= 0.3560 + 0.1250 (corrosion) + 0.0000 (ext.corrosion) = minimum of 0.4810
Circumferential Stress Calculations per Appendix 1-1(a)(1)
t =PRo
SE + 0.4P=
284.00 * 43.0000
19700 * 0.85 + 0.4 * 284.00= 0.7244 + 0.1250 (corrosion) + 0.0000 (ext.corrosion) = minimum of 0.8494
Maximum External Pressure Calculation per Paragraph UG-28
Pa (using nominalt) =4B
3(Do / t)=
4 * 5414
3 * ( 86.0000 / 0.8750 )= maximum external pressure of 73.45 P
Extreme Fiber Elongation Calculation per Paragraph UCS-79
Elongation =50t
Rf=
50 * 1.0000
42.5000= elongation of 1.18
External loads do not control design.
Advanced Pressure Vessel version: 10.1.5 Computer Engineering, Inc. Section VIII, Division 1, 2007 Edition, 2008 AddenPage 9 of 95
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Pressure Vessel Engineering, Ltd.Shell 5
Job No: PVE-3602 Sample 13 Vessel Number: Sample 13Number: 5 Mark Number: S5
Date Printed: 11/12/2009
Nominal Shell Thickness Selected = 1.0000 in.
Advanced Pressure Vessel version: 10.1.5 Computer Engineering, Inc. Section VIII, Division 1, 2007 Edition, 2008 AddenPage 10 of 95
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Pressure Vessel Engineering, Ltd.Shell 6
Customer: Pressure Vessel Engineering LtdJob No: PVE-3602 Sample 13 Vessel Number: Sample 13
Number: 6 Mark Number: S6
Date Printed: 11/12/2009
Cylindrical Shell Design Information
Design Pressure: 250.00 PSI Design Temperature: 550 FStatic Head: 17.00 PSI Long. Joint Efficiency: 85 %
Shell Material: SA-516 Gr. 70 Factor B Chart: CS-2Material Condition: Normalized Material Stress (hot): 19700 PSI
Shell Length: 72.0000 in. Material Stress (cold): 20000 PSICompressive Stress: 10819 PSI
Corrosion Allowance: 0.1250 in. Actual Circumferential Stress: 19075 PSIExternal Corrosion Allowance: 0.0000 in. Actual Longitudinal Stress: 9380 PSI
Outside Diameter (new): 122.2500 in.Outside Diameter (corroded): 122.2500 in. Specific Gravity: 1.00
Shell Surface Area: 192.03 Sq. Ft. Weight of Fluid: 29452.36 lb.Shell Estimated Volume: 3525.52 Gal. Total Flooded Shell Weight: 38082.68 lb.
Circ. Joint Efficiency: 85 % Shell Weight: 8630.32 lb.
Minimum Design Metal Temperature Data
Min. Temperature Curve: D Pressure at MDMT: 250.00 PSIUCS-66(b) reduction: No Minimum Design Metal Temperature: -20 FUCS-68(c) reduction: No Computed Minimum Temperature: -26 F
External Pressure Data
Design Pressure (Pa): 15.00 PSI Design Temperature: 550 F
Dimension L: 294.0000 in.Ext. Minimum t: 0.6939 in. Ext. Nominal t: 1.1250 in.Minimum L/Do: 2.4049 Nominal L/Do: 2.4049Minimum Do/t: 214.8880 Nominal Do/t: 122.2500
Minimum Factor A:0.0001862 Nominal Factor A:0.0004285Minimum Factor B: 2418 PSI Nominal Factor B: 5573 PSI
Design Thickness Calculations
Longitudinal Stress Calculations per Paragraph UG-27(c)(2)
t =PR
2SE + 0.4P=
267.00 * 60.1250
2 * 19700 * 0.85 + 0.4 * 267.00= 0.4778 + 0.1250 (corrosion) + 0.0000 (ext.corrosion) = minimum of 0.6028
Circumferential Stress Calculations per Appendix 1-1(a)(1)
t =PRo
SE + 0.4P=
267.00 * 61.1250
19700 * 0.85 + 0.4 * 267.00= 0.9685 + 0.1250 (corrosion) + 0.0000 (ext.corrosion) = minimum of 1.0935
Maximum External Pressure Calculation per Paragraph UG-28
Pa (using nominalt) =4B
3(Do / t)=
4 * 5573
3 * ( 122.2500 / 1.0000 )= maximum external pressure of 60.78 P
Extreme Fiber Elongation Calculation per Paragraph UCS-79
Elongation =50t
Rf=
50 * 1.1250
60.5625= elongation of 0.93
External loads do not control design.
Advanced Pressure Vessel version: 10.1.5 Computer Engineering, Inc. Section VIII, Division 1, 2007 Edition, 2008 AddenPage 11 of 95
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Pressure Vessel Engineering, Ltd.Shell 6
Job No: PVE-3602 Sample 13 Vessel Number: Sample 13Number: 6 Mark Number: S6
Date Printed: 11/12/2009
Nominal Shell Thickness Selected = 1.1250 in.
Advanced Pressure Vessel version: 10.1.5 Computer Engineering, Inc. Section VIII, Division 1, 2007 Edition, 2008 AddenPage 12 of 95
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Pressure Vessel Engineering, Ltd.Shell 7
Customer: Pressure Vessel Engineering LtdJob No: PVE-3602 Sample 13 Vessel Number: Sample 13
Number: 7 Mark Number: S7
Date Printed: 11/12/2009
Cylindrical Shell Design Information
Design Pressure: 250.00 PSI Design Temperature: 550 FStatic Head: 3.50 PSI Long. Joint Efficiency: 85 %
Shell Material: SA-516 Gr. 70 Factor B Chart: CS-2Material Condition: Normalized Material Stress (hot): 19700 PSI
Shell Length: 12.0000 in. Material Stress (cold): 20000 PSICompressive Stress: 12806 PSI
Corrosion Allowance: 0.1250 in. Actual Circumferential Stress: 6229 PSIExternal Corrosion Allowance: 0.0000 in. Actual Longitudinal Stress: 2965 PSI
Outside Diameter (new): 37.2500 in.Outside Diameter (corroded): 37.2500 in. Specific Gravity: 1.00
Shell Surface Area: 9.75 Sq. Ft. Weight of Fluid: 423.57 lb.Shell Estimated Volume: 50.70 Gal. Total Flooded Shell Weight: 806.22 lb.
Circ. Joint Efficiency: 85 % Shell Weight: 382.65 lb.
Minimum Design Metal Temperature Data
Min. Temperature Curve: D Pressure at MDMT: 250.00 PSIUCS-66(b) reduction: No Minimum Design Metal Temperature: -20 FUCS-68(c) reduction: No Computed Minimum Temperature: -30 F
External Pressure Data
Design Pressure (Pa): 15.00 PSI Design Temperature: 550 F
Dimension L: 294.0000 in.Ext. Minimum t: 0.4224 in. Ext. Nominal t: 1.0000 in.Minimum L/Do: 7.8926 Nominal L/Do: 7.8926Minimum Do/t: 125.2520 Nominal Do/t: 42.5714
Minimum Factor A:0.0001088 Nominal Factor A:0.0006686Minimum Factor B: 1409 PSI Nominal Factor B: 8458 PSI
Design Thickness Calculations
Longitudinal Stress Calculations per Paragraph UG-27(c)(2)
t =PR
2SE + 0.4P=
253.50 * 17.7500
2 * 19700 * 0.85 + 0.4 * 253.50= 0.1340 + 0.1250 (corrosion) + 0.0000 (ext.corrosion) = minimum of 0.2590
Circumferential Stress Calculations per Appendix 1-1(a)(1)
t =PRo
SE + 0.4P=
253.50 * 18.6250
19700 * 0.85 + 0.4 * 253.50= 0.2803 + 0.1250 (corrosion) + 0.0000 (ext.corrosion) = minimum of 0.4053
Maximum External Pressure Calculation per Paragraph UG-28
Pa (using nominalt) =4B
3(Do / t)=
4 * 8458
3 * ( 37.2500 / 0.8750 )= maximum external pressure of 264.90 P
Extreme Fiber Elongation Calculation per Paragraph UCS-79
Elongation =50t
Rf=
50 * 1.0000
18.1250= elongation of 2.76
External loads do not control design.
Advanced Pressure Vessel version: 10.1.5 Computer Engineering, Inc. Section VIII, Division 1, 2007 Edition, 2008 AddenPage 13 of 95
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Pressure Vessel Engineering, Ltd.Shell 7
Job No: PVE-3602 Sample 13 Vessel Number: Sample 13Number: 7 Mark Number: S7
Date Printed: 11/12/2009
Nominal Shell Thickness Selected = 1.0000 in.
Advanced Pressure Vessel version: 10.1.5 Computer Engineering, Inc. Section VIII, Division 1, 2007 Edition, 2008 AddenPage 14 of 95
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Pressure Vessel Engineering, Ltd.Shell 8
Customer: Pressure Vessel Engineering LtdJob No: PVE-3602 Sample 13 Vessel Number: Sample 13
Number: 8 Mark Number: S8
Date Printed: 11/12/2009
Cylindrical Shell Design Information
Design Pressure: 250.00 PSI Design Temperature: 550 FStatic Head: 3.50 PSI Long. Joint Efficiency: 85 %
Shell Material: SA-516 Gr. 70 Factor B Chart: CS-2Material Condition: Normalized Material Stress (hot): 19700 PSI
Shell Length: 104.0000 in. Material Stress (cold): 20000 PSICompressive Stress: 11946 PSI
Corrosion Allowance: 0.1250 in. Actual Circumferential Stress: 10990 PSIExternal Corrosion Allowance: 0.0000 in. Actual Longitudinal Stress: 5346 PSI
Outside Diameter (new): 37.2500 in.Outside Diameter (corroded): 37.2500 in. Specific Gravity: 1.00
Shell Surface Area: 84.52 Sq. Ft. Weight of Fluid: 3828.81 lb.Shell Estimated Volume: 458.32 Gal. Total Flooded Shell Weight: 5922.91 lb.
Circ. Joint Efficiency: 85 % Shell Weight: 2094.11 lb.
