lecture 3: enzyme kinetics km dan vmax i. introduction 1. basic enzyme reactions 1. enzyme...
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LECTURE 3:ENZYME KINETICS
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After the completion of the lecture and masteringthe lecture materials, students will be able to1. to explain enzyme substrate interaction in the
conversion of substrate to product2. to explain the order of chemical reactions3. to explain enzyme kinetics particularly the rate of
reactions as a function of substrate concentration4. to calculate KM and Vmax of reactions catalyzed by
enzymes5. to explain characteristics of enzymes based kinetic
analysis of enzymatic reactions
LECTURE OUTLINEI. INTRODUCTION
1. Definition2. Basic Enzyme
Reactions3. The rate of reaction
II. ENZYME-SUBSTRATEINTERACTION1. Lock and Key"
Hypothesis2. The "Induced Fit"
1. The formation of ESComplex
3. Initial VelocityAssumption
4. Total EnzymeIV. PENETUAN KM DAN
I. INTRODUCTION1. Basic Enzyme Reactions
1. Enzyme kinetics is the study of thechemical reactions that are catalyzedby enzymes or the study of the rates ofenzyme-catalyzed reactions.
The branch of chemistry which deals with the ratesof chemical processes is known as chemical kinetics
2. Enzymes, functioning as catalysts, increase thespeed of a chemical reactions, and are not used upin the reactions.The basic enzymatic reaction can be represented asfollowsS + E P + E (1)where E = enzyme, S = substrate, and P = product ofthe reaction.
3. A theory to explain the catalytic action of enzymeswas developed by Savante Arrhenius in 1888, aSwedish chemist. He proposed that the substrate (S)and enzyme (E) formed some intermediatesubstance known as the enzyme substrate complexas shown below.S + E ES (2)
4. If this reaction is combined with the original reactionequation (1), the following results:S + E ES P + E (3)
5. The existence of an intermediate enzyme-substratecomplex has been demonstrated in the laboratory, forexample, using catalase and a hydrogen peroxidederivative.
6. At Yale University, Kurt G. Stern in 1937 observedspectral shifts in catalase as the reaction it catalyzedproceeded.- This experimental evidence indicates that the
enzyme first unites in some way with the substrateand then returns to its original form after thereaction is concluded.
2. The rate of reaction1. The rate of reaction (V) is the quantity of substrate
(S) converted to product, or the amount product (P)produced per unit time.
2. Reactions follow zero order kinetics whensubstrate concentrations are high.- Zero order means there is no increase in the
rate of the reaction when more substrate isadded.Zero orderSP
Where V is the rate (velocity) of reaction
Order Rate Commentszero k rate is independent of substrateconcentrationfirst k[S] rate is proportional to the first power ofsubstrate concentration
second k[S][S]=k[S]2 rate is proportional to the square of the
k[S1][S2]rate is proportional to the first power ofeach of two reactants
The rate of enzymatic reaction is influenced bythe interaction of enzyme and substrate.
The two types of interaction between enzymeand substrate1. Lock and Key" Hypothesis2. The "Induced Fit" Hypothesis
1. "Lock and Key" Hypothesis- Emil Fischer in 1890 proposed "Lock and Key"
- The shape, or configuration (form in space), of theactive site is especially designed for the specificsubstrate involved.
- As the active site is made up of protein, the formof active site in space (configuration) isdetermined by the amino acid sequence of theenzyme in the active site.
- It is also important that the native configuration of theentire enzyme molecule must be intact for the activesite to have the correct configuration.
- In such a case, the substrate then fits into the activesite of the enzyme in much the same way as a keyfits into a lock.
- Enzyme examples follow the lock and key hypothesisare RNase A, cyclophilin A, and dihydrofolatereductase (Sullivan & Holyoak, 2008)
2. The "Induced Fit" Hypothesis- Enzymes are highly flexible, conformationally
dynamic molecules.- Many of their remarkable properties, including
substrate binding and catalysis, are due to theirstructural pliancy.
- Realization of the conformational flexibility ofproteins led Daniel Koshland to hypothesize that thebinding of a substrate (S) by an enzyme is aninteractive process.
