nhdt ckdt.pdf
TRANSCRIPT
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NGN HNG THI MN: CU KIN IN T
Dng cho h HTX ngnh IN T VIN THNG
(60 tit 4 tn ch)
CHNG I: GII THIU CHUNG V CU KIN IN T Cu hi loi 1: 1/ Theo l thuyt di nng lng ca vt cht th rng vng cm E
G ca cht bn
dn c gi tr: a E
G = 0eV 2eV
b EG = 0eV
c EG > 6eV
d EG = 0eV 6eV
2/ Cc tnh cht vt l in c bn ca cht in mi l: hng s in mi , tn hao in mi (P
a),
bn v in E.t.
, nhit chu ng v in tr cch in. a ng. b Sai. 3/ Da theo lch s pht trin ca cng ngh in t th cu kin in t c chia lm 5 loi l cu kin in t chn khng, cu kin in t bn dn, cu kin vi mch, cu kin in t nan. a ng b Sai 4/ H s nhit ca in tr sut biu th: a S thay i ca in tr sut khi nhit thay i mt khong l t.
b S thay i ca in tr khi nhit thay i C01
c S thay i ca in tr sut khi nhit thay i C01 .
d S tng ca in tr sut khi nhit thay i C01 .
5/ Tnh dn in ca cht bn dn tp loi N do: a Ht dn in t quyt inh. b Ht dn l trng quyt nh. c Ht dn in t v ht dn l trng quyt nh. d Cc i-on m quyt nh. 6/ Tnh dn in ca cht bn dn tp loi P do:
HC VIN CNG NGH BU CHNH VIN THNG Km10 ng Nguyn Tri, H ng-H Ty
Tel: (04).5541221; Fax: (04).5540587 Website: 0Hhttp://www.e-ptit.edu.vn; E-mail: [email protected]
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a Ht dn l trng quyt nh b Ht dn in t quyt nh c Cc i-on m quyt nh. d Ht dn in t v ht dn l trng quyt nh 7/ Cc tnh cht c trng cho vt liu t l t thm tng i (
r), in tr sut
(), h s nhit ca in tr sut (). a ng b Sai 8/ Ti nhit phng, mt ming tinh th silic nguyn cht hot ng ging nh a Cht cch in b Cht dn in km c Mt on dy ng. d Mt ngun in 9/ Dng in trong cht in mi gm c 2 thnh phn l a Dng in phn cc v dng in r b Dng in khuch tn v dng in phn cc. c Dng in phn cc v dng in tri. d Dng in khuch tn v dng in tri 10/ Vt liu bn dn quang l hp cht c bit c lin kt hai, ba hoc bn thnh phn ca cc nguyn t thuc a Nhm 2 v nhm 4 b Nhm 3 v nhm 5. c Nhm 4 v nhm 5 d nhm 3 v nhm 6 Cu hi loi 2: 11/ Dng in trong cht bn dn gm c: a Ba thnh phn l dng in r, dng in phn cc, dng in khuch tn b Hai thnh phn l dng in khuch tn v dng in tri c Hai thnh phn l dng in khuch tn v dng in chuyn dch (dng phn cc). d Bn thnh phn l dng in r, dng in khuch tn, dng in phn cc v dng in tri 12/ Ferit t mm l vt liu t c dng rng ri nht tn s cao do c: a in dn sut cao, t thm ban u thp, gi tr cm ng t bo ha thp b in dn sut cao, t thm ban u cao, gi tr cm ng t bo ha thch hp c in dn sut cao, t thm ban u cao, gi tr cm ng t bo ha thp d in dn sut thp, t thm ban u cao, gi tr cm ng t bo ha thch hp 13/ K hiu di y l ca cu kin in t no?
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a it bn dn b Cu kin thch anh c T in d Khng phi k hiu ca cu kin in t 14/ Cht in mi th ng thng c dng lm a in tr b in tr v t in c T in v cht cch in. d Li cun dy v bin p Cu hi loi 3:
15/ Mt ming bn dn silic c pha thm photpho nng 315.10.5,1 cm .
Hy tnh nng ht dn trong ming bn dn ti nhit K0300 . (cho bit n
i =
310.10.5,1 cm ).
a Nn =
315.10.5,1 cm ; Pn =
35.10 cm .
b Nn =
315.10.5,1 cm ; Pn =
35.10.5,1 cm .
c Nn =
315.10.5,1 cm ; Pn =
35.10.5,1 cm .
d Nn =
35.10 cm ; Pn =
35.10.5,1 cm . 16/ ng nguyn cht l kim loi dn in tt v in tr sut ca n l:
a m10 b m210.3 c m6 d 0,0175 .m 17/ Thch anh thng c dng trong cc b to dao ng c tn s dao ng a Rt n nh b Rt thp c Rt cao d Trung tn
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CHNG 2: CC CU KIN IN T TH NG
Cu hi loi 1: 18/ Vt liu cn in dng ch to in tr l a Cht cch in b Cht dn in c in tr sut thp c Cht dn in c in tr sut cao d Tt c cc loi vt liu trn 19/ Trn thn in tr thng c cc nh sn xut ghi cc tham s chnh sau: Tr s in tr, dung sai ca tr s in tr, in p lm vic cho php a Sai b ng 20/ Tecmixto l in tr c h s nhit mang gi tr m a ng b Sai 21/ Khi s dng t in chng ta cn ch cc tham s chnh ca chng l: tr s dung lng, dung sai, in p lm vic a Sai b ng 22/ Tn tht ca cun cm c biu th trong s mch tng ng bi a Mt in tr ni tip vi cun dy. b Mt in tr song song vi cun dy. c Mt in tr v mt t in mc song song vi cun dy d Mt t in mc song song vi cun dy. 23/ Bin p cao tn dng truyn tn hiu c chn lc th dng loi ghp lng, cn bin p cao tn dng bin i tng tr th dng loi ghp cht a ng b Sai 24/ T ha l loi t m cht in mi l dung dch ha hc a ng b Sai 25/ Varixto l in tr m tr s ca n c iu khin bng a Dng in chy qua n. b Nhit mi trng c in p t ln n d T trng xung quanh n 26/ T xoay c th c nhiu ngn. Mi ngn c cc l tnh v cc l ng ch to t ng nguyn cht, t xen k nhau a Sai b ng
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Cu hi loi 2: 27/ Mt in tr mu c cc vng mu theo th t: vng - tm - l cy - vng kim c tr s in tr l a 4700 5%K b 470 10%K c 470 5%M d 4,7 10%M 28/ Lut in tr l mt tham s c bn ca: a Bin tr b in tr mng kim. c in tr than tng hp. d Tt c cc loi in tr. 29/ Khi t in lm vic tn s cao th phi ch n: a in p lm vic cho php ca t in. b Tn hao cng sut trong t thng qua h s tn hao DF. c C 3 tham s trn. d Dung sai ca t in tnh theo %. 30/ Cc tham s k thut c bn ca cun cm l a in cm (L), h s phm cht (Q), in dung ring ca cun cm (C). b in cm (L), in tr ni tip biu th tn hao ca cun cm (R
S), kch thc
cun cm c in cm (L), tn s lm vic gii hn (f
gh), in dung ring ca cun cm (C).