Minimum Design Metal Temperature Data
Min. Temperature Curve: D Pressure at MDMT: 250.00 PSIUCS-66(b) reduction: Yes Minimum Design Metal Temperature: -20 FUCS-68(c) reduction: No Computed Minimum Temperature: -55 F
External Pressure Data
Design Pressure (Pa): 15.00 PSI Design Temperature: 550 F
Dimension L: 294.0000 in.Ext. Minimum t: 0.4224 in. Ext. Nominal t: 0.6250 in.Minimum L/Do: 7.8926 Nominal L/Do: 7.8926Minimum Do/t: 125.2520 Nominal Do/t: 74.5000
Minimum Factor A:0.0001088 Nominal Factor A:0.0002451Minimum Factor B: 1409 PSI Nominal Factor B: 3184 PSI
Design Thickness Calculations
Longitudinal Stress Calculations per Paragraph UG-27(c)(2)
t =PR
2SE + 0.4P=
253.50 * 18.1250
2 * 19700 * 0.85 + 0.4 * 253.50= 0.1368 + 0.1250 (corrosion) + 0.0000 (ext.corrosion) = minimum of 0.2618
Circumferential Stress Calculations per Appendix 1-1(a)(1)
t =PRo
SE + 0.4P=
253.50 * 18.6250
19700 * 0.85 + 0.4 * 253.50= 0.2803 + 0.1250 (corrosion) + 0.0000 (ext.corrosion) = minimum of 0.4053
Maximum External Pressure Calculation per Paragraph UG-28
Pa (using nominalt) =4B
3(Do / t)=
4 * 3184
3 * ( 37.2500 / 0.5000 )= maximum external pressure of 56.98 P
Extreme Fiber Elongation Calculation per Paragraph UCS-79
Elongation =50t
Rf=
50 * 0.6250
18.3125= elongation of 1.71
External loads do not control design.
Advanced Pressure Vessel version: 10.1.5 Computer Engineering, Inc. Section VIII, Division 1, 2007 Edition, 2008 AddenPage 15 of 95
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Pressure Vessel Engineering, Ltd.Shell 8
Job No: PVE-3602 Sample 13 Vessel Number: Sample 13Number: 8 Mark Number: S8
Date Printed: 11/12/2009
Nominal Shell Thickness Selected = 0.6250 in.
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Pressure Vessel Engineering, Ltd.Ring Stiffener 1
Customer: Pressure Vessel Engineering LtdJob No: PVE-3602 Sample 13 Vessel Number: Sample 13
Number: 1 Mark Number: RS1
Date Printed: 11/12/2009
Stiffener Design Information
Description: Ring 1
Quantity: 1Stiffener Is: Outside Design Temperature: 550 F
Material: SA-36 Factor B Chart: CS-2Stress(hot): 16600 PSI Stress(cold): 16600 PSI
As: 5.0000 sq. in. Ls: 294.0000 in.d1: 5.0000 in. d2: 1.0000 in.
Corrosion Allowance: 0.0000 in.
Cylindrical Shell Design InformationShell 5
External Pressure: 15.00 PSI Shell Factor B Chart: CS-2Shell Thickness: 1.0000 in. Shell Outside Diameter: 86.0000 in.
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Pressure Vessel Engineering, Ltd.Ring Stiffener 1
Job No: PVE-3602 Sample 13 Vessel Number: Sample 13Number: 1 Mark Number: RS1
Date Printed: 11/12/2009
FLATBAR Stiffener CalculationsAvailable Moments of Intertia
Available Stiffening Ring Moment of Inertia (I)
y =d1
2=
5.0000
2= 2.5000
I =d2 * d1
12=
1.0000 * 5.0000
12= 10.4167 in.
Lsh = 1.1 * Do * t = 1.1 * 86.0000 * 0.8750 = 9.5421
Ash(Shell Area) = Lsht = 9.5421 * 0.8750 = 8.3493 sq.
Ish(Shell Moment of Inertia) =Lsht
12=
9.5421 * 0.8750
12= 0.5327 in.
X(Neutral Axis) =As(t + y) + (Ash * t)
As + Ash=
5.0000 * (0.8750 + 2.5000) + (8.3493 * * 0.8750)
5.0000 + 8.3493= 1.5377
I' = I + Ish + As * ((t + y) - X) + Ash * (X - t) = 10.4167 + 0.5327 +
5.0000 * ((0.8750 + 2.5000) - 1.5377) + 8.3493 * (1.5377 - ( * 0.8750)) = 37.9341 in.
Required Moments of Inertia
Factor B = PDo
t +
As
Ls
= 15.00 * 86.0000
0.8750 +
5.0000
294.0000
= 1085 P
From Factor B Table Factor A = 0.00008
Ring Moment(Is) =
Do * Ls t +
As
Ls
* A
14=
86.0000 * 294.00000.8750 +
5.0000
294.0000
* 0.0000840
14= 11.6376 in.
Combined Moment(Is') =
Do * Ls t +
As
Ls
* A
10.9=
86.0000 * 294.00000.8750 +
5.0000
294.0000
* 0.0000840
10.9= 14.9474 in.
I' greater than or equal to Is'Stiffener Ring PASSES the requirements of UG-29
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Pressure Vessel Engineering, Ltd.Ring Stiffener 2
Customer: Pressure Vessel Engineering LtdJob No: PVE-3602 Sample 13 Vessel Number: Sample 13
Number: 2 Mark Number: RS2
Date Printed: 11/12/2009
Stiffener Design Information
Description: Ring 2Quantity: 1
Stiffener Is: Outside Design Temperature: 550 FMaterial: SA-36 Factor B Chart: CS-2
Stress(hot): 16600 PSI Stress(cold): 16600 PSIAs: 5.0000 sq. in. Ls: 294.0000 in.d1: 5.0000 in. d2: 1.0000 in.
Corrosion Allowance: 0.0000 in.
Cylindrical Shell Design InformationShell 2
External Pressure: 15.00 PSI Shell Factor B Chart: CS-2Shell Thickness: 1.1250 in. Shell Outside Diameter: 122.2500 in.
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Pressure Vessel Engineering, Ltd.Ring Stiffener 2
Job No: PVE-3602 Sample 13 Vessel Number: Sample 13Number: 2 Mark Number: RS2
Date Printed: 11/12/2009
FLATBAR Stiffener CalculationsAvailable Moments of Intertia
Available Stiffening Ring Moment of Inertia (I)
y =d1
2=
5.0000
2= 2.5000
I =d2 * d1
12=
1.0000 * 5.0000
12= 10.4167 in.
Lsh = 1.1 * Do * t = 1.1 * 122.2500 * 1.0000 = 12.1623
Ash(Shell Area) = Lsht = 12.1623 * 1.0000 = 12.1623 sq.
Ish(Shell Moment of Inertia) =Lsht
12=
12.1623 * 1.0000
12= 1.0135 in.
X(Neutral Axis) =As(t + y) + (Ash * t)
As + Ash=
5.0000 * (1.0000 + 2.5000) + (12.1623 * * 1.0000)
5.0000 + 12.1623= 1.3740
I' = I + Ish + As * ((t + y) - X) + Ash * (X - t) = 10.4167 + 1.0135 +
5.0000 * ((1.0000 + 2.5000) - 1.3740) + 12.1623 * (1.3740 - ( * 1.0000)) = 43.3201 in.
Required Moments of Inertia
Factor B = PDo
t +
As
Ls
= 15.00 * 122.2500
1.0000 +
5.0000
294.0000
= 1352 P
From Factor B Table Factor A = 0.00010
Ring Moment(Is) =
Do * Ls t +
As
Ls
* A
14=
122.2500 * 294.00001.0000 +
5.0000
294.0000
* 0.0001050
14= 33.5143 in.
Combined Moment(Is') =
Do * Ls t +
As
Ls
* A
10.9=
122.2500 * 294.00001.0000 +
5.0000
294.0000
* 0.0001050
10.9= 43.0459 in.
I' greater than or equal to Is'Stiffener Ring PASSES the requirements of UG-29
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Pressure Vessel Engineering, Ltd.Ring Stiffener 3
Customer: Pressure Vessel Engineering LtdJob No: PVE-3602 Sample 13 Vessel Number: Sample 13
Number: 3 Mark Number: RS3
Date Printed: 11/12/2009
Stiffener Design Information
Description:Quantity: 1
Stiffener Is: Outside Design Temperature: 550 FMaterial: SA-36 Factor B Chart: CS-2
Stress(hot): 16600 PSI Stress(cold): 16600 PSIAs: 5.0000 sq. in. Ls: 294.0000 in.d1: 5.0000 in. d2: 1.0000 in.
Corrosion Allowance: 0.0000 in.
Cylindrical Shell Design InformationShell 6
External Pressure: 15.00 PSI Shell Factor B Chart: CS-2Shell Thickness: 1.1250 in. Shell Outside Diameter: 122.2500 in.
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Pressure Vessel Engineering, Ltd.Ring Stiffener 3
Job No: PVE-3602 Sample 13 Vessel Number: Sample 13Number: 3 Mark Number: RS3
Date Printed: 11/12/2009
FLATBAR Stiffener CalculationsAvailable Moments of Intertia
Available Stiffening Ring Moment of Inertia (I)
y =d1
2=
5.0000
2= 2.5000
I =d2 * d1
12=
1.0000 * 5.0000
12= 10.4167 in.
Lsh = 1.1 * Do * t = 1.1 * 122.2500 * 1.0000 = 12.1623
Ash(Shell Area) = Lsht = 12.1623 * 1.0000 = 12.1623 sq.
Ish(Shell Moment of Inertia) =Lsht
12=
12.1623 * 1.0000
12= 1.0135 in.
X(Neutral Axis) =As(t + y) + (Ash * t)
As + Ash=
5.0000 * (1.0000 + 2.5000) + (12.1623 * * 1.0000)
5.0000 + 12.1623= 1.3740
I' = I + Ish + As * ((t + y) - X) + Ash * (X - t) = 10.4167 + 1.0135 +
5.0000 * ((1.0000 + 2.5000) - 1.3740) + 12.1623 * (1.3740 - ( * 1.0000)) = 43.3201 in.
Required Moments of Inertia
Factor B = PDo
t +
As
Ls
= 15.00 * 122.2500
1.0000 +
5.0000
294.0000
= 1352 P
From Factor B Table Factor A = 0.00010
Ring Moment(Is) =
Do * Ls t +
As
Ls
* A
14=
122.2500 * 294.00001.0000 +
5.0000
294.0000
* 0.0001050
14= 33.5143 in.
Combined Moment(Is') =
Do * Ls t +
As
Ls
* A
10.9=
122.2500 * 294.00001.0000 +
5.0000
294.0000
* 0.0001050
10.9= 43.0459 in.
