NORAFIQAH BINTI ABDULLAH ED229U6A 2009854406

Lesson Plan

Class : 4 Zamrud

Date : 11th May 2012

Time : 8.30 – 9.00 am (30 minutes)

Topic : 5.0 The straight line

Learning Objectives : By the end of this lesson, student should be able to

1. Understand the concept of gradient of a straight line in Cartesian coordinates.

Learning Outcomes : By the end of the lesson, student should be able to:

1. Derive the formula for the gradient of a straight line.

2. Calculate the gradient of the straight line passing through two points and formulate the equation of

the straight line.

Teaching Aids : Power Point Presentation, white board marker pen and worksheet.

Teaching method : Group discussion.

Attitude and value : Co-operation, respect and confident.

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NORAFIQAH BINTI ABDULLAH ED229U6A 2009854406

Step / time Contents Teaching and Learning Activities

Teacher’s Role Student’s Role

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NORAFIQAH BINTI ABDULLAH ED229U6A 2009854406

Set Induction

( 3 minutes)

The concept of gradient of a straight line.

Gradient of AB

Vertical displacement

= Horizontal displacement

1) Teacher show the animation of the cartoon skiing down the hill using slide show.

Teacher asks the students about this animation.

What is actually doing by that cartoon?

What is represented by the action of cartoon skiing down the hill?

2) Then, teacher gives another two pictures that represent different stiffness of slope.

1) Students give answer for the question that teacher asks.

The cartoon is skiing down the hill.

The action of the cartoon skiing down the hill represents the hill has the slope.

2) Students give answer for the questions asks by the teacher.

The left picture show a group

3

A

B

Horizontaldisplacement

Verticaldisplace-ment

y

NORAFIQAH BINTI ABDULLAH ED229U6A 2009854406

Step / time Contents Teaching and Learning Activities

Teacher’s Role Student’s Role

Development 1

( 10 minutes)

1) Deriving the formula for the gradient of a straight line.

1) Teacher introduces the definition of the gradient by using slide show.

2) Teacher displays a diagram with a straight line in the Cartesian coordinate system.

Example 1 :

3) Teacher asks the following questions : a) What is the gradient of PQ?b) What is the coordinate of point P?c) What is the coordinate of point Q?d) How do you know that?

1) Students take note on the definition of the gradient of a straight line.

2) Student answers the questions based on their knowledge.

Expected answer (a):

Gradient of PQ

Vertical displacement= Horizontal displacement

=

Expected answer (b) :

Expected answer (c) :

4B

Verticaldisplacement

xP

Q

0

Vertical displacement

Horizontal displacement

= 5 units

= 4 units

A

B

NORAFIQAH BINTI ABDULLAH ED229U6A 2009854406

Step / time Contents Teaching and Learning Activities

Teacher’s Role Student’s Role

Example 2 :

3) Teacher asks students to state the vertical and horizontal displacement.a) What is the vertical and horizontal

displacement of this figure?

4) Teacher asks students to determine the gradient of AB.

3) Students answer the question by counting the units and give the answer.

Expected answer :

Vertical = 6 unitsHorizontal = 3 units

4) Students give answer by using the formula as below.

Gradient of AB, mAB,

Vertical displacement= Horizontal displacement

=

= 2

5

1

7

x 1

y

4

NORAFIQAH BINTI ABDULLAH ED229U6A 2009854406

Step / time Contents Teaching and Learning Activities

Teacher’s Role Student’s Role

Gradient,

= the change in y -coordinate

the change in x-coordinate

=

5) Teacher asks students : -

How do you find the vertical and

horizontal displacement when the

diagram without table grid?

6) Teacher makes a generalization of the

formula for the gradient of a straight line.

The change in y-coordinate

=

The change in x-coordinate

=

5) Students can get the vertical and

horizontal displacement by

subtraction.

6) Student can derive the formula for

gradient of a straight line in Cartesian

coordinate.

Gradient, m

= the change in y -coordinate

the change in x-coordinate

=

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NORAFIQAH BINTI ABDULLAH ED229U6A 2009854406

Step / time Contents Teaching and Learning Activities

Teacher’s Role Student’s Role

Calculate the gradient of a straight line.

Formula for the gradient of a straight line passing through

and is :

m =

7) Teacher asks students to use the formula to determine the gradient in the diagram.

Example 1 :

Gradient of PQ,

mPQ = =

=

= 1

7) Students use the formula to determine the gradient.

7

x

y

NORAFIQAH BINTI ABDULLAH ED229U6A 2009854406

Step / time Contents Teaching and Learning Activities

Teacher’s Role Student’s Role

8) Then, teacher asks the student what would happen to the gradient if they choose P as and Q as .

9) Using the same example, teacher explain that if the position changes, gradient remains the same.

Example 2 :

y

8) Students give the answer of the question.

Expected answer:The gradient is still the same.

9) Students take note to teacher’s explanation.

8

x0

NORAFIQAH BINTI ABDULLAH ED229U6A 2009854406

Step / time Contents Teaching and Learning ActivitiesTeacher’s Role Student’s Role

Development 2( 10 minutes)

2) Calculate the gradient of the line and formulate the equation of the line.

Then, teacher asks the student to find the gradient of that straight line passing through PQ.

1) Teacher introduces and teaches students about the equation of the straight line using the aid of PowerPoint presentation.

Students give the answer.

Expected answer:Gradient of PQ,

mPQ =

=

=

= 1 1) Students write the notes on teacher’s explanation on the equation of the straight line.

Teaching and Learning Activities

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NORAFIQAH BINTI ABDULLAH ED229U6A 2009854406

Step / time Contents Teacher’s Role Student’s Role2) Teacher provides example to the student using slides.

3) Teacher provides another example to make students more clearly understand about these subtopics.

2) Students copy the example given by the teacher.

3) Students copy and take note on the example given by the teacher.

Step / time Contents Teaching and Learning Activities

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NORAFIQAH BINTI ABDULLAH ED229U6A 2009854406

Teacher’s Role Student’s RoleExercise( 5 minutes)

1) Teacher gives some exercise using slides show as ‘enrichment exercise’.

2) Teacher distributes the handout to students.

3) Teacher asks students to complete the

1) Students take the handout and discussed with their friends.

2) Students complete the handout given by the teacher.

3) Students involve in answer discussion in the class.

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NORAFIQAH BINTI ABDULLAH ED229U6A 2009854406

Conclusion( 2 minutes)

.

exercise in 5 minutes before discussed the answer in the class.

1) Teacher recall about today’s lesson.

2) Today they learnt how to derive the gradient of the line and to formulate the equation of straight line.

1) Students give respond to teacher about today’s lesson.2) Students volunteer to state the steps to formulate the equation of the straight line.

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