d H s phm cht (Q), in dung ring ca cun cm (C), s vng dy (N). 31/ Cun dy khng li lm vic tn s cao thng yu cu phi c a in cm cao, h s phm cht nh, in dung ring cao tn s lm vic. b in cm n nh, h s phm cht cao, in dung ring nh tn s lm vic c in cm thch hp, h s phm cht cao, in dung ring ln tn s lm vic d in cm n nh, h s nhit cao, in dung ring ln tn s lm vic 32/ Li trong cun dy ferit c th iu chnh c a Thay i tn s lm vic gii hn ca cun dy. b Thay i in cm ca cun dy c Thay i tn tht ca cun dy d Thay i c 3 tham s k thut trn 33/ Khi s dng in tr ta phi bit c cc tham s c bn no ca chng? a H s nhit, cng sut tiu tn v khong nhit lm vic b Tr s in tr, h s nhit v dng in cc i c Tr s in tr, dung sai, in p lm vic cho php. d Tr s in tr, dung sai v cng sut tiu tn (nu c). 34/ Khi s dng t in ta phi bit c cc tham s c bn no ca chng? a H s nhit, cng sut tiu tn v khong nhit lm vic b Tr s in dung, dung sai v cng sut tiu tn c Tr s in dung, h s nhit v dng in cc i d Tr s in dung, dung sai v in p lm vic cho php
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Cu hi loi 3: 35/ Bin p m tn c p ng tn s khng bng phng trong khong tn s thp di 100Hz v cao hn 10KHz l do nh hng ca in cm ca cun s cp v tn hao nng lng ca li st t (do in cm r v in dung phn tn gia cc vng dy) tng ln? a ng b Sai 36/ Mt in tr c ghi tr s l 1 k v dung sai l 5%, hi tr s ca in tr c th l bao nhiu?
a Khong t 0,95K 10,5K b Khong t 950 1050 c Khong t 950 1000 d Khong t 1K 1,5K
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CHNG 3: IT BN DN Cu hi loi 1. 37/ Tnh cht vt l c bn ca lp tip xc P-N l kh nng dn in tt khi c phn cc thun v phn cc ngc a Sai b ng 38/ Khi tip xc P-N phn cc thun th a Hng ro th nng tng, b dy lp tip xc gim, in tr lp tip xc gim b Hng ro th nng tng, b dy lp tip xc tng, in tr lp tip xc tng c Hng ro th nng gim, b dy lp tip xc tng, in tr lp tip xc tng d Hng ro th nng gim, b dy lp tip xc gim, in tr lp tip xc gim 39/ Khi tip xc P-N phn cc thun, dng in thun chy qua lp tip xc l do a Cc ht dn a s chuyn ng tri di tc dng ca in trng tip xc to nn. b Cc ht dn thiu s khuch tn qua lp tip xc to nn. c C ht dn a s v thiu s chuyn ng tri di tc ng ca in trng to nn d Cc ht dn a s khuch tn qua lp tip xc to nn 40/ Nguyn l hot ng ca it bn dn da vo tnh dn in mt chiu ca lp tip xc P-N a ng b Sai 41/ Trn thc t, it bn dn c phn cc thun khi in p t ln it phi:
a AK DU U b AK DU U= c 0AKU V> d AK DU U 42/ K hiu sau y ch cu kin no:
a i t St-ky. b i t chnh lu. c i t zener d i t tunen. 43/ Varicap l i t bn dn c chc nng nh mt: a Cun cm b Bin p c in tr d T in
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44/ i t chnh lu ch hot ng khi ch phn cc thun a ng b Sai 45/ c tnh c bn ca i t chnh lu l a Gi tr dng in thun cc i v in p ngc cho php b Gi tr dng in thun cc i v in p thun cho php. c Gi tr dng in thun cc i v nhit lm vic cho php d Gi tr dng in thun cc i v cng sut tiu tn cc i 46/ Dng in ngc bo ha ca it bn dn s l: a Xp x 2 ln i vi mi mt s tng nhit ln C
020 . b Xp x 2 ln i vi mi mt s tng nhit ln C
010 c Xp x 3 ln i vi s tng nhit ln C
010 . d Xp x 2 ln i vi mi mt s tng nhit ln C
015 . 47/ it c kh nng bin i dng in xoay chiu thnh mt chiu c gi l a it n p. b it chuyn mch. c it tunen. d it chnh lu. 48/ in p ngc cho php ca it thng c chn bng a 0,6 U
.t.
b 0,5 U.t.
c U.t.
d 0,8 U.t.
49/ it Stky l loi it c lp tip xc: a Bn dn - bn dn b Bn dn- vt liu t c Bn dn - kim loi d Bn dn - cht cch in Cu hi loi 2: 50/ Mi quan h gia dng in v in p t trn i t bn dn c biu din bng cng thc:
a
+= 10 T
AK
VU
eII vi I
0 l dng in ngc bo ha.
b
= 10 T
AK
VU
eII vi I
0 l dng in ngc bo ha.
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c
2
0 1
= T
AK
VU
eII vi I
0 l dng in ngc bo ha
d
= 10 T
AK
VU
eII vi I
0 l dng in ngc bo ha.
51/ in tr ng (R
i) ca it l mt tham s quan trng, n c tnh theo cng
thc
a 0IUR Di =
vi I0 l dng in ngc bo ha
b M
Ti I
VR = vi I
M l dng in ca i t ch tnh
c M
Di I
UR = vi I
M l dng in ti ch lm vic tnh
d M
Ti I
VR = vi I
M l dng in ca i t ch ng
52/ it bn dn c coi nh mt in tr c tr s
T
M
VRI
= khi n hot ng ch
a Phn cc thun v vi tn hiu nh tn s cao b Phn cc ngc v vi tn hiu nh c Phn cc thun v vi tn hiu nh tn s thp. d Phn cc thun 53/ S tng ng ca it bn dn c dng mch nh hnh v di khi n lm vic ch
a Phn cc thun v vi tn hiu nh tn s thp b Phn cc ngc v vi tn hiu nh tn s thp c Phn cc thun v vi tn hiu nh tn s cao d Phn cc ngc v vi tn hiu nh tn s cao 54/ Khi it phn cc ngc th dng in chy qua n l bao nhiu? a 0 mA b 300 mA c Khng phi nhng gi tr trn d 1 mA
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55/ S tng ng ca mt it phn cc thun di y c coi nh
a Mt ngun in p thc b Mt ngun dng l tng. c Mt ngun in p l tng d Mt in tr thc 56/ Tham s quan trng nht ca it xung l a Thi gian phc hi chc nng ngt t
p.
b Thi gian xung tf.