I' greater than or equal to Is'Stiffener Ring PASSES the requirements of UG-29
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Pressure Vessel Engineering, Ltd.Conical Reducer 1
Customer: Pressure Vessel Engineering LtdJob No: PVE-3602 Sample 13 Vessel Number: Sample 13
Number: 1 Mark Number: R1
Date Printed: 11/12/2009
Conical Reducer Design Information
Design Pressure: 250.00 PSI Design Temperature: 550 FStatic Head: 34.00 PSI Joint Efficiency: 85 %
Conical Reducer Material: SA-516 Gr. 70 Factor B Chart: CS-2Material Condition: Normalized Material Stress (hot): 19700 PSI
Corrosion Allowance: 0.1250 in. Material Stress (cold): 20000 PSIExternal Corrosion Allowance: 0.0000 in. Actual Conical Reducer Stress: 18226 PSISmall End of Cone Located at: Bottom Outside Ds : 86.0000 in.
Outside Diameter : 122.2500 in. Cone Height (h) : 120.0000 in.angle a (): 8.59
Conical Reducer Surface Area: 275.69 Sq. Ft. Specific Gravity: 1.00Conical Reducer Estimated Volume: 4256.50 Gal. Weight of Fluid: 35499.18 lb.
Conical Reducer Weight: 13726.15 lb. Total Flooded Conical Reducer Weight: 49225.33 lb.
Minimum Design Metal Temperature Data
Min. Temperature Curve: D Pressure at MDMT: 250.00 PSIUCS-66(b) reduction: No Minimum Design Metal Temperature: -20 FUCS-68(c) reduction: No Computed Minimum Temperature: -21 F
External Pressure Data
Design Pressure (Pa): 15.00 PSI Design Temperature: 550 FExt. Minimum t: 0.5053 in. Ext. Nominal t: 1.2500 in.
Minimum te: 0.3760 in. Nominal te: 1.1124 in.Minimum Factor A:0.0002814 Nominal Factor A:0.0014486
Minimum Factor B: 3657 PSI Nominal Factor B: 10066 PSI
Design Thickness Calculations
Design Thickness Calculations per Appendix 1-4(e)
t =PDo
2 cos (SE + 0.4P)=
284.00 * 122.2500
2 * 0.9888 * (19700 * 0.85 + 0.4 * 284.00 )= 1.0414 + 0.1250 (corrosion) + 0.0000 (ext.corrosion)
= minimum of 1.1664
Maximum External Pressure Calculation per Paragraph UG-33
Pa (using nominalt) =4B
3Dl
te
=4 * 10066
3122.2500
1.1124
= = maximum external pressure of 122.13 P
Extreme Fiber Elongation Calculation per Paragraph UCS-79
elongation =50t
Rf=
50 * 1.2500
42.3750= elongation of 1.47
Nominal Conical Reducer Thickness Selected = 1.2500 in.
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Pressure Vessel Engineering, Ltd.Conical Reducer 2
Customer: Pressure Vessel Engineering LtdJob No: PVE-3602 Sample 13 Vessel Number: Sample 13
Number: 2 Mark Number: R2
Date Printed: 11/12/2009
Conical Reducer Design Information
Design Pressure: 250.00 PSI Design Temperature: 550 FStatic Head: 3.50 PSI Joint Efficiency: 85 %
Conical Reducer Material: SA-516 Gr. 70 Factor B Chart: CS-2Material Condition: Normalized Material Stress (hot): 19700 PSI
Corrosion Allowance: 0.1250 in. Material Stress (cold): 20000 PSIExternal Corrosion Allowance: 0.0000 in. Actual Conical Reducer Stress: 19688 PSISmall End of Cone Located at: Top Outside Ds : 37.2500 in.
Outside Diameter : 122.2500 in. Cone Height (h) : 100.0000 in.angle a (): 23.03
Conical Reducer Surface Area: 189.05 Sq. Ft. Specific Gravity: 1.00Conical Reducer Estimated Volume: 2236.83 Gal. Weight of Fluid: 18655.18 lb.
Conical Reducer Weight: 8443.82 lb. Total Flooded Conical Reducer Weight: 27099.00 lb.
Minimum Design Metal Temperature Data
Min. Temperature Curve: D Pressure at MDMT: 224.75 PSIUCS-66(b) reduction: No Minimum Design Metal Temperature: -20 FUCS-68(c) reduction: No Computed Minimum Temperature: -26 F
External Pressure Data
Design Pressure (Pa): 15.00 PSI Design Temperature: 550 FExt. Minimum t: 0.4624 in. Ext. Nominal t: 1.1250 in.
Minimum te: 0.3105 in. Nominal te: 0.9203 in.Minimum Factor A:0.0003408 Nominal Factor A:0.0018060
Minimum Factor B: 4431 PSI Nominal Factor B: 10518 PSI
Design Thickness Calculations
Design Thickness Calculations per Appendix 1-4(e)
t =PDo
2 cos (SE + 0.4P)=
253.50 * 122.2500
2 * 0.9203 * (19700 * 0.85 + 0.4 * 253.50 )= 0.9995 + 0.1250 (corrosion) + 0.0000 (ext.corrosion)
= minimum of 1.1245
Maximum External Pressure Calculation per Paragraph UG-33
Pa (using nominalt) =4B
3Dl
te
=4 * 10518
3122.2500
0.9203
= = maximum external pressure of 105.57 P
Extreme Fiber Elongation Calculation per Paragraph UCS-79
elongation =50t
Rf=
50 * 1.1250
18.0625= elongation of 3.11
Nominal Conical Reducer Thickness Selected = 1.1250 in.
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Pressure Vessel Engineering, Ltd.Head 1
Customer: Pressure Vessel Engineering LtdJob No: PVE-3602 Sample 13 Vessel Number: Sample 13
Number: 1 Mark Number: H1
Date Printed: 11/12/2009
Ellipsoidal Head Design Information
Design Pressure: 250.00 PSI Design Temperature: 550 FStatic Head: 34.00 PSI Joint Efficiency: 100 %
Head Material: SA-516 Gr. 70 Factor B Chart: CS-2Material Condition: Normalized Material Stress (hot): 19700 PSI
Corrosion Allowance: 0.1250 in. Material Stress (cold): 20000 PSIExternal Corrosion Allowance: 0.0000 in. Actual Head Stress: 13701 PSI
Head Location: Bottom Straight Flange : 1.5000 in.Outside Diameter : 86.0000 in. Head Depth (ho) : 22.1250 in.
Thin Out : 0.2500 in.
K =1
6[2 + (D/2h) ] : 1.00
Head Surface Area: 57.14 Sq. Ft. Specific Gravity: 1.00
Head Estimated Volume: 365.50 Gal. Weight of Fluid: 3048.30 lb.Head Weight: 2879.93 lb. Total Flooded Head Weight: 5928.22 lb.
Minimum Design Metal Temperature Data
Min. Temperature Curve: D Pressure at MDMT: 250.00 PSIUCS-66(b) reduction: No Minimum Design Metal Temperature: -20 FUCS-68(c) reduction: No Computed Minimum Temperature: -30 F
External Pressure Data
Design Pressure (Pa): 15.00 PSI Design Temperature: 550 F
Ext. Minimum t: 0.6023 in. Ext. Nominal t: 1.2500 in.Minimum t - Ca - ext. Ca - Thin Out: 0.2273 in. Nominal t - Ca - ext. Ca. - Thin Out: 0.8750 in.
Minimum Factor A:0.0003797 Nominal Factor A:0.0014618Minimum Factor B: 4939 PSI Nominal Factor B: 10083 PSI
Design Thickness Calculations
Design Thickness Calculations per Appendix 1-4(c)
t =PDoK
2SE + 2P(K - 0.1)=
284.00 * 86.0000 * 1.00
2 * 19700 * 1.00 + 2 * 284.00 * (1.00 - 0.1)
= 0.6120 + 0.1250 (corrosion) + 0.0000 (ext.corrosion) + 0.2500(thin out) = minimum of 0.9870
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Pressure Vessel Engineering, Ltd.Head 1
Job No: PVE-3602 Sample 13 Vessel Number: Sample 13Number: 1 Mark Number: H1
Date Printed: 11/12/2009
Maximum External Pressure Calculation per Paragraph UG-33
Pa (using nominalt) =B
Ro
t
=10083
74.8200
0.8750
= maximum external pressure of 117.92
Extreme Fiber Elongation Calculation per Paragraph UCS-79
elongation =75t
Rf=
75 * 1.2500
14.4075= elongation of 6.51
tmin(external) =1.67PDo K
2SE + 2(1.67P)(K - 0.1)=
1.67 * 15.00 * 86.0000 * 1.00
2 * 19700 * 1.0 + 2(1.67 * 15.00) * (1.00 - 0.1 )
= Greater of(0.0546(Calc),0.0938(MinT)) + 0.1250 (corrosion) + 0.0000 (ext. corrosion) + 0.2500 (Thinout)= minimum of 0.4688
Nominal Head Thickness Selected = 1.2500 in.Minimum Thickness after forming, ts (uncorroded) = 1.0000 in.
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Pressure Vessel Engineering, Ltd.Head 2
Customer: Pressure Vessel Engineering LtdJob No: PVE-3602 Sample 13 Vessel Number: Sample 13
Number: 2 Mark Number: H2
Date Printed: 11/12/2009
Ellipsoidal Head Design Information
Design Pressure: 250.00 PSI Design Temperature: 550 FStatic Head: 0.00 PSI Joint Efficiency: 100 %
Head Material: SA-516 Gr. 70 Factor B Chart: CS-2Material Condition: Normalized Material Stress (hot): 19700 PSI
Corrosion Allowance: 0.1250 in. Material Stress (cold): 20000 PSIExternal Corrosion Allowance: 0.0000 in. Actual Head Stress: 12070 PSI
Head Location: Top Straight Flange : 1.5000 in.Outside Diameter : 37.2500 in. Head Depth (ho) : 9.5938 in.
Thin Out : 0.0625 in.
K =1
6[2 + (D/2h) ] : 0.99
Head Surface Area: 11.39 Sq. Ft. Specific Gravity: 1.00
Head Estimated Volume: 33.37 Gal. Weight of Fluid: 278.34 lb.Head Weight: 258.30 lb. Total Flooded Head Weight: 536.64 lb.
Minimum Design Metal Temperature Data
Min. Temperature Curve: D Pressure at MDMT: 250.00 PSIUCS-66(b) reduction: No Minimum Design Metal Temperature: -20 FUCS-68(c) reduction: No Computed Minimum Temperature: -55 F
External Pressure Data
Design Pressure (Pa): 15.00 PSI Design Temperature: 550 F
Ext. Minimum t: 0.2860 in. Ext. Nominal t: 0.5625 in.Minimum t - Ca - ext. Ca - Thin Out: 0.0985 in. Nominal t - Ca - ext. Ca. - Thin Out: 0.3750 in.
