neraca massa dan energi

3
Nama : Yulinda (061440410812) Kelas : 2EGB NERACA MASSA DAN ENERGI TUGAS 3 19. For the operation of a refrigeration plant it is desired to prepare a solution of sodium chloride containing 20% by weight of the anhydrous salt. a. Calculate the weight of sodium chloride that should be added to one gallon of water at 30⁰C in order to prepare this solution. (ans 2,070 lb) b. Calculate the volume of solution formed per gallon of water used, keeping the temperature at 30⁰C. (ans 1,090 gallons) Terjemahan : Untuk mengoperasikan mesin pendingin (refrigeration plant) dibutuhkan larutan yang mengandung 20% natrium klorida. a. Hitung berat natrium klorida yang harus ditambahkan kedalam 1 gallon air pada temperatur 30⁰C. (Jawaban 2,070 lb) b. Hitung volume larutan yang terbentuk per gallon of water pada temperatur 30⁰C. (Jawaban 1,090 gallons) Jawab NaCl = 20%

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chemical process principal (material and energy balance) chapter 3 Behavior of ideal gas. Problem no. 19

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Nama: Yulinda (061440410812)Kelas: 2EGB

NERACA MASSA DAN ENERGI TUGAS 3

19. For the operation of a refrigeration plant it is desired to prepare a solution of sodium chloride containing 20% by weight of the anhydrous salt. a. Calculate the weight of sodium chloride that should be added to one gallon of water at 30C in order to prepare this solution. (ans 2,070 lb)b. Calculate the volume of solution formed per gallon of water used, keeping the temperature at 30C. (ans 1,090 gallons)

Terjemahan :Untuk mengoperasikan mesin pendingin (refrigeration plant) dibutuhkan larutan yang mengandung 20% natrium klorida.a. Hitung berat natrium klorida yang harus ditambahkan kedalam 1 gallon air pada temperatur 30C. (Jawaban 2,070 lb)b. Hitung volume larutan yang terbentuk per gallon of water pada temperatur 30C. (Jawaban 1,090 gallons)

Jawab

NaCl = 20% H2O = 80% = 1 gallon = 1 gallon x = 0,1336 ft3

a) NaCl yang harus ditambahkan kedalam gallon of water NaCl = x H2O = x 1 gallon =0,25 gallon x = 2,08 lb

b) - pada 30oC = 0,9957 gr/cm3 = = 62,161 lb/ft3 - Spgr NaCl pada 30oC = 1,14- = x Spgr NaCl = 62,161 lb/ft3 x 1,14 = 70,86 lb/ft3 H2O = Volume H2O x = 0,1336 ft3 x 62,161 lb/ft3 = 8,304 lb Wtotal larutan = W NaCl + W H2O = 2,08 lb + 8,304 lb = 10,384 lb Volume larutan yang terbentuk = = = 0,1465 ft3 = 0,1465 ft3 x = 1,096 gallon