c in p nh thng Udt
d Thi gian ln tr
57/
S tng ng ca mt it phn cc thun di y c coi nh
a Mt ngun in p l tng b Mt ngun dng l tng c Mt in tr thc d Mt ngun in p thc 58/ S tng ng ca mt i t phn cc ngc di y c coi nh
a Mt ngun in p thc b Mt ngun dng l tng c Mt in tr thc d Mt ngun in p l tng 59/ Mt it xung c thi gian phc hi chc nng ngt t
p < 10ns thuc loi
a Tc nhanh b Tc chm. c Tc qu chm d Tc trung bnh. 60/ it Stky l loi it xung c tc chuyn mch a Tc nhanh
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b Tc chm. c Tc qu chm d Tc trung bnh. Cu hi loi 3: 61/ Cng in trng tip xc (E
0) ca lp tip xc P-N khi trng thi cn bng
nhit c xc nh theo cng thc:
a 20 lni
AD
nNNKTE =
vi N
D, N
A l nng ca tp cht Nhn v tp cht Cho, tng ng
b 20 lni
ADT n
NNVE =
vi ND, N
A l nng ca tp cht Nhn v tp cht Cho, tng ng v V
T l
in th nhit
c
220lnln
i
AT
i
DT n
NVnNVE ==
vi N
D, N
A l nng ca tp cht Nhn v tp cht Cho, tng ng v V
T l
in th nhit
d A
D
N
NKTE ln0 =
vi N
D, N
A l nng ca tp cht Nhn v tp cht Cho, tng ng.
62/ Hy tnh cng dng in chy qua i t trong s mch di y
a 0 mA b 14 mA c 20 mA. d 14 A 63/ Hy tnh cng sut tiu tn ca it zener khi bit in p ngun cung cp U
S =
24V, in p trn it l 10V v dng in qua i t l 20mA a 480 mW b 280 mW c 200 mW d 200 W
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64/ Cho s mch nh hnh v di y vi it silic, hy tnh dng in chy trong mch khi iot phn cc thun
a 0 A b 9,3 mA c 9,3 A d 10 mA 65/ Cho mch in nh hnh v. Hy cho bit gi tr in tr l bao nhiu c dng in qua it xp x 10 mA?
a 1 K b 430 K c 500 d 430 66/ Mt it c in p l 0,7V v dng in chy qua n l 50mA. Hi cng sut ca n l bao nhiu? a 50 mW b 35 mW c 35 W d 3,5 W. 67/ in p n nh U
. (V
Z) ca mt it zener ph thuc vo
a in p ngoi t ln n b Dng in ngc bo ha c Nng tp cht ca cht bn dn d Phng php ta nhit cho it Cu hi loi 4: 68/ Hai it mc ni tip. it th nht c in p phn cc l 0,75 V v it th hai c in p phn cc l 0,8 V.
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Nu dng in i qua it th nht l 100mA, hi dng in i qua it th hai l bao nhiu? a 100 mA b 140 mA c 80 mA d 120 mA 69/ Cho mch in nh hnh v. in p ti im ni gia R
1 v R
2 o c l 3 V.
in p gia i t v in tr 5 Ko c 0 V. Hi iu g xy ra trong mch in?
a i t b ni tt b Mch hot ng bnh thng c in tr b ni tt d i t b t hng 70/ C hai it mc ni tip vi nhau vi ngun in cung cp c mch l 1,4V. it th nht c in p l 0,75V. Nu dng in chy qua i t th nht l 500mA, hi it th hai c cng sut l bao nhiu? a 325 mW b C 3 p n trn u khng ng c 300 mW d 375 mW
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CHNG 4: TRANZITO LNG CC (BJT) Cu hi loi 1. 71/ Trong tranzito lng cc loi N-P-N, ht dn a s trong phn gc l a Khng phi hai loi ht dn trn b Cc in t t do c C hai loi ht dn trn. d Cc l trng 72/ Khi tranzito hot ng ch tch cc, lp tip xc pht-gc c a Phn cc ngc. b Phn cc thun. c Khng dn in d Hot ng vng nh thng 73/ Khi tranzito hot ng ch tch cc, lp tip xc gp-gc c a Hot ng vng nh thng b Phn cc ngc. c Phn cc thun d Khng dn in 74/ Phn gc ca cc tranzito lng cc rt mng v a C pha tp cao. b C pha tp thp c L kim loi. d Pha tp cht l nguyn t c ha tr nm. 75/ Trong mt tranzito loi N-P-N c phn cc ch tch cc, cc in t trong phn pht c nng lng vt qua hng ro th nng ca a Tt c cc vng trn. b Lp tip xc pht-gc. c Vng ti hp. d Lp tip xc gp-gc. 76/ Khi mt in t t do ti hp vi mt l trng trong phn gc ca tranzito th in t t do ny s tr thnh a Mt in t ha tr. b Mt in t t do khc. c Mt ht dn a s. d Mt in t trong vng dn. 77/ Yu t no quan trng nht ni v dng in cc gp (I
C)?
a N rt nh. b N xp x bng dng in cc pht (I
E).
c N c o bng miliampe. d N bng dng in cc gc (I
B) chia cho h s khuch i dng in.
78/ Khi tranzito lng cc hot ng ch ngt th: a Tip xc pht-gc v tip xc gp-gc c phn cc thun. b Tip xc pht-gc phn cc ngc v tip xc gp-gc c phn cc thun
-
c Tip xc pht-gc phn cc thun v tip xc gp-gc c phn cc ngc d Tip xc pht-gc v tip xc gp-gc c phn cc ngc. 79/ Khi tranzito lng cc hot ng ch bo ha th a Tip xc pht-gc phn cc thun v tip xc gp-gc c phn cc ngc. b Tip xc pht-gc v tip xc gp-gc c phn cc ngc. c Tip xc pht-gc phn cc ngc v tip xc gp-gc c phn cc thun. d Tip xc pht-gc v tip xc gp-gc c phn cc thun 80/ Khi tranzito lng cc hot ng ch tch cc th a Tip xc pht-gc v tip xc gp-gc c phn cc ngc. b Tip xc pht-gc v tip xc gp-gc c phn cc thun. c C ba trng hp phn cc trn u ng d Tip xc pht-gc phn cc thun v tip xc gp-gc c phn cc ngc 81/ Nguyn l hot ng ca hai loi tranzito lng cc P-N-P v N-P-N l hon ton ging nhau k c ngun cung cp bn ngoi t ln cc chn cc? a Sai b ng 82/ Trong vng tch cc ca mt tranzito lng cc ch to t silic, in p gc-pht (U
BE) l
a 0,7 V b 0,3 V c 0 V d 1 V 83/ Trong vng bo ha ca mt tranzito lng cc, in p gp-pht (U
CE) l
a 1 V b 0,7 V c 0 V d 0,3 V 84/ Mt tranzito trong mch in c phn cc vi cc in p tnh l U
BE = 0,7V;
UCE
= 0,2 V.