Minimum Factor A:0.0003799 Nominal Factor A:0.0014464Minimum Factor B: 4941 PSI Nominal Factor B: 10064 PSI
Design Thickness Calculations
Design Thickness Calculations per Appendix 1-4(c)
t =PDoK
2SE + 2P(K - 0.1)=
250.00 * 37.2500 * 0.99
2 * 19700 * 1.00 + 2 * 250.00 * (0.99 - 0.1)
= 0.2314 + 0.1250 (corrosion) + 0.0000 (ext.corrosion) + 0.0625(thin out) = minimum of 0.4189
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Pressure Vessel Engineering, Ltd.Head 2
Job No: PVE-3602 Sample 13 Vessel Number: Sample 13Number: 2 Mark Number: H2
Date Printed: 11/12/2009
Maximum External Pressure Calculation per Paragraph UG-33
Pa (using nominalt) =B
Ro
t
=10064
32.4075
0.3750
= maximum external pressure of 116.45
Extreme Fiber Elongation Calculation per Paragraph UCS-79
elongation =75t
Rf=
75 * 0.5625
6.2369= elongation of 6.76
tmin(external) =1.67PDo K
2SE + 2(1.67P)(K - 0.1)=
1.67 * 15.00 * 37.2500 * 0.99
2 * 19700 * 1.0 + 2(1.67 * 15.00) * (0.99 - 0.1 )
= Greater of(0.0234(Calc),0.0938(MinT)) + 0.1250 (corrosion) + 0.0000 (ext. corrosion) + 0.0625 (Thinout)= minimum of 0.2813
Nominal Head Thickness Selected = 0.5625 in.Minimum Thickness after forming, ts (uncorroded) = 0.5000 in.
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Pressure Vessel Engineering, Ltd.N1
Customer: Pressure Vessel Engineering LtdJob No: PVE-3602 Sample 13 Vessel Number: Sample 13
Number: 1 Mark Number: N1ID Number: N1
Date Printed: 11/12/2009
Nozzle Design Information
Design Pressure: 250.00 PSI Design Temperature: 550 FStatic Head: 0.00 PSI Nozzle Efficiency (E): 100 %
Nozzle Material: SA-106 Gr. B Joint Efficiency (E1): 1.00Factor B Chart: CS-2
External Projection: 2.0000 in. Allowable Stress at Design Temperature (Sn): 17100 PSI
Internal Projection: 0.0000 in. Allowable Stress at Ambient Temperature: 17100 PSIInside Corrosion Allowance: 0.1250 in. Correction Factor (F): 1.00
External Corrosion Allowance: 0.0000 in. Nozzle Path: NoneNozzle Pipe Size: 8 Nozzle Pipe Schedule: 80Nozzle ID (new): 7.6250 in. Nozzle Wall Thickness(new): 0.5000 in.
Nozzle ID (corroded): 7.8750 in. Nozzle Wall Thickness(corroded): 0.3750 in.Outer "h" Limit: 1.6875 in. Upper Weld Leg Size(Weld 41): 0.3750 in.
Internal "h" Limit: 0.6250 in. Internal Weld Leg Size(Weld 43): 0.0000 in.OD, Limit of Reinforcement: 15.7500 in. Outside Groove Weld Depth: 1.2500 in.
Minimum Design Metal Temperature
Min. Temp. Curve: B Pressure at MDMT: 250.00 PSIUCS-66(b) reduction: Yes Minimum Design Metal Temperature: -20 FUCS-68(c) reduction: No Computed Minimum Temperature: -125 F
Reinforcing Pad Information
Reinforcing Material: SA-516 Gr. 70 Allowable Stress at Design Temperature(Sp): 19700 PSIAllowable Stress at Ambient Temperature: 20000 PSI
Reinforcing Plate Thickness(te): 0.7500 in. Repad to Vessel Weld Leg Size(Weld 42): 0.6250 in.OD, Reinforcing Plate(Dp): 10.0000 in. Repad to Nozzle Groove Weld Depth: 0.7500 in.
Host Component: Head 1 - Head 1
Material: SA-516 Gr. 70 Head wall thickness(new): 1.2500 in.
Material Stress(Sv): 19700 PSI Head wall thickness - thin out (corroded): 0.8750 in.
Nozzle Detail Information
Upper Weld Leg Size(Weld 41): 0.3750
Nozzle Wall Thickness(tn): 0.5000
Outside Groove Weld Depth: 1.2500
Repad to Vessel Weld Leg Size(Weld 42): 0.6250
Repad Thickness(te): 0.7500
Nozzle passes through the vessel, attached by a groove weld.Pipe Size: 8 Schedule: 80
Nozzle is adequate for UG-45 requirements.Opening is adequately reinforced for Internal Pressure.Opening is adequately reinforced for External Pressure.
Weld Strength Paths are adequate.
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Pressure Vessel Engineering, Ltd.N1
Job No: PVE-3602 Sample 13 Vessel Number: Sample 13Number: 1 Mark Number: N1
ID Number: N1
Date Printed: 11/12/2009
Required Head Thickness per Paragraph UG-37(a)
tr =
P K1 Do
(2SE + 0.8P) =
250.00 * 0.9000 * 86.0000
(2 * 19700 * 1 + 0.8 * 250.00) = 0.4886
Nozzle Required Thickness Calculations
Required Nozzle Thickness for Internal Pressure per Paragraph UG-37(a)
trn =PRn
SE - 0.6P=
250.00 * 3.9375
17100 * 1 - 0.6 * 250.00= 0.0581
Required Nozzle Thickness for External Pressure per Paragraph UG-37(a)
trn =3 * Do * Pa
4B=
3 * 8.6250 * 15.00
4 * 6410= 0.0152
Strength Reduction Factors
fr1 = min
Sn
Sv, 1.0000
= min
17100
19700, 1.0000
= 0.8680 fr2 = min
Sn
Sv, 1.0000
= min
17100
19700, 1.0000
= 0.8680
fr3 = min
Sn
Sv, 1.0000
= min
17100
19700, 1.0000
= 0.8680 fr4 = min
Sp
Sv, 1.0000
= min
19700
19700, 1.0000
= 1.0000
UG-45 Thickness Calculations
Nozzle Thickness for Pressure Loading (plus corrosion) per Paragraph UG-45(a)
t =PRn
SE - 0.6P+ Ca + ext. Ca =
250.00 * 3.9375
17100 * 1.00 - 0.6 * 250.00+ 0.1250 + 0.0000 = 0.1831
Nozzle Thickness for Internal Pressure (plus corrosion) per Paragraph UG-45(b)(1)
t =P K Do
(2SE + 2P(K - 0.1))+ Ca + ext. Ca =
250.00 * 1.0000 * 86.0000
(2 * 19700 * 1 + 2 * 250.00 * (1.0000 - 0.1))+ 0.1250 + 0.0000 = 0.6645
Nozzle Thickness for External Pressure (plus corrosion) per Paragraph UG-45(b)(2)
t =P K Do
(2SE + 2P(K - 0.1))+ Ca + ext. Ca =
15.00 * 1.0000 * 86.0000
(2 * 19700 * 1 + 2 * 15.00 * (1.0000 - 0.1))+ 0.1250 + 0.0000
= Greater Of (0.0327(Calculated), 0.0938(MinimumAllowed)) + 0.1250 (corrosion) + 0.0000 (ext.corrosion) = 0.2188Minimum Thickness for Internal and External Pressure per Paragraph UG-45(b)(3)
t = Greater of the thicknesses determined by UG-45(b)(1) or UG-45(b)(2) = 0.6645
Minimum Thickness of Standard Wall Pipe (plus corrosion) per Paragraph UG-45(b)(4)
t = minimum thickness of standard wall pipe + Ca + ext. Ca = 0.4067
Nozzle Minimum Thickness per Paragraph UG-45(b)t = Smallest of UG-45(b)(3) or UG-45(b)(4) = 0.4067
Wall thickness = tn * 0.875(pipe) = 0.4375 is greater than or equal to UG-45 value of 0.4067
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Pressure Vessel Engineering, Ltd.N1
Job No: PVE-3602 Sample 13 Vessel Number: Sample 13Number: 1 Mark Number: N1
ID Number: N1
Date Printed: 11/12/2009
Nozzle Reinforcement Calculations
Area Required for Internal Pressure
A = d tr F + 2 tn tr F (1 - fr1) = (7.8750 * 0.4886 * 1.00) + (2 * 0.3750 * 0.4886 * 1.00 * (1 - 0.8680)) = 3.8961 sq. Area Available - Internal Pressure
A1 Formula 1 = d(E1 t - F tr) - 2tn(E1 t - F tr)(1 - fr1) =7.8750 * (1.00 * 0.8750 - 1.00 * 0.4886) - 2 * 0.3750 * (1.00 * 0.8750 - 1.00 * 0.4886) * (1 - 0.8680) = 3.0047sq. in.
A1 Formula 2= 2(t + tn)(E1 t - F tr) - 2tn(E1 t - F tr)(1 - fr1) =2 * (0.8750 + 0.3750)(1.00 * 0.8750 - 1.00 * 0.4886) - 2 * 0.3750 * (1.00 * 0.8750 - 1.00 * 0.4886) * (1 - 0.8680)
= 0.9278sq. in.A1 = Larger value of A1 Formula 1 and A1 Formula 2 = 3.0047 sq.
A2 Formula 1 = 5(tn - trn) fr2 t = 5(0.3750 - 0.0581) * 0.8680 * 0.8750 = 1.2035sq. in.A2 Formula 2= 2(tn - trn) fr2 (2.5 tn + te ) = 2(0.3750 - 0.0581) * 0.8680 * (2.5 * 0.3750 + 0.7500) = 0.9284sq. in.
A2 = Smaller value of A2 Formula 1 and A2 Formula 2 = 0.9284 sq.
A3 = Smaller value of the following :
5 * t * ti * fr2 = 5 * 0.8750 * 0.2500 * 0.8680 = 0.9494 sq. in.5 * ti * ti * fr2 = 5 * 0.2500 * 0.2500 * 0.8680 = 0.2713 sq. in.2 * h * ti * fr2 = 2 * 0.0000 * 0.2500 * 0.8680= 0.0000 sq. in.
= 0.0000 sq.
A41 = (leg) * fr3 = (0.3750) * 0.8680 = 0.1221 sq.
A42 = (leg) * fr4 = (0.6250) * 1.0000 = 0.3906 sq.
A43 = (leg) * fr2 = 0 * 0.8680 = 0.0000 sq.
A5 = (Dp - d - 2tn) te fr4 = (10.0000 - 7.8750 - 2 * 0.3750) * 0.7500 * 1.0000 = 1.0313 sq.
