perpendicular lines. ┴ perpendicular lines are lines that intersect in a right angle. ┴ the...
TRANSCRIPT
Perpendicular
Perpendicular
LinesLines
Perp
endic
ula
r
Perp
endic
ula
r Li
nes
Lines
┴Perpendicular lines are lines that Perpendicular lines are lines that intersect in a right angle.intersect in a right angle.
┴The slopes of perpendicular lines are The slopes of perpendicular lines are negative reciprocals of each other. negative reciprocals of each other. (Multiplying the two slopes together (Multiplying the two slopes together & their product will equal –1.)& their product will equal –1.)
┴Find the equation of a perpendicular: Find the equation of a perpendicular: a.) first find the a.) first find the slope (slope (m)m) of the given line; of the given line;
b.) find the equation of the line b.) find the equation of the line through the given point with opposite through the given point with opposite reciprocal slope.reciprocal slope.
Test
ing if
Lin
es
Test
ing if
Lin
es
Are
A
re
Perp
endic
ula
r
Perp
endic
ula
r
1Are the lines 2 5 and 4 perpendicular?
2x y y x
Find the slope of 2 5 2
2 5
x y m
y x
1 1Find the slope of 4
2 2y x m
Since the slopes are negative reciprocals of each other the lines are perpendicular.
12 1
2
Gra
phs
of
Gra
phs
of
Perp
endic
ula
r
Perp
endic
ula
r Li
nes
Lines
The red line is the graph of y = – 2x + 5
and the blue line is the graph ofy = – 1/2 x +4
Pract
ice T
est
ing if
Pract
ice T
est
ing if
Li
nes
Are
Li
nes
Are
Pe
rpendic
ula
r
Perp
endic
ula
r6 3 5
3 6 5
52 32
x y
y x
y x
m
Are the lines 6 3 5 and 2 4 4 perpendicular?x y y x
2 4 4
2 2
2
y x
y x
m
Since the slopes are not negative reciprocals of each other (their product is not -1) the lines are not perpendicular
Pract
ice T
est
ing if
Pract
ice T
est
ing if
Li
nes
Are
Li
nes
Are
Pe
rpendic
ula
r
Perp
endic
ula
r
Are the lines 2 4 and 4 2 6 perpendicular?x y x y
2 4
2 4
1 221
2
x y
y x
y x
m
4 2 6
2 4 6
2 3
2
x y
y x
y x
m
Since the slopes are negative reciprocals of each other (their product is -1) the lines are perpendicular.
Const
ruct
ing
Const
ruct
ing
Perp
endic
ula
r
Perp
endic
ula
r Li
nes
Lines
Find the equation of a line going through the point (3, -5) and perpendicular to 2 83y x
The slope of the perpendicular line will be m = 3/2.
┴Using the slope-intercept form of an equation where the slope m = 3/2 andthe point is (3, -5) we get…
Pract
ice
Pract
ice
Const
ruct
ing
Const
ruct
ing
Perp
endic
ula
r
Perp
endic
ula
r
Lines
Lines
Find the equation of the line going through the point (4,1) and Perpendicular to 3 7y x
Find the equation of the line going through the point (-2,7) and perpendicular to 2 8x y
Hom
ew
ork
Hom
ew
ork