Hi tranzito hot ng ch no? a Tch cc b Bo ha c Khng phi cc ch trn d Ngt 85/ Mt tranzito trong mch in c phn cc vi cc in p tnh l: U
BE = 0 V;
CE CU E . Hi tranzito hot ng ch no? a Bo ha. b Khng phi cc ch trn c Ngt d Tch cc 86/ Tranzito c coi nh mt chuyn mch khi hot ng ch a Ngt v bo ha
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b Ngt v tch cc c Khng phn cc d Bo ha v tch cc. 87/ Trong tranzito lng cc loi P-N-P ht dn c bn no to ra dng in gp? a Ht dn l trng b Ht dn in t c Tt c cc loi ht dn trn d Cc Ion 88/ Quan h gia h s khuch i dng in v c m t qua cng thc:
a = 1
b += 1
c = 1
d += 1
Cu hi loi 2: 89/ Quan h gia dng in gp v dng in gc trong tranzito lng cc th hin qua cng thc a I
C = + (+1)I
CB0
b IC = (+1)I
B + I
CB0
c IC = I
B + (+1)I
CB0
d IC = I
B + I
CB0
90/ Quan h gia dng in gp v dng in pht trong tranzito lng cc th hin qua cng thc a I
C = I
E + I
CB0
b IC = (I
E + I
CB0)
c IC = I
E - I
CB0
d IC = I
E
91/
Mt tranzito c dng in pht l 10 mA, dng in gp l 9,95 mA. Hi dng
in gc l bao nhiu? a 0,5 mA b 19,95 mA c 0,05 mA d 1mA 92/ Dng in cc gp l 5 mA, dng in gc l 0,02 mA. Hi h s khuch i dng in l bao nhiu? a 50 b 25 c 250
-
d 100 93/ Mt tranzito c h s khuch i dng in l 125 v dng in gc l 30A. Hi dng in cc gp l bao nhiu? a 37,5 mA b 3,75 A c 3,75 mA d 375 A 94/ Tranzito trong s c mc theo cch no?
a Gc chung (CB). b Pht chung (CE) c Dacling tn d Gp chung (CC). 95/ Tranzito trong s mch c mc theo cch no?
a Gp chung (CC) b Gc chung (CB). c Daclingtn d Pht chung (CE). 96/ Trong mng 4 cc di, tranzito c mc theo cch no?
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a Gp chung (CC). b Gc chung (CB) c Dacling tn d Pht chung (CE). 97/ Trong mng 4 cc di, tranzito c mc theo cch no?
a Daclingtn b Pht chung (CE) c Gp chung (CC). d Gc chung (CB). 98/ Nu h s khuch i dng in = 200 v dng in cc gp l 100mA th dng in cc gc s l a 2 A b 0,5 mA c 20A d 2 mA 99/ Cho s mch nh hnh v, hy cho bit tranzito hot ng ch no?
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a Tch cc b Bo ha. c Khng phi 3 ch trn d Ngt 100/ Hy cho bit tranzito trong mch c mc theo cch no?
a Cc pht chung b Cc gp chung c Daclingtn d Cc gc chung Cu hi loi 3: 101/ Cho mch in nh hnh v. Hy xc nh in tr tng ng R
B = R
1//R
2
-
a 5,866 K b 170 c 14 K d 30 K 102/ Cho mch in nh hnh v. Hy xc nh in tr tng ng R
B = R
1//R
2 ?
a 10 K b 7,5 K c 5 K d 20 K 103/ Cho s mch nh hnh v. Hy xc inh in p U
B?
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a 7,5 V b 10 V c 5 V d 6 V 104/ Cho s mch nh hnh v, hy cho bit tranzito lm vic ch no?
a Bo ha b Ngt c Khng phi ba ch trn. d Tch cc 105/ Hy cho bit tranzito trong s mch di c phn cc theo cch no?
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a Mch nh thin hi tip in p b Mch nh thin c nh c Mch nh thin hi tip c n nh nhit d Mch nh thin phn p 106/ Hy cho bit tranzito trong s mch di c phn cc theo cch no?
a Mch nh thin hi tip in p b Mch nh thin phn p c Mch nh thin hi tip c n nh nhit d Mch nh thin c nh c mch n nh nhit 107/ Hy cho bit tranzito trong s mch di c phn cc theo cch no?
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a Mch nh thin c nh b Mch nh thin hi tip in p c n nh nhit c Mch nh thin hi tip in p d Mch nh thin phn p 108/ Cho mch in nh hnh v di: Tranzito Q
1 c h s
1 = 90, tranzito Q
2 c h
s 2 = 70.
Hi h s khuch i dng in ca c mch l bao nhiu?
a 320 b 160 c 6300 d 20 Cu hi loi 4: 109/ Cho mch in nh hnh v, hy xc nh h s n nh nhit S ca mch nu h s khuch i dng in ca tranzito = 100?
-
a S = 15,1 b S = 34,1 c S = 101 d S = 9,5 110/ Cho mch in nh hnh v c tranzito silic v U
B = 10V; R
B = 100K.
Hi dng in cc gc IB l bao nhiu?
a 93 A b 100 A c 100 mA d 93 mA 111/ Cho mch in nh hnh v vi dng in cc gp I
C = 1 mA; in tr R
C =
3,6K; v in p ngun cung cp V
C = 10V. Hi in p gia cc gp- pht U
CE bng bao
nhiu?
-
a U
CE = 0,64 V
b UCE
= 6,4 V
c UCE
= 10 V
d UCE
= 9 V
112/ Cho mch in nh hnh v vi dng in cc gp l 1 mA; ngun in cung cp V
C = 10 V;
in p gia cc gp-pht UCE
= 6,4 V. Hy xc inh cng sut ca tranzito trong mch l bao nhiu?
a 6,4 W b 10 mW c 10 W d 6,4 mW 113/ Hy xc nh dng in I
C ca tranzito trong s mch in sau. Tranzito ch
to t silic c =100 v ICB0
= 0mA
-
a 25 A b 3,3 mA c 2,15 mA d 3,1 mA 114/ Hy xc nh in p U
CE ca tranzito trong s mch di y khi bit dng
in IC = 10 mA;
ngun EC =10V; in tr R
C = 470; R
B = 100K?
