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Thursday, October 2, 2014 Today: Submit all Outstanding Forms... Literal & Other Equations Review Khan Academy Topics

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Page 1: Oct.2, 2014

Thursday, October 2, 2014

Today: Submit all Outstanding Forms...

Literal & Other Equations Review Khan Academy Topics

Page 2: Oct.2, 2014

Very Impressive:@ the Khan Academy

For Tuesday & Wednesday only… 1154 mins. 19.83 hours

Page 3: Oct.2, 2014

Formulas & Vocabulary Page1. Dimension:

Length & Width.The dimensions of a 2-dimensional object are?The dimensions of a 3-dimensional object are?. Length, Width, & Height

3. Formula for the volume of a rectangular 3-dimensional object is:

The amount of space, measured in cubic units, (lwh) that an object or substance occupies.

2. Volume:

Length x Width x Height

The measure of a thing in a given direction.

Most grocery products are “sold by weight, not by volume” Why?

Page 4: Oct.2, 2014

Formulas:

Class Notes Section of your

notebook, pls.

b. Find the height of a cylinder with volume of 3140 feet and radius of 10 ft.

Page 5: Oct.2, 2014

Class Notes:Tips for Solving Literal & Other

Equations:1. If the variable you are solving for is inside the parenthesis, you must distribute first.

9p = 3(k + 5) for k

2. If the variable you are solving for is outside the parenthesis, simply perform the opposite operation.9 = k(p + 5) for k

3. When clearing fractions, if the denominator being multiplied has two or more terms, it must be distributed on the other side.

5k( 2p + 4) = 9 = for p

Literal Equations:

We need to separate the ‘k’ from the 5 in this case. Solve the equation.

Page 6: Oct.2, 2014

Class Notes:

Tips for Solving Literal & Other Equations:

4. Always check to see if every term has something in common. You can then factor the common part out.3kp – 7km – 9k – 1 = -7p +

10 for k first

3kp – 7km – 9k = -7p + 11

Then,

k(3p – 7m – 9) = -7p + 11

Now What?

k= -7p + 11 (3p – 7m – 9)

Class Notes:

Page 7: Oct.2, 2014

Tips for Solving Literal & Other Equations:

5. If an entire term can be factored out, replace it inside the parenthesis with a ‘1’2p + 8px = ?

2p(1 + 4x) check by distributing the 2p again.

6. When solving fractional equations, you may have to clear fractions more than once.

Class Notes:

4 – 2x = 𝟔−𝟑 𝒙𝟑

20 – 10x =5

Complete the first step.Now we distribute the....

Solve for x.

Page 8: Oct.2, 2014

Tips for Solving Literal & Other Equations:

7. Two equal fractions is called a proportion.Proportions can be solved by cross multiplying.The following is not a proportion. How must this

problem be solved?Finish It

Class Notes:

= solve

Warm Up Section of your notebook,

pls.

Page 9: Oct.2, 2014

This week at the Academy..

Page 10: Oct.2, 2014

This week at the Academy..

Page 11: Oct.2, 2014

This week at the Academy..

Page 12: Oct.2, 2014

Solve for a: Q = 3a + 5ac

Solve for h: A = ah - bh

Warm-Up: Literal Equations

What can be factored out of both terms?

Find the missing dimension:

P = 60

L = 19

3(x + 6) + 2x – 6 = 8x -2(3x – 6) -2 Same Rules; don’t do anything

different!Lastly, this beauty...

Page 13: Oct.2, 2014

3rd & 4th Periods

Warm Up

Lastly, this beauty...

4 - 2A number is doubled, and then 5 is added. When then divided by 3, the result is 7.

Write the equation, then solve

A triangle has an area of 28 ft.2 and a base of 4 sq. feet. What is the height of the triangle?

Rewrite using the correct formula, then solve

Page 14: Oct.2, 2014

1st & 2nd Periods;

Complete class work from Tuesday

Begin Mixed Equation/Formula Practice

3rd & 4th Periods; Mixed Equation/Formula

Practice