mathematics objective questions part 11

8/19/2019 Mathematics Objective Questions Part 11

1/10

w w

w . e x a

m r a c e

. c o m

IC.S.E Pt

r-2t)(l3

I

of

ltl

M THEM TICS

2.

3,

-1.

5,

The number

of

elements m a.finite field is

ah ays a

3.

prime number

b. e1


2/10

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w . e x a

m r a c e

. c o m

11

12.

13

.

IS

16

,

W11ich of

the following

r i n ~

nrc integral

domoins7

L 2M

2. z,,

3.

~ l

4 z.,.

Select

the

tOrt OO

l

an

swer

using,

l.bC

e ~ J

giYen below:


3/10

w w

w . e x a

m r a c e

. c o m

2.3.

24.

Y jfj a=b+r and

z

fl

= ~

Which

of U>ese subsets of

e

vector s

pa

ce

f fi

q

is ar<

o ( • ) '

"· X o

nl

y

b. Y •nd

. .

X. Y •nd Z

tl.

X

and

Z

Lel

m

;

I)

be

o cube root of

[\

n

~

.

l h ~

dell::mtinttnl

Qf

lite rmoari.x 1

t

.,

'

is

t PI I

lL. ••

b.

-.'l

'

. ..

::>upi OSe P Is an n ·n n t a t r i . ~ u c l a

Llta

l

k '

dln8oruol olt ntcnl"ofPP

1

is :tao. Consid.:r

tho

o w ~ s

l.

tlo

e k'"

' ' ~ of

P

iS z.crpose

QfX.

a,

0

b. 2

c.

3

d. 4

26

27.

28.

29.

3 1.

oi 10

Let T be o linear tansformation from u 3-

dimen$ional •·ector s

pace

V into " 2-

dimcnsinAI

vector space

\V. Tltcri

T

a, can be both u>jective nor sul)eclive

II. C

io l>

c neith

er

injective r j c c l i v e

c.

cnn be

smjec

tn

•c:

but

uannol

be

surj

cf

tive

d.

can bo iJuecHvc: b

ut

cannot be

UJjCIJl

ive

Let \ V ~ , \V, ,\ \

7

3 be s p ~ C ~ ' S of 3

VCC

LOJ'li

s·pace Y

rod

1 llo•r W c Wt. Tiocn

which

one Qf the following is cQrrec

l?

•.

w,,-, f\V,• WJ

w,

. w,

,-

wl

b.

Wrn(

W

:+

W,

)=\V.

r+

Wr

- Wl

c. W

1

u (W:+ W

1

)=W:I WJ

d. None

orth.,

obo

vc

l

..t'

l

~ h

f.t

anti he

VC:C

I(In

uC

a vdC

II)r

sp•cc v

tJVI r lite

lii ld

I . T r

nod

ore

arbitrruy c lements ofF


4/10

w w

w . e x a

m r a c e

. c o m

b,

c 2

· 3

l f V l•

a vec[Qr • p•


5/10

w w

w . e x a

m r a c e

. c o m5.

c. - '- • -

1

= I

-J.

Ol

j l

b

n. J

cir ;; < b.b

7,.i,'f

I•

b,

J

;,

;;

Xb

l ;;_

bY

c.

p , --

h- - JJ.p h)

cl.

Jft axH>· r;.

i>>

0 1 ~ line 3x + -1) •

2"-0

C

UI. .

r.ho

lt

·axls olA

and

v-axis

at B.

11u:n

r.hc in center of lhe

lrianglcOAB, whcre.O is che origin is

.t. ( t. 2)

b. (2. 2 )

c.

(1

2.

1

2


6/10

w w

w . e x a

m r a c e

. c o m

54

55

Ul

ftx) x''

1/x

. when s

•

0

nnd

fl .s)

=

0 • when

x = ll

Then f\x) c

on

be

dinbn:ntiale ;llllthe

IWigin

providctl p

ia

o. Any rea I number

h,

Zero

c. One

il An lntoacr

)J'C:tler

limn

I

A 1mction llx) d i t f a c n t i ~ b l in the

d0$od

and

bounded i n l r n

[p.

ttl • rhe

di:flbrcrnial r (p)

und

f'(q)

arc such th

.o

t

f(p) 0

anci i '

(q) 0. llton

1lx1

wm

n

mt

me on

[p . qJ

11.

ncithct inlimutn nor supremum

b. surremum and notln Jmum

c infimum :md not Upremum

d. none of

he

above

S(i. CQru;ider

the fullowing

sta

tem"' lll:

I. "di:fferentioble function is continuous

2.

a

i n u ~ u .

f11n

etian

i• difter..-. linb lc

3.

u

cout:inuo

tlll

function

ou ;t

closod

intervol [o,

bJ qf

finite

g

un

ifo

nnly

continu o

u.< on

[4.b)

Which

of

h i:Jie


7/10

w w

w . e x a

m r a c e

. c o m

64

.