a 4,7 V b 5,3 V c 4,0 V d 6,3 V
-
CHNG 5: TRANZITO TRNG (FET) Cu hi loi 1. 115/ FET: a C h s khuch i in p rt cao b L mt cu kin c iu khin bng dng in c C tr khng vo thp d L mt cu kin c iu khin bng in p 116/ to ra dng in trong mch, mt tranzito n cc s dng a Ch mt loi ht dn: hoc in t t do, hoc l trng b C hai loi ht dn l in t t do v l trng c Ch mi in t t do d Ch mi ht dn l trng 117/ Tr khng vo ca JFET a Gn bng 1 b Rt ln c Khng th on trc c d Gn bng zero 118/ in p cc Ca ca FET thc hin vic iu khin a Dng in mng b in p ngt t l c rng ca knh d C ba phng n cn li 119/ Lp tip xc P-N gia cc Ngun v cc Ca ca JFET cn phi: a Phn cc ngc b C ba phng n cn li u sai c Phn cc thun d Hoc phn cc thun, hoc phn cc ngc 120/ Cc ht dn trong JFET knh P l a Cc in t t do v cc l trng b Cc in t t do c C th l in t t do hoc c th l l trng d Cc l trng 121/ FET hot ng a s ta phi phn cc sao cho cc tip xc P-N phi phn cc thun v cc ht dn phi chuyn ng t cc ngun qua knh v cc mng to nn dng in trong FET? a Sai b ng 122/ MOSFET knh sn hot ng trng thi ngho ht dn gn nh a Mt ngun dng b Mt JFET c Mt in tr d Mt MOSFET knh cm ng
-
123/ MOSFET knh cm ng bt u dn khi in p U
GS bng:
a in p bo ha (UDSbh
)
b in p ngng (UGSth
)
c in p ngt (UGSngt
)
d in p khuu (UB0
)
124/ Khi mt JFET ch ngt th cc lp tip xc P-N (lp ngho ht dn) s: a Dn in b Chm vo nhau c Trm ph ln nhau d Cch xa nhau ra 125/ Trong mt JFET knh N, khi in p cc ca cng m hn th knh dn nm gia hai lp tip xc s tr nn: a Hp hn b Rng hn c Dn in tt hn d Giu ht dn hn 126/ vng thun tr ca c tuyn ra trong FET, dng in t l vi in p theo qui lut a ng cong parabol b ng thng c Khng thay i d ng cong hypecbol 127/ vng bo ha ca c tuyn ra trong FET, dng in t l vi in p theo qui lut a ng cong parabol b ng cong hypecbol c Khng thay i d ng thng 128/ Vt liu phn Ngun v phn Mng ca MOSFET knh cm ng loi N l: a Bn dn thun b Kim loi c Bn dn tp loi N d Bn dn tp loi P 129/ Tr khng vo ca JFET c gi tr nm trong khong:
a K)1010( 1310 b )1010( 1310 c )1010( 1513 d )1010( 86 130/ Tr khng vo ca MOSFET c gi tr nm trong khong
a )1010( 1513 b K)1010( 1614
-
c )1010( 86 d )1010( 1310 131/ Vt liu knh dn ca JFET knh N l cht a Hp kim b Bn dn loi N c Bn dn loi P d Bn dn thun Cu hi loi 2. 132/ Mun cho MOSFET knh cm ng loi P hot ng ta phi cp ngun in phn cc sao cho
a 0 GSthGS UU v UDS
> 0
b GSthGS UU < 0 v UDS
< 0
c 0 GSthGS UU v UDS
< 0
d 0 GSthGS UU v UDS
> 0
133/ Mun cho MOSFET knh cm ng loi N hot ng ta phi cp ngun in phn cc sao cho
a 0 GSthGS UU v UDS
>0
b 0 GSthGS UU v UDS
0
134/ Mt JFET c dng in mng bo ha I
Dbh = 20mA v in p mng bo ha
UDSbh
= 5V.
Hi in tr mt chiu ca JFET vng thun tr l bao nhiu? a RD
S = 2,5 K
b RDS = 250 K
c RDS = 100
d RDS = 250
135/ Cng thc tnh dng in mng ca tranzito trng JFET l:
a
2
0 1
=
GSngat
GSDD U
UII
b
=
GSngat
GSDD U
UII 10
-
c
2
0 1
=
GSngat
GSDD U
UKII
d
2
0 1
+=
GSngat
GSDD U
UII
136/ Tranzito 2N5902 c dng in mng bo ha l 500A v in p mng-ngun bo ha U
DSbh l 2V,
Hi in tr mng RDS
trong vng thun tr l bao nhiu? a RD
S = 40
b RDS = 4 K
c RDS = 10 K
d RDS = 100
137/ Tranzito 2N5457 c gi tr dng in mng bo ha I
Dbh l 5 mA v in p ngt
UGSngt
l -6 V.
Hy tnh h s K khi in p UGS
l 0 V?
a K = 2. b K = 5. c K = 1 d K = 6. 138/ Tranzito 2N5902 c cc tham s I
G l 5 pA ti in p U
GS bng 20 V nhit
phng. Hi tr khng vo ca n l bao nhiu nhit phng?
a = 1210.4VZ b = 1010.5VZ c = 910.4VZ d = 1510.4VZ 139/ Trong cng thc tnh dng in cc mng I
D = KI
D0 ca JFET, h s K l:
a
+=
GSngat
GS
UU
K 1
b
2
=
GSngat
GS
UU
K
c
2
1
=
GSngat
GS
UU
K
d
2
1
+=
GSngat
GS
UU
K
-
140/ Trong s mc cc ngun chung, h s khuch i in p ln nht ca mt FET c th t c l:
a 150 300 = b 10 30 = c 1 < d 5 10 = 141/ Trong s mc cc mng chung, h s khuch i in p ln nht ca mt FET c th t c l a 5 10 = b 150 300 = c 10 30 = d 1 < 142/ c tuyn iu khin ca FET : I
D = f(U
GS) khi U
DS khng i l mt:
a ng cong hypecbol. b ng thng. c ng cong parabol. d ng khng xc nh trc Cu hi loi 3. 143/ Cho mch in nh hnh v, hy cho bit in p mng-ngun U
DS l bao
nhiu?
a UD
S = 11 V
b UDS = 9 V
c UDS = 17 V
d UDS = 5 V
144/ Cho mch in nh hnh v, hy cho bit dng in mng I
D l bao nhiu?
-
a ID = 7,5 A b ID = 7,5 mA c ID = 17 mA d ID = 20 mA 145/ Hy cho bit tranzito trong s mch c mc theo cch no?
a Pht chung. b Mng chung. c Ca chung. d Ngun chung 146/ Hy cho bit tranzito trong s c mc theo cch no?
-
a Ngun chung b Mng chung. c Ca chung. d Pht chung. 147/ Tranzito trong s c phn cc cch no?
a T phn cc. b Phn cc hi tip. c Phn cc phn p. d Phn cc c nh. 148/ Hy cho bit tranztito trong s c phn cc theo cch no?
-
a Phn cc hi tip. b Phn cc c nh. c Phn cc t cp. d Phn cc phn p Cu hi loi 4. 149/ Cho mch in nh hnh v, hy cho bit in p mng-ngun U
DS l bao
nhiu?
a UD
S = 1,2 V.
b UDS = 11V.
c UDS = 4 V.
d UDS = 13,8 V
150/ Cho s mch nh hnh v, hy cho bit in p mng-ngun U
DS l bao
nhiu?
-
a UD
S = 7,5 V.
b UDS = 9 V.
c UDS = 0 V.
d UDS = 11 V.