Area Available (Internal Pressure) = A1 + A2 + A3 + A41 + A42 + A43 + A5 = 5.4771 sq. in., which is greater than A (3.8961)
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Pressure Vessel Engineering, Ltd.N1
Job No: PVE-3602 Sample 13 Vessel Number: Sample 13Number: 1 Mark Number: N1
ID Number: N1
Date Printed: 11/12/2009
Nozzle Reinforcement Calculations
Area Required for External Pressure
A = * (d tr F + 2 tn tr F (1 - fr1)) = * ((7.8750 * 0.2273 * 1.0) + (2 * 0.3750 * 0.2273 * 1.0 * (1 - 0.8680))) = 0.9062 sq. Area Available - External Pressure
A1 Formula 1 = d(E1 t - F tr) - 2tn(E1 t - F tr)(1 - fr1) =7.8750 * (1.00 * 0.8750 - 1.00 * 0.2273) - 2 * 0.3750 * (1.00 * 0.8750 - 1.00 * 0.2273) * (1 - 0.8680) = 5.0365sq. in.
A1 Formula 2= 2(t + tn)(E1 t - F tr) - 2tn(E1 t - F tr)(1 - fr1) =2 * (0.8750 + 0.3750)(1.00 * 0.8750 - 1.00 * 0.2273) - 2 * 0.3750 * (1.00 * 0.8750 - 1.00 * 0.2273) * (1 - 0.8680)
= 1.5551 sq. in.A1 = Larger value of A1 Formula 1 and A1 Formula 2 = 5.0365 sq.
A2 Formula 1 = 5(tn - trn) fr2 t = 5(0.3750 - 0.0152) * 0.8680 * 0.8750 = 1.3664sq. in.A2 Formula 2= 2(tn - trn) fr2 (2.5 tn + te ) = 2(0.3750 - 0.0152) * 0.8680 * (2.5 * 0.3750 + 0.7500) = 1.0541 sq. in.A2 = Smaller value of A2 Formula 1 and A2 Formula 2 = 1.0541 sq.
A3 = Smaller value of the following :
5 * t * ti * fr2 = 5 * 0.8750 * 0.2500 * 0.8680 = 0.9494 sq. in.5 * ti * ti * fr2 = 5 * 0.2500 * 0.2500 * 0.8680 = 0.2713 sq. in.2 * h * ti * fr2 = 2 * 0.0000 * 0.2500 * 0.8680= 0.0000 sq. in.
= 0.0000 sq.
A41 = (leg) * fr3 = (0.3750) * 0.8680 = 0.1221 sq.
A42 = (leg) * fr4 = (0.6250) * 1.0000 = 0.3906 sq.
A43 = (leg) * fr2 = 0 * 0.8680 = 0.0000 sq.
A5 = (Dp - d - 2tn) te fr4 = (10.0000 - 7.8750 - 2 * 0.3750) * 0.7500 * 1.0000 = 1.0313 sq.
Area Available (External Pressure) = A1 + A2 + A3 + A41 + A42 + A43 + A5 = 7.6346 sq. in., which is greater than A (0.9062)
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Pressure Vessel Engineering, Ltd.N1
Job No: PVE-3602 Sample 13 Vessel Number: Sample 13Number: 1 Mark Number: N1
ID Number: N1
Date Printed: 11/12/2009
Nozzle Weld Strength Calculations
Attachment Weld Strength per Paragraph UW-16 (Corroded Condition)
Weld 41 tmin = smaller of 0.75, te, or tn = smaller of 0.75, 0.7500, or 0.3750 = 0.3750
Weld 41 Leg min. =(smaller of 0.25 or (tmin * 0.7)) + ext. CA
0.7=
0.2500
0.7= 0.3571
Weld 41, actual weld leg = 0.3750
Weld 42 tmin = smaller of 0.75, t, or te = smaller of 0.75, 0.8750, or 0.7500 = 0.7500
Weld 42 Leg min. =0.5 * tmin + ext. CA
0.7=
0.5 * 0.7500 + 0.0000
0.7= 0.5357
Weld 42, actual weld leg = 0.6250
Unit Stresses per Paragraphs UG-45(c) and UW-15Nozzle wall in shear = 0.70 * Sn = 0.70 * 17100 = 11970 PUpper fillet, Weld 41, in shear = 0.49 * Material Stress = 0.49 * 17100 = 8379 PVessel groove weld, in tension = 0.74 * Material Stress = 0.74 * 17100 = 12654 POuter fillet, Weld 42, in shear = 0.49 * Material Stress = 0.49 * 19700 = 9653 PRepad groove weld, in tension = 0.74 * Material Stress = 0.74 * 17100 = 12654 P
Strength of Connection ElementsNozzle wall in shear = * * mean nozzle diameter * tn * Nozzle wall in shear unit stress =
* * 8.2500 * 0.3750 * 11970 = 58100Upper fillet in shear = * * Nozzle OD * weld leg * upper fillet in shear unit stress = * * 8.6250 * 0.3750 * 8379 = 42500
Groove Weld in Tension = * * Nozzle OD * groove depth * groove weld tension unit stress = * * 8.6250 * 0.8750 * 12654 = 149900Outer fillet in shear = * * Plate OD * weld leg * outer fillet in shear unit stress = * * 10.0000 * 0.6250 * 9653 = 94700Repad groove weld = * * Nozzle OD * Groove Depth * repad groove weld in tension unit stress =
* * 8.6250 * 0.7500 * 12654 = 128500
Load to be carried by welds, per UG-41(b)(1) and Fig. UG-41.1 sketch (a)
W = [A - A1 + 2 tn fr1(E1t - Ftr)] Sv = [3.8961 - 3.0047 + 2 * 0.3750 * 0.8680 * (1.00 * 0.8750 - 1.0000 * 0.4886)] * 19700 = 22500W1-1 = (A2 + A5 + A41 + A42) * Sv = (0.9284 + 1.0313 + 0.1221 + 0.3906) * 19700 = 48700W2-2 = (A2 + A3 + A41 + A43 + 2 tn t fr1) Sv = (0.9284 + 0.0000 + 0.1221 + 0.0000 + 2 * 0.3750 * 0.8750 * 0.8680) * 19700 = 31900W3-3 = (A2 + A3 + A5 + A41 + A42 + A43 + 2 tn t fr1) * Sv =
(0.9284 + 0.0000 + 1.0313 + 0.1221 + 0.3906 + 0.0000 + 2 * 0.3750 * 0.8750 * 0.8680) * 19700 = 59900
Check Strength PathsPath 1-1 = Outer fillet in shear + Nozzle wall in shear = 94700 + 58100 = 152800Path 2-2 = Upper fillet in shear + Repad groove weld + Groove weld in tension + Inner fillet in shear =
42500 + 128500 + 149900 + 0 = 320900Path 3-3 = Outer fillet in shear + Inner fillet in shear + Groove weld in tension = 94700 + 0 + 149900 = 244600
Advanced Pressure Vessel version: 10.1.5 Computer Engineering, Inc. Section VIII, Division 1, 2007 Edition, 2008 AddenPage 33 of 95
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Job No: PVE-3602 Sample 13 Vessel Number: Sample 13Number: 1 Mark Number: N1
ID Number: N1
Date Printed: 11/12/2009
Plate Strength = A5 * Sp = 1.0313 * 19700 = 20317
Outer fillet weld strength(94700) is greater than plate strength(20317).
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Pressure Vessel Engineering, Ltd.N2
Customer: Pressure Vessel Engineering LtdJob No: PVE-3602 Sample 13 Vessel Number: Sample 13
Number: 2 Mark Number: N2ID Number: 2
Date Printed: 11/12/2009
Nozzle Design Information
Design Pressure: 250.00 PSI Design Temperature: 550 FStatic Head: 0.00 PSI Nozzle Efficiency (E): 100 %
Nozzle Material: SA-106 Gr. B Joint Efficiency (E1): 1.00Factor B Chart: CS-2
External Projection: 6.0000 in. Allowable Stress at Design Temperature (Sn): 17100 PSI
Internal Projection: 0.0000 in. Allowable Stress at Ambient Temperature: 17100 PSIInside Corrosion Allowance: 0.1250 in. Correction Factor (F): 1.00
External Corrosion Allowance: 0.0000 in. Nozzle Path: NoneNozzle Pipe Size: 6 Nozzle Pipe Schedule: 160Nozzle ID (new): 5.1890 in. Nozzle Wall Thickness(new): 0.7180 in.
Nozzle ID (corroded): 5.4390 in. Nozzle Wall Thickness(corroded): 0.5930 in.Outer "h" Limit: 1.4825 in. Upper Weld Leg Size(Weld 41): 0.3750 in.
Internal "h" Limit: 1.1700 in. Internal Weld Leg Size(Weld 43): 0.0000 in.OD, Limit of Reinforcement: 10.8780 in. Outside Groove Weld Depth: 1.0000 in.
Minimum Design Metal Temperature
Min. Temp. Curve: B Pressure at MDMT: 250.00 PSIUCS-66(b) reduction: Yes Minimum Design Metal Temperature: -20 FUCS-68(c) reduction: No Computed Minimum Temperature: -135 F
Host Component: Shell 1 - Shell 1
Material: SA-516 Gr. 70 Shell wall thickness(new): 1.0000 in.Material Stress(Sv): 19700 PSI Shell wall thickness(corroded): 0.8750 in.
Nozzle Detail Information
Upper Weld Leg Size(Weld 41): 0.3750
Nozzle Wall Thickness(tn): 0.7180
Outside Groove Weld Depth: 1.0000
Nozzle passes through the vessel, attached by a groove weld.Pipe Size: 6 Schedule: 160
Nozzle is adequate for UG-45 requirements.Opening is adequately reinforced for Internal Pressure.Opening is adequately reinforced for External Pressure.
Weld Strength Paths are adequate.
