lecture 2 - electrical and electonic principles
TRANSCRIPT
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8/17/2019 Lecture 2 - Electrical and Electonic Principles
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Electrical andElectronic
PrinciplesLECTURE # 2BYHYATT QURESHI
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Recap
• Defne car!e" crrent" $olta!e
• E%plain te &or'in! o( )H*+s LA,
• E%plain te di-erence .et&een f%ed and $aria.leresistor
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E%plain te di-erence .et&een Resistors in series aResistors in Parallel
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In tis lectre" /o &ill learn 0
• 1indin! E-ecti$e resistance
• Anal/se te &or'in! o( Cople% Resistor 3et&or's
• Circit desi!nin! (or Resistor 3et&or's
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E-ecti$e Resistance
Te $ale o( one sin!le resistor tat cold replace all oter resistors in te net&or'4
Yo can do tis in con$enient sta!es" pro!ressi$el/redcin! te n.er o( resistors in te net&or' ./co.inin! series and parallel resistors4
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Resistance 3et&or's
A net&or' is a co.ination o( parallel and seriescircits4 In order to fnd te total resistance" te circst .e .ro'en do&n step ./ step ./ identi(/in! teseries and parallel circits and replacin! te &it asin!le resistor4 Te (ollo&in! e%aple so&s tis4
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Resistance 3et&or's
1ind te total resistance (or te net&or'so&n and calclate te crrents I6 and I2
1irst identi(/ t&o series circits and replace te ./ sin!le resistors427 8 97 5 :7 6; 8 6=:7 8 6=9;? 5 2;4@6 '4
Te total crrent is IT5 =RT 5 6;7=2;@67 5 7477;< Ap;4< A4
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Sol$e te total resistance andcrrent4
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Sol$e te total resistance andcrrent4
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• Ans&ers0 E-ecti$e Resistance is ;;249: and Crre749;2 A
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Circit Desi!nin! (or Resistors
Resistors o( 62 " 9 and 27 are a$aila.le4 So& te aid o( la.elled circit s'etces" o& can t&o or o( tese .e arran!ed to prodce te (ollo&in! resista$ale
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•Resistors o( ; " ; and ; are a$aila.le4 So& &
te aid o( la.elled circit s'etces" o& can t&o orore o( tese .e arran!ed to prodce te (ollo&inresistance $ale
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Resistors o( 2@ "
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IRCH)11S CURRE3T LA, RULE
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irco-+s Crrent La& states tat
J Te Al!e.raic s o( te crrent present at a KnctinodeF in a circit is ero4M
I68 I28 I
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Tis rle concerns te crrents No&in! in and ot o( a Knction4 It sipl/ states tat te total crrent enterin Knction eOals te total crrent lea$in! te Knction4Consider 9 condctors carr/in! crrents into and ot Knction as so&n4
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Si!n con$ention
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Crrent No&in! to&ards te Knction is Positi$e 8F• Crrent No&in! a&a/ (ro te Knction is 3e!ati$e
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Sppose I6 5 2 Aps" I< 5 9 Aps and I9 5 @ ADeterine I2 4
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I68 I28 I
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Calclate te crrents I6 and I2 in te net&.elo&4
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