marking scheme(a)
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8/6/2019 Marking Scheme(a)
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MARKING SCHEME
MATHEMATICSPMR
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20 Subjective Questions ( 60 marks )
Time : 1 hour 45 minutes
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Popular Topics
1. Fractions - ( 2 marks)2. Decimals ± (2 marks)
3. Integer s/ Dir ected Number s
± (2 marks)
4. Squar e ,Squar e Roots,Cubes, Cubes Roots
( 3marks )
5. Algebraic Expr essions ± 3
to 4 questions- ( 7 m )6. Linear Equations ± (3m)
7. Algebraic Formulae ± (3 m)
8. Geometr ical,constr uctions ± (6m)
9. Loci in Two Dimensions ±
(5 m)
10. Transformations ± (4m)
11.Statistics - (4 to 7m)
12.Indices ± (5m)
13.Linear Inequalities-(4m)
14.Graphs of Functions(4 m)
15. Tr igonometry ± (2m)
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1 Calculate the value of 3
2)6.0(14 z
. [ 2 marks ] Answer:
10
914
10
914
2
3
10
614
3
2
10
614
!
!
v!
z!
K1
N1
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1 Calculate the value of 3
2)6.0(14 z
. [ 2 marks ] Answer:
20
1814
20
1814
2
3
10
614
3
2
10
614
!
!
v!
z!
K1
N0
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1 Calculate the value of 3
2)6.0(14 z
. [ 2 marks ] Answer:
10
914
201814
20
1814
2
3
10
614
32
10614
!
!
!
v!
z!
K1
N1
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1 Calculate the value of 3
2)6.0(14 z
. [ 2 marks ] Answer:
9.14
9.014
10
9
14
2
3
10
614
3
2
10
614
!
!
!
v!
z!
K1
N1
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2 Calculate the value of ¹ º
¸©ª
¨v
3
2
5
4
8
11
and expr ess the answer as a f raction in its lowest term.
[ 2 marks ] Answer:
203
15
2
8
915
1012
8
9
!
v!
¹
º
¸©
ª
¨
v!
K1
N1
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2 Calculate the value of ¹ º
¸©ª
¨v
3
2
5
4
8
11
and expr ess the answer as a f raction in its lowest term.
[ 2 marks ] Answer:
12018
15
2
8
915
1012
8
9
!
v!
¹
º
¸©
ª
¨
v!
K1
N0
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2 Calculate the value of ¹ º
¸©ª
¨v
3
2
5
4
8
11
and expr ess the answer as a f raction in its lowest term.
[ 2 marks ] Answer:
12018
15
2
8
9
15
1012
8
9
!
v!
¹ º
¸©ª
¨
v!
K1
N1
20
3!
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3 (a) Find the value of 49.0
(b) Calculate the value of 3
116
25¹¹ º
¸©©ª
¨
[ 3 marks ]
= 0.7 P1
Answer:
(a)
(b)
64
1
4
1
1
4
5
3
3
!
¹ º
¸©ª
¨!
¹
º
¸©
ª
¨!
K1
N1
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3 (a) Find the value of 49.0
(b) Calculate the value of 3
116
25¹¹ º
¸©©ª
¨
[ 3 marks ]
= 0.7 P1
Answer:
(a)
(b)
64
1
8
1
1
4
5
2
3
!
¹ º
¸©ª
¨!
¹
º
¸©
ª
¨!
K0
N0
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y
x
R
R'
2 4 6 8
2
4
8
6
4. In Diagram 1, R ' is the image of R under transformation W.
Descr ibe in full transformation W
Answer:
Translation ¹¹
º
¸©©
ª
¨
4
6
translation 6 units to the r ight, 4 units down.
¹¹ º
¸©©ª
¨
4
6.
Translation or
P2Or
awar d P1 -
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y
x
R
R'
2 4 6 8
2
4
8
6
4. In Diagram 1, R ' is the image of R under transformation W.
Descr ibe in full transformation W
Answer:
Transilation ¹¹
º
¸©©
ª
¨
4
6
¹ º
¸
©ª
¨
4
6.
Translation
Or
P1
awar d P1 -
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y
x
R
R'
2 4 6 8
2
4
8
6
4. In Diagram 1, R ' is the image of R under transformation W.
Descr ibe in full transformation W
Answer:
Translation 4
6
)4,6(
.
Transilation
Or
P1
P0
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5 In Diagram 2, PQR is a straight line and PT = 3
1RS .
= 15
9
=
5
3
K1
N1
P R
T
5 c m 3 c m
S
y
Q
13 c m
Find the value of cos y º.
Answer :
(2 marks)
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5 In Diagram 2, PQR is a straight line and PT = 3
1RS .
=
15
9
=
RS
QR
K1N0
P R
T
5 c m 3 c m
S
y
Q
13 c m
Find the value of cos y º.
Answer :
(2 marks)
cos y º
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5 In Diagram 2, PQR is a straight line and PT = 3
1RS .
=
13
3
=
RS
QR
K0N0
If label QR = 9 cm or
label RS = 15 cm
Awar d B1
P R
T
5 c m 3 c m
S
y
Q
13 c m
Find the value of cos y º.
Answer :
(2 marks)
cos y º
9 cm
15 cm
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6 Diagram 3 shows a r ight pr ism with a squar e base.
3 cm
4 cm
Net of prism must be correct
The drawing of the net for the
Prism must be in actual
measurement or accor dingto actual scale
Accurate drawing
K1
K1
N1
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6 Diagram 3 shows a r ight pr ism with a squar e base.