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Pressure Vessel Engineering, Ltd.N2
Job No: PVE-3602 Sample 13 Vessel Number: Sample 13Number: 2 Mark Number: N2
ID Number: 2
Date Printed: 11/12/2009
Required Shell Thickness per Paragraph UG-37(a)
tr =
PRo
SE + 0.4P =
250.00 * 43.0000
19700 * 1 + 0.4 * 250.00 = 0.5429
Nozzle Required Thickness Calculations
Required Nozzle Thickness for Internal Pressure per Paragraph UG-37(a)
trn =PRn
SE - 0.6P=
250.00 * 2.7195
17100 * 1 - 0.6 * 250.00= 0.0401
Required Nozzle Thickness for External Pressure per Paragraph UG-37(a)
trn =3 * Do * Pa
4B=
3 * 6.6250 * 15.00
4 * 3548= 0.0212
Strength Reduction Factors
fr1 = min
Sn
Sv, 1.0000
= min
17100
19700, 1.0000
= 0.8680 fr2 = min
Sn
Sv, 1.0000
= min
17100
19700, 1.0000
= 0.8680
fr3 = min
Sn
Sv, 1.0000
= min
17100
19700, 1.0000
= 0.8680
UG-45 Thickness Calculations
Nozzle Thickness for Pressure Loading (plus corrosion) per Paragraph UG-45(a)
t =PRn
SE - 0.6P+ Ca + ext. Ca =
250.00 * 2.7195
17100 * 1.00 - 0.6 * 250.00+ 0.1250 + 0.0000 = 0.1651
Nozzle Thickness for Internal Pressure (plus corrosion) per Paragraph UG-45(b)(1)
t =PRo
SE + 0.4P+ Ca + ext. Ca =
250.00 * 43.0000
19700 * 1 + 0.4 * 250.00+ 0.1250 + 0.0000 = 0.6679
Nozzle Thickness for External Pressure (plus corrosion) per Paragraph UG-45(b)(2)
t =PRo
SE + 0.4P+ Ca + ext. Ca =
15.00 * 43.0000
19700 * 1 + 0.4 * 15.00+ 0.1250 + 0.0000
= Greater Of (0.0327(Calculated), 0.0938(MinimumAllowed)) + 0.1250 (corrosion) + 0.0000 (ext.corrosion) = 0.2188Minimum Thickness for Internal and External Pressure per Paragraph UG-45(b)(3)
t = Greater of the thicknesses determined by UG-45(b)(1) or UG-45(b)(2) = 0.6679
Minimum Thickness of Standard Wall Pipe (plus corrosion) per Paragraph UG-45(b)(4)
t = minimum thickness of standard wall pipe + Ca + ext. Ca = 0.3700
Nozzle Minimum Thickness per Paragraph UG-45(b)t = Smallest of UG-45(b)(3) or UG-45(b)(4) = 0.3700
Wall thickness = tn * 0.875(pipe) = 0.6282 is greater than or equal to UG-45 value of 0.3700
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Pressure Vessel Engineering, Ltd.N2
Job No: PVE-3602 Sample 13 Vessel Number: Sample 13Number: 2 Mark Number: N2
ID Number: 2
Date Printed: 11/12/2009
Nozzle Reinforcement Calculations
Area Required for Internal Pressure
A = d tr F + 2 tn tr F (1 - fr1) = (5.4390 * 0.5429 * 1.00) + (2 * 0.5930 * 0.5429 * 1.00 * (1 - 0.8680)) = 3.0378 sq. Area Available - Internal Pressure
A1 Formula 1 = d(E1 t - F tr) - 2tn(E1 t - F tr)(1 - fr1) =5.4390 * (1.00 * 0.8750 - 1.00 * 0.5429) - 2 * 0.5930 * (1.00 * 0.8750 - 1.00 * 0.5429) * (1 - 0.8680) = 1.7543sq. in.
A1 Formula 2= 2(t + tn)(E1 t - F tr) - 2tn(E1 t - F tr)(1 - fr1) =2 * (0.8750 + 0.5930)(1.00 * 0.8750 - 1.00 * 0.5429) - 2 * 0.5930 * (1.00 * 0.8750 - 1.00 * 0.5429) * (1 - 0.8680)
= 0.9231 sq. in.A1 = Larger value of A1 Formula 1 and A1 Formula 2 = 1.7543 sq.
A2 Formula 1 = 5(tn - trn) fr2 t = 5(0.5930 - 0.0401) * 0.8680 * 0.8750 = 2.0997sq. in.A2 Formula 2= 5(tn - trn) fr2 tn = 5(0.5930 - 0.0401) * 0.8680 * 0.5930 = 1.4230sq. in.
A2 = Smaller value of A2 Formula 1 and A2 Formula 2 = 1.4230 sq.
A3 = Smaller value of the following :
5 * t * ti * fr2 = 5 * 0.8750 * 0.4680 * 0.8680 = 1.7773 sq. in.5 * ti * ti * fr2 = 5 * 0.4680 * 0.4680 * 0.8680 = 0.9506 sq. in.2 * h * ti * fr2 = 2 * 0.0000 * 0.4680 * 0.8680= 0.0000 sq. in.
= 0.0000 sq.
A41 = (leg) * fr2 = (0.3750) * 0.8680 = 0.1221 sq.
A43 = (leg) * fr2 = 0 * 0.8680 = 0.0000 sq.
Area Available (Internal Pressure) = A1 + A2 + A3 + A41 + A43 = 3.2994 sq. in., which is greater than A (3.0378)
Nozzle Reinforcement Calculations
Area Required for External Pressure
A = * (d tr F + 2 tn tr F (1 - fr1)) = * ((5.4390 * 0.4580 * 1.0) + (2 * 0.5930 * 0.4580 * 1.0 * (1 - 0.8680))) = 1.2814 sq. Area Available - External Pressure
A1 Formula 1 = d(E1 t - F tr) - 2tn(E1 t - F tr)(1 - fr1) =5.4390 * (1.00 * 0.8750 - 1.00 * 0.4580) - 2 * 0.5930 * (1.00 * 0.8750 - 1.00 * 0.4580) * (1 - 0.8680) = 2.2028sq. in.
A1 Formula 2= 2(t + tn)(E1 t - F tr) - 2tn(E1 t - F tr)(1 - fr1) =
2 * (0.8750 + 0.5930)(1.00 * 0.8750 - 1.00 * 0.4580) - 2 * 0.5930 * (1.00 * 0.8750 - 1.00 * 0.4580) * (1 - 0.8680)
= 1.1590sq. in.A1 = Larger value of A1 Formula 1 and A1 Formula 2 = 2.2028 sq.
A2 Formula 1 = 5(tn - trn) fr2 t = 5(0.5930 - 0.0212) * 0.8680 * 0.8750 = 2.1715sq. in.A2 Formula 2= 5(tn - trn) fr2 tn = 5(0.5930 - 0.0212) * 0.8680 * 0.5930 = 1.4716sq. in.A2 = Smaller value of A2 Formula 1 and A2 Formula 2 = 1.4716 sq.
A3 = Smaller value of the following :5 * t * ti * fr2 = 5 * 0.8750 * 0.4680 * 0.8680 = 1.7773 sq. in.
5 * ti * ti * fr2 = 5 * 0.4680 * 0.4680 * 0.8680 = 0.9506 sq. in.2 * h * ti * fr2 = 2 * 0.0000 * 0.4680 * 0.8680= 0.0000 sq. in.
= 0.0000 sq.
A41 = (leg) * fr2 = (0.3750) * 0.8680 = 0.1221 sq.
A43 = (leg) * fr2 = 0 * 0.8680 = 0.0000 sq.
Area Available (External Pressure) = A1 + A2 + A3 + A41 + A43 = 3.7965 sq. in., which is greater than A (1.2814)
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Pressure Vessel Engineering, Ltd.N3
Customer: Pressure Vessel Engineering LtdJob No: PVE-3602 Sample 13 Vessel Number: Sample 13
Number: 3 Mark Number: N3ID Number: 3
Date Printed: 11/12/2009
Nozzle Design Information
Design Pressure: 250.00 PSI Design Temperature: 550 FStatic Head: 0.00 PSI Nozzle Efficiency (E): 100 %
Nozzle Material: SA-105 Joint Efficiency (E1): 1.00Factor B Chart: CS-2
External Projection: 6.0000 in. Allowable Stress at Design Temperature (Sn): 19000 PSIInternal Projection: 2.0000 in. Allowable Stress at Ambient Temperature: 20000 PSI
Inside Corrosion Allowance: 0.1250 in. Correction Factor (F): 1.00External Corrosion Allowance: 0.0000 in. Nozzle Path: None
Nozzle ID (new): 2.0000 in. Nozzle Wall Thickness(new): 0.6600 in.Nozzle ID (corroded): 2.2500 in. Nozzle Wall Thickness(corroded): 0.5350 in.
Outer "h" Limit: 1.3375 in. Upper Weld Leg Size(Weld 41): 0.3750 in.Internal "h" Limit: 1.0250 in. Internal Weld Leg Size(Weld 43): 0.5625 in.
OD, Limit of Reinforcement: 5.0700 in. Outside Groove Weld Depth: 1.0000 in.
Minimum Design Metal Temperature
Min. Temp. Curve: B Pressure at MDMT: 250.00 PSIUCS-66(b) reduction: Yes Minimum Design Metal Temperature: -20 FUCS-68(c) reduction: No Computed Minimum Temperature: -133 F
Host Component: Shell 4 - Shell 4
Material: SA-516 Gr. 70 Shell wall thickness(new): 1.0000 in.Material Stress(Sv): 19700 PSI Shell wall thickness(corroded): 0.8750 in.
Nozzle Detail Information
Upper Weld Leg Size(Weld 41): 0.3750
Internal Weld Leg Size(Weld 43): 0.5625
Nozzle Wall Thickness(tn): 0.6600
Outside Groove Weld Depth: 1.0000
Nozzle passes through the vessel, attached by a groove weld.Nozzle is adequate for UG-45 requirements.
Opening is adequately reinforced for Internal Pressure.
Opening is adequately reinforced for External Pressure.Reinforcement calculations are not required per UG-36(c)(3)(a)See Uw-14 for exceptions.
Weld Strength Paths are adequate.
