naming ions and naming and writing ionic compounds
TRANSCRIPT
Naming Ions and Naming and Writing Ionic Compounds
Monoatomic ions• cations lose valence electrons and therefore
are positively charged– transition metals form more than one cation
with different ionic charges– charge is determined from the # of
electrons lost• Fe2+ lost two electrons• Fe3+ lost three electrons
– naming• Stock system
– a Roman numeral is used to show the charge of the transition metal
» Fe2+ is iron(II) and Fe+3 is iron(III)
Naming Ions
Term DefinitionAg1+ silverCd2+ cadmiumZn2+ zincAu1+ gold(I)/aurousAu3+ gold(III)/auricCo2+ cobalt(II)/cobaltousCo3+ cobalt(III)/cobalticCr2+ chromium(II)/chromousCr3+ chromium(III)/chromicCu1+ copper(I)/cuprousCu2+ copper(II)/cupricFe2+ iron(II)/ferrousFe3+ iron(III)/ferricHg2
2+ mercury(I)/mercurousHg2+ mercury(II)/mercuricMn2+ manganese(II)Mn3+ manganese(III)Mn4+ manganese(IV)Ni2+ nickel(II)/nickelousNi3+ nickel(III)/nickelicPb2+ lead(II)/plumbousPb4+ lead(IV)/plumbicH1+ hydrogenH1- hydride
– anions gain valence electrons and therefore are negatively charged• change ending to -ide
Polyatomic ions• composed of more than one atom that
form a single unit/ion with a charge– most end with -ite or –ate
• the –ite ending indicates one less oxygen than the –ate ending
– ionic charge is the same for both
Naming ionic compounds• Binary Compounds
– cation is written first, followed by the anion with and –ide ending• Cs2O cesium oxide
• SrF2 strontium fluoride
• CuO copper(II) oxide– oxygen is always 2- and therefore copper will be 2+
• Cu2O copper(I) oxide– oxygen is 2- and therefore needed two copper
atoms with 1- charge
–SnF2 ?• fluorine is always 1- and therefore tin
will be 2+
–Stock system tin(II) fluoride–Traditional system stannous fluoride
–SnS2 ?• sulfur is always 2- and therefore tin will
be 4+
–Stock system tin(IV) sulfide–Traditional system stannic sulfide
Writing formulas for ionic compounds
• write symbol of cation and then anion
• add subscripts to balance the charges– calcium bromide
• Ca2+ and Br1- is CaBr2
– potassium sulfide
• K+1 and S2- is K2S
– iron(III) oxide
• Fe+3 and O2- is Fe2O3
crisscross method
• the ionic charge number of each ion is crossed over and becomes the subscript for the other ion
Formula to NameFe(NO3)3
Choose the correct name for the compound
1. Iron trinitrate
2. iron(I) nitrate
3. iron(III) nitrite
4. iron(III) nitrate
5. none of the abovenext
problemPolyatomic IonsPeriodic Chart
Name to Formulasodium chlorite
Choose the correct formula for the compound
1. NaCl
2. NaClO
3. NaClO2
4. Na(ClO)2
5. none of the above
next problem
PrefixesPeriodic Chart