151/ Cho s mch nh hnh v. Hi in p trn cc ca l bao nhiu nu bit dng in mng l I
D = 15 mA?
a UG = 5 V b UG = 15 V c UG = 0 V d UG = 10 V 152/ Cho s mch nh hnh v. Hi in p trn cc mng l bao nhiu nu bit dng in mng l I
D = 12 mA?
-
a UD = 13 V b UD = 25 V c UD = 15 V d UD = 0 V 153/ Cho mch in nh hnh v. Hi in p U
DS l bao nhiu nu bit dng in mng I
D = 10 mA?
a UD
S = 5 V
b UDS = 10 V
c UDS = 20 V
d UDS = 15 V
154/ Cho mch in nh hnh v. Hi dng in mng l bao nhiu?
-
a ID = 4,72 mA b ID = 0,25 mA. c ID = 0,5 mA. d ID = 5,55 mA
-
CHNG 6: CU KIN THYRISTOR Cu hi loi 1.
155/ Thyristo c th s dng nh: a Mt ngun dng. b Mt b khuch i. c Mt cng tc chuyn mch d Mt in tr. 156/ kch thch mt cu kin thyristo dn in ta s dng a Hi tip. b Hi tip dng. c S dng mt dng in. d Tranzito lng cc. 157/ Dng in no sau y c th bt thyristo dn in a Dng in nh thng. b Dng in duy tr I
H.
c Dng in ngc bo ha. d Dng in kch thch I
G.
158/ Dng in ant nh nht gi cho thyristo dn in c gi l: a Dng in duy tr. b Dng in nh thng. c Dng in ngc bo ha. d Dng in kch thch. 159/ Chnh lu silic c iu khin (SCR) c a Ba vng pha tp cht bn dn. b Hai lp tip xc P-N. c Bn lp tip xc P-N. d Ba lp tip xc P-N. 160/ kch thch cho SCR dn in ngi ta thng: a Dng ci ngt in. b Kch thch cc iu khin G. c Dng dng in duy tr. d Dng hin tng nh thng lp tip xc P-N. 161/ Triac tng ng vi: a Hai diac mc song song. b it c bn lp bn dn. c Hai SCR mc song song v ngc chiu nhau. d Hai SCR u song song v cng chiu nhau. 162/ in p cn thit t ln cc pht ca UJT n dn in c gi l: a in p trng U
V
b in p nh UP
c in p kch khi UK
-
d in p nh khuu UB0
Cu hi loi 2. 163/ Dng UJT to dao ng xung ngi ta s dng on c tuyn a in tr m. b in tr dng. c vng ngt. d in tr m v in tr dng 164/ in p nh ca UJT c tnh theo cng thc a UP = U
BB + 0,7 V
b UP = UBB
c UP = UBB
- 0,7 V
d UP = UBB
+ 0,7 V
165/ iu kin mch dao ng phng np s dng UJT hot ng tt l
a Dng in I > IV v t in 1 0,01TF C F >
b Dng in I < IP v I > I
V.
c Dng in IV > I > I
P v t in
d Dng in I < IP v t in 1 0,01TF C F >
166/ Khi SCR dn in, ta ngt dng in iu khin th SCR s ngng dn? a Sai. b ng. 167/ Tc dng ca dng in kch thch a vo cc G ca SCR l a Gim ht dn a s cho lp bn dn P
1.
b Gim ht dn thiu s cho lp bn dn N1
c Gia tng ht dn thiu s cho lp bn dn P2
d Gia tng ht dn a s cho lp bn dn P2
-
CHNG 7: VI MCH TCH HP (IC) Cu hi loi 1. 168/ Vi mch tch hp l cu kin c u im c bn: a Kch thc nh. b Tiu th t nng lng. c tin cy cao. d Tt c cc iu k y. 169/ Loi vi mch tch hp c sn xut v s dng nhiu nht l a Vi mch bn dn. b Vi mch mng mng. c Vi mch lai. d Vi mch mng dy. 170/ Cng ngh ch to vi mch bn dn l: a Cng ngh plana v plana-epitaxi. b Cng ngh bc hi v lng ng trong chn khng. c Kt hp tt c cc cng ngh ny. d Cng ngh quang khc. 171/ it trong vi mch c tch hp di dng a Tranzito c ni tt chn cc. b it nguyn th. c Mt lp tip xc P=N. d Mt t in. 172/ Vi mch khuch i thut ton thuc loi: a Vi mch lai. b Vi mch s. c Vi mch tuyn tnh. d T hp vi mch tranzito-it. 173/ Tng vo ca IC khuch i thut ton l b khuch i vi sai c: a m bo an ton cho cc tranzito trong IC. b Tr khng vo ln v h s khuch i ln. c Tr khng ra nh. d Di tn s lm vic rng. 174/ IC khuch i thut ton c a Mt li vo v mt li ra. b Hai li vo v hai li ra. c Hai li vo v mt li ra. d Ba li vo v mt li ra. 175/ Mt b khuch i thut ton tt cn c a H s khuch i vi sai ln v h s khuch i ng pha ln. b Tr khng vo ln v h s khuch i ng pha ln. c H s khuch i vi sai ln v h s khuch i ng pha nh. d H s khuch i vi sai nh v h s khuch i ng pha ln. 176/ Vi mch s hin nay c ch to trn c s:
-
a Ch cc tranzito trng. b Cc tranzito lng cc v tranzito trng. c Ch cc tranzito lng cc. d Cc tranzito, cc t in, cc in tr v cun dy. 177/ Vi mch s c s dng rng ri hin nay l loi a H TTL v h CMOS. b H RTL. c H DTL. d H TL. 178/ Vi mch nh l mt cu kin in t c kh nng: a Lu tr d liu v cc chng trnh iu khin di dng s nh phn. b Lu tr cc d liu di dng s nh phn. c Lu tr d liu v cc chng trnh iu khin di dng s thp phn. d Lu tr cc ch ci v cc ch s. 179/ ROM l b nh c kh nng c v vit? a Sai. b ng. 180/ RAM l b nh tm thi, khi mt in cung cp th tin tc trong n b xa ngay? a Sai. b ng. 181/ EPROM l b nh: a C th xa i v vit li. b Ch c vit mt ln do ngi sn xut. c C kh nng c/vit. d Ch c vit mt ln do ngi s dng. 182/ LSI l vi mch tch hp c cha a n 10 phn t. b Ln hn 100 phn t. c Ln hn 1000 phn t. d T 10 n 100 phn t. Cu hi loi 2. 183/ B khuch i thut ton c th khuch i: a C tn hiu xoay chiu (ac) v mt chiu (dc). b Ch tn hiu xoay chiu (ac). c Khng tn hiu xoay chiu (ac) v khng tn hiu mt chiu(dc). d Ch tn hiu mt chiu (dc). 184/ Tng vo ca mt b khuch i thut ton thng l: a B khuch i vi sai. b B khuch i cng sut ch B. c B khuch i mc cc pht chung (CE). d B khuch i cao tn. 185/ Ti tn s khuch i n v, h s khuch i in p ca b khuch i thut ton bng:
-
a KU = K
U0.