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Pressure Vessel Engineering, Ltd.N3
Job No: PVE-3602 Sample 13 Vessel Number: Sample 13Number: 3 Mark Number: N3
ID Number: 3
Date Printed: 11/12/2009
Required Shell Thickness per Paragraph UG-37(a)
tr =
PRo
SE + 0.4P =
250.00 * 43.0000
19700 * 1 + 0.4 * 250.00 = 0.5429
Nozzle Required Thickness Calculations
Required Nozzle Thickness for Internal Pressure per Paragraph UG-37(a)
trn =PRn
SE - 0.6P=
250.00 * 1.1250
19000 * 1 - 0.6 * 250.00= 0.0149
Required Nozzle Thickness for External Pressure per Paragraph UG-37(a)
trn =3 * Do * Pa
4B=
3 * 3.3200 * 15.00
4 * 2717= 0.0138
Strength Reduction Factors
fr1 = min
Sn
Sv, 1.0000
= min
19000
19700, 1.0000
= 0.9645 fr2 = min
Sn
Sv, 1.0000
= min
19000
19700, 1.0000
= 0.9645
fr3 = min
Sn
Sv, 1.0000
= min
19000
19700, 1.0000
= 0.9645
UG-45 Thickness Calculations
Nozzle Thickness for Pressure Loading (plus corrosion) per Paragraph UG-45(a)
t =PRn
SE - 0.6P+ Ca + ext. Ca =
250.00 * 1.1250
19000 * 1.00 - 0.6 * 250.00+ 0.1250 + 0.0000 = 0.1399
Nozzle Thickness for Internal Pressure (plus corrosion) per Paragraph UG-45(b)(1)
t =PRo
SE + 0.4P+ Ca + ext. Ca =
250.00 * 43.0000
19700 * 1 + 0.4 * 250.00+ 0.1250 + 0.0000 = 0.6679
Nozzle Thickness for External Pressure (plus corrosion) per Paragraph UG-45(b)(2)
t =PRo
SE + 0.4P+ Ca + ext. Ca =
15.00 * 43.0000
19700 * 1 + 0.4 * 15.00+ 0.1250 + 0.0000
= Greater Of (0.0327(Calculated), 0.0938(MinimumAllowed)) + 0.1250 (corrosion) + 0.0000 (ext.corrosion) = 0.2188Minimum Thickness for Internal and External Pressure per Paragraph UG-45(b)(3)
t = Greater of the thicknesses determined by UG-45(b)(1) or UG-45(b)(2) = 0.6679
Minimum Thickness of Standard Wall Pipe (plus corrosion) per Paragraph UG-45(b)(4)
t = minimum thickness of standard wall pipe + Ca + ext. Ca = 0.3140
Nozzle Minimum Thickness per Paragraph UG-45(b)t = Smallest of UG-45(b)(3) or UG-45(b)(4) = 0.3140
Wall thickness = tn = 0.6600 is greater than or equal to UG-45 value of 0.3140
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Pressure Vessel Engineering, Ltd.N4
Customer: Pressure Vessel Engineering LtdJob No: PVE-3602 Sample 13 Vessel Number: Sample 13
Number: 4 Mark Number: N4ID Number: 4
Date Printed: 11/12/2009
Nozzle Design Information
Design Pressure: 250.00 PSI Design Temperature: 550 FStatic Head: 0.00 PSI Nozzle Efficiency (E): 100 %
Nozzle Material: SA-312 TP316L, High Joint Efficiency (E1): 1.00Factor B Chart: HA-4
External Projection: 6.0000 in. Allowable Stress at Design Temperature (Sn): 14400 PSIInternal Projection: 2.0000 in. Allowable Stress at Ambient Temperature: 16700 PSI
Inside Corrosion Allowance: 0.1250 in. Correction Factor (F): 1.00External Corrosion Allowance: 0.0000 in. Nozzle Path: None
Nozzle Pipe Size: 4 Nozzle Pipe Schedule: 120Nozzle ID (new): 3.6240 in. Nozzle Wall Thickness(new): 0.4380 in.
Nozzle ID (corroded): 3.8740 in. Nozzle Wall Thickness(corroded): 0.3130 in.Developed Opening: 3.6240 in. Tangential Dimension L: 4.0000 in.
Outer "h" Limit: 1.5325 in. Upper Weld Leg Size(Weld 41): 0.3750 in.Internal "h" Limit: 0.4700 in. Internal Weld Leg Size(Weld 43): 0.5000 in.
OD, Limit of Reinforcement: 7.7480 in. Outside Groove Weld Depth: 1.1250 in.Minimum Design Metal Temperature
Minimum Design Metal Temperature: -20 FMaterial is exempt from impact testing per UHA-51(d)
Reinforcing Pad Information
Reinforcing Material: SA-516 Gr. 70 Allowable Stress at Design Temperature(Sp): 19700 PSIAllowable Stress at Ambient Temperature: 20000 PSI
Reinforcing Plate Thickness(te): 0.7500 in. Repad to Vessel Weld Leg Size(Weld 42): 0.6250 in.OD, Reinforcing Plate(Dp): 7.0000 in. Repad to Nozzle Groove Weld Depth: 0.7500 in.
Host Component: Cone 2 - Conical Reducer 2
Material: SA-516 Gr. 70 Conical Reducer wall thickness(new): 1.1250 in.
Material Stress(Sv): 19700 PSInical Reducer wall thickness - thin out (corroded): 1.0000 in.Distance from small end of cone: 50.0000 in. Diameter of Cone at Nozzle: 79.7500 in.
Nozzle Detail Information
Upper Weld Leg Size(Weld 41): 0.3750
Internal Weld Leg Size(Weld 43): 0.5000
Nozzle Wall Thickness(tn): 0.4380
Outside Groove Weld Depth: 1.1250
Repad to Vessel Weld Leg Size(Weld 42): 0.6250
Repad Thickness(te): 0.7500
tangential to the vessel wall, attached by a groove weld.Pipe Size: 4 Schedule: 120
Nozzle is adequate for UG-45 requirements.
Opening is adequately reinforced for Internal Pressure.Opening is adequately reinforced for External Pressure.
Weld Strength Paths are adequate.
Advanced Pressure Vessel version: 10.1.5 Computer Engineering, Inc. Section VIII, Division 1, 2007 Edition, 2008 AddenPage 40 of 95
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Pressure Vessel Engineering, Ltd.N4
Job No: PVE-3602 Sample 13 Vessel Number: Sample 13Number: 4 Mark Number: N4
ID Number: 4
Date Printed: 11/12/2009
Required Conical Reducer Thickness per Paragraph UG-37(a)
tr =
PDo
(2 * cos (SE + 0.4P)) =250.00 * 79.7500
(2 * 0.9203 * (19700 * 1 + 0.4 * 250.00)) = 0.5471
Nozzle Required Thickness Calculations
Required Nozzle Thickness for Internal Pressure per Paragraph UG-37(a)
trn =PRn
SE - 0.6P=
250.00 * 1.9370
14400 * 1 - 0.6 * 250.00= 0.0340
Required Nozzle Thickness for External Pressure per Paragraph UG-37(a)
trn =3 * Do * Pa
4B=
3 * 4.5000 * 15.00
4 * 3051= 0.0167
Strength Reduction Factors
fr1 = min
Sn
Sv, 1.0000
= min
14400
19700, 1.0000
= 0.7310 fr2 = min
Sn
Sv, 1.0000
= min
14400
19700, 1.0000
= 0.7310
fr3 = min
Sn
Sv, 1.0000
= min
14400
19700, 1.0000
= 0.7310 fr4 = min
Sp
Sv, 1.0000
= min
19700
19700, 1.0000
= 1.0000
UG-45 Thickness Calculations
Nozzle Thickness for Pressure Loading (plus corrosion) per Paragraph UG-45(a)
t =PRn
SE - 0.6P+ Ca + ext. Ca =
250.00 * 1.9370
14400 * 1.00 - 0.6 * 250.00+ 0.1250 + 0.0000 = 0.1590
Nozzle Thickness for Internal Pressure (plus corrosion) per Paragraph UG-45(b)(1)
t =PDo
(2 * cos (SE + 0.4P))+ Ca + ext. Ca =
250.00 * 79.7500
(2 * 0.9203 * (19700 * 1 + 0.4 * 250.00))+ 0.1250 + 0.0000 = 0.6721
Nozzle Thickness for External Pressure (plus corrosion) per Paragraph UG-45(b)(2)
t =PDo
(2 * cos (SE + 0.4P))+ Ca + ext. Ca =
15.00 * 79.7500
(2 * 0.9203 * (19700 * 1 + 0.4 * 15.00))+ 0.1250 + 0.0000
= Greater Of (0.0330(Calculated), 0.0938(MinimumAllowed)) + 0.1250 (corrosion) + 0.0000 (ext.corrosion) = 0.2188Minimum Thickness for Internal and External Pressure per Paragraph UG-45(b)(3)
t = Greater of the thicknesses determined by UG-45(b)(1) or UG-45(b)(2) = 0.6721
Minimum Thickness of Standard Wall Pipe (plus corrosion) per Paragraph UG-45(b)(4)
t = minimum thickness of standard wall pipe + Ca + ext. Ca = 0.3324
Nozzle Minimum Thickness per Paragraph UG-45(b)t = Smallest of UG-45(b)(3) or UG-45(b)(4) = 0.3324
Wall thickness = tn * 0.875(pipe) = 0.3832 is greater than or equal to UG-45 value of 0.3324
Advanced Pressure Vessel version: 10.1.5 Computer Engineering, Inc. Section VIII, Division 1, 2007 Edition, 2008 AddenPage 41 of 95
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Pressure Vessel Engineering, Ltd.N4
Job No: PVE-3602 Sample 13 Vessel Number: Sample 13Number: 4 Mark Number: N4
ID Number: 4
Date Printed: 11/12/2009
Nozzle Reinforcement Calculations
Area Required for Internal Pressure
A = d tr F + 2 tn tr F (1 - fr1) = (3.8740 * 0.5471 * 1.00) + (2 * 0.3130 * 0.5471 * 1.00 * (1 - 0.7310)) = 2.2116 sq. Area Available - Internal Pressure
A1 Formula 1 = d(E1 t - F tr) - 2tn(E1 t - F tr)(1 - fr1) =3.8740 * (1.00 * 1.0000 - 1.00 * 0.5471) - 2 * 0.3130 * (1.00 * 1.0000 - 1.00 * 0.5471) * (1 - 0.7310) = 1.6783sq. in.
A1 Formula 2= 2(t + tn)(E1 t - F tr) - 2tn(E1 t - F tr)(1 - fr1) =2 * (1.0000 + 0.3130)(1.00 * 1.0000 - 1.00 * 0.5471) - 2 * 0.3130 * (1.00 * 1.0000 - 1.00 * 0.5471) * (1 - 0.7310)
= 1.1130sq. in.A1 = Larger value of A1 Formula 1 and A1 Formula 2 = 1.6783 sq.
A2 Formula 1 = 5(tn - trn) fr2 t = 5(0.3130 - 0.0340) * 0.7310 * 1.0000 = 1.0197sq. in.A2 Formula 2= 2(tn - trn) fr2 (2.5 tn + te ) = 2(0.3130 - 0.0340) * 0.7310 * (2.5 * 0.3130 + 0.7500) = 0.6251 sq. in.
A2 = Smaller value of A2 Formula 1 and A2 Formula 2 = 0.6251 sq.
A3 = Smaller value of the following :
5 * t * ti * fr2 = 5 * 1.0000 * 0.1880 * 0.7310 = 0.6871 sq. in.5 * ti * ti * fr2 = 5 * 0.1880 * 0.1880 * 0.7310 = 0.1292 sq. in.2 * h * ti * fr2 = 2 * 1.8750 * 0.1880 * 0.7310= 0.5153 sq. in.
= 0.1292 sq.
A41 = (leg) * fr3 = (0.3750) * 0.7310 = 0.1028 sq.
