mehmet m. kunt eastern mediterranean univeristy scipy 2010 june 28 … · 2014-02-02 · june...
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Mehmet M. KuntEastern Mediterranean Univeristy
SciPy 2010June 28‐ July 3Austin, Texas
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OutlineTransportation engineering teaching for civil engineering studentsObjectiveWhat is expected?Current SituationCoding of the ConceptExamplesBenefits
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Transportation engineering teaching in civil engineering
Third year courseFundamentals of transportation engineering in one semesterMost of the students have no background on transportation engineeringUse of commercial software is limited:
BudgetCommercial software are specialized so one software will not cover all the subjectsPython is versatile and flexible so any problem can be solved
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ObjectiveUsing a software tool that will help the students to
Understand the conceptCheck their hand calculation accuracyUse software for what‐if analysis
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What is expected?The students need to learn, understand and use engineering principles to solve the problems.
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Current SituationVisual examples as given in textbooks are limitedDoing what if analysis may take away precious teaching timeThe students may have problem in
Understanding the problem, how to solve it?Selecting the appropriate formula for the solutionUsing the right unit in the calculations (i.e., radians vsdegrees)
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Current SituationSurveying students on learning styles
Visual learning style is mainly usedProblem solving duration estimation
Hand calculation (with a calculator)Using Python
Post‐test survey of students
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Current SituationDuration in minutes for one problem
Surveying students on learning styles
Visual is most preferredProblem solving duration estimation
Hand calculation (with a calculator)Using Python
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Current Situation
Surveying students on learning styles
Visual is most preferredProblem solving duration estimation
Hand calculation (with a calculator)Using Python
Average duration = 5 min
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Coding of the conceptEquationsPython Code
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c
ss R
L2
=θ
cs RLA =4
5
40AL
LX sss −=
6
7
2
3
3366 AL
AL
Y sss −=
⎟⎠⎞
⎜⎝⎛= −
XYd 1tan
22 YXc +=
( )scs RYp θcos1−−=
scs RXk θsin−=
( ) ⎟⎠⎞
⎜⎝⎛ Δ+=
2tan' pRT c
sradcc LRL −Δ=
Spiral CurveInput:Δ, Rc, Ls
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Coding of the concept‐Python Modules
Python 2.6.5NumpyMatplotlib
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Coding of the concept‐Python Functions
Python 2.6.5Numpy
Degree to radian conversion (pi)Array calculationsArray statistics – average(), mean (), std()Linear algebra – lstsq()Trigonometric functions
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Portland Cement Concrete Pavement Thickness Design based on Costs of subbase and pavement
Vertical Curve – Sag or Crest, finding the lowest or highest point
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Limiting Stress
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CIVL361 TRANSPORTATION ENGINEERINGInstructor: Dr. Mehmet M. Kunt
Computer Name: datron-86c6bb17 Date : 2010-06-28IP Number is : 94.79.97.87
Input Variables=============================================================g1 = -2.7 %; g2 = 1.5 %; Length of the Curve = 3.5 sta=============================================================
RESULTS===========================================================THIS IS A SAG VERTICAL CURVE
Rate of change of grade is 1.200 %/StaLocation of lowest point is 2.25 sta from BVCStation of PI = 150 + 0 staElevation of PI = 25.0 mStation of BVC = 148 + 25 staElevation of BVC = 29.73 mStation of lowest point = 150 + 50 staElevation of lowest point = 26.69 m===========================================================
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CIVL361 TRANSPORTATION ENGINEERINGInstructor: Dr. Mehmet M. Kunt
Computer Name: datron-86c6bb17 Date : 2010-06-28IP Number is : 94.79.97.87
Input Variables=============================================================g1 = 2.7 %; g2 = -1.5 %; Length of the Curve = 3.5 sta=============================================================
RESULTS===========================================================THIS IS A CREST VERTICAL CURVE
Rate of change of grade is -1.200 %/StaLocation of highest point is 2.25 sta from BVCStation of PI = 150 + 0 staElevation of PI = 25.0 mStation of BVC = 148 + 25 staElevation of BVC = 20.27 mStation of highest point = 150 + 50 staElevation of highest point = 23.31 m===========================================================
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BenefitsTime savings (one problem for 24 students saved two‐8 hr day)Efficient, accurate, reliable problem solving environmentAllows the instructor to discuss more cases, advanced issueAllows build‐up of knowledge without forcing the students to memorize the examples or assumptionsThe attention will be on using the right input and obtaining the right decisions
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