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Fall 2005 Costas Busch - RPI 1 Regular Expressions

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Page 1: Regular Expressions

Fall 2005 Costas Busch - RPI 1

Regular Expressions

Page 2: Regular Expressions

Fall 2005 Costas Busch - RPI 2

Regular ExpressionsRegular expressions describe regular languages

Example:

describes the language

*)( cba

,...,,,,,*, bcaabcaabcabca

Page 3: Regular Expressions

Fall 2005 Costas Busch - RPI 3

Recursive Definition

,,

1

1

21

21

*

r

r

rr

rr

Are regular expressions

Primitive regular expressions:

2r1rGiven regular expressions and

Page 4: Regular Expressions

Fall 2005 Costas Busch - RPI 4

Examples

)(* ccbaA regular expression:

baNot a regular expression:

Page 5: Regular Expressions

Fall 2005 Costas Busch - RPI 5

Languages of Regular Expressions : language of regular expression

Example

rL r

,...,,,,,*)( bcaabcaabcacbaL

Page 6: Regular Expressions

Fall 2005 Costas Busch - RPI 6

Definition

For primitive regular expressions:

aaL

L

L

Page 7: Regular Expressions

Fall 2005 Costas Busch - RPI 7

Definition (continued)

For regular expressions and

1r 2r

2121 rLrLrrL

2121 rLrLrrL

** 11 rLrL

11 rLrL

Page 8: Regular Expressions

Fall 2005 Costas Busch - RPI 8

ExampleRegular expression: *aba

*abaL *aLbaL *aLbaL *aLbLaL

*aba ,...,,,, aaaaaaba

,...,,,...,,, baababaaaaaa

Page 9: Regular Expressions

Fall 2005 Costas Busch - RPI 9

Example

Regular expression bbabar *

,...,,,,, bbbbaabbaabbarL

Page 10: Regular Expressions

Fall 2005 Costas Busch - RPI 10

Example

Regular expression bbbaar **

}0,:{ 22 mnbbarL mn

Page 11: Regular Expressions

Fall 2005 Costas Busch - RPI 11

Example

Regular expression *)10(00*)10( r

)(rL = { all strings with at least two consecutive 0 }

Page 12: Regular Expressions

Fall 2005 Costas Busch - RPI 12

Example

Regular expression )0(*)011( r

)(rL = { all strings without two consecutive 0 }

Page 13: Regular Expressions

Fall 2005 Costas Busch - RPI 13

Equivalent Regular Expressions

Definition:

Regular expressions and

are equivalent if

1r 2r

)()( 21 rLrL

Page 14: Regular Expressions

Fall 2005 Costas Busch - RPI 14

Example L= { all strings without

two consecutive 0 }

)0(*)011(1 r

)0(*1)0(**)011*1(2 r

LrLrL )()( 211r 2rand

are equivalentregular expr.

Page 15: Regular Expressions

Fall 2005 Costas Busch - RPI 15

Regular Expressionsand

Regular Languages

Page 16: Regular Expressions

Fall 2005 Costas Busch - RPI 16

Theorem

LanguagesGenerated byRegular Expressions

RegularLanguages

Page 17: Regular Expressions

Fall 2005 Costas Busch - RPI 17

LanguagesGenerated byRegular Expressions

RegularLanguages

LanguagesGenerated byRegular Expressions

RegularLanguages

Proof:

Page 18: Regular Expressions

Fall 2005 Costas Busch - RPI 18

Proof - Part 1

r)(rL

For any regular expression

the language is regular

LanguagesGenerated byRegular Expressions

RegularLanguages

Proof by induction on the size of r

Page 19: Regular Expressions

Fall 2005 Costas Busch - RPI 19

Induction BasisPrimitive Regular Expressions: ,,Corresponding NFAs

)()( 1 LML

)(}{)( 2 LML

)(}{)( 3 aLaML

regularlanguages

a

Page 20: Regular Expressions

Fall 2005 Costas Busch - RPI 20

Inductive Hypothesis Suppose that for regular expressions and , and are regular languages

1r 2r)( 1rL )( 2rL

Page 21: Regular Expressions

Fall 2005 Costas Busch - RPI 21

Inductive StepWe will prove:

1

1

21

21

*

rL

rL

rrL

rrL

Are regular Languages

Page 22: Regular Expressions

Fall 2005 Costas Busch - RPI 22

By definition of regular expressions:

11

11

2121

2121

**

rLrL

rLrL

rLrLrrL

rLrLrrL

Page 23: Regular Expressions

Fall 2005 Costas Busch - RPI 23

)( 1rL )( 2rLBy inductive hypothesis we know: and are regular languages

Regular languages are closed under:

*1

21

21

rL

rLrL

rLrL Union

Concatenation

Star

We also know:

Page 24: Regular Expressions

Fall 2005 Costas Busch - RPI 24

Therefore:

** 11

2121

2121

rLrL

rLrLrrL

rLrLrrL

Are regularlanguages

)())(( 11 rLrL is trivially a regular language(by induction hypothesis)

Page 25: Regular Expressions

Fall 2005 Costas Busch - RPI 25

For any regular language there is a regular expression with

Proof - Part 2

LanguagesGenerated byRegular Expressions

RegularLanguages

Lr LrL )(

We will convert an NFA that accepts to a regular expression

L

Page 26: Regular Expressions

Fall 2005 Costas Busch - RPI 26

Since is regular, there is aNFA that accepts it

LM

LML )(

Take it with a single final state

Page 27: Regular Expressions

Fall 2005 Costas Busch - RPI 27

From construct the equivalentGeneralized Transition Graphin which transition labels are regular

expressions

M

Example:

a

ba,

cM

a

ba

c

CorrespondingGeneralized transition graph

Page 28: Regular Expressions

Fall 2005 Costas Busch - RPI 28

Another Example:

ba a

b

b

0q 1q 2q

ba,a

b

b

0q 1q 2q

b

bTransition labels are regular expressions

Page 29: Regular Expressions

Fall 2005 Costas Busch - RPI 29

Reducing the states:

ba a

b

b

0q 1q 2q

b

0q 2q

babb*

)(* babb

Transition labels are regular expressions

Page 30: Regular Expressions

Fall 2005 Costas Busch - RPI 30

Resulting Regular Expression:

0q 2q

babb*

)(* babb

*)(**)*( bbabbabbr

LMLrL )()(

Page 31: Regular Expressions

Fall 2005 Costas Busch - RPI 31

In GeneralRemoving a state:

iq q jqa b

cde

iq jq

dae* bce*dce*

bae*

Page 32: Regular Expressions

Fall 2005 Costas Busch - RPI 32

0q fq

1r

2r

3r4r

*)*(* 213421 rrrrrrr

LMLrL )()(

The resulting regular expression:

By repeating the process until two states are left, the resulting graph is

Initial graph Resulting graph

Page 33: Regular Expressions

Fall 2005 Costas Busch - RPI 33

Standard Representations of Regular Languages

Regular Languages

DFAs

NFAsRegularExpressions

Page 34: Regular Expressions

Fall 2005 Costas Busch - RPI 34

When we say: We are given a Regular Language

We mean:

L

Language is in a standard representation

L

(DFA, NFA, or Regular Expression)