A42 = Allowable Weld 42 area * fr4 = 0.3276 * 1.0000 = 0.3276 sq.
A43 = (leg) * fr2 = (0.3214) * 0.7310 = 0.0755 sq.
A5 = (Dp - d - 2tn) te fr4 = (7.0000 - 3.8740 - 2 * 0.3130) * 0.7500 * 1.0000 = 1.8750 sq.
Area Available (Internal Pressure) = A1 + A2 + A3 + A41 + A42 + A43 + A5 = 4.8135 sq. in., which is greater than A (2.2116)
Advanced Pressure Vessel version: 10.1.5 Computer Engineering, Inc. Section VIII, Division 1, 2007 Edition, 2008 AddenPage 42 of 95
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Pressure Vessel Engineering, Ltd.N4
Job No: PVE-3602 Sample 13 Vessel Number: Sample 13Number: 4 Mark Number: N4
ID Number: 4
Date Printed: 11/12/2009
Nozzle Reinforcement Calculations
Area Required for External Pressure
A = * (d tr F + 2 tn tr F (1 - fr1)) = * ((3.8740 * 0.3374 * 1.0) + (2 * 0.3130 * 0.3374 * 1.0 * (1 - 0.7310))) = 0.6820 sq. Area Available - External Pressure
A1 Formula 1 = d(E1 t - F tr) - 2tn(E1 t - F tr)(1 - fr1) =3.8740 * (1.00 * 1.0000 - 1.00 * 0.3374) - 2 * 0.3130 * (1.00 * 1.0000 - 1.00 * 0.3374) * (1 - 0.7310) = 2.4553sq. in.
A1 Formula 2= 2(t + tn)(E1 t - F tr) - 2tn(E1 t - F tr)(1 - fr1) =2 * (1.0000 + 0.3130)(1.00 * 1.0000 - 1.00 * 0.3374) - 2 * 0.3130 * (1.00 * 1.0000 - 1.00 * 0.3374) * (1 - 0.7310)
= 1.6284sq. in.A1 = Larger value of A1 Formula 1 and A1 Formula 2 = 2.4553 sq.
A2 Formula 1 = 5(tn - trn) fr2 t = 5(0.3130 - 0.0167) * 0.7310 * 1.0000 = 1.0829sq. in.A2 Formula 2= 2(tn - trn) fr2 (2.5 tn + te ) = 2(0.3130 - 0.0167) * 0.7310 * (2.5 * 0.3130 + 0.7500) = 0.6638sq. in.A2 = Smaller value of A2 Formula 1 and A2 Formula 2 = 0.6638 sq.
A3 = Smaller value of the following :
5 * t * ti * fr2 = 5 * 1.0000 * 0.1880 * 0.7310 = 0.6871 sq. in.5 * ti * ti * fr2 = 5 * 0.1880 * 0.1880 * 0.7310 = 0.1292 sq. in.2 * h * ti * fr2 = 2 * 1.8750 * 0.1880 * 0.7310= 0.5153 sq. in.
= 0.1292 sq.
A41 = (leg) * fr3 = (0.3750) * 0.7310 = 0.1028 sq.
A42 = Allowable Weld 42 area * fr4 = 0.3276 * 1.0000 = 0.3276 sq.
A43 = (leg) * fr2 = (0.3214) * 0.7310 = 0.0755 sq.
A5 = (Dp - d - 2tn) te fr4 = (7.0000 - 3.8740 - 2 * 0.3130) * 0.7500 * 1.0000 = 1.8750 sq.
Area Available (External Pressure) = A1 + A2 + A3 + A41 + A42 + A43 + A5 = 5.6292 sq. in., which is greater than A (0.6820)
Advanced Pressure Vessel version: 10.1.5 Computer Engineering, Inc. Section VIII, Division 1, 2007 Edition, 2008 AddenPage 43 of 95
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Pressure Vessel Engineering, Ltd.N4
Job No: PVE-3602 Sample 13 Vessel Number: Sample 13Number: 4 Mark Number: N4
ID Number: 4
Date Printed: 11/12/2009
Nozzle Weld Strength Calculations
Attachment Weld Strength per Paragraph UW-16 (Corroded Condition)
Weld 41 tmin = smaller of 0.75, te, or tn = smaller of 0.75, 0.7500, or 0.3130 = 0.3130
Weld 41 Leg min. =(smaller of 0.25 or (tmin * 0.7)) + ext. CA
0.7=
0.2191
0.7= 0.3130
Weld 41, actual weld leg = 0.3750
Weld 42 tmin = smaller of 0.75, t, or te = smaller of 0.75, 1.0000, or 0.7500 = 0.7500
Weld 42 Leg min. =0.5 * tmin + ext. CA
0.7=
0.5 * 0.7500 + 0.0000
0.7= 0.5357
Weld 42, actual weld leg = 0.6250
Weld 43 tmin = smaller of 0.75, t, or tn = smaller of 0.75, 1.0000, or 0.3130 = 0.3130
Weld 43 Leg min. =(smaller of 0.25 or (tmin * 0.7)) + ca
0.7=
(smaller of 0.25 or (0.3130 * 0.7)) + 0.1250
0.7=
0.3441
0.7= 0.4916
Weld 43, actual weld leg = 0.5000
Unit Stresses per Paragraphs UG-45(c) and UW-15Nozzle wall in shear = 0.70 * Sn = 0.70 * 14400 = 10080 PUpper fillet, Weld 41, in shear = 0.49 * Material Stress = 0.49 * 14400 = 7056 PVessel groove weld, in tension = 0.74 * Material Stress = 0.74 * 14400 = 10656 PInner fillet, Weld 43, in shear = 0.49 * Material Stress = 0.49 * 14400 = 7056 POuter fillet, Weld 42, in shear = 0.49 * Material Stress = 0.49 * 19700 = 9653 P
Repad groove weld, in tension = 0.74 * Material Stress = 0.74 * 14400 = 10656 P
Strength of Connection ElementsNozzle wall in shear = * * mean nozzle diameter * tn * Nozzle wall in shear unit stress =
* * 4.1870 * 0.3130 * 10080 = 20700Upper fillet in shear = * * Nozzle OD * weld leg * upper fillet in shear unit stress = * * 4.5000 * 0.3750 * 7056 = 18700Groove Weld in Tension = * * Nozzle OD * groove depth * groove weld tension unit stress =
* * 4.5000 * 1.1250 * 10656 = 84700Inner fillet in shear = * * Nozzle OD * weld leg * inner fillet in shear unit stress = * * 4.5000 * 0.3214 * 7056 = 16000Outer fillet in shear = * * Plate OD * weld leg * outer fillet in shear unit stress = * * 7.0000 * 0.6250 * 9653 = 66300Repad groove weld = * * Nozzle OD * Groove Depth * repad groove weld in tension unit stress =
* * 4.5000 * 0.7500 * 10656 = 56500
Advanced Pressure Vessel version: 10.1.5 Computer Engineering, Inc. Section VIII, Division 1, 2007 Edition, 2008 AddenPage 44 of 95
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Pressure Vessel Engineering, Ltd.N4
Job No: PVE-3602 Sample 13 Vessel Number: Sample 13Number: 4 Mark Number: N4
ID Number: 4
Date Printed: 11/12/2009
Load to be carried by welds, per UG-41(b)(1) and Fig. UG-41.1 sketch (a)W = [A - A1 + 2 tn fr1(E1t - Ftr)] Sv = [2.2116 - 1.6783 + 2 * 0.3130 * 0.7310 * (1.00 * 1.0000 - 1.0000 * 0.5471)] * 19700 = 14600W1-1 = (A2 + A5 + A41 + A42) * Sv = (0.6251 + 1.8750 + 0.1028 + 0.3276) * 19700 = 57700W2-2 = (A2 + A3 + A41 + A43 + 2 tn t fr1) Sv = (0.6251 + 0.1292 + 0.1028 + 0.0755 + 2 * 0.3130 * 1.0000 * 0.7310) * 19700 = 27400W3-3 = (A2 + A3 + A5 + A41 + A42 + A43 + 2 tn t fr1) * Sv =
(0.6251 + 0.1292 + 1.8750 + 0.1028 + 0.3276 + 0.0755 + 2 * 0.3130 * 1.0000 * 0.7310) * 19700 = 70800
Check Strength PathsPath 1-1 = Outer fillet in shear + Nozzle wall in shear = 66300 + 20700 = 87000Path 2-2 = Upper fillet in shear + Repad groove weld + Groove weld in tension + Inner fillet in shear =
18700 + 56500 + 84700 + 16000 = 175900Path 3-3 = Outer fillet in shear + Inner fillet in shear + Groove weld in tension = 66300 + 16000 + 84700 = 167000
Plate Strength = A5 * Sp = 1.8750 * 19700 = 36938
Outer fillet weld strength(66300) is greater than plate strength(36938).
Advanced Pressure Vessel version: 10.1.5 Computer Engineering, Inc. Section VIII, Division 1, 2007 Edition, 2008 AddenPage 45 of 95
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Pressure Vessel Engineering, Ltd.M2
Customer: Pressure Vessel Engineering LtdJob No: PVE-3602 Sample 13 Vessel Number: Sample 13
Number: 5 Mark Number: M2ID Number: M2
Date Printed: 11/12/2009
Nozzle Design Information
Design Pressure: 250.00 PSI Design Temperature: 550 FStatic Head: 0.00 PSI Nozzle Efficiency (E): 85 %
Nozzle Material: SA-240 Gr. 316L, High Joint Efficiency (E1): 1.00Factor B Chart: HA-4
External Projection: 12.0000 in. Allowable Stress at Design Temperature (Sn): 14400 PSI
Internal Projection: 0.0000 in. Allowable Stress at Ambient Temperature: 16700 PSIInside Corrosion Allowance: 0.1250 in. Correction Factor (F): 1.00
External Corrosion Allowance: 0.0000 in. Nozzle Path: NoneNozzle ID (new): 22.0000 in. Nozzle Wall Thickness(new): 1.0000 in.
Nozzle ID (corroded): 22.2500 in. Nozzle Wall Thickness(corroded): 0.8750 in.Developed Opening: 22.0000 in. Tangential Dimension L: 22.0000 in.
Outer "h" Limit: 2.5000 in. Upper Weld Leg Size(Weld 41): 0.3750 in.Internal "h" Limit: 1.8750 in. Internal Weld Leg Size(Weld 43): 0.0000 in.
OD, Limit of Reinforcement: 44.5000 in. Outside Groove Weld Depth: 1.1250 in.
Minimum Design Metal Temperature
Minimum Design Metal Temperature: -20 FMaterial is exempt from impact testing per UH