problems in linear equations

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St. Angela ( Group 5) PROBLEMS IN LINEAR EQUATIONS

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Problems in linear equations. St. Angela ( Group 5). 1 st proble m. 1 st problem. Paula is now 18 years old and her colleague Monica is now 14 years old. How many years ago was Paula twice as old as Monica?. Chart. Solution. (18-x) - 2(14-x) 18-x = 28-2x. answer. X = 10. - PowerPoint PPT Presentation

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Page 1: Problems in linear equations

St. Angela ( Group 5)

PROBLEMS IN LINEAR

EQUATIONS

Page 2: Problems in linear equations

1ST PROBLEM

Page 3: Problems in linear equations

Paula is now 18 years old and her colleague Monica is now 14 years old. How many years ago was Paula twice as old as Monica?

1ST PROBLEM

Page 4: Problems in linear equations

Past Present

Paula 18-x 18

Monica 14-x 14

CHART

Page 5: Problems in linear equations

(18-x) - 2(14-x)18-x = 28-2x

SOLUTION

Page 6: Problems in linear equations

X = 10

ANSWER

Page 7: Problems in linear equations

2nd Problem

Page 8: Problems in linear equations

A triangular Pyramid with a square base has a height equal to two times the side of it’s base. Find the dimension of the Pyramid if the volume is 100 cu. cm

2ND PROBLEM

Page 9: Problems in linear equations

Height = 2

Side of the base = x

NOTE = Volume of the pyramid = 1/3 ( Area of the base) x height

100 = 1/3 (x^2)(2x)

100 = 2/3 (x^3)

X = cube root of 150

Height = 2x

2( cube root of 150)

SOLUTION

Page 10: Problems in linear equations

Height = 2 cube root of 150

Side of base = cube root of 150

ANSWER

Page 11: Problems in linear equations

3RD PROBLEM

Page 12: Problems in linear equations

JJ is three times older as Jan-Jan. Three years ago, JJ was four times as old as

Jan-Jan. the sum of there age is?

3RD PROBLEM

Page 13: Problems in linear equations

Past Present

JJ 3x-3 3x

Jan-Jan X-3 x

CHART

Page 14: Problems in linear equations

3x-3 = 4(x-3)3x-3 = 4x-12

X-12 = 3x = Jan- Jan’s age3x = 27 ( JJ’s age )

SOLUTION

Page 15: Problems in linear equations

Sum of ages = 9 + 27 = 36

ANSWERS