3 cm
4 cm
Net of prism must be correct
The drawing of the net for the
Prism must be in actual
measurement or accor dingto actual scale
Accurate drawing
K1
K1
N0
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6 Diagram 3 shows a r ight pr ism with a squar e base.
3 cm
4 cm
Net of prism must be correct
The drawing of the net for the
Prism must be in actual
measurement or accor dingto actual scale
Accurate drawing
K0
K0
N0
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7. Diagram 4 is drawn on a squar e gr id paper. On the squar e gr id, draw
the image of tr iangle JKL under a 90º anticlockwise r otation
about the point P .
J
K L
P
J '
K '
L'
P2
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7. Diagram 4 is drawn on a squar e gr id paper. On the squar e gr id, draw
the image of tr iangle JKL under a 90º anticlockwise r otation
about the point P .
J
K L
P
'
P2
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7. Diagram 4 is drawn on a squar e gr id paper. On the squar e gr id, draw
the image of tr iangle JKL under a 90º anticlockwise r otation
about the point P .
J
K L
P
J '
K '
L'
P0
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8. Diagram 5 is a pie char t which shows the number of pupils
in five gr oups who complete an assignment dur ing a
motivational camp. ( 5 marks)
Tuah
10Jebat
x
Kasturi
2x
Lekiu
12
Lekir 8
It is given that the total number of pupils whoComplete the assignment is 36.
(a) Find the value of x
(b) Calculate the angle of the sector representing
the Tuah group. Show your working.
(C) State the mode of your data
Answer :
X = 2
r!
rv!
100
360
36
10
Mode = Lekiu
P2
P1
K1
N1
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8. Diagram 5 is a pie char t which shows the number of pupils
in five gr oups who complete an assignment dur ing a
motivational camp. ( 5 marks)
Tuah
10Jebat
x
Kasturi
2x
Lekiu
12
Lekir 8
It is given that the total number of pupils whoComplete the assignment is 36.
(a) Find the value of x
(b) Calculate the angle of the sector representing
the Tuah group. Show your working.
(C) State the mode of your data
Answer :
4
r!
rv!
100
1010
Mode = Lekiu , 12 P0
CJP1
K1
N1
2
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8. Diagram 5 is a pie char t which shows the number of pupils
in five gr oups who complete an assignment dur ing a
motivational camp. ( 5 marks)
Tuah
10Jebat
x
Kasturi
2x
Lekiu
12
Lekir 8
It is given that the total number of pupils whoComplete the assignment is 36.
(a) Find the value of x
(b) Calculate the angle of the sector representing
the Tuah group. Show your working.
(C) State the mode of your data
Answer :
X = 2
r!
rv!
100
360
36
10
Mode = Lekiu (12) P2
P1
K1
N1
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8. Diagram 5 is a pie char t which shows the number of pupils
in five gr oups who complete an assignment dur ing a
motivational camp. ( 5 marks)
Tuah
10Jebat
x
Kasturi
2x
Lekiu
12
Lekir 8
It is given that the total number of pupils whoComplete the assignment is 36.
(a) Find the value of x
(b) Calculate the angle of the sector representing
the Tuah group. Show your working.
(C) State the mode of your data
Answer :
X = 2
r!
rv!
100
360
36
10
Mode = Lekiu
Fr equency = 12
P2
P1
K1
N1
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2
2
9 Simplif y (2 x ± 3 ) ± (6 + 7 x )
Answer :
(2 marks)
= 4 x -12 x + 9 - 6 ± 7 x
± 19 x + 3
2
= 4 x 2
K1
N1
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2
2
9 Simplif y (2 x ± 3 ) ± (6 + 7 x )
Answer :
(2 marks)
= 4 x -12 x + 9 - 6 ± 7 x
± 19 x + 3= 4 x
K1
N0
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2
2
9 Simplif y (2 x ± 3 ) ± (6 + 7 x )
Answer :
(2 marks)
= 4 x -12 x + 9 - 6 + 7 x
± 5 x + 3
2
= 4 x 2
K1
N0
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10 (a) Solve the inequality 2 + x � 7.
(b) List all the integer value of x which satisf y both
the inequalites 1 ± x < 2 and 212
1e x [ 4 marks ]
Answer : (a) 5u x
(b)1- x < 2
-x < 2 - 1
-x < 1
x > -1
x = 0, 1, 2,3, 4, 5, 6
P1
K1K1
N1
6
23
122
1
212
1
e
ve
e
e
x
x
x
x
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10 (a) Solve the inequality 2 + x � 7.
(b) List all the integer value of x which satisf y both
the inequalites 1 ± x < 2 and 212
1e x [ 4 marks ]
Answer : (a) 5u x
(b)
x = 0, 1, 2, 3, 4, 5, 6
P1
K1
K0
N0
6e x
x < -1
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10 (a) Solve the inequality 2 + x � 7.
(b) List all the integer value of x which satisf y both
the inequalites 1 ± x < 2 and 212
1e x [ 4 marks ]
Answer : (a) 5u x
(b) x > -1
x = -1, 0, 1, 2, 3, 4, 5, 6
P1
K1
K1N0
6e x
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10 (a) Solve the inequality 2 + x � 7.
(b) List all the integer value of x which satisf y both
the inequalites 1 ± x < 2 and 212
1e x [ 4 marks ]
Answer : (a) 5u x
(b)
61 e x
x = 0, 1, 2, 3, 4, 5, 6
Note :
P1
N1
K1K1
6e x
x < -1