65

66.

,7

b

5N f(yl'()

c..

4..CF(y1x )

"·

4x

4

F'(ykl

l'he only double

po111

1

ofthe

"un·a

(X 2): - Y(Y 1

-

0 ; . :

u. (

~

1>. (V.Ol

c:. (2, IJ

d. (2, 2)

cqual tQ;

.o.

4u

b. uz

d. 2u

..

Let A., -

J

.,.

.

rib'. Then lloc of

Ao otAs is

II

18

b. 119

c:. J/ Hl

d. - I ' l l

'

i1Je .lfc or parabola

l =4ax

between the

points, where Ue latus

rectum.

and a Una

parallel

to

Uoc

latus rectum.

and :ol twicc

th

e

d i . ~ t a of l a l t ~ • rectum l'mm the

verle:<

meet t

he

par:obol•. ts l'eVolved abouLthe

l


8/10

w w

w . e x a

m r a c e

. c o m

I f n n

l ulture

of ye.ul .y

0

is

th

e am ount

of

)I

e

ast

p

rts

1

lima t and

if J

u b l t > ~ ~ in tluc

then 1he 11mount

c l c d

nf'ter 3 tloyK

equals

.-.

. 3yo

b.

s

y.,

c.

9y,

d 27yo

75 1f the r.ate u f growth ;, prqportional

tq

lh"

amo

unt

x of the su'bolton

oe presem and

dxl

dl

t.cx,

tben .'( ;., equal to (11illl C

1

c:onstMo)

a.


9/10

w w

w . e x a

m r a c e

. c o m

84. A plllticle

~ c t e d

ppon

by three f o r c e ~

w h o mngnltudes

al>

proportlunal

to

(t)

J .S.S;(lil 5. 7, 10: ~ n d (iii) 5. 7. 14:

oan

be

liOTonJ :c l

at

rest

a.

on in

e

ase tii)

b. OW) in t: :I •;t

ll

el fon.'t>l

. If P is

mn v"'tl

paraiJcl

tn illSolf thrQlgll a distance

or 4 em. U1cn lb.: n.:

li

uiiAnl tl T' und Q

mOV

e$ lhrougb •

dl

$lance of

S7

n_ tn1

b.

cm

"·

et11

p Q

'

d.

_: __ em

p

Q

rhe

r e s u

l ~ 1 n oflhe Ioree.' > a.od Q is R. If

Q

1;,

doubl

dd

lben

R gets doublod in

magnitude

J{ "

ogain doubled

if Q

i•

' ..... ..

reversed 'l'hen P'. Q· ond

R'

nre

in

the

rnt o

••

2 : 2

b,

3 : 2 : 2

c. 2 : 3 : 2

d. 2 : 3:3

SR. ·rwo force• P nn


10/10

w w

w . e x a

m r a c e

. c o m

t l

12 tilrle$

93. 51 ellen of a certain laJ18t13ge are to be

uniquely cOOed U.'iillQ KTriogs of6 bits, In

llli5 $)

litem

, h.uw m•ny

J l O S . ~ i b l o

non

ptinlable control chancter:s

can

be

uniquely coded'/

a.

()

b. 8

c.

L3

tL

77

'Vbl

cb of Ute foUel\\i ug logle

:tl

oj>l r ltions

equivalem lo lh• j iven oonn.;ction7

n.

A+(D. C)

b.

B

.C

e. A.

(B

+

C)

tL

B->tion

is perfonnt113

dme.

f

a. OOU(l010 I

b. 00101000

c. tll 0001100

d. 01100000

9/ ,

A

~ > T I

J I ( i \ ) lf

lhc ~ i l i o n of lite

resullnnt

uf

lw

li

pnmllcl forces which an:

like, remn ins nnnlle"'d when the forces

nre

int ~ .

"'

JH>int

r

on

t

\fl

tiW P

1-\C

•

: l>ltt R

is

1rue

9

8.

L ~ n

n

3 nod

let

the

comp

l

ex

nu

mbors

Ol. ,t:t.,_ ._ et, b< Ute rootl

l

\Vith 01.>"

1.

Assertl.on (A):

For

any

posltiw

i m ~ g e r

P

l , (I· 0.: ) ( · X

1

)

.

..

1

-(l,)

is : t g ~ i n a

positive mtegl f.

Reason

(R); For ;iny po>lrive inttg.:r t, (I·

u,) (t·

u,).

... hx..J

e q w l ~

mathematics objective questions part 11

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