b KU = Zero
c KU = 1.
d 0 / 2U VK K= 186/ Tr khng vo ca b khuch i thut ton c tng vo dng JFET l: a Thp. b Trung bnh. c Cao. d Rt cao. 187/ Nu hai ngun cung cp ca mt b khuch i thut ton l 15 V, th in p ra cc i ca n l bao nhiu? a 15V b 12V c (12 14 )V V d 30V 188/ dc c tuyn truyn t ca b khuch i thut ton th hin a in p ra. b Tr khng vo. c H s khuch i in p. d Tr khng ra. 189/ Mt b khuch i thut ton c h s khuch i in p l 500.000. Nu in p ra l 1 V, th in p vo s l a 5 mV. b 10 mV. c 2 mV. d 2 V. 190/ tn s cao hn tn s ct, h s khuch i ca b khuch i thut ton gim vi tc a 10 dB/decade
b 2/2 dB/decade c 20 dB/decade d 0,707/decade. 191/ H s khuch i in p ca mt b khuch i thut ton bng 1 ti: a Tn s ct. b Tn s dao ng. c Di tn s lm vic. d Tn s khuch i n v. 192/ Mt IC 741C c cc tham s: a Tr khng ra khong 75 b H s khuch i in p bng khong 100.000 c Tt c cc tham s nu ra. d Tr khng vo khong 2 M
-
Cu hi loi 3. 193/ Cho mch nh hnh v. Hi h s khuch i ca mch l bao nhiu?
a Ku = 11 b Ku = -100 c Ku = -10 d Ku = 10 194/ H s khuch i in p ca mch l bao nhiu?
a Ku = -10 b Ku = 11 c Ku = -11 d Ku = 110
-
CHNG 8: CU KIN QUANG IN T Cu hi loi 1. 195/ Bc x nh sng l mt dng ca bc x in t c di tn s dao ng: a T Hz
1514 1010 b T Hz
96 1010 . c T Hz
108 1010 d T Hz
2019 1010 196/ Vng hng ngoi c bc sng : a T 100m 10 mm b T 780 nm 100m c T 380 nm 780nm d T 50 nm 380nm 197/ di bc sng bc x ca vt cht ph thuc vo: a Nng lng vng cm. b Nng tp cht trong vt cht. c S lng nguyn t ha hc c trong vt cht d Ha tr ca nguyn t vt cht 198/ LED hng ngoi l it c kh nng bc x a nh sng cc tm. b nh sng nhn thy. c nh sng hng ngoi. d Tt c cc loi nh sng k ra trn. 199/ Vng nh sng nhn thy c bc sng a T 380 nm 780nm b T 780 nm 100m c T 50 nm 380nm d T 100m 10 mm 200/ LED ch th l it c kh nng bc x a Tt c cc loi nh sng k ra trn. b nh sng hng ngoi. c nh sng nhn thy. d nh sng cc tm. 201/ Cc LED bc x cc bc sng khc nhau s c in p phn cc khc nhau? a Sai. b ng. 202/ Khi nhit lm vic tng th di bc sng bc x ca LED ngn li? a ng. b Sai. 203/ LED hng ngoi cu trc d th kp c thm:
-
a Hai lp giam gi ht dn v mt lp giam gi nh sng. b Ba lp giam gi ht dn v nh sng. c Hai lp giam gi ht dn. d Hai lp giam gi ht dn v nh sng. 204/ So vi vng ti hp, hng ro th nng ca hai lp giam gi ht dn trong LED d th kp a Thp hn. b Cao hn. c C th cao hn hoc c th thp hn d Bng nhau. 205/ Chit sut ca cht bn dn trong vng tch cc ca LED d th kp l a Thp nht b Cao nht. c Bng cc vng ln cn. d Bng zero. 206/ Hai dng c bn ca LED hng ngoi cu trc d th kp dng cho si quang l loi bc x b mt v loi bc x cnh a Sai. b ng. 207/ Cht bn dn dng ch to LASER phi c pha tp vi nng a Thp. b Trung bnh. c Khng xc nh d Rt cao. 208/ Cu trc ca it LASER phc tp hn ca LED c bn l a C nhiu lp giam gi ht dn hn. b C kch thc ln hn. c C nhiu lp bn dn hn. d C hc cng hng. 209/ Hc cng hng Fabry Perot ca it LASER c to ra nh: a Hai cnh bn x x ca LASER. b Hai lp giam gi ht dn trong cu kin. c Mt ci hp c ch to bn trong cu kin. d Hai gng phn chiu c nh hng. 210/ Mun LASER hot ng phi cp ngun phn cc thun cho cu kin? a Sai. b ng. 211/ c tnh quan trng ca LASER l: a c tuyn truyn t. b c tuyn vn-ampe. c c tuyn tn s. d c tuyn bc x. 212/ Mt ch th tinh th lng (LCD) l mt cu kin bn dn pht quang?
-
a ng. b Sai. 213/ LCD hot ng ta cn cp cho n mt in p a Xoay chiu hoc mt chiu u c. b Xoay chiu. c Xoay chiu khng ln in p mt chiu. d Mt chiu. 214/ Vt liu bn dn ch to in tr quang c gi l a Vt liu bn dn nhy quang. b Vt liu bn dn suy bin. c Vt liu bn dn cm quang. d Tt c cc tn gi trn. 215/ it quang hot ng khi n c phn cc thun? a Sai. b ng. Cu hi loi 2. 216/ LED ch th bc x nh sng mu c in p phn cc thun l: a U
D = 3,0 V
b UD = (2,0 2,2) V
c UD = (2,4 2,7) V
d UD = (1,6 1,8) V
217/ LED hng ngoi ch to t cht GaAs c in p phn cc thun l a U
D = (2,4 2,7) V
b UD = (2,0 2,2) V
c UD = (1,6 1,8) V
d UD
= 3,0 V
218/ Ngun sng ca LED l ng hng v c rng ph a Khong t (40 100) nm. b Khong < 2 nm. c Khong t (1 2) nm. d Khong t (2 40) nm. 219/ LASER bn dn l cu kin c kh nng a To ra nh sng c cng cao. b To ra nh sng t qu trnh hp th quang. c To ra nh sng ng hng v c rng ph ln. d To ra v khuch i nh sng n sc c tnh kt hp v pha. 220/ Tham s chnh ca LASER l: a Hiu sut lng t vi phn ngoi. b C ba phng n cn li. c Tn s cng hng. d rng ph bc x.
-
221/ Chiu di hc cng hng L ca LASER ln hn nhiu di bc sng bc x nn a C ba mt dc tn ti trong LASER. b C duy nht mt mt dc tn ti trong LASER. c C rt nhiu mt dc tn ti trong LASER. d C hai mt dc tn ti trong LASER. 222/ Khi chiu nh sng vo in tr quang th in tr ca n: a Gim xung. b Tng ln. c Khng xc nh d Khng i. 223/ nhy tng i ca in tr quang ph thuc vo quang ph chiu vo n? a Sai. b ng 224/ it quang hot ng da trn nguyn l: a Qu trnh bc x v qu trnh hp th quang trong cht bn dn b Qu trnh bc x t pht trong cht bn dn. c Qu trnh hp th quang trong cht bn dn. d Qu trnh bc x kch thch trong cht bn dn. 225/ it quang ch to t silic c nhy cao vng bc sng a T (0,56 0,65) m. b T (1,3 1,6) m. c T (0,65 0,85) m. d T (0,85 0,9) m. 226/ Ti sao i t quang loi PIN c nhy cao hn i t quang loi tip xc P-N? a V n c kh nng khuch i dng in quang ln M ln. b V n c lp tip xc P-N rng hn. c V n c vng hp th quang l bn dn nguyn tnh v kh rng. d V n c ch to t cht bn dn c nng tp cht cao. 227/ it quang thc c cu trc c bit nhm mc ch to ra vng c in trng mnh gi l vng thc to ra a Hin tng nhn in tch bi qu trnh ion ha do va chm. b Hin tng nhn in tch do pht x th cp c Hin tng nhn in tch do qu trnh hp th quang. d Hin tng tng dng in quang do s ti hp t ca cc ht dn 228/ So vi tranzito quang th it quang c: a Tn s hot ng thp hn nhng nhy cao hn. b Tn s hot ng cao hn v nhy cao hn. c Tn s hot ng cao hn nhng nhy thp hn. d Tn s hot ng v nhy xp x nhau. 229/ T bo quang in l cu kin bn dn c kh nng chuyn i tn hiu quang sang tn hiu in? a ng. b Sai.
-
230/ V mt cu trc c th coi tranzito quang nh mt mch tch hp gm c mt it quang v a it thng. b Mt tranzito thng. c Mt thyristo thng. d Mt LED. 231/ Trong thyristo quang, tn hiu quang ch c nhim v: a Khuch i in p. b Kch cho thyristo quang dn in v khuch i dng in qua n c Khuch i dng in. d Kch cho thyristo quang dn in. 232/ Cu to ca mt b ghp quang gm c a Mt it quang v mt tranzito quang. b Mt it pht quang (LED) v mt in tr quang. c Mt t bo quang in v mt cu kin thu quang. d Mt it pht quang (LED) v mt cu kin thu quang. 233/ Tham s quan trng nht ca b ghp quang l a in dung cch in. b H s truyn t dng in (CTR) c in th cch li. d in tr cch in. 234/ Dng tranzito quang Dacling tn nhm mc ch a Tng nhy ca tranzito quang. b Tng tn s hot ng. c Gim tr khng ra ca tranzito quang. d Tng tr khng vo ca tranzito quang. Cu hi loi 3. 235/ Tr s in tr cn thit mc ni tip vi LED c tnh theo cng thc:
a IU
R CCT =
b IUUR DCCT
+=
c IUR DT =
d IUUR DCCT
=
236/ iu kin c pht laser v bin l: I(2L) = I(0) vi I(2L)- mt trng quang ti Z = 2L; L- chiu di hc cng hng; I(0)- mt trng quang gc v v pha l: 1
2 Lje vi - hng s lan truyn ca nh sng? a ng. b Sai.
-
237/ nhy ca it quang c tnh theo cng thc
a 0
.P
hIS ph
=
b 0PI
S ph=
c .
0
phIPS =
d phIPS .0=
238/ So vi cc loi it quang th it quang thc APD yu cu ngun in cung cp a Cng ging nh cc loi it khc. b Cao. c Thp v n nh d Cao v n nh v nhit. 239/ Dng quang in trong tranzito quang c to nn l do a Cc ht dn l trng mi sinh ra trong qu trnh hp th quang b Cc ht in t t do mi sinh ra trong qu trnh hp th quang.. c Cc ht dn t phn pht khuch tn sang. d Cc ht dn mi sinh ra do qu trnh hp th quang trong phn gc ca cu kin. 240/ Dng in quang s cp I
ph ca it quang c tnh theo cng thc
a
( )fp
w
ph RLe
hPqI +
+=
11
10
b
( )fp
w
ph RLe
hPqI
+=
11
10
c
( )fp
w
ph RLe
hPI +
+=
11
10
d
( )fp
w
ph RLe
hPI
+=
11
10
241/ H s khuch i dng in quang trong it quang thc APD c tnh theo cng thc
a ( )ndtphM
ph VVIIM
/11
==
b ( )ndtM
phph VVI
IM
/11
==
c ( )dtphM
ph VVIIM
/11
+==
-
d ( )dtMph
ph VVII
M/1
1==
242/ Bc sng bc x nh l mt hm ca nng lng vng cm biu din bng cng thc
a )(24,1)(eVE
nmG
=
b )()(
eVEhm
G
=
c )(1240)(
eVEm
G
=
d )(24,1)(eVE
mG
=
243/ Hiu sut lng t ha ca i t quang c tnh theo cng thc:
a 0PI ph=
b
hPqI ph
//
0
=
c
hPI ph/0
=
d 0
/P
qI ph=
244/ Mt b ghp quang c dng vo l 2 mA, dng ra l 100 mA. Hi h s truyn t dng in l bao nhiu? a 5000% b 50% c 500% d 100% Cu hi loi 4. 245/ Mt laser ch to t Ga
1-xAl
xAs vi x = 0,15 th c E
G = 1,6 eV.
Hy tnh di bc sng bc x ra? a = 775 nm b = 1100 nm c = 1300 nm d = 1,55 m 246/ Nng lng nh sng c bc sng l 1550 nm l bao nhiu electron vn? a EG = 0,65 eV b EG = 1,43 eV c EG = 0,80 eV d EG = 0,75 eV
-
247/ Mt laser hot ng bc sng l 1100nm c chiu di hc cng hng L=500m v chit sut n = 3,7. Hi khong cch tn s bc x l bao nhiu? a f = 50 GHz b f = 81 GHz c f = 2,2 GHz d f = 68 GHz 248/ Mt laser hot ng bc sng l 1100nm c chiu di hc cng hng L=500m v chit sut n = 3,7. Hi khong cch bc sng bc x l bao nhiu? a = 1,1 nm b = 0,22 nm c = 0,5 nm d = 0,33 nm 249/ Mt it quang thc (APD) c dng in quang s cp l 0,25A v dng in nhn quang l 10A. Hi h s nhn M ca it ny l bao nhiu? a Mp
h = 400
b Mph = 25
c Mph = 2,5
d Mph = 40
250/ Mt photodiode c nhy l 0,65 A/W. Nu chiu ln n mt cng sut quang l P
0 = 10W. Hi dng quang in l bao
nhiu? a I
P = 6,5 A
b IP = 0,065 A
c IP = 6,5 mA
d IP = 10 A