- The shape of the enzyme's active site is actuallymodified upon binding S, in a process of dynamicrecognition between enzyme and substrate aptlycalled induced fit.
In essence, substrate binding alters the conformationof the protein, so that the protein and the substrate "fit"each other more precisely.
The process is truly interactive in that the conformationof the substrate also changes as it adapts to theconformation of the enzyme. An example of enzymefollow Induced-fit hypothesis is Rubisco.
Induced Fit Model
Hexokinase has a large induced fit motion that closesover the substrates adenosine triphosphate (ATP) andxylose.
Hexokinase catalyzesthe following reaction.
Gucose + ATP Glucose-6P + ADP
Binding sites in blue,substrates in blackand Mg2+ cofactor inyellow. (PDB: 2E2N ,2E2Q)
III. MICHAELIS-MENTEN MODELLeonor Michaelis and Maud L. Menten proposed ageneral theory of enzyme action in 1913 whilestudying the hydrolysis of sucrose catalyzed by theenzyme invertase.
1. The formation of ES Complex Their theory was based on the assumption that the
enzyme (E) and its substrate (S) associate reversiblyto form an enzyme-substrate complex, ES
k1E + S ES E + Pk2k3k4
E = Enzyme, S = Substrate, P = Product, ES = Enzyme-Substratecomplex , and k1, k2, k3 & k4 = rate constants. k4 is very small andignored
For instance, the breakdown of sucrose toglucose and fructose through a hydrolysisreaction catalyzed by sucrase (invertase)
Sucrose + H20 Glucose + Fructose If environmental factors
are constant, the rate ofproduct formation(reaction rate of velocity,V) is dependent uponthe concentration ofenzyme and substrate
- [E] = enzyme concentration- [S] = substrate concentration
Effect of [E] to study the effect of increasing the [E] upon the
reaction rate, the substrate must be present in anexcess amount so that the reaction is independentof the [S].[S][E]
The formation of productproceeds at a rate which islinear with time.
Any change in the amount ofproduct formed over a specified
[S] is constant
period of time is dependent upon the level ofenzyme present.
The reactions with the rates independent ofsubstrate concentration but equal to someconstant k are said to be "zero order" .
The influence of [S] The concentration of substrate [S] greatly
influences the rate of product formation (thevelocity of a reaction, V)- Studying the effects of [S] on the velocity of a
reaction is complicated by the reversibility of enzymereactions, e.g. conversion of product back tosubstrate
- To overcome this problem, initial velocity (V0)measurements are used. At the start of a reaction, [S] is in large excess of [P] [S][P]
thus the initial velocity of the reaction (V0) will bedependent on substrate concentration [S]
When initial velocity is plotted against [S], a hyperboliccurve is found and characterized by an approximatelyconstant maximum of reaction rate (Vmax)
High [S]Saturating [E]
Vmax represents the maximum reaction velocity This occurs at [S] >> E, and all available enzyme is
"saturated" with bound substrate, meaning only theES complex is present
The association/dissociation of ES complex isassumed to be a rapid equilibrium, and theenzyme:substrate dissociation constant is Ks.At equilibrium,k2[ES] = k1[E][S]and
2. Steady-State Assumption The interpretations of Michaelis and Menten were
refined and extended in 1925 by Briggs andHaldane, by assuming [ES] quickly reaches aconstant value in such a dynamic system.
That is, ES is formed rapidly from E + S, anddisappears by its two possible fates- dissociation to regenerate E + S, and- reaction to form E + P
This assumption is termed the steady-stateassumption and is expressed as
3. Initial Velocity Assumption Enzymes accelerate the rate of the reverse
reaction as well as the forward reaction, then theconversion of E+P to ES or k4[E][P] = k3[ES]
If we observe only the initial velocity for thereaction immediately after E and S are mixed inthe absence of P, the rate of any back reaction isnegligible.
Therefore, k4[E][P] = 0 as [P] is essentially 0which gives
k1E + S ES E + Pk2k3
Given such simplification, the system described byequation above is analyzed in order to describethe